4.4 Communications
Key Takeaways
- Analog modulation varies a carrier: AM changes amplitude, FM changes frequency, and PM changes phase; FM and PM are angle-modulation methods that trade bandwidth for noise immunity.
- Standard AM transmission bandwidth equals twice the highest message frequency, BW = 2·fm (double-sideband), while FM bandwidth follows Carson's rule, BW ≈ 2(Δf + fm).
- The Shannon–Hartley theorem gives the maximum error-free channel capacity C = B·log2(1 + S/N), in bits per second, where B is bandwidth in hertz and S/N is the linear signal-to-noise ratio.
- Signal-to-noise ratio in decibels is SNR(dB) = 10·log10(S/N); to use Shannon's formula you must convert dB back to the linear power ratio.
- Digital modulation (ASK, FSK, PSK, QAM) encodes bits onto a carrier; higher-order schemes pack more bits per symbol but need a higher SNR, and multiplexing (FDM, TDM, CDM) shares one channel among many signals.
Modulating a carrier
The Communications area is 5-8 questions and is highly formula-driven, which makes it a reliable point source if you know where the equations live in the FE Reference Handbook. Modulation impresses a low-frequency message signal onto a high-frequency carrier so it can be transmitted efficiently. The three classic analog methods change different carrier properties:
- Amplitude modulation (AM) varies the carrier amplitude in proportion to the message.
- Frequency modulation (FM) varies the carrier frequency.
- Phase modulation (PM) varies the carrier phase.
FM and PM are together called angle modulation: they keep amplitude constant and encode information in the angle, which makes them far more resistant to amplitude noise than AM — the reason FM radio sounds cleaner. The cost is bandwidth.
Bandwidth
Bandwidth questions reduce to a few rules. For standard double-sideband AM, with a message band-limited to fm, the transmission bandwidth is:
BW(AM) = 2 · fm
For FM, the bandwidth is estimated with Carson's rule, where Δf is the peak frequency deviation:
BW(FM) ≈ 2(Δf + fm)
| Scheme | Carrier property varied | Bandwidth |
|---|---|---|
| AM (DSB) | Amplitude | 2·fm |
| SSB | Amplitude (one sideband) | fm |
| FM | Frequency | ≈ 2(Δf + fm) |
| PM | Phase | Depends on deviation and fm |
Channel capacity and SNR
The headline result of information theory is the Shannon–Hartley theorem, giving the maximum error-free data rate (channel capacity) over a band-limited noisy channel:
C = B · log2(1 + S/N)
Here C is capacity in bits per second, B is the channel bandwidth in hertz, and S/N is the linear signal-to-noise power ratio. Capacity grows linearly with bandwidth but only logarithmically with SNR — doubling bandwidth doubles capacity, while doubling SNR barely changes it.
The most common trap is the signal-to-noise ratio (SNR) unit. SNR is usually quoted in decibels:
SNR(dB) = 10 · log10(S/N)
Before plugging into Shannon's formula, convert dB to a linear ratio: S/N = 10^(SNR_dB/10). For example, 30 dB means S/N = 10^3 = 1000, so the (1 + S/N) term is 1001.
Digital modulation and multiplexing
Digital systems map bits onto a carrier. The basic schemes mirror the analog ones:
- ASK (amplitude-shift keying) — bits set amplitude levels.
- FSK (frequency-shift keying) — bits select among frequencies.
- PSK (phase-shift keying) — bits set carrier phase (BPSK = 1 bit/symbol, QPSK = 2 bits/symbol).
- QAM (quadrature amplitude modulation) — combines amplitude and phase; 16-QAM carries 4 bits/symbol, 64-QAM carries 6.
Higher-order schemes pack more bits per symbol (bits/symbol = log2 M for M states) but demand a higher SNR to keep symbols distinguishable. Multiplexing shares one physical channel among many signals: FDM (frequency-division) assigns separate frequency bands, TDM (time-division) assigns time slots, and CDM/CDMA (code-division) assigns orthogonal codes.
A communication channel has a bandwidth of 4 kHz and a signal-to-noise ratio of 30 dB. Using the Shannon–Hartley theorem, the maximum channel capacity is approximately:
Which statement about FM (frequency modulation) compared with AM (amplitude modulation) is correct for the FE exam?