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100+ Free RME Board Exam Practice Questions

PRC Registered Master Electrician (RME) Licensure Examination practice questions are available now; exam metadata is being verified.

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PRC Master Plumber Licensure Examination (MPLE, Philippines)

Practice Questions
2026 Statistics

Key Facts: RME Board Exam Exam

70%

Passing Average

RA 7920 Sec. 19

50%

Technical Weight

RA 7920 Sec. 19

50%

PEC Weight

RA 7920 Sec. 19

1 day

Exam Duration

RA 7920 Sec. 19

PHP 900

Complete Exam Fee

PRC List of Requirements

50%

Minimum Per Subject

RA 7920 Sec. 19

The RME board exam has two subjects weighted Technical Subjects 50% and Philippine Electrical Code Parts 1 and 2 50%. It is administered by the PRC Board of Electrical Engineering under RA 7920 on one eight-hour day. To pass, candidates need a general average of at least 70% with no subject rating below 50%. Coverage includes Ohm's Law, machines, control equipment, test instruments, RA 7920 RME rules, and PEC wiring, protection, and safety requirements.

Sample RME Board Exam Practice Questions

Try these sample questions to test your RME Board Exam exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A resistive load draws 5 A from a 120 V DC source. What is the resistance of the load?
A.24 Ω
B.20 Ω
C.600 Ω
D.0.042 Ω
Explanation: Ohm's Law states R = V/I. Dividing 120 V by 5 A gives 24 Ω. Master electricians use this relationship constantly when sizing resistors, heaters, and verifying measured loads.
2A 2.0 kW heater operates continuously on 220 V AC. Approximately what current does it draw?
A.4.5 A
B.9.1 A
C.11 A
D.440 A
Explanation: Power P = V × I for a resistive load, so I = P/V = 2000 W / 220 V ≈ 9.09 A. Rounding to 9.1 A is appropriate for practical sizing and measurement checks.
3Three identical 30 Ω resistors are connected in parallel across a 90 V source. What is the total current drawn from the source?
A.1 A
B.3 A
C.9 A
D.10 A
Explanation: Each parallel branch carries I = V/R = 90/30 = 3 A. Three identical branches draw 3 × 3 = 9 A total. Parallel resistors share the same voltage, so branch currents add.
4In a purely resistive AC circuit, which statement is correct?
A.Current leads voltage by 90°
B.Current lags voltage by 90°
C.Power factor is always zero
D.Voltage and current are in phase
Explanation: In a purely resistive circuit, voltage and current reach peaks and zeros together, so they are in phase and the power factor is 1.0. Inductive circuits lag and capacitive circuits lead.
5A series circuit contains a 12 Ω resistor and a 16 Ω inductive reactance at 60 Hz. What is the impedance magnitude?
A.20 Ω
B.4 Ω
C.28 Ω
D.192 Ω
Explanation: Series impedance Z = √(R² + X_L²) = √(12² + 16²) = √(144 + 256) = √400 = 20 Ω. This 3-4-5 relationship is a common exam shortcut for RL series circuits.
6A single-phase motor draws 8 A at 230 V with a power factor of 0.80. What is the approximate real power input?
A.1.84 kW
B.1.47 kW
C.2.30 kW
D.2.94 kW
Explanation: Real power P = V × I × pf = 230 × 8 × 0.80 = 1472 W ≈ 1.47 kW. Apparent power would be V × I = 1.84 kVA, which is larger than real power when pf < 1.
7Two resistors of 10 Ω and 40 Ω are connected in series across 100 V. What voltage appears across the 40 Ω resistor?
A.20 V
B.40 V
C.80 V
D.100 V
Explanation: Series current I = 100/(10+40) = 2 A. Voltage across 40 Ω is I × R = 2 × 40 = 80 V. Voltage divides in proportion to resistance in a series circuit.
8For a balanced three-phase wye (star) load, the line voltage is related to the phase voltage by which factor?
A.Line voltage equals phase voltage
B.Line voltage = 3 × phase voltage
C.Line voltage = phase voltage / √3
D.Line voltage = √3 × phase voltage
Explanation: In a balanced wye system, V_L = √3 × V_ph because line-to-line voltage spans two phase windings with 120° separation. Phase current equals line current in wye.
9A 480 V, three-phase balanced load draws 20 A line current at a power factor of 0.90. Approximately what is the three-phase real power?
A.15.0 kW
B.8.3 kW
C.9.0 kW
D.17.3 kW
Explanation: Three-phase real power P = √3 × V_L × I_L × pf = 1.732 × 480 × 20 × 0.90 ≈ 14,964 W ≈ 15.0 kW. Omitting √3 is a common calculation error.
10If the frequency of an AC supply doubles while inductance stays constant, inductive reactance X_L will:
A.Halve
B.Double
C.Remain the same
D.Increase by a factor of four
Explanation: Inductive reactance X_L = 2πfL is directly proportional to frequency. Doubling frequency doubles X_L when L is unchanged, which raises impedance of inductive loads.

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Verified exam format metadata for PRC Registered Master Electrician (RME) Licensure Examination is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.