2.2 Statically Loaded Connection Details, Geometry Limits & Transitions

Key Takeaways

  • Base metal allowable shear stress is 0.40Fy, while weld metal allowable shear stress is 0.30FEXX on the effective weld throat area.
  • For material 1/4 in. [6 mm] or thicker, the maximum fillet weld size along edges is thickness minus 1/16 in. [1.6 mm] to maintain plate corner visibility for visual inspection.
  • The minimum effective length of a structural fillet weld is 4 times the nominal leg size (4w); welds shorter than 4w cannot be credited with an effective size exceeding 1/4 of their length.
  • Intermittent fillet weld segments must have a minimum length of 1-1/2 in. [38 mm], and lap joints require an overlap of at least 5 times the thinner plate thickness (minimum 1 in. [25 mm]).
  • Plug and slot welds must have a minimum hole width of plate thickness plus 5/16 in. [8 mm]; plates over 5/8 in. [16 mm] thick require a minimum weld fill depth of half the thickness, not less than 5/8 in.
Last updated: August 2026

2.2 Statically Loaded Connection Details, Geometry Limits & Transitions

Quick Answer: Under AWS D1.1:2025 Clause 4 Part B, allowable stresses for statically loaded connections limit base metal shear to $0.40 F_y$ and weld metal shear to $0.30 F_{EXX}$ across the effective throat ($A_w = t_e \times L$). The maximum fillet weld size along the edge of material $\ge 1/4\text{ in.}$ [$6\text{ mm}$] is $t - 1/16\text{ in.}$ [$1.6\text{ mm}$]. Fillet welds must have an effective length $\ge 4w$, and intermittent segments must be $\ge 1\text{-}1/2\text{ in.}$ [$38\text{ mm}$]. Lap joints require an overlap $\ge 5t_{thinner}$ (minimum $1.0\text{ in.}$ [$25\text{ mm}$]). Plug and slot welds require minimum hole width $d_{min} = t + 5/16\text{ in.}$, with full depth filling for $t \le 5/8\text{ in.}$ [$16\text{ mm}$] and at least half-thickness (minimum $5/8\text{ in.}$) for thicker plates.

Statically loaded structures (buildings, industrial trusses, architectural frames) are designed using Allowable Stress Design (ASD) principles. AWS D1.1 Clause 4 Part B establishes strict detailing geometry to ensure welds develop required strength without inducing local buckling, excessive restraint, or uninspectable weld profiles.


Available Strength of Welded Joints (Clause 4.7 & Table 4.3)

Welded joints are sized so that applied stresses under design service loads do not exceed allowable stress limits for either the base metal or the filler metal.

Master Allowable Stress Schedule (Table 4.3, ASD Values)

Type of Joint & StressBase Metal Allowable StressFiller Metal Strength LevelWeld Metal Allowable Stress
CJP Groove: Tension normal to effective area$0.60 F_y$ (tensile yield)Matching filler metal requiredEqual to base metal ($0.60 F_y$)
CJP Groove: Compression normal to effective area$0.60 F_y$ (bearing/compression)Matching or undermatching fillerEqual to base metal ($0.60 F_y$)
CJP Groove: Shear on effective area$0.40 F_y$ (shear yield)Matching filler metal$0.30 F_{EXX}$
PJP Groove: Shear parallel to weld axis$0.40 F_y$Matching or undermatching$0.30 F_{EXX}$ (on effective throat $E$)
PJP Groove: Tension normal to effective area$0.60 F_y$Matching or undermatching$0.30 F_{EXX}$ (on effective throat $E$)
Fillet Welds: Shear on effective throat$0.40 F_y$ (governing shear area)Matching or undermatching$0.30 F_{EXX}$ (on effective throat $t_e$)
Plug & Slot Welds: Shear parallel to faying surface$0.40 F_y$Matching or undermatching$0.30 F_{EXX}$ (on nominal hole area)

Matching vs. Undermatching Filler Metals

  • Matching Filler Metal: The filler metal nominal tensile strength ($F_{EXX}$) matches or exceeds the specified minimum tensile strength of the base metal (e.g., E7018 on ASTM A36 or A572 Gr. 50 steel). Required for CJP groove welds in tension.
  • Undermatching Filler Metal: The filler metal has lower yield and tensile strength than the base metal (e.g., E7018 on ASTM A514 $100\text{ ksi}$ quench-and-tempered steel). Undermatching is permitted in fillet welds and PJP groove welds where design strength is governed by shear on the weld throat. Using undermatching electrodes reduces residual stress, increases weld metal ductility, and significantly decreases hydrogen-induced cold cracking risks in high-strength, restrained joints.

Worked Example 1: Unit Shear Capacity ($q_{all}$) of Fillet Welds

Problem: Calculate the allowable shear capacity per linear inch ($q_{all}$) for a $5/16\text{ in.}$ [$0.3125\text{ in.}$] equal-leg fillet weld deposited with E70 filler metal ($F_{EXX} = 70\text{ ksi}$ [485 MPa]) on ASTM A36 base metal ($F_y = 36\text{ ksi}$, $F_u = 58\text{ ksi}$).

Calculation:

  1. Calculate effective throat ($t_e$): te=0.707×w=0.707×0.3125 in.=0.221 in.[5.61 mm]t_e = 0.707 \times w = 0.707 \times 0.3125\text{ in.} = 0.221\text{ in.} \quad [5.61\text{ mm}]
  2. Calculate weld metal allowable shear stress ($F_v$): Fv=0.30×FEXX=0.30×70 ksi=21.0 ksi[145 MPa]F_v = 0.30 \times F_{EXX} = 0.30 \times 70\text{ ksi} = 21.0\text{ ksi} \quad [145\text{ MPa}]
  3. Calculate allowable load per linear inch ($q_{all}$): qall=Fv×te=21.0 ksi×0.221 in.=4.64 kips/in.(4,640 lbs/in.)[812 N/mm]q_{all} = F_v \times t_e = 21.0\text{ ksi} \times 0.221\text{ in.} = 4.64\text{ kips/in.} \quad (4,640\text{ lbs/in.}) \quad [812\text{ N/mm}] (Shortcut formula: $q_{all} = 0.707 \times 0.30 \times 70 \times w = 14.85 \times w = 14.85 \times 0.3125 = 4.64\text{ kips/in.}$)

Maximum Fillet Weld Size Along Edges (Clause 4.10 & Figure 4.7)

When a fillet weld is deposited along the exterior edge of a plate or rolled shape, the welding arc tends to melt away the upper corner of the plate. To preserve the original plate edge so the inspector can verify leg size and throat thickness, Clause 4.10 (illustrated by Figure 4.7) mandates:

  • Base metal thickness $t < 1/4\text{ in.}$ [$6\text{ mm}$]: The maximum fillet weld size is the full thickness of the base metal ($w_{max} = t$).
  • Base metal thickness $t \ge 1/4\text{ in.}$ [$6\text{ mm}$]: The maximum fillet weld size shall be $1/16\text{ in.}$ [$1.6\text{ mm}$] less than the plate thickness: wmax=t1/16 in.[t1.6 mm]\mathbf{w_{max} = t - 1/16\text{ in.} \quad [t - 1.6\text{ mm}]}

Code Exception: The weld may be built out to the full edge thickness if the contract design drawings explicitly designate the weld to be built out flush with the plate surface.


Minimum Length of Fillet Welds & Short Weld Penalties (Clause 4.10)

Fillet welds rely on uniform stress distribution along their longitudinal axis. For very short welds, arc starts and crater stops occupy a significant percentage of the weld length, causing severe end notch stress peaks.

  • Minimum Effective Length: The minimum effective length of a structural fillet weld shall not be less than $4 \times$ the nominal leg size ($L_{min} \ge 4w$).
  • Short Weld Size Reduction: If a fillet weld is shorter than $4w$, the weld cannot be credited with its nominal leg size. The effective weld size ($w_{eff}$) used in design calculations is capped at $1/4$ of the actual weld length: weff=Lactual4w_{eff} = \frac{L_{actual}}{4}

Worked Example 2: Short Fillet Weld Design Penalty

Problem: A drawing specifies a $3/8\text{ in.}$ [$0.375\text{ in.}$] fillet weld with an actual length of only $1.0\text{ in.}$ [$25.4\text{ mm}$]. Calculate the effective weld size credited for structural capacity.

Calculation:

  1. Check code minimum length rule: $4w = 4 \times 0.375\text{ in.} = 1.50\text{ in.}$ [$38.1\text{ mm}$].
  2. Since actual length $L = 1.0\text{ in.} < 1.50\text{ in.}$, the short weld penalty applies: weff=L4=1.0 in.4=0.250 in.(1/4 in.)[6.35 mm]w_{eff} = \frac{L}{4} = \frac{1.0\text{ in.}}{4} = 0.250\text{ in.} \quad (1/4\text{ in.}) \quad [6.35\text{ mm}]
  3. Effective throat credited: $t_e = 0.707 \times 0.250\text{ in.} = 0.177\text{ in.}$ (instead of $0.707 \times 0.375 = 0.265\text{ in.}$). The connection loses $33.3%$ of its expected nominal capacity.

Intermittent Fillet Welds (Clause 4.10)

Intermittent fillet welds consist of short, spaced weld segments used where continuous welding would provide excessive strength, induce distortion, or overheat thin web assemblies:

  • Minimum Segment Length: An intermittent fillet weld segment shall have a minimum effective length of $1\text{-}1/2\text{ in.}$ [$38\text{ mm}$] ($L_{seg} \ge 1.5\text{ in.}$). Under welding symbol conventions, a callout of 5/16 [fillet] 2-6 denotes $5/16\text{ in.}$ leg size, $2\text{ in.}$ segment length, and $6\text{ in.}$ center-to-center pitch ($4\text{ in.}$ clear spacing between welds).
  • Maximum Longitudinal Spacing (Pitch $s$):
    • Compression members: Spacing shall not exceed $s \le 4000 t / \sqrt{F_y}$, or $12\text{ in.}$ [$300\text{ mm}$], or $24 \times$ the thickness of the thinner plate joined.
    • Tension members: Spacing shall not exceed $24 \times$ the thickness of the thinner plate, up to a maximum of $12\text{ in.}$ [$300\text{ mm}$].
  • Staggered vs. Chain Intermittent Welds: In staggered arrangements on opposite sides of a joint, the spacing rules apply to the pitch on each individual side.

Lap Joints & Longitudinal Fillet Welds (Clause 4.8 & 4.10)

Lap joints create eccentric load paths that induce secondary bending moments across the faying surfaces. AWS D1.1 regulates lap geometry to control prying and plate distortion:

  • Minimum Overlap: The minimum overlap between joined parts shall not be less than $5 \times$ the thickness of the thinner part joined, and in no case less than $1.0\text{ in.}$ [$25\text{ mm}$]: Overlapmax(5×tthinner,1.0 in.)\mathbf{\text{Overlap} \ge \max(5 \times t_{thinner}, 1.0\text{ in.})}
  • Longitudinal Fillet Welds Alone: When longitudinal fillet welds alone are used along the sides of an end lap connection (without transverse end welds):
    • The length of each longitudinal fillet weld shall not be less than the perpendicular transverse distance ($W$) between them ($L_{weld} \ge W$).
    • The transverse spacing between longitudinal welds shall not exceed $16 \times$ the thickness of the thinner part or $8.0\text{ in.}$ [$200\text{ mm}$], unless intermediate plug/slot welds or transverse welds are provided to prevent plate buckling.
  • End Returns (Boxing - Clause 4.10): Where fillet welds terminate at ends or sides of parts, they shall be continuous around the corners for a distance of not less than $2 \times$ the nominal leg size ($2w$) where boxing is designated on design drawings.

Plug and Slot Weld Detailing (Clause 4.11)

Plug and slot welds are circular holes or elongated slots in one plate filled with weld metal to fuse to the underlying faying plate. They transmit shear in lap joints or prevent plate buckling:

Dimensional Limitations Table (Clause 4.11)

Detail ParameterPlug WeldsSlot Welds
Minimum Hole Width / Diameter$d_{min} = t + 5/16\text{ in.}$ [$t + 8\text{ mm}$]$W_{min} = t + 5/16\text{ in.}$ [$t + 8\text{ mm}$]
Maximum Hole Width / Diameter$d_{max} = 2.25 \times t$ (or $3.0\text{ in.}$ max)$W_{max} = 2.25 \times t$
Maximum Slot LengthN/A (circular hole)$L_{max} \le 10 \times \text{Width} (W)$
Slot Corner RadiiN/ASemicircular ends ($R \ge W/2$) or $45^\circ$ chamfers
Minimum Center-to-Center Spacing$4 \times \text{Diameter} (4d)$Longitudinal: $2 \times L_{slot}$; Transverse: $4 \times W$
Depth of Filling ($t \le 5/8\text{ in.}$ [$16\text{ mm}$])Full thickness of plate ($t$)Full thickness of plate ($t$)
Depth of Filling ($t > 5/8\text{ in.}$ [$16\text{ mm}$])$\ge 1/2 \times t$, but not less than $5/8\text{ in.}$$\ge 1/2 \times t$, but not less than $5/8\text{ in.}$

Note on Stress: The allowable shear stress on the effective area of a plug or slot weld at the faying surface is $0.30 F_{EXX}$ or $0.40 F_y$ of the base metal, whichever is smaller. Plug and slot welds are prohibited from carrying direct tensile loads.

Test Your Knowledge

What is the maximum allowable fillet weld size along the edge of a 3/8 in. [9.5 mm] thick structural steel gusset plate in a statically loaded connection?

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Test Your Knowledge

A lap joint connects a 1/8 in. [3.2 mm] thick sheet to a 3/8 in. [9.5 mm] thick base plate. What is the minimum required overlap length between the joined parts according to AWS D1.1 Clause 4.8?

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Test Your Knowledge

A structural engineer designs a plug weld in a 7/8 in. [22.2 mm] thick cover plate joined to a base beam flange. What is the minimum depth of weld filling required by AWS D1.1 Clause 4.11?

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