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Key Facts: EGEL Plus Ingeniería en Biotecnología Exam

201

Total items on the official EGEL Plus BIOTEC (141 disciplinary + 60 transversal)

Ceneval, Guía para el sustentante EGEL Plus BIOTEC

9 hours

Two sessions of 4.5 hours each on the same day

Ceneval, Guía para el sustentante EGEL Plus BIOTEC

1000

Minimum Índice Ceneval for a Satisfactorio level in an area or section

Ceneval, Guía para el sustentante EGEL Plus BIOTEC

1150

Minimum Índice Ceneval for a Sobresaliente level

Ceneval, Guía para el sustentante EGEL Plus BIOTEC

MXN 1,885

Individual national Examen desde casa fee in 2026

Ceneval EGEL portal

Ceneval's EGEL Plus BIOTEC is a 201-item, nine-hour Spanish exit exam: 141 disciplinary items in three areas plus 60 transversal language and communication items.

Sample EGEL Plus Ingeniería en Biotecnología Practice Questions

Try these sample questions to review concepts for the EGEL Plus Ingeniería en Biotecnología exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1An enzyme-catalyzed reaction follows standard Michaelis-Menten kinetics with a maximum velocity Vmax = 120 μmol/(min·mg) and a Michaelis constant Km = 4.0 mM. What is the initial reaction rate (v) when the substrate concentration [S] is 6.0 mM?
A.72.0 μmol/(min·mg)
B.48.0 μmol/(min·mg)
C.80.0 μmol/(min·mg)
D.180.0 μmol/(min·mg)
Explanation: According to the Michaelis–Menten equation, v = (Vmax · [S]) / (Km + [S]) = (120 · 6.0) / (4.0 + 6.0) = 720 / 10.0 = 72.0 μmol/(min·mg). At a substrate concentration 1.5 times Km, the rate is 60% of Vmax.
2A Lineweaver-Burk double-reciprocal plot (1/v versus 1/[S]) yields a straight line described by the linear regression equation y = 0.25x + 0.05, where 1/v is in (μmol/min)⁻¹ and 1/[S] is in mM⁻¹. What are the values of Vmax and Km for this enzymatic system?
A.Vmax = 0.05 μmol/min, Km = 0.25 mM
B.Vmax = 20 μmol/min, Km = 5.0 mM
C.Vmax = 4.0 μmol/min, Km = 0.20 mM
D.Vmax = 20 μmol/min, Km = 0.20 mM
Explanation: In the Lineweaver-Burk equation 1/v = (Km/Vmax)·(1/[S]) + 1/Vmax, the y-intercept equals 1/Vmax and the slope equals Km/Vmax. Given y-intercept = 0.05 (μmol/min)⁻¹, Vmax = 1 / 0.05 = 20 μmol/min. With slope = 0.25 mM⁻¹·(μmol/min)⁻¹, Km = slope · Vmax = 0.25 · 20 = 5.0 mM (or from the x-intercept = -1/Km = -0.05/0.25 = -0.20 mM⁻¹, Km = 1/0.20 = 5.0 mM).
3A purified recombinant industrial biocatalyst is evaluated in the presence of a reversible inhibitor. Kinetic assays indicate that the apparent Km increases from 2.5 mM to 7.5 mM, while the maximum velocity Vmax remains unchanged at 150 μmol/(min·mg). Which type of inhibition does this observation demonstrate?
A.Non-competitive inhibition
B.Uncompetitive inhibition
C.Competitive inhibition
D.Irreversible suicide inhibition
Explanation: Competitive inhibitors bind reversibly to the free enzyme's active site, competing directly with substrate binding. This increases the apparent Km (reflecting reduced apparent affinity) because higher substrate concentrations are required to displace the inhibitor, while high [S] completely outcompetes the inhibitor to achieve the same true Vmax.
4A solution of a purified therapeutic single-chain antibody fragment (molar mass = 28,000 g/mol) is analyzed in a 1.00 cm path length quartz cuvette. At 280 nm, the absorbance is 0.840. Given a theoretical molar absorptivity (extinction coefficient) ε280 = 42,000 M⁻¹·cm⁻¹, what is the mass concentration of the antibody fragment in mg/mL?
A.0.84 mg/mL
B.1.26 mg/mL
C.0.020 mg/mL
D.0.56 mg/mL
Explanation: By the Beer-Lambert law, A = ε · b · c. Therefore, molar concentration c = A / (ε · b) = 0.840 / (42,000 M⁻¹·cm⁻¹ · 1.00 cm) = 2.00 × 10⁻⁵ M (or mol/L). To convert to mass concentration: (2.00 × 10⁻⁵ mol/L) · (28,000 g/mol) = 0.560 g/L = 0.56 mg/mL.
5A sample from a high-cell-density bioreactor culture of Escherichia coli is diluted for spectrophotometric quantification. A 0.20 mL aliquot of the culture broth is diluted with physiological saline to a final volume of 5.00 mL. The optical density at 600 nm (OD600) of this diluted sample is measured as 0.360 in the linear range. What is the true OD600 of the original fermentation broth?
A.9.00
B.8.64
C.0.0144
D.1.80
Explanation: The dilution factor (DF) is the ratio of final volume to initial aliquot volume: DF = 5.00 mL / 0.20 mL = 25. The original optical density is obtained by multiplying the measured optical density by the dilution factor: OD600_original = 0.360 · 25 = 9.00.
6In SDS-PAGE analysis of proteins, sodium dodecyl sulfate (SDS) and beta-mercaptoethanol (or DTT) perform distinct roles during sample preparation. Which statement accurately describes the specific molecular function of beta-mercaptoethanol in this analytical technique?
A.It imparts a uniform negative charge-to-mass ratio along the polypeptide backbone
B.It reduces covalent disulfide bridges between cysteine residues to linearize multisubunit complexes
C.It stains the polyacrylamide gel matrix to allow fluorometric quantification
D.It establishes a discontinuous pH gradient between the stacking and resolving gels
Explanation: Beta-mercaptoethanol is a reducing agent that cleaves inter- and intra-molecular covalent disulfide bonds (–S–S–) between cysteine residues, ensuring that polypeptide subunits completely dissociate and unfold into individual linear chains. SDS provides the uniform negative charge-to-mass ratio and hydrophobic denaturation.
7When designing a plasmid expression vector for high-level recombinant protein synthesis in Escherichia coli, which regulatory element must be placed upstream of the start codon (ATG) to ensure efficient recruitment and positioning of the 30S ribosomal subunit on the mRNA transcript?
A.Kozak consensus sequence
B.TATAAT Pribnow box
C.Shine-Dalgarno sequence
D.Polyadenylation signal (AATAAA)
Explanation: The Shine-Dalgarno sequence is the prokaryotic ribosome binding site (consensus sequence AGGAGG), located approximately 6 to 10 nucleotides upstream of the initiation codon. It base-pairs complementarily with the 3' end of the 16S ribosomal RNA in the 30S ribosomal subunit to properly position the initiation complex for translation.
8A biotechnology research team aims to insert a 1.8 kb gene encoding an industrial xylanase into an expression plasmid. They choose to digest both the insert and vector with two different restriction enzymes that generate non-complementary sticky ends (e.g., EcoRI and HindIII). What is the primary operational advantage of this dual-digestion cloning strategy?
A.It enables the recombinant construct to replicate stably in both Gram-negative and Gram-positive hosts without an origin of replication
B.It increases the chemical stability of the phosphodiester bonds against exonuclease degradation
C.It eliminates the necessity of using T4 DNA ligase and ATP in the ligation reaction
D.It prevents self-ligation (recircularization) of the vector and enforces directional (sense-oriented) insertion of the gene
Explanation: Using two different restriction enzymes that generate distinct, non-complementary overhangs (directional cloning) prevents the linearized vector from recircularizing on itself and forces the DNA insert to anneal and ligate in one specific orientation relative to the promoter.
9During aerobic batch fermentation of Saccharomyces cerevisiae for bioethanol or baker's yeast production, high concentrations of glucose (>0.15 g/L) lead to ethanol formation despite fully aerobic conditions and high dissolved oxygen levels. Which physiological phenomenon causes this metabolic overflow?
A.Crabtree effect (aerobic fermentation / glucose repression)
B.Pasteur effect
C.Warburg effect in prokaryotes
D.Stringent response triggered by uncharged tRNAs
Explanation: The Crabtree effect (glucose effect) occurs in Crabtree-positive yeasts like Saccharomyces cerevisiae when high external glucose concentrations accelerate glycolysis beyond the capacity of the pyruvate dehydrogenase complex and respiratory chain, while glucose also represses respiratory gene expression, shunting pyruvate into ethanol fermentation even under aerobic saturation.
10A culture of Escherichia coli is inoculated into a minimal medium containing both glucose and lactose. The culture exhibits diauxic growth with two distinct exponential phases separated by a lag period. What molecular mechanism accounts for the preferential consumption of glucose and the temporary silencing of the lac operon during the first phase?
A.High intracellular levels of cyclic AMP (cAMP) bind to CAP, displacing RNA polymerase
B.Glucose transport via the PEP-PTS system keeps adenylate cyclase inactive, lowering cAMP levels and preventing CAP-cAMP activation of the lac promoter
C.Lactose repressor protein (LacI) is irreversibly degraded by an ATP-dependent Lon protease in the presence of glucose
D.Glucose directly acetylates lactose permease, leading to rapid lysosomal degradation of the transporter
Explanation: Catabolite repression in E. coli operates via the phosphoenolpyruvate:sugar phosphotransferase system (PEP-PTS). During glucose uptake, unphosphorylated EIIA^Glc accumulates and inhibits adenylate cyclase, resulting in low intracellular cAMP levels. Without the cAMP-CAP activator complex, RNA polymerase cannot efficiently initiate transcription at the lac promoter even if allolactose is present.

About the EGEL Plus Ingeniería en Biotecnología Exam

Independent EGEL Plus Ingeniería en Biotecnología practice by OpenExamPrep. The official Ceneval examination is in Spanish and has 201 three-option items: 141 disciplinary items in Sistemas biológicos y herramientas analíticas en biotecnología, Ingeniería de producción biotecnológica, and Ingeniería de los bioprocesos y caracterización del bioproducto, and 60 transversal Lenguaje y Comunicación items. This bank is an English-language study adaptation with four-option multiple-choice questions, not an official translation or format simulation. Disciplinary stems and explanations are in English. Language and communication items keep their Spanish passages and answer options, because Spanish usage is the skill being tested, and give their instructions and explanations in English.

Exam sponsor: Centro Nacional de Evaluación para la Educación Superior (Ceneval). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

201 three-option items: 141 disciplinary items (Sistemas biológicos y herramientas analíticas en biotecnología 54, Ingeniería de producción biotecnológica 33, Ingeniería de los bioprocesos y caracterización del bioproducto 54) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.

Time Limit

Two sessions of 4.5 hours each on the same day (9 hours in total)

Passing Score

Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación

Exam / Certification Fees

MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

54 of 141 disciplinary items

Sistemas biológicos y herramientas analíticas en biotecnología

Biochemistry and metabolism (19), cell biology and genetics (10), microbiology (11), and molecular biology and genetic engineering (14)

33 of 141 disciplinary items

Ingeniería de producción biotecnológica

Bioreactor engineering (11), culture systems (10) and kinetic parameters (12)

54 of 141 disciplinary items

Ingeniería de los bioprocesos y caracterización del bioproducto

Cell disruption and solid-liquid separation (17), concentration (9), purification (11) and finishing (8) of bioactives or products, and design of the separation bioprocess (9)

60 of 201 total items

Lenguaje y Comunicación

Reading comprehension of academic, literary and public-interest texts (30 items) and indirect writing, which asks candidates to choose the version of a text that is correct, coherent and well punctuated (30 items)

Preparing for the EGEL Plus Ingeniería en Biotecnología Exam

What You Need to Know

  • Passing score: Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación
  • Assessment: 201 three-option items: 141 disciplinary items (Sistemas biológicos y herramientas analíticas en biotecnología 54, Ingeniería de producción biotecnológica 33, Ingeniería de los bioprocesos y caracterización del bioproducto 54) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.
  • Time limit: Two sessions of 4.5 hours each on the same day (9 hours in total)
  • Exam / certification fees: MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount Official sources

Using Our Practice Resources

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EGEL Plus Ingeniería en Biotecnología: Suggested Study Strategy

1Review quantitative biochemistry: Michaelis-Menten rates, Lineweaver-Burk plots, inhibition patterns, glycolysis yields and Beer-Lambert protein quantification.
2Master bioreactor engineering equations: Monod growth, yields, chemostat dilution and washout, oxygen transfer (kLa and OTR), impeller power and Reynolds number, and the sterilization Del factor.
3Downstream processing carries 54 of the 141 disciplinary items: practice cell disruption kinetics, centrifuge scale-up, cake filtration, ultrafiltration with rejection, chromatography sizing, and overall process yield.
4Know the logic of a separation train (removal of insolubles, isolation, purification, polishing) and design heuristics for placing expensive steps.
5Prepare for Lenguaje y Comunicación by reading academic articles, essays and public notices in Spanish, and by reviewing agreement, punctuation, accentuation and connectors.

Frequently Asked Questions

What is the EGEL Plus Ingeniería en Biotecnología?

The EGEL Plus Ingeniería en Biotecnología (EGEL Plus BIOTEC) is Ceneval's national exit examination for graduates of the Licenciatura en Ingeniería en Biotecnología and related programs. It measures the knowledge and skills considered indispensable at the end of the degree, plus Spanish reading comprehension and indirect writing. Institutions may use the result as a graduation requirement, a titulación option or part of a course grade, under their own rules; a Testimonio does not by itself determine the award of the degree or the cédula profesional.

How many questions are on the official EGEL Plus BIOTEC and how long is it?

The official exam has 201 items: 141 disciplinary items (Sistemas biológicos y herramientas analíticas en biotecnología 54, Ingeniería de producción biotecnológica 33, Ingeniería de los bioprocesos y caracterización del bioproducto 54) and 60 Lenguaje y Comunicación items (30 reading comprehension and 30 indirect writing). It is given on one day in two sessions of 4.5 hours each (9 hours). About 15% of the items are pilot items that do not count toward the result.

How is the EGEL Plus BIOTEC scored?

Each area and section is reported on the Índice Ceneval from 700 to 1300: 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio and 1150-1300 Sobresaliente. The global result follows a conjunctive rule weighted toward the disciplinary section: Satisfactorio or better in the disciplinary section earns at least a Testimonio de Desempeño Satisfactorio, while a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación. Candidates with a global Sobresaliente who take the exam for the first time within one year of finishing the degree are eligible for the Premio Ceneval al Desempeño de Excelencia-EGEL.

Can I use a calculator or formula sheet on the EGEL Plus BIOTEC?

Yes. The official guide allows a non-programmable scientific calculator, which may not be shared between candidates. No formula sheet is listed among the permitted materials, so memorize the formulas you need.

Why is this practice bank in English if the official exam is in Spanish?

The official Ceneval exam is in Spanish. This bank is an independent English-language study adaptation with four-option questions, not an official translation or format simulation. Disciplinary questions and explanations are in English so you can review the engineering content. Language and communication items keep their Spanish passages and options because they test Spanish usage, and their instructions and explanations are in English.

How does EGEL Plus Ingeniería en Biotecnología differ from EGEL Plus Química and Biología?

It is a separate exam for biotechnology engineering graduates. Its structure gives most weight to biological systems and analytical tools (54 items) and to bioprocess separation and product characterization (54 items), with 33 items on biotechnological production engineering (bioreactors, culture systems and kinetics).