3.4 Geometry, Measurement, and Data Interpretation

Key Takeaways

  • Perimeter measures boundary length, area measures enclosed two-dimensional surface, and volume measures three-dimensional capacity; linear scaling by kk scales area by k2k^2 and volume by k3k^3.

  • The Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) and primitive triples ((3,4,5)(3, 4, 5), (5,12,13)(5, 12, 13), (8,15,17)(8, 15, 17)) allow rapid calculation of distances and hypotenuses without squaring large numbers.

  • Angle relationships on parallel lines cut by a transversal establish that alternate interior, alternate exterior, and corresponding angles are equal, while consecutive interior angles are supplementary (180∘180^\circ).

  • Data interpretation relies on careful unit inspection, axis verification, and percentage-to-degree conversions for pie charts (1%=3.6∘1\% = 3.6^\circ, 100%=360∘100\% = 360^\circ), while the median is the most robust average in skewed data.

Last updated: October 2026

3.4 Geometry, Measurement, and Data Interpretation

The final module of Numerical Reasoning synthesizes spatial-quantitative measurement with data literacy. Geometry items evaluate your grasp of plane figures, geometric scaling, angle theorems, and solids, while data interpretation tests your capacity to extract facts, discern trends, and compute summary statistics from graphs and tables under timed conditions.


Plane Geometry: Perimeter and Area

Perimeter is the one-dimensional total distance around the boundary of a closed figure, whereas area measures the two-dimensional surface enclosed within that boundary.

Primary Plane Figures and Area Formulations

Geometric FigurePerimeter / CircumferenceArea FormulaKey Notes & Non-Calculator Tips
SquareP=4sP = 4sA=s2=12d2A = s^2 = \frac{1}{2} d^2Diagonal d=s2d = s\sqrt{2}
RectangleP=2(l+w)P = 2(l + w)A=l×wA = l \times wDiagonal d=l2+w2d = \sqrt{l^2 + w^2}
TriangleP=a+b+cP = a + b + cA=12bhA = \frac{1}{2} b hAltitude hh must be perpendicular to base bb
ParallelogramP=2(a+b)P = 2(a + b)A=b×hA = b \times hUse vertical height hh, never slant side
TrapezoidP=a+b1+c+b2P = a + b_1 + c + b_2A=b1+b22×hA = \frac{b_1 + b_2}{2} \times hArea equals median ×\times height
CircleC=2πr=πdC = 2\pi r = \pi dA=πr2A = \pi r^2Use π≈227\pi \approx \frac{22}{7} when rr is a multiple of 7; else 3.143.14

Special Right Triangles

Memorizing the exact side ratios of special right triangles eliminates the need for manual square root extraction:

  • 45∘−45∘−90∘45^\circ - 45^\circ - 90^\circ Triangle (Isosceles Right): Side ratio is 1:1:21 : 1 : \sqrt{2}. If legs are length xx, the hypotenuse is x2x\sqrt{2}.
  • 30∘−60∘−90∘30^\circ - 60^\circ - 90^\circ Triangle: Side ratio is 1:3:21 : \sqrt{3} : 2. Opposite the 30∘30^\circ angle is xx (shortest leg), opposite 60∘60^\circ is x3x\sqrt{3}, and opposite 90∘90^\circ is 2x2x (hypotenuse).

Composite Plane Figures

To compute the area of composite figures (e.g., an L-shaped room, an athletic track, or a shaded border), decompose the figure into standard shapes. Either:

  1. Partition into non-overlapping sub-rectangles/triangles and sum their individual areas; or
  2. Compute the bounding area and subtract the unshaded cutout portion (Ashaded=Aouter−AinnerA_{\text{shaded}} = A_{\text{outer}} - A_{\text{inner}}).

Solid Geometry: Volume and Geometric Scaling Laws

Volume quantifies three-dimensional capacity, measured in cubic units (m3m^3, cm3cm^3, or liters, where 1 liter=1,000 cm31\text{ liter} = 1,000\text{ cm}^3).

Standard 3D Solids

  • Rectangular Prism (Box): V=l×w×hV = l \times w \times h Total Surface Area (TSA)=2(lw+lh+wh)\text{Total Surface Area } (TSA) = 2(lw + lh + wh) Space Diagonal=l2+w2+h2\text{Space Diagonal} = \sqrt{l^2 + w^2 + h^2}

  • Right Circular Cylinder: V=πr2hV = \pi r^2 h Lateral Surface Area (LSA)=2πrh\text{Lateral Surface Area } (LSA) = 2\pi r h Total Surface Area (TSA)=2πrh+2πr2\text{Total Surface Area } (TSA) = 2\pi r h + 2\pi r^2

The Fundamental Geometric Scaling Laws

Questions frequently test what occurs when dimensions are scaled by a constant factor kk:

  • All linear dimensions (perimeter, circumference, radius, height, diagonal) scale by k1k^1.
  • All surface areas (lateral area, base area, total surface area) scale by k2k^2.
  • All volumes and capacities scale by k3k^3.

Non-Calculator Example: If the radius of a cylindrical water tank is doubled while its height remains constant, how does its volume change? The radius is squared in the volume formula (V=πr2hV = \pi r^2 h), so doubling the radius (k=2k = 2) multiplies the volume by 22=42^2 = 4.


Angle Theorems and the Pythagorean Theorem

Angle Fundamentals

  • Complementary Angles: Two angles whose measures sum to 90∘90^\circ.
  • Supplementary Angles: Two angles whose measures sum to 180∘180^\circ.
  • Vertical Angles: Non-adjacent angles formed by two intersecting lines; vertical angles are always congruent (equal in measure).
  • Triangle Angle Sum Theorem: The interior angles of any planar triangle sum to 180∘180^\circ.
  • Exterior Angle Theorem: The measure of an exterior angle of a triangle is equal to the sum of the measures of its two remote interior angles.

Parallel Lines Cut by a Transversal

When two parallel lines are intersected by a transversal line, eight angles are created, forming exactly two equal measure groups:

  • Congruent pairs: Alternate interior angles, alternate exterior angles, and corresponding angles are equal.
  • Supplementary pairs: Consecutive interior angles (co-interior) on the same side of the transversal sum to 180∘180^\circ.

The Pythagorean Theorem and Primitive Triples

In every right triangle with legs aa and bb and hypotenuse cc: a2+b2=c2a^2 + b^2 = c^2

To save time on the non-calculator exam, memorize the essential primitive Pythagorean triples and their common scalar multiples (k×{a,b,c}k \times \{a, b, c\}):

  • Family {3,4,5}\{3, 4, 5\}: Multiples include {6,8,10}\{6, 8, 10\}, {9,12,15}\{9, 12, 15\}, {12,16,20}\{12, 16, 20\}, {15,20,25}\{15, 20, 25\}.
  • Family {5,12,13}\{5, 12, 13\}: Multiples include {10,24,26}\{10, 24, 26\}.
  • Family {8,15,17}\{8, 15, 17\}: Multiples include {16,30,34}\{16, 30, 34\}.
  • Family {7,24,25}\{7, 24, 25\}: Primitive set.

If legs are 9 and 12, recognize the ratio 3:43 : 4, indicating the hypotenuse must be 5×3=155 \times 3 = 15, avoiding squaring and root operations.


Data Interpretation: Reading Tables, Charts, and Graphs

Data interpretation items evaluate your ability to synthesize information presented in visual and tabular formats.

Formats and Scanning Rules

  1. Data Tables: Always verify row and column headers and note measurement units (e.g., "in thousands", "in millions of PHP").
  2. Bar Charts: Used for discrete categorical comparisons. Check the baseline: if the vertical axis begins at a non-zero value, bar heights exaggerate relative differences.
  3. Line Graphs: Used for continuous time-series data. The slope between two points indicates the rate of change; steeper lines represent faster growth or decline.
  4. Pie Charts (Circle Graphs): Sectors represent parts of a whole (100%100\% or 360∘360^\circ).
    • Conversion factor: 1%=3.6∘1\% = 3.6^\circ, and 10%=36∘10\% = 36^\circ.
    • To convert degrees (θ\theta) into percentage: P=θ360∘×100%=θ3.6∘P = \frac{\theta}{360^\circ} \times 100\% = \frac{\theta}{3.6^\circ}.
    • To convert percentage into degrees: θ=P×3.6∘\theta = P \times 3.6^\circ.

Descriptive Statistics: Measures of Central Tendency and Dispersion

1. Arithmetic Mean (Average)

xˉ=∑xn=x1+x2+⋯+xnn\bar{x} = \frac{\sum x}{n} = \frac{x_1 + x_2 + \dots + x_n}{n}

Tip

The Assumed Mean (Deviation) Shortcut: When computing the mean of numbers close to each other (e.g., 83, 87, 88, 92, 85), do not sum the full values. Pick an assumed mean of 85 and sum the signed deviations: (83−85)+(87−85)+(88−85)+(92−85)+(85−85)=−2+2+3+7+0=+10(83-85) + (87-85) + (88-85) + (92-85) + (85-85) = -2 + 2 + 3 + 7 + 0 = +10. Divide the net deviation by n=5n=5: +105=+2\frac{+10}{5} = +2. True mean =85+2=87= 85 + 2 = 87.

2. Median

The middle value when data points are arranged in ascending order:

  • If nn is odd, the median is the single middle element at position n+12\frac{n + 1}{2}.
  • If nn is even, the median is the arithmetic mean of the two middle elements at positions n2\frac{n}{2} and n2+1\frac{n}{2} + 1.
  • The median is resistant to extreme outliers, making it superior to the mean when distributions are heavily skewed (such as household income statistics).

3. Mode and Range

  • Mode: The value that appears with the greatest frequency. A distribution may have one mode (unimodal), two modes (bimodal), multiple modes, or no mode if all values appear with equal frequency.
  • Range: The simplest measure of dispersion: Range=xmax−xmin\text{Range} = x_{\text{max}} - x_{\text{min}}.

Step-by-Step Worked Problems

Worked Example 1: Composite Area and the Pythagorean Theorem

Problem: A school community garden in Laguna is designed in the shape of a right-angled triangle. Its two perpendicular legs measure 12 meters and 16 meters. A circular concrete composting station with a radius of 2 meters is constructed inside the garden. What is the length of the perimeter boundary fence along the hypotenuse, and what is the remaining plantable soil area of the garden? (Use π≈3.14\pi \approx 3.14).

Step-by-Step Solution:

  1. Determine the hypotenuse using Pythagorean triples:
    • The legs are 12 and 16. Divide both by their greatest common factor, 4: 124=3\frac{12}{4} = 3 and 164=4\frac{16}{4} = 4.
    • This is a scaled {3,4,5}\{3, 4, 5\} triple with scale factor k=4k = 4.
    • Hypotenuse =5×4=20 meters= 5 \times 4 = 20\text{ meters}.
  2. Calculate the total area of the triangular garden: Atriangle=12×base×height=12×12×16=6×16=96 m2A_{\text{triangle}} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 12 \times 16 = 6 \times 16 = 96\text{ m}^2
  3. Calculate the area occupied by the circular composting station: Acircle=πr2=3.14×22=3.14×4=12.56 m2A_{\text{circle}} = \pi r^2 = 3.14 \times 2^2 = 3.14 \times 4 = 12.56\text{ m}^2
  4. Calculate the remaining plantable soil area: Aplantable=Atriangle−Acircle=96−12.56=83.44 m2A_{\text{plantable}} = A_{\text{triangle}} - A_{\text{circle}} = 96 - 12.56 = 83.44\text{ m}^2

Worked Example 2: Target Score Using the Deviation Method

Problem: A student completes four periodic assessment quizzes in Numerical Reasoning, scoring 82, 87, 89, and 84. What score must the student achieve on the fifth and final quiz to obtain an overall average score of exactly 86 across all five assessments?

Step-by-Step Solution:

  1. Method A — Total Points Architecture:
    • Target total points required: 5×86=430 points5 \times 86 = 430\text{ points}.
    • Current total points earned: 82+87+89+84=342 points82 + 87 + 89 + 84 = 342\text{ points}.
    • Required fifth score: 430−342=88 points430 - 342 = 88\text{ points}.
  2. Method B — Deviation Architecture (Mental Shortcut):
    • Calculate deviations of each known quiz from target 86:
      • Quiz 1: 82−86=−482 - 86 = -4
      • Quiz 2: 87−86=+187 - 86 = +1
      • Quiz 3: 89−86=+389 - 86 = +3
      • Quiz 4: 84−86=−284 - 86 = -2
    • Sum the deviations: (−4)+(+1)+(+3)+(−2)=−2(-4) + (+1) + (+3) + (-2) = -2.
    • To achieve an overall net deviation of 0, Quiz 5 must provide a balance of +2+2.
    • Required fifth score: 86+2=88 points86 + 2 = 88\text{ points}.
Test Your Knowledge

A right-triangular community garden plot has perpendicular legs measuring 12 meters and 16 meters. A circular water fountain with a radius of 2 meters is constructed inside the garden. What is the remaining plantable land area of the garden? (Use π ≈ 3.14).

A

78.26 square meters

B

80.44 square meters

C

83.44 square meters

D

88.56 square meters

Test Your Knowledge

In a survey of Senior High School elective track preferences among 720 Grade 10 students, a pie chart displays the Technical-Professional (Tech-Pro) Track with a central angle of exactly 108°. How many students indicated a preference for the Tech-Pro Track?

A

180 students

B

196 students

C

204 students

D

216 students

Test Your Knowledge

A candidate takes five simulation exams in Numerical Reasoning. The scores on the first four exams are 78, 83, 85, and 90. To attain a target mean score of 85 across all five exams, what score must the candidate achieve on the fifth exam?

A

87

B

89

C

91

D

93

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