3.1 Percentages, Profit, Loss & Discount Calculations
Key Takeaways
- Memorizing fraction-to-percentage equivalents up to 1/20 speeds up SBI PO Quantitative Aptitude calculations by eliminating long division.
- Successive percentage changes follow the net change formula x + y + (xy / 100), where increments are positive and decrements are negative.
- Profit and loss percentages are calculated on Cost Price (CP), whereas discounts are always computed on Marked Price (MP).
- The CP-to-MP ratio formula MP / CP = (100 + Profit %) / (100 - Discount %) directly solves multi-step markup and discount problems.
- Dishonest trader calculations depend on actual goods delivered versus revenue charged: Profit % = (Error / False Weight) * 100.
Percentages, Profit, Loss & Discount Calculations
Percentages and Profit & Loss form the foundation of Quantitative Aptitude in banking examinations. In the SBI PO exam, direct arithmetic questions and complex Data Interpretation (DI) sets heavily rely on fast percentage computations and profit dynamics. Mastering fraction conversions, successive changes, and dishonest trader concepts is essential to solve questions within tight sectional time limits.
1. Percentage Fundamentals & Fraction Equivalents
A percentage represents a fraction with a denominator of 100. Converting percentages into simplified fractions enables rapid mental math during calculation-heavy sections.
Essential Fraction-to-Percentage Reference Table
| Fraction | Percentage | Decimal Equivalent | Fraction | Percentage | Decimal Equivalent |
|---|---|---|---|---|---|
| 1/2 | 50.00% | 0.50 | 1/11 | 9.09% | 0.0909 |
| 1/3 | 33.33% | 0.3333 | 1/12 | 8.33% | 0.0833 |
| 1/4 | 25.00% | 0.25 | 1/13 | 7.69% | 0.0769 |
| 1/5 | 20.00% | 0.20 | 1/14 | 7.14% | 0.0714 |
| 1/6 | 16.67% | 0.1667 | 1/15 | 6.67% | 0.0667 |
| 1/7 | 14.28% | 0.1428 | 1/16 | 6.25% | 0.0625 |
| 1/8 | 12.50% | 0.1250 | 1/17 | 5.88% | 0.0588 |
| 1/9 | 11.11% | 0.1111 | 1/18 | 5.55% | 0.0555 |
| 1/10 | 10.00% | 0.1000 | 1/20 | 5.00% | 0.0500 |
Percentage Increase, Decrease & Product Constancy
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Percentage Change Formula:
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Product Constancy Rule: If $A \times B = C$, and $A$ increases by $\frac{1}{x}$, then to keep $C$ constant, $B$ must decrease by $\frac{1}{x + 1}$.
- Example: If the price of petrol increases by 25% (which is $\frac{1}{4}$), consumption must decrease by $\frac{1}{4+1} = \frac{1}{5} = 20%$ to keep expenditure unchanged.
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Successive Percentage Changes: If a value undergoes successive percentage changes of $x%$ and $y%$, the effective net percentage change is: (Note: Use positive values for increases and negative values for decreases.)
2. Profit, Loss & Marked Price Core Principles
Understanding financial terminology is critical for solving word problems:
- Cost Price (CP): Price at which an item is purchased, including overhead expenses.
- Selling Price (SP): Price at which an item is sold to a buyer.
- Marked Price (MP): Price printed on the tag (List Price).
- Profit / Loss: Profit occurs when $SP > CP$; Loss occurs when $CP > SP$.
- Discount: Reduction offered on the Marked Price: $\text{Discount} = MP - SP$.
Fundamental Formulas
| Concept | Standard Formula | Multiplier / Fraction Shortcut |
|---|---|---|
| Profit % | $\left(\frac{SP - CP}{CP}\right) \times 100$ | $SP = CP \times \left(1 + \frac{P%}{100}\right)$ |
| Loss % | $\left(\frac{CP - SP}{CP}\right) \times 100$ | $SP = CP \times \left(1 - \frac{L%}{100}\right)$ |
| Discount % | $\left(\frac{MP - SP}{MP}\right) \times 100$ | $SP = MP \times \left(1 - \frac{D%}{100}\right)$ |
| CP-MP Relation | $\frac{MP}{CP} = \frac{100 + \text{Profit %}}{100 - \text{Discount %}}$ | Direct ratio bridging CP and MP |
Golden Rule: Profit and Loss percentages are ALWAYS computed on the Cost Price (CP) unless explicitly instructed otherwise. Discount is ALWAYS computed on the Marked Price (MP).
3. Step-by-Step Worked Math Examples
Worked Example 1: Net Percentage & Expenditure Adjustments
Problem: The price of sugar rises by 30%. By what percentage should a household reduce its sugar consumption so that total expenditure increases by only 4%?
Step-by-Step Solution:
- Let initial Price $= P_1 = 100$ and initial Consumption $= C_1 = 100$. Initial Expenditure $= 100 \times 100 = 10,000$.
- New Price $P_2 = 100 + 30% \text{ of } 100 = 130$.
- Desired New Expenditure $= 10,000 + 4% \text{ of } 10,000 = 10,400$.
- Let new consumption be $C_2$. Then $130 \times C_2 = 10,400 \implies C_2 = \frac{10,400}{130} = 80$.
- Reduction in consumption $= 100 - 80 = 20$.
- Percentage reduction $= \left(\frac{20}{100}\right) \times 100 = 20%$.
Worked Example 2: Markup, Discount, and CP-MP Ratio
Problem: A trader marks his goods 40% above the cost price and grants a discount of 15% to cash buyers. If he makes a profit of ₹380, find the cost price of the goods.
Step-by-Step Solution:
- Let Cost Price ($CP$) $= 100x$.
- Marked Price ($MP$) $= 100x + 40% \text{ of } 100x = 140x$.
- Discount $= 15% \text{ of } 140x = 0.15 \times 140x = 21x$.
- Selling Price ($SP$) $= MP - \text{Discount} = 140x - 21x = 119x$.
- Profit $= SP - CP = 119x - 100x = 19x$.
- Given Profit $= ₹380 \implies 19x = 380 \implies x = 20$.
- Therefore, $CP = 100 \times 20 = ₹2,000$.
Worked Example 3: Dishonest Shopkeeper & False Weights
Problem: A merchant claims to sell wheat at a 5% loss on cost price, but uses a false weight that measures 800 grams instead of 1 kilogram. Calculate his net profit percentage.
Step-by-Step Solution:
- Let the Cost Price of $1,000\text{ g}$ of wheat be ₹$1,000$ (so $1\text{ g} = ₹1$).
- The merchant claims a 5% loss on CP, so his Selling Price for $1\text{ kg} (1,000\text{ g})$ is ₹$1,000 - 5% \text{ of } 1,000 = ₹950$.
- However, he actually delivers only $800\text{ g}$ of wheat to the customer.
- Actual cost incurred by the merchant for $800\text{ g} = ₹800$.
- Net Profit $= \text{Revenue} - \text{Actual Cost} = 950 - 800 = ₹150$.
- $\text{Net Profit %} = \left(\frac{150}{800}\right) \times 100 = \frac{150}{8} = 18.75%$.
4. Advanced SBI PO Exam Strategies & Common Traps
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Selling Two Items at Same SP: If two items are sold at the same selling price, one at a profit of $x%$ and the other at a loss of $x%$, there is ALWAYS an overall net loss given by: Trap: Candidates often assume the net effect is 0% profit/loss. Remember that $CP$ values differ, creating an overall loss.
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"Buy X Get Y Free" Offer Discount Formula: Example: "Buy 3 Get 2 Free" yields a discount of $\frac{2}{3+2} \times 100 = \frac{2}{5} \times 100 = 40%$.
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Successive Discounts Shortcut: For two successive discounts $d_1%$ and $d_2%$, single equivalent discount is:
A shopkeeper offers two successive discounts of 20% and 15% on an article. What is the single equivalent discount percentage?
A dishonest trader claims to sell sugar at cost price but uses a false weight of 850 grams instead of 1 kilogram. What is his exact profit percentage?
An article costing ₹800 is marked up to yield a 25% profit even after granting a 20% discount. What is the marked price of the article?
A trader sells two watches for ₹2,400 each. On one watch he gains 20%, and on the other he loses 20%. What is his overall gain or loss percentage?