8.2 Heat Transfer Coefficients and Overall U

Key Takeaways

  • The film (convective) coefficient h appears in Q̇ = h A ΔT_film; small h means large thermal resistance 1/(hA).
  • Resistances in series add: process film + wall conduction + utility film (+ fouling layers) for a composite barrier.
  • Overall heat transfer coefficient U is defined by Q̇ = U A ΔT_overall, so 1/(UA) equals the sum of the individual resistances (with area basis stated).
  • Fouling factors R_f increase thermal resistance over time as deposits build; dirty exchangers need higher ΔT or more area for the same duty.
  • Plant maintenance—cleaning, filtration, proper velocities, and water treatment—protects design U and energy efficiency on Qatar process units.
Last updated: August 2026

8.2 Heat Transfer Coefficients and Overall U

Quick Answer: Each film has resistance 1/(hA); a wall has L/(kA). Sum series resistances to get 1/(UA). Then Q̇ = U A ΔT. Fouling factors add more resistance as deposits grow—cleaning and good fluid quality protect U.

Section 8.1 defined h and k. Equipment design almost never uses a single film alone: heat crosses two fluids and a wall (plus dirt). The overall heat transfer coefficient U packages that stack so duty calculations stay compact. On UPDA/MMUP Chemical Domain C, expect conceptual questions about controlling resistance, dirty vs clean U, and what happens when one film coefficient changes.

Film Coefficient h in Equipment Language

For one convective surface:

Q̇ = h A (T_surface − T_bulk)

If h is…Resistance 1/(hA) is…Temperature drop across that film is…
Large (turbulent liquid, boiling)SmallSmall for a given Q̇
Small (gas film, natural convection, viscous oil)LargeLarge—this side “controls”

Rule of thumb: The side with the smallest h (largest film resistance) often dominates the overall resistance unless the wall is thick insulation or heavy fouling intervenes.

What Raises h?

  • Higher velocity / turbulence (higher Re) for single-phase forced flow
  • Higher fluid thermal conductivity (helps Nu and the fluid k in h = Nu k/L)
  • Phase change (boiling/condensation) when properly designed
  • Inserts, fins, or enhanced surfaces (raise effective A or disrupt films)

What Lowers h?

  • Laminar flow, low velocity, high viscosity
  • Gas instead of liquid on that side
  • Maldistribution, bypassing, or stratified two-phase regimes (advanced plant issues)

Resistances in Series

For steady heat flow through layers with no accumulation, the heat rate Q̇ is the same through each layer. Temperature drops add:

ΔT_total = Q̇ (R₁ + R₂ + R₃ + …)

Plane-Wall Composite (Same Area A)

Imagine process fluid | fouling | metal wall | fouling | utility fluid:

LayerResistance
Process film1 / (h_h A)
Process-side foulingR_f,h / A (if R_f is a fouling factor in m²·K/W)
Metal wallL / (k_w A)
Utility-side foulingR_f,c / A
Utility film1 / (h_c A)

Then:

1 / (U A) = 1/(h_h A) + R_f,h/A + L/(k_w A) + R_f,c/A + 1/(h_c A)

Cancel A (same area basis):

1/U = 1/h_h + R_f,h + L/k_w + R_f,c + 1/h_c

U then satisfies:

Q̇ = U A ΔT

where ΔT is the overall driving force between the two bulk fluids (or a suitable mean such as LMTD in Section 8.3).

Cylindrical Walls (Pipes and Tubes)

Inner and outer areas differ. Engineers define U on inside or outside area:

Q̇ = U_i A_i ΔT = U_o A_o ΔT

Wall resistance becomes a logarithmic form, e.g. ln(r_o/r_i)/(2π k L) for length L. For UPDA MCQs, remember:

  • State the area basis when comparing U values
  • Thin metal tubes: wall resistance is often small vs films and fouling
  • Thick insulation on pipe OD: conduction resistance can dominate

Overall Heat Transfer Coefficient U

QuantityMeaning
UOverall coefficient including all series resistances (W/(m²·K))
AReference heat-transfer area (often tube OD or ID)
ΔTOverall bulk-to-bulk temperature difference (or mean)
Clean UCalculated without fouling factors
Service / dirty UIncludes fouling; used for sizing for end-of-run

Typical order-of-magnitude U values (very approximate; depend strongly on fluids):

Duty typeRough U (W/(m²·K))
Gas–gas (no fins)10–50
Gas–liquid20–300
Liquid–liquid (low viscosity)200–1500
Condensing steam–liquid500–4000+

Do not memorize a single “correct” U for all exchangers; use the table as relative intuition: gas films and viscous oils pull U down; condensing steam pulls U up.

Worked Numerical: Clean Plane Composite

A flat heat-transfer surface has:

  • h_hot = 800 W/(m²·K)
  • Wall: L = 0.005 m, k_w = 40 W/(m·K)
  • h_cold = 400 W/(m²·K)
  • No fouling

1/U = 1/800 + 0.005/40 + 1/400 = 0.00125 + 0.000125 + 0.0025 = 0.003875 m²·K/W

U ≈ 258 W/(m²·K)

TermContribution to 1/U
Hot film0.00125
Wall0.000125
Cold film0.00250
Sum0.003875

Interpretation: The cold film is the largest resistance (~64% of 1/U). Improving cold-side turbulence raises U more than polishing an already conductive thin metal wall. The wall term is almost negligible—classic for thin steel.

If cold-side h doubles to 800 W/(m²·K):

1/U = 0.00125 + 0.000125 + 0.00125 = 0.002625 → U ≈ 381 W/(m²·K)

A large gain from fixing the controlling film.

Fouling Factors and Why Plants Care

Fouling is unwanted deposit on heat-transfer surfaces: scale, sludge, corrosion products, biological growth, coke, polymer, or sand/silt.

Fouling factor R_f (m²·K/W) is an extra series resistance. Designers often take values from standards or company practice for water, crude, etc.

1/U_dirty = 1/U_clean + R_f,total

(with R_f,total the sum of side-specific factors on the chosen area basis).

Effect of foulingProcess consequence
U decreasesFor fixed area and terminal temperatures, duty falls
To keep dutyNeed more area, higher ΔT, or more utilities
Pressure dropDeposits can also raise ΔP and hurt pumps/compressors
ReliabilityUnder-deposit corrosion, hot spots, tube failures

Worked Numerical: Add Fouling

Using the previous clean U ≈ 258 W/(m²·K), add total fouling R_f = 0.0004 m²·K/W:

1/U_dirty = 1/258 + 0.0004 ≈ 0.003876 + 0.0004 = 0.004276

U_dirty ≈ 234 W/(m²·K) (~9% drop)

If fouling is severe, R_f = 0.002 m²·K/W:

1/U = 0.003876 + 0.002 = 0.005876 → U ≈ 170 W/(m²·K) (~34% drop)

CaseU (W/(m²·K))
Clean258
Light fouling R_f = 0.0004234
Heavy fouling R_f = 0.002170

Maintenance and Operations Implications (Qatar Plant Context)

Process facilities in Qatar—gas processing, LNG, refining, petrochemicals, desalination-related utilities—run exchangers hard in hot, sometimes dusty or saline environments. Exam-relevant links:

  • Cooling water systems: scale and biofouling; treatment programs protect U and reduce cleaning frequency
  • Crude / heavy hydrocarbon services: fouling factors are large by design; plan turnaround cleaning
  • Air coolers: fin-side fouling (dust, sand) cuts air-side h and effective U
  • Velocity selection: higher velocity can reduce deposition but raises pressure drop and erosion risk—an engineering tradeoff
  • Monitoring: rising approach temperatures or falling duty at fixed flows signals fouling or lost area

Design practice: Size on dirty U so the exchanger still meets duty at end of run; clean U is higher at start-up (overperformance until fouling builds).

Controlling Resistance Diagnosis

ObservationLikely message
One fluid is a gas, other is a liquidGas film often controls
Both sides liquid, thin metal, cleanSmaller h side controls
Heavy insulation or polymer liningWall/conduction may control
Performance collapses after months on hard waterFouling resistance grew
Doubling metal thickness barely changes dutyWall was not controlling

Fins are added on the low-h side (usually gas) to increase area where resistance is high—conceptual point for equipment awareness.

Coupling to Energy Balances

From Chapter 4, a single-stream cooler needs Q̇ = ṁ C_p ΔT_fluid (approx.). That duty must also equal U A ΔT_overall (with proper mean ΔT). If fouling drops U, either outlet temperatures move (less cooling/heating) or operators raise utility flow/temperature difference—until limits are hit.

Common Traps

  • Adding conductivities instead of resistances
  • Comparing U values defined on different area bases (ID vs OD)
  • Ignoring fouling on water or crude services when the stem emphasizes “after six months online”
  • Assuming metal wall always dominates (usually false for thin tubes)
  • Confusing h (one film) with U (overall)

Exam Workflow

  1. Sketch layers: film | foul | wall | foul | film.
  2. Write each R; sum for 1/(UA).
  3. Identify the largest R (controlling).
  4. Predict effect of changing h, L, k, or R_f on U and Q̇.
  5. Connect dirty U to cleaning and end-of-run design.

Section 8.3 applies U and A with LMTD (and F corrections) for real exchangers—the temperature difference is no longer a single flat ΔT when both streams change temperature along the unit.

Test Your Knowledge

For thin-walled tubular exchangers with two liquid films, which statement about series resistances is most accurate?

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Test Your Knowledge

How is the overall heat transfer coefficient U related to individual series resistances when all are written on the same area basis?

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Test Your Knowledge

A cooler is designed with fouling factors so that U_dirty < U_clean. What is the main plant implication?

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D