7.2 Pulleys, Wheels and Axles, and Inclined Planes

Key Takeaways

  • A single fixed pulley provides an IMA=1\text{IMA} = 1 (acting solely as a direction changer), whereas a single movable pulley provides an IMA=2\text{IMA} = 2 (halving the required effort while doubling rope pull distance).

  • In block and tackle systems, the Ideal Mechanical Advantage equals the exact number of rope strands directly supporting the load and movable pulley block.

  • Downward effort strands running off a fixed pulley do not support the load and are excluded from strand counts, whereas upward effort strands pulling directly from a movable pulley are included.

  • An inclined plane trades distance for force with an IMA=L/h=1/sin⁡θ\text{IMA} = L / h = 1 / \sin \theta, while wedges and screws function as mobile and helical variations of the inclined plane.

  • A wheel and axle operates as a continuous rotating lever with an Ideal Mechanical Advantage equal to the ratio of the wheel radius to the axle radius (IMA=Rwheel/raxle\text{IMA} = R_{\text{wheel}} / r_{\text{axle}}).

Last updated: October 2026

7.2 Pulleys, Wheels and Axles, and Inclined Planes

Pulleys, inclined planes, and wheel-and-axle systems represent primary engineering solutions for lifting heavy loads vertically against gravity. In each mechanism, the mechanical advantage is achieved by trading displacement distance for effort force. Mastering these simple machines requires understanding the geometry of force vectors and the distribution of mechanical tension.


Pulleys: Fixed, Movable, and Block & Tackle Systems

A pulley is a grooved wheel (sheave) that turns around an axle mounted inside a housing or frame (block), designed to support and guide a flexible cord, cable, or rope.

1. Single Fixed Pulley

A fixed pulley has its axle firmly anchored to an immovable overhead structure (e.g., a ceiling beam or crane mast).

  • Mechanical Behavior: When pulling the rope downward, the load rises upward by the identical distance (de=dLd_e = d_L).
  • Mechanical Advantage: IMA=1.0\text{IMA} = 1.0.
  • Function: It does not multiply force. Its sole advantage is changing the direction of the applied force, allowing an operator to pull downward—working with gravity and utilizing their own body weight—rather than lifting upward against gravity.

2. Single Movable Pulley

A movable pulley is attached directly to the load itself, moving upward and downward along with the load.

  • Mechanical Behavior: The rope is anchored overhead at one end, loops under the movable pulley, and the free end is pulled upward by the operator.
  • Tension Distribution: The total downward weight of the load (FLF_L) is shared equally between the two upward-supporting rope segments on either side of the pulley:

T=FL2  ⟹  Fe=FL2T = \frac{F_L}{2} \implies F_e = \frac{F_L}{2}

  • Displacement: To lift the load by a vertical height of hh, both supporting rope strands must shorten by hh. Consequently, the operator must pull 2h2h of rope (de=2dLd_e = 2 d_L).
  • Mechanical Advantage: IMA=2.0\text{IMA} = 2.0.
  • Function: It cuts the required lifting force in half, at the expense of doubling the length of rope that must be hauled.
Single Fixed vs. Single Movable Pulley:

      FIXED PULLEY (IMA = 1)                 MOVABLE PULLEY (IMA = 2)
         [ Ceiling Anchor ]                     [ Ceiling Anchor ]
                 |                                      |
               ( O ) <--- Fixed Axle                    |      ^ Effort (Fe = W/2)
              /     \                                   |      |
             /       v Effort (Fe = W)                  \     /
            |                                            \   /
          [Load] (Weight W)                               ( O ) <--- Movable Axle
                                                            |
                                                          [Load] (Weight W)

3. Block and Tackle Systems and the Strand-Counting Rule

A block and tackle combines multiple fixed and movable pulleys into two blocks to achieve high mechanical advantage.

To determine the Ideal Mechanical Advantage of any block and tackle system on an exam, use the Strand-Counting Rule:

  1. Identify the movable pulley block (the block that moves with the load).
  2. Count only the rope strands that directly emerge from and support the movable block.
  3. The Direction Rule: Inspect the free end of the rope where the effort is applied:
    • If the effort rope pulls downward (running off an overhead fixed pulley), it does NOT support the movable block. Do not count it.
    • If the effort rope pulls upward (running directly off a movable pulley), it DOES help support the load. Count it.

IMA=n(where n is the number of supporting rope strands)\text{IMA} = n \quad (\text{where } n \text{ is the number of supporting rope strands})

Ideal Effort Fe=Floadn,de=n×dL\text{Ideal Effort } F_e = \frac{F_{\text{load}}}{n}, \qquad d_e = n \times d_L

ArrangementStrands holding the moving blockIMAIdeal effort for a 600 N load
One fixed pulleyNone (there is no moving block)1600 N
One movable pulley, rope anchored overhead, free end pulled upward22300 N
Two-sheave fixed block and two-sheave moving block, rope anchored to the fixed block, free end leaving the fixed block downward44150 N
The same blocks, rope anchored to the moving block, free end leaving the moving block upward55120 N

In the four-strand case, the downward pull on the free end comes off a fixed pulley, so it does not hold up the moving block. In the five-strand case, the free end pulls upward directly on the moving block, so it counts.

Important

Always verify the direction of the final effort strand. In a standard block and tackle where the rope passes once over each pulley: if the rope exits from the top block downward, IMA=number of pulleys in system\text{IMA} = \text{number of pulleys in system}. If the rope exits from the bottom block upward, IMA=number of pulleys+1\text{IMA} = \text{number of pulleys} + 1.


Inclined Planes (Ramps)

An inclined plane is a flat, stationary supporting surface tilted at an angle θ\theta to the horizontal. It enables a heavy load to be raised to an elevation hh by pushing or pulling it along the sloping ramp length LL.

Force Vector Resolution

Gravity pulls an object of mass mm straight down with weight W=mgW = mg. On an incline, this gravitational vector is resolved into two perpendicular components:

  1. Parallel Component (F∥F_\parallel): Pulls the object down along the ramp surface: F∥=Wsin⁡θ=mg(hL)F_\parallel = W \sin \theta = mg \left(\frac{h}{L}\right)
  2. Perpendicular Normal Component (F⊥F_\perp): Presses the object firmly into the ramp surface: F⊥=Wcos⁡θF_\perp = W \cos \theta
Inclined Plane Force Vectors:

         /|  
        / |  
       /  |  
    L /   | h (Height)
     /    |  
    /     |  
   /___θ__|  
   Base (b)

   Gravity (W = mg) splits into:
   - Down the ramp: F_parallel = mg * sin(θ) = mg * (h / L)
   - Into the ramp: F_normal   = mg * cos(θ)

Mechanical Advantage of a Ramp

In an ideal frictionless scenario, the effort force FeF_e needed to push the load up the ramp at constant speed must balance F∥F_\parallel:

Fe=W(hL)  ⟹  IMA=FloadFeffort=Lh=1sin⁡θF_e = W \left(\frac{h}{L}\right) \implies \text{IMA} = \frac{F_{\text{load}}}{F_{\text{effort}}} = \frac{L}{h} = \frac{1}{\sin \theta}

  • A ramp 10 m10\text{ m} long that rises 2 m2\text{ m} vertically has an IMA=10/2=5.0\text{IMA} = 10 / 2 = 5.0. An operator needs only 200 N200\text{ N} of ideal effort to lift a 1,000 N1,000\text{ N} load.
  • If friction is present with coefficient μ\mu, the actual effort required must overcome both gravity and friction: Fe,actual=Wsin⁡θ+ffriction=Wsin⁡θ+μWcos⁡θF_{e,\text{actual}} = W \sin \theta + f_{\text{friction}} = W \sin \theta + \mu W \cos \theta

Wedges and Screws: Mobile and Helical Inclined Planes

Both the wedge and the screw are direct mechanical adaptations of the inclined plane.

1. The Wedge

While an inclined plane remains stationary while the load moves up its slope, a wedge is a mobile double inclined plane that is driven into or under a load to separate, split, or lift it.

IMAwedge=Length of Wedge (L)Thickness / Width of Wedge (t)\text{IMA}_{\text{wedge}} = \frac{\text{Length of Wedge } (L)}{\text{Thickness / Width of Wedge } (t)}

  • A long, thin wedge has a high mechanical advantage and penetrates easily, but must be driven deep into the material to produce a given separation.
  • A short, blunt wedge has a low mechanical advantage, requiring a massive driving force (e.g., from a sledgehammer), but yields rapid lateral expansion.
  • Common examples include axes, chisels, knife blades, nails, doorstops, and plowshares.

2. The Screw

A screw is an inclined plane wrapped helically around a central cylinder. The spiral ridge formed by the incline is the thread.

  • Pitch (pp): The linear distance between two consecutive thread crests, representing the axial distance the screw advances into a material in exactly one full 360∘360^\circ rotation.
  • Mechanical Advantage: When a screw is rotated by an effort applied at the tip of a handle or lever of radius rr (such as a screwdriver handle or screw jack lever), the effort moves through the circumference of a circle (2πr2\pi r) while the load advances by one pitch (pp):

IMAscrew=2πrp\text{IMA}_{\text{screw}} = \frac{2\pi r}{p}

Because the circumference 2πr2\pi r is enormously larger than the tiny thread pitch pp (often 1 to 5 mm1\text{ to }5\text{ mm}), screws generate exceptionally large mechanical advantage (often exceeding 500500 to 2,0002,000). Furthermore, the extensive friction between the threads prevents screws from "back-driving" under load, making them inherently self-locking (e.g., car jacks, clamps, vises, threaded bolts).


Wheels and Axles

A wheel and axle consists of two rigidly connected concentric cylinders of different diameters that rotate together about a shared central axis.

Wheel and Axle Mechanism:

       (====== Wheel (Radius R) =====)
               |               |
               |  [= Axle =]   |
               |  (Radius r)   |
               +-------+-------+
                       |
                       v Load (Suspended on axle)

1. Applied to the Wheel (Force Multiplier)

When the input effort is applied to the perimeter of the larger cylinder (the wheel) to rotate the smaller cylinder (the axle), the system acts as a continuous rotating Class 1 or Class 2 lever:

IMA=Radius of Wheel (Rwheel)Radius of Axle (raxle)=Dwheeldaxle\text{IMA} = \frac{\text{Radius of Wheel } (R_{\text{wheel}})}{\text{Radius of Axle } (r_{\text{axle}})} = \frac{D_{\text{wheel}}}{d_{\text{axle}}}

Because Rwheel>raxleR_{\text{wheel}} > r_{\text{axle}}, the IMA\text{IMA} is strictly greater than 1. Effort force is multiplied at the axle. Examples include automobile steering wheels, doorknobs, screwdriver handles driving a narrow blade tip, winches, and windlasses.

2. Applied to the Axle (Speed Multiplier)

When input torque is supplied directly to the axle to turn the wheel (such as an engine driveshaft turning a car wheel, or a bicycle chain turning the rear hub), the IMA\text{IMA} is less than 1. This configuration trades force multiplication for substantial increases in linear speed and distance traveled along the wheel's outer rim.

Summary table: simple machines

Simple MachineIdeal Mechanical Advantage (IMA)Key VariablesTypical Application
Fixed Pulley1.01.0Direction onlyFlagpole, window blinds
Movable Pulley2.02.0Number of supporting lines (n=2n=2)Construction hoisting
Block & TacklennTotal strands supporting movable blockHeavy crane rigging, boat sails
Inclined PlaneL/h=1/sin⁡θL / h = 1 / \sin \thetaRamp length (LL) vs. vertical rise (hh)Wheelchair ramps, freight docks
WedgeL/tL / tPenetration length (LL) vs. thickness (tt)Splitting mauls, chisels, knife edges
Screw Jack2πr/p2\pi r / pLever radius (rr) vs. thread pitch (pp)Automotive jacks, workshop vises
Wheel and AxleRwheel/raxleR_{\text{wheel}} / r_{\text{axle}}Wheel radius (RR) vs. axle radius (rr)Steering wheels, winches, doorknobs
Test Your Knowledge

A crane rigging system utilizes a block and tackle assembly supporting a heavy steel crate. The overhead fixed block contains two pulleys, and the lower movable block contains two pulleys. The rope is anchored to the fixed overhead frame, passes successively around all four pulleys, and the free end emerges from the top fixed pulley where a worker pulls downward. How many rope segments directly support the movable block, what is the system's Ideal Mechanical Advantage, and what downward effort force is required to suspend a 600 N crate in an ideal frictionless system?

A

2 supporting segments, IMA = 2, Effort = 300 N

B

3 supporting segments, IMA = 3, Effort = 200 N

C

4 supporting segments, IMA = 4, Effort = 150 N

D

5 supporting segments, IMA = 5, Effort = 120 N

Test Your Knowledge

A logistics crew must load an 800 N industrial compressor onto a truck cargo bed 1.5 meters above the ground using an inclined loading ramp. Due to site constraints, they install a 6.0-meter-long ramp. Because of friction along the wooden ramp, the system operates at an efficiency of 80%. What is the Ideal Mechanical Advantage of the ramp, and what actual effort force parallel to the incline must the workers exert to push the compressor up the ramp at constant speed?

A

IMA = 0.25, Actual Effort = 640 N

B

IMA = 4.0, Actual Effort = 250 N

C

IMA = 4.0, Actual Effort = 160 N

D

IMA = 4.0, Actual Effort = 200 N

Test Your Knowledge

A heavy-duty screw jack has a thread pitch of 4.0 mm, meaning the load advances axially by 4.0 mm for every complete 360-degree rotation. The jack is operated by turning a horizontal lever handle whose outer grip is located 280 mm from the center of the screw. Assuming negligible friction for theoretical calculation, what is the Ideal Mechanical Advantage (IMA) of this screw jack? (Use π≈3.1416\pi \approx 3.1416)

A

Approximately 70

B

Approximately 220

C

Approximately 440

D

Approximately 880

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