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Key Facts: Senegal Baccalauréat Série S1 Exam
10/20
Minimum weighted average required for immediate admission (Premier Groupe)
Office du Baccalauréat du Sénégal
Coeff 8
Coefficient for both Mathematics and Physical Sciences in Série S1
Décret portant organisation du Baccalauréat
5,000 FCFA
Registration fee; optional papers cost an additional 1,000 FCFA each
Office du Baccalauréat — 2026 registration conditions
Sample Senegal Baccalauréat Série S1 Practice Questions
Try these sample questions to review concepts for the Senegal Baccalauréat Série S1 exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1What is the limit of the rational function f(x) = (e^(2x) - 1) / x as x approaches 0?
A.2
B.1
C.0
D.e^2
Explanation: Using the standard limit definition of the derivative of e^(kx) at x = 0, lim_{x->0} (e^(kx) - 1)/x = k. Here k = 2, so the limit evaluates to 2.
2What is the first derivative of f(x) = x * ln(x) for all x > 0?
A.ln(x) + 1
B.ln(x)
C.1 / x
D.x + ln(x)
Explanation: Applying the product rule (u*v)' = u'*v + u*v' with u(x) = x and v(x) = ln(x) gives f'(x) = 1 * ln(x) + x * (1/x) = ln(x) + 1.
3Evaluate the definite integral of (4x^3 - 6x + 2) dx from x = 0 to x = 1.
A.0
B.1
C.2
D.-1
Explanation: The antiderivative is F(x) = x^4 - 3x^2 + 2x. Evaluating between 0 and 1 yields F(1) - F(0) = (1^4 - 3(1)^2 + 2(1)) - 0 = 1 - 3 + 2 = 0.
4Using integration by parts, what is the antiderivative of f(x) = x * e^x with respect to x?
A.(x - 1) * e^x + C
B.(x + 1) * e^x + C
C.x^2 * e^x / 2 + C
D.x * e^x - e^(-x) + C
Explanation: Let u = x (so du = dx) and dv = e^x dx (so v = e^x). Then int x * e^x dx = u*v - int v du = x * e^x - int e^x dx = x * e^x - e^x + C = (x - 1) * e^x + C.
5What is the unique solution of the differential equation y' + 2y = 0 satisfying y(0) = 5?
A.y(x) = 5 * e^(-2x)
B.y(x) = 5 * e^(2x)
C.y(x) = -2 * e^(5x)
D.y(x) = 5 - 2x
Explanation: The differential equation y' + ay = 0 has general solution y(x) = C * e^(-ax). With a = 2, y(x) = C * e^(-2x). Applying y(0) = 5 gives C = 5, so y(x) = 5 * e^(-2x).
6What are the modulus and principal argument of the complex number z = -1 + i * sqrt(3)?
A.|z| = 2 and arg(z) = 2*pi/3
B.|z| = 2 and arg(z) = pi/3
C.|z| = 4 and arg(z) = 2*pi/3
D.|z| = sqrt(2) and arg(z) = 5*pi/6
Explanation: The modulus is |z| = sqrt((-1)^2 + (sqrt(3))^2) = sqrt(1 + 3) = 2. Writing z = 2 * (-1/2 + i * sqrt(3)/2), we find cos(theta) = -1/2 and sin(theta) = sqrt(3)/2, which gives theta = 2*pi/3.
7In an arithmetic sequence (u_n) with initial term u_0 = 3 and common difference d = 4, what is the value of u_10?
A.43
B.40
C.47
D.37
Explanation: For an arithmetic sequence starting at index 0, the nth term is given by u_n = u_0 + n*d. For n = 10, u_10 = 3 + 10 * 4 = 3 + 40 = 43.
8What is the dot product of the vectors u = (3, -2, 1) and v = (1, 4, -2) in R^3?
A.-7
B.7
C.-3
D.9
Explanation: The dot product is u . v = (3)(1) + (-2)(4) + (1)(-2) = 3 - 8 - 2 = -7.
9A card is drawn at random from a standard well-shuffled 52-card deck. What is the probability of drawing an Ace?
A.1/13
B.1/52
C.1/4
D.4/13
Explanation: There are 4 Aces in a standard deck of 52 cards. The probability is therefore 4 / 52 = 1 / 13.
10What is the Cartesian equation of the tangent line to the curve y = x^3 - 2x at the point where x = 1?
A.y = x - 2
B.y = x - 1
C.y = 3x - 4
D.y = -x
Explanation: First, evaluate the function at x = 1: y(1) = 1^3 - 2(1) = -1. Differentiating yields y' = 3x^2 - 2, so the slope is m = y'(1) = 3(1)^2 - 2 = 1. The tangent line is y - (-1) = 1 * (x - 1), which simplifies to y = x - 2.
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