13.3 Project Economics, Estimating, and Cost Control
Key Takeaways
- Simple payback ignores discounting and post-payback life; discounted payback is always longer than simple payback
- Net present value accepts a project when NPV exceeds zero and governs over IRR for mutually exclusive alternatives because IRR is scale-blind
- Capital cost scales with the six-tenths rule C₂ = C₁(Q₂/Q₁)^0.6, so doubling capacity costs roughly 52 percent more, not twice as much
- Historical costs must be escalated by the ratio of cost indices before reuse, and Lang factors convert equipment cost to installed plant cost only at order-of-magnitude accuracy
- Qatari contracts commonly work from a re-measured bill of quantities, so quantity errors in design surface as cost growth in the final account
Screening a project: payback, present worth, and rate of return
Once cost structures and discounting are in hand, the remaining question is how a project gets approved. Three measures dominate, and each answers a different question.
Simple payback
Payback period = Initial investment / Annual net cash inflow
A heat-recovery retrofit costs QAR 6,000,000 and saves QAR 1,500,000 per year:
Payback = 6,000,000 / 1,500,000 = 4.0 years
Payback is popular because it is instant and because it is a crude risk screen—the shorter the payback, the less time the assumptions have to be wrong. Its two weaknesses are that it ignores the time value of money and ignores everything after the payback point, so it silently favours short-lived projects over durable ones.
Discounted payback
Discount each year's saving before accumulating it. For the same retrofit at 10%:
| Year | Saving | Discounted saving | Cumulative |
|---|---|---|---|
| 1 | 1,500,000 | 1,363,636 | 1,363,636 |
| 2 | 1,500,000 | 1,239,669 | 2,603,306 |
| 3 | 1,500,000 | 1,127,010 | 3,730,316 |
| 4 | 1,500,000 | 1,024,555 | 4,754,871 |
| 5 | 1,500,000 | 931,414 | 5,686,285 |
| 6 | 1,500,000 | 846,739 | 6,533,024 |
The cumulative discounted saving passes QAR 6,000,000 during year 6, so discounted payback is about 5.4 years against a simple payback of 4.0. Discounting always lengthens payback, and the gap widens with the discount rate.
Net present worth
NPV = Σ [CF_t / (1 + i)ᵗ] − Initial investment, with the decision rule accept if NPV > 0.
For the retrofit over an 8-year life at 10%, the series present-worth factor is 5.335:
NPV = 1,500,000 × 5.335 − 6,000,000 = 8,002,000 − 6,000,000 = +QAR 2,002,000
Positive, so the project creates value at a 10% cost of capital. NPV is the theoretically sound measure because it uses every cash flow and states the answer in money.
Rate of return
The internal rate of return is the discount rate at which NPV equals zero, and the rule is accept if IRR exceeds the minimum acceptable rate of return (MARR), also called the hurdle rate. IRR is intuitive to managers because it is a percentage, but it can mislead when comparing projects of very different size—a 40% return on QAR 200,000 creates far less value than a 15% return on QAR 20 million. When NPV and IRR disagree on mutually exclusive projects, NPV wins.
| Measure | Question it answers | Main weakness |
|---|---|---|
| Simple payback | How fast do I get my money back? | Ignores discounting and post-payback life |
| Discounted payback | Same, adjusted for time value | Still ignores post-payback life |
| NPV | How much value is created? | Requires a defensible discount rate |
| IRR | What return does the project earn? | Scale-blind; misbehaves on unusual cash-flow patterns |
Estimating capital cost
Estimate classes
Estimate accuracy improves as engineering definition improves. The class names and ranges vary by owner and by industry, but the progression is universal:
| Stage | Basis | Commonly quoted accuracy |
|---|---|---|
| Order of magnitude | Capacity and analogy to a similar plant | roughly ±30 to ±50% |
| Study / budget | Preliminary equipment list, block flow diagram | roughly ±20 to ±30% |
| Definitive / control | Detailed engineering, firm quotations, take-off quantities | roughly ±10 to ±15% |
You are not expected to recite a specific class table. You are expected to know that early estimates carry wide ranges and generous contingency, that late estimates support baselines and commitments, and that quoting a concept estimate as if it were a definitive one is how projects acquire their first credibility problem.
The six-tenths rule
Capital cost scales sub-linearly with capacity, because equipment cost tracks surface area while capacity tracks volume:
C₂ = C₁ × (Q₂ / Q₁)ⁿ, with n ≈ 0.6 as the generic exponent
A 50,000 t/y unit cost QAR 200 million. Estimate a 100,000 t/y unit:
C₂ = 200 × (100,000 / 50,000)^0.6 = 200 × 2^0.6 = 200 × 1.516 = QAR 303 million
Doubling capacity costs about 52% more, not 100% more. That single result is the economy of scale that drives world-scale plant sizing in Qatar's petrochemical sector—and the exponent is an approximation valid only within a reasonable capacity range and for the same technology.
Escalating an old cost with an index
C_now = C_then × (Index_now / Index_then)
An equipment package quoted at QAR 4.0 million when the cost index stood at 550, re-priced at an index of 660:
C_now = 4.0 × (660 / 550) = QAR 4.8 million
Never reuse a historical cost without escalating it—a five-year-old quotation is not a current estimate.
From equipment cost to installed plant cost
Purchased equipment is only a fraction of a plant. A Lang-factor approach multiplies the delivered equipment cost by a single factor—commonly quoted around 4 to 5 for fluid-processing plants—to approximate total installed capital including piping, instrumentation, electrical, civils, engineering, and contingency. Treat the factor as an order-of-magnitude tool, not a substitute for a take-off.
Bills of quantities in the Qatar contract context
Qatari construction contracts commonly work from a bill of quantities (BOQ): a schedule of measured work items, each with a description, a unit, a quantity, and a rate. Three consequences a process engineer meets in practice:
- Rates are per unit of measured work, so a design change that adds quantity adds cost automatically, without needing a variation for the rate itself.
- Measurement follows a defined method tied to the project specification, which is why QCS language and BOQ items have to align.
- Re-measurement at completion means the final account reflects actual quantities—so sloppy quantity estimates in design surface as cost growth at handover, not as a surprise at tender.
Linking economics to project cost control
Chapter 14 covers the project-management side: the cost baseline, earned value, and variance analysis. The handshake between the two chapters is straightforward:
- This chapter decides whether to spend the money—break-even, depreciation, payback, NPV, IRR.
- Chapter 14 decides whether the spending is under control once approved—cost baseline, CPI and SPI, contingency versus management reserve.
An engineer who confuses the two will try to answer a "should we sanction this?" question with an earned-value index, or a "are we overspending?" question with an IRR. Read which side of the sanction decision the stem sits on before you pick a tool.
Traps to drill
| Trap | Correction |
|---|---|
| Using simple payback to compare projects with different lives | Payback ignores everything after the payback point; use NPV |
| Assuming discounted payback is shorter than simple payback | Discounting always lengthens payback |
| Preferring the higher IRR on mutually exclusive projects | NPV governs when the two measures conflict |
| Scaling capital cost linearly with capacity | Use the exponent rule; doubling capacity costs roughly 52% more |
| Reusing a historical quotation without escalation | Apply the cost-index ratio |
| Treating a Lang factor or a concept estimate as a firm price | These are order-of-magnitude tools with wide bands |
A heat-recovery retrofit costs QAR 6,000,000 and saves QAR 1,500,000 per year. What is the simple payback period, and how would the discounted payback at 10 percent compare?
A 50,000 tonne per year plant cost QAR 200 million. Using the six-tenths rule, what is the order-of-magnitude cost of a 100,000 tonne per year plant of the same technology?
Two mutually exclusive projects are proposed. Project A has an IRR of 40 percent on a QAR 200,000 investment; Project B has an IRR of 15 percent on a QAR 20 million investment, with a hurdle rate of 10 percent. Which selection logic is sound?