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100+ Free BCS Written EEE (892) Practice Questions

Prepare for the BCS Written Post-Related Electrical and Electronics Engineering, Subject Code 892 exam with instant access — no signup required.

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Key Facts: BCS Written EEE (892) Exam

892

BPSC subject code for post-related Electrical and Electronics Engineering

Official BCS written syllabus PDF

200 marks

Post-related written paper (Part I 100 + Part II 100)

Official BCS written syllabus PDF

50% aggregate

Written-stage pass on the 900-mark written examination

BPSC BCS examination page

Tk. 200 / Tk. 50

50th BCS application fee (general / reduced categories)

50th BCS circular reporting citing PSC; confirm live circular

4 hours

Duration used for BPSC 200-mark written papers on this site

Longstanding BPSC sitting practice; confirm current routine

Descriptive

Official item type (not MCQ)

BPSC written examination structure

BPSC Subject Code 892 is a 200-mark, typically 4-hour descriptive EEE paper (Part I/II, 100 marks each) inside the 900-mark written stage. Written pass is 50% aggregate on 900 marks (BPSC page). Application fee is Tk. 200 general / Tk. 50 reduced (50th BCS), with no separate written fee. This page offers 100 English MCQs as a study aid, not an official-paper simulation.

Sample BCS Written EEE (892) Practice Questions

Try these sample questions to test your BCS Written EEE (892) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A 24 V DC source is connected across an 8 Ω resistor. What is the current?
A.3 A
B.8 A
C.16 A
D.192 A
Explanation: Ohm’s law states I = V/R. Substituting the given values gives I = 24/8 = 3 A. Power would be P = VI = 72 W, but the question asks only for current.
2At a circuit node, 4 A and 2 A enter and 3 A leaves. What current must leave through the remaining branch to satisfy KCL?
A.1 A
B.6 A
C.9 A
D.3 A
Explanation: Kirchhoff’s current law requires the algebraic sum of currents at a node to be zero: currents in equal currents out. Incoming 4 A + 2 A = 6 A, so if 3 A already leaves, the remaining outgoing current is 3 A.
3An 18 V source feeds 3 Ω in series with 6 Ω. What is the voltage across the 6 Ω resistor?
A.6 V
B.9 V
C.12 V
D.18 V
Explanation: Series current is I = 18/(3+6) = 2 A. Voltage across 6 Ω is IR = 12 V, which is also the voltage-divider result 18 × 6/9. The 3 Ω resistor takes the remaining 6 V.
4A 6 Ω resistor is in parallel with a 3 Ω resistor. What is the equivalent resistance?
A.9 Ω
B.4.5 Ω
C.1 Ω
D.2 Ω
Explanation: For two parallel resistors, Req = R1 R2/(R1+R2) = 18/9 = 2 Ω. Equivalently, 1/Req = 1/6 + 1/3 = 1/2, so Req = 2 Ω. Parallel equivalent is always smaller than the smallest branch (3 Ω).
5Two voltage sources share a mesh: 10 V and an opposing 5 V with 2 Ω and 3 Ω in series around the loop. What is the mesh current?
A.0.5 A
B.1 A
C.2 A
D.3 A
Explanation: KVL around the mesh: 10 − 2I − 3I − 5 = 0, so 5 = 5I and I = 1 A. The net voltage driving the loop is the difference of the sources; the resistances add because they are in series in that mesh.
6Maximum power is transferred to a load when the load resistance equals:
A.Zero
B.Infinity
C.The Thevenin resistance seen by the load
D.Twice the Thevenin resistance
Explanation: The DC maximum-power-transfer theorem states that PL is maximised when RL = RTh (the Thevenin resistance of the network attached to the load). For AC networks the match is to the complex conjugate of ZTh.
7A 12 V source has 4 Ω in series, then a 12 Ω shunt to ground. What are VTh and RTh at the shunt terminals (load removed)?
A.12 V and 4 Ω
B.9 V and 3 Ω
C.9 V and 4 Ω
D.6 V and 3 Ω
Explanation: With the load removed, VTh is the open-circuit voltage on the 12 Ω branch: voltage divider 12 × 12/(4+12) = 9 V. RTh is 4 Ω in parallel with 12 Ω after deactivating the independent source (replace 12 V by a short): 4 || 12 = 3 Ω.
8For the same network (VTh = 9 V, RTh = 3 Ω), the Norton equivalent current is:
A.3 A
B.9 A
C.27 A
D.1 A
Explanation: Norton current is IN = VTh/RTh = 9/3 = 3 A, which is also the current through a short placed at the load terminals. The Norton resistance equals RTh = 3 Ω in parallel with the current source.
9A Thevenin source VTh = 12 V, RTh = 4 Ω feeds a matched load. What is the maximum power delivered to the load?
A.36 W
B.18 W
C.12 W
D.9 W
Explanation: With RL = RTh, load current is VTh/(2 RTh) = 12/8 = 1.5 A, so PL = I² RL = 2.25 × 4 = 9 W. Equivalently Pmax = VTh²/(4 RTh) = 144/16 = 9 W. Half of the source power is dissipated in RTh.
10A sinusoidal voltage is v(t) = 170 sin(ωt) V. What is its RMS value (nearest volt)?
A.170 V
B.85 V
C.240 V
D.120 V
Explanation: For a sinusoid, Vrms = Vm/√2. 170/√2 ≈ 120.2 V, which is the standard 120 V RMS associated with a 170 V peak. Average of a full-period sine is zero; the 85 V figure is a half-cycle average, not RMS.

About the BCS Written EEE (892) Exam

BCS Written Post-Related Electrical and Electronics Engineering (Subject Code 892) is the 200-mark technical paper for Bangladesh Civil Service technical/professional cadre and dual-cadre applicants whose post-related subject is EEE. The official BPSC syllabus splits 100 marks of circuits, machines, power systems, and power plants (Part I) and 100 marks of electronics, communications, microprocessors, and control (Part II). The live paper is descriptive. This free bank is an English-language MCQ study adaptation—not an official translation, format simulation, or substitute for written calculation and essay practice.

Assessment

Technical/professional cadre written stage is 900 marks, including this 200-mark post-related EEE paper (Part I 100 marks: circuits, machines/transformers, power system, power plant; Part II 100 marks: electronics and power electronics, communication, microprocessor and interfacing, control systems). Official answers are handwritten. This bank is an English MCQ study aid only.

Time Limit

4 hours (duration used for BPSC 200-mark written papers on this site and in longstanding BPSC sitting practice; confirm the current routine)

Passing Score

50% aggregate on the 900-mark written examination (BPSC page), plus per-paper minima as set by BPSC. Confirm the current circular.

Exam Fee

Tk. 200 general (50th BCS); Tk. 50 reduced categories; no separate written/viva fee. Confirm the live circular. (Bangladesh Public Service Commission (BPSC))

BCS Written EEE (892) Exam Content Outline

13%

Part I — Electrical Circuits

Basic R, L, C; Ohm’s law; nodes; Kirchhoff’s laws; mesh/nodal analysis; Thevenin, Norton, superposition, and maximum power transfer; RLC resonance and filters; AC and three-phase power.

16%

Part I — Electrical Machines and Transformers

Induced EMF, DC generators and motors, synchronous machines, three-phase and single-phase induction motors, stepper motors, and single- and three-phase transformers including OC/SC tests and connections.

13%

Part I — Power System

Single-line and per-unit models, short/medium/long lines, symmetrical and unsymmetrical faults, swing equation and equal-area criterion, FACTS, HVDC, circuit breakers, and protective relays.

8%

Part I — Power Plant Engineering

Load curves and plant factors, thermal/hydro/nuclear and barge-mounted plant, renewables, heat rate and incremental cost, bus layouts, and reactor shielding basics.

20%

Part II — Electronics and Power Electronics

Diodes, BJT/FET amplifiers, op-amps, oscillators, digital combinational and sequential logic, ADC/DAC, and converters using SCR, MOSFET, IGBT, choppers, and inverters.

13%

Part II — Communication Engineering

Noise and channel capacity, AM/FM/PM, sampling, PCM/DM, ASK/PSK/FSK, spread spectrum, and TDM/FDM/CDMA.

9%

Part II — Microprocessor and Interfacing

8086 real-mode addressing, flags, interrupts and 8259A, 8255A PPI, 8254 timer, converters, and DMA.

8%

Part II — Control Systems

System classification, transfer functions, signal-flow graphs, Routh–Hurwitz, error constants, root locus, and PI/PD/PID cascade compensation.

How to Pass the BCS Written EEE (892) Exam

What You Need to Know

  • Passing score: 50% aggregate on the 900-mark written examination (BPSC page), plus per-paper minima as set by BPSC. Confirm the current circular.
  • Assessment: Technical/professional cadre written stage is 900 marks, including this 200-mark post-related EEE paper (Part I 100 marks: circuits, machines/transformers, power system, power plant; Part II 100 marks: electronics and power electronics, communication, microprocessor and interfacing, control systems). Official answers are handwritten. This bank is an English MCQ study aid only.
  • Time limit: 4 hours (duration used for BPSC 200-mark written papers on this site and in longstanding BPSC sitting practice; confirm the current routine)
  • Exam fee: Tk. 200 general (50th BCS); Tk. 50 reduced categories; no separate written/viva fee. Confirm the live circular.

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

BCS Written EEE (892) Study Tips from Top Performers

1Weight revision 50/50 between Part I (circuits, machines, power, plants) and Part II (electronics, communications, 8086, control), matching the official 100/100 split.
2Practise full numeric workings for Ohm/KVL, Thevenin, AC rms and three-phase power, transformer EMF and efficiency, slip, and converter duty-cycle relations—the live paper is calculation-heavy.
3For protection and FACTS, name the actual device or relay characteristic (mho, IDMT, STATCOM, UPFC) rather than a vague ‘protective gear’ phrase.
4After MCQ drill, write timed long answers: equivalent circuits, phasor diagrams, and one-line fault sketches, because the official format is descriptive.
5Confirm fees, age, viva marks, and the written routine from the current BPSC circular; do not treat a previous cycle’s logistics as frozen.

Frequently Asked Questions

What is BCS Written Electrical and Electronics Engineering (Subject Code 892)?

It is the 200-mark post-related written paper for BCS technical/professional cadre (and dual-cadre) applicants whose designated subject is Electrical and Electronics Engineering. BPSC splits it into Part I and Part II, 100 marks each.

Is the official paper multiple choice?

No. The official BPSC paper is descriptive (written calculations, derivations, and long answers). This bank is an English-language MCQ study adaptation, not an official translation, format simulation, or substitute for handwriting practice.

How many questions are on the official EEE paper?

BPSC does not publish a fixed item count for Subject Code 892. The paper is specified as 200 marks, not as a published number of MCQs.

What is the written pass mark?

The BPSC page requires 50% aggregate on the 900-mark written examination, with per-paper minima as set by BPSC. Confirm the circular for the cycle you are sitting.

How long is the paper?

BPSC 200-mark written papers are treated on this site as 4-hour sittings, matching longstanding BPSC practice. Confirm the duration on the current written routine.

What is the application fee?

For the 50th BCS the published fee is Tk. 200 general and Tk. 50 for ethnic-minority, persons-with-disabilities, and third-gender applicants, paid via Teletalk. There is no separate written or viva fee. Confirm the live circular.

What does the viva carry?

The BPSC examination page still lists viva voce as 200 marks with a 50% pass. News coverage from the 47th BCS onward has reported a 100-mark viva, and PSC has discussed reducing it further. Confirm the current circular rather than assuming either figure.

In what language is this practice bank?

Official BCS written papers may be answered in Bangla or English as permitted. This bank is an original English-language MCQ study adaptation of the BPSC EEE syllabus, not an official BPSC paper or translation.