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100+ Free TG POLYCET Practice Questions

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Key Facts: TG POLYCET Exam

30%

Qualifying Score

36/120 Marks

120

Total Questions

No negative marking

2.5 hrs

Exam Time

150 Minutes

₹500

General Fee

SBTET TS

SBTET

Administrator

Telangana

TG POLYCET is a state-level offline entrance exam conducted by SBTET Telangana for admissions into diploma courses in engineering and technology in Telangana. The exam has 120 multiple-choice questions (Mathematics: 60, Physics: 30, Chemistry: 30) with no negative marking and a qualifying mark of 30% (36/120) for general candidates.

Sample TG POLYCET Practice Questions

Try these sample questions to test your TG POLYCET exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1If two positive integers a and b are written as a = x^3 * y^2 and b = x * y^3, where x and y are prime numbers, then what is the HCF(a, b)?
A.x * y^2
B.x^3 * y^3
C.x^2 * y
D.x^4 * y^5
Explanation: The Highest Common Factor (HCF) of two numbers is the product of the lowest power of each common prime factor involved in the numbers. For a = x^3 * y^2 and b = x * y^3, the common prime factors are x and y. The lowest power of x is x^1 (from b) and the lowest power of y is y^2 (from a). Therefore, HCF(a, b) = x * y^2.
2Which of the following numbers is an irrational number?
A.3 + sqrt(4)
B.2 - sqrt(3)
C.sqrt(9) / 3
D.0.121212... (repeating)
Explanation: The difference or sum of a rational number and an irrational number is always irrational. Here, 2 is rational and sqrt(3) is irrational, making 2 - sqrt(3) irrational. On the other hand, 3 + sqrt(4) = 3 + 2 = 5 (rational), sqrt(9)/3 = 3/3 = 1 (rational), and 0.121212... is a non-terminating repeating decimal which can be represented as a rational fraction (4/33).
3What is the value of log_3(243) + log_2(32)?
A.8
B.10
C.12
D.15
Explanation: We can write 243 as 3^5 and 32 as 2^5. Using the logarithmic identity log_b(x^y) = y * log_b(x), we get: log_3(243) = log_3(3^5) = 5 * log_3(3) = 5 * 1 = 5. Similarly, log_2(32) = log_2(2^5) = 5 * log_2(2) = 5 * 1 = 5. Adding the two values: 5 + 5 = 10.
4If log_10(x) = y, then what is the value of log_10(100 * x^2) in terms of y?
A.2 + 2y
B.100 + 2y
C.2y
D.2 + y
Explanation: Using the properties of logarithms, log_b(m * n) = log_b(m) + log_b(n) and log_b(m^p) = p * log_b(m). Therefore, log_10(100 * x^2) = log_10(100) + log_10(x^2) = log_10(10^2) + 2 * log_10(x) = 2 + 2y.
5If the decimal expansion of the number 14587 / 1250 terminates, after how many decimal places will it terminate?
A.2
B.3
C.4
D.5
Explanation: The prime factorization of the denominator 1250 is 2^1 * 5^4. The decimal expansion of a rational number p/q terminates after k decimal places, where k is the maximum of the exponents of 2 and 5 in the prime factorization of the denominator. Here, the exponent of 5 is 4, which is greater than the exponent of 2 (which is 1). Therefore, the decimal expansion terminates after 4 decimal places.
6If A = {x : x is a letter in the word 'MATHEMATICS'} and B = {x : x is a letter in the word 'STATISTICS'}, then what is n(A - B)?
A.2
B.3
C.4
D.5
Explanation: First, write the sets A and B in roster form by listing unique letters. A = {M, A, T, H, E, I, C, S} and B = {S, T, A, I, C}. The set A - B consists of elements that are in A but not in B. A - B = {M, H, E}. Therefore, the number of elements in A - B, denoted as n(A - B), is 3.
7If set A has 4 elements and set B has 5 elements, what is the maximum possible number of elements in A U B?
A.4
B.5
C.9
D.20
Explanation: The number of elements in the union of two sets is given by n(A U B) = n(A) + n(B) - n(A ∩ B). To maximize n(A U B), we must minimize n(A ∩ B). The minimum possible value of n(A ∩ B) is 0 (when A and B are disjoint sets). Thus, the maximum possible number of elements in A U B is n(A) + n(B) = 4 + 5 = 9.
8If A = {x : x is a multiple of 3, x ≤ 15} and B = {x : x is a multiple of 5, x ≤ 15} where x is a natural number, then what is A ∩ B?
A.{15}
B.{3, 5, 15}
C.{3, 6, 9, 12, 15}
D.∅ (Empty set)
Explanation: In roster form, A = {3, 6, 9, 12, 15} and B = {5, 10, 15}. The intersection A ∩ B consists of elements common to both sets, which is {15}.
9For any two sets A and B, which of the following is equivalent to the set (A - B) U (B - A) U (A ∩ B)?
A.A U B
B.A ∩ B
C.A - B
D.Universal Set U
Explanation: The set A - B consists of elements in A only. B - A consists of elements in B only. A ∩ B consists of elements common to both. The union of these three disjoint regions covers all elements that belong to A, B, or both. This is the definition of the union of the two sets, A U B.
10If set A is the set of all isosceles triangles and set B is the set of all equilateral triangles, which of the following relationships is correct?
A.A ⊂ B
B.B ⊂ A
C.A ∩ B = ∅
D.A = B
Explanation: An equilateral triangle has all three sides equal, which means it also has at least two sides equal. Therefore, every equilateral triangle is also an isosceles triangle. This means set B (equilateral triangles) is a proper subset of set A (isosceles triangles), represented as B ⊂ A.

About the TG POLYCET Exam

State-level entrance examination in Telangana for admission into engineering and technology diploma courses.

Questions

120 scored questions

Time Limit

2.5 hours

Passing Score

30% (36/120)

Exam Fee

₹500 (State Board of Technical Education and Training (SBTET), Telangana)

TG POLYCET Exam Content Outline

50%

Mathematics

Real Numbers, Sets, Polynomials, Linear & Quadratic Equations, Progressions, Geometry, Coordinate Geometry, Trigonometry, Mensuration, Probability, Statistics

25%

Physics

Reflection & Refraction of Light, Human Eye & Colourful World, Electric Current, Electromagnetism

25%

Chemistry

Chemical Equations, Acids, Bases & Salts, Atomic Structure, Periodic Classification, Chemical Bonding, Metallurgy, Carbon & its Compounds

How to Pass the TG POLYCET Exam

What You Need to Know

  • Passing score: 30% (36/120)
  • Exam length: 120 questions
  • Time limit: 2.5 hours
  • Exam fee: ₹500

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

TG POLYCET Study Tips from Top Performers

1Focus on 10th-grade Mathematics as it constitutes 50% of the exam and covers key algebraic and geometric topics.
2Revise key Physics concepts like Refraction of Light and Electric Current, which contain high-weightage numerical problems.
3In Chemistry, ensure strong familiarity with the Periodic Table, Chemical Bonding, and carbon compounds.
4Practice solving objective questions within a time limit to build speed and accuracy.

Frequently Asked Questions

What is the TG POLYCET exam?

TG POLYCET (Telangana State Polytechnic Common Entrance Test) is a state-level entrance examination conducted by the State Board of Technical Education and Training (SBTET), Telangana. It is held for admission into various diploma courses in engineering, technology, and other streams offered by polytechnics in Telangana.

What is the qualifying mark for TG POLYCET?

The minimum qualifying mark for the TG POLYCET is 30% of the maximum marks, which corresponds to 36 marks out of 120 for general and OBC category candidates. There are no minimum qualifying marks prescribed for candidates belonging to Scheduled Castes (SC) and Scheduled Tribes (ST).

What is the exam pattern of TG POLYCET for engineering?

The exam is a pen-and-paper (OMR-based) test consisting of 120 multiple-choice questions for the engineering (MPC) stream. It includes 60 questions in Mathematics, 30 questions in Physics, and 30 questions in Chemistry. There is no negative marking for incorrect answers.

What is the duration of the exam?

The duration of the TG POLYCET entrance examination is 2.5 hours (150 minutes).

What are the core subjects tested in TG POLYCET?

The subjects tested are Mathematics (60 questions), Physics (30 questions), and Chemistry (30 questions), all based on the Class 10 (SSC) syllabus of Telangana Board of Secondary Education.