100+ Free CG PPT Practice Questions

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Key Facts: CG PPT Exam

150 MCQs

Total questions split across Physics, Chemistry, and Math

CG Vyapam guidelines

3 hours

Total exam duration (offline OMR-based)

CG Vyapam bulletin

+1 / 0

Marking scheme with NO negative marking

CG Vyapam exam rules

Class 10

Standard level for Science and Mathematics syllabus

CG PPT Syllabus

100

Free practice questions here

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CG PPT is the state-level polytechnic entrance exam in Chhattisgarh, India, featuring 150 MCQs across Physics, Chemistry, and Mathematics with no negative marking. Application fees range from INR 100 to INR 200 (free for Chhattisgarh domiciles).

Sample CG PPT Practice Questions

Try these sample questions to test your CG PPT exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1If the radius of curvature of a spherical convex mirror is 32 cm, what is its focal length?

A.8 cm

B.16 cm

C.32 cm

D.64 cm

Explanation: For a spherical mirror, the focal length (f) is exactly half of its radius of curvature (R), given by the formula f = R/2. Therefore, f = 32 cm / 2 = 16 cm. Convex mirrors have a positive focal length.

2A beam of light travels from vacuum into a glass slab with a refractive index of 1.5. If the speed of light in vacuum is 3 × 10^8 m/s, what is the speed of light in the glass?

A.1.5 × 10^8 m/s

B.2.0 × 10^8 m/s

C.3.0 × 10^8 m/s

D.4.5 × 10^8 m/s

Explanation: The refractive index (n) of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light in that medium (v), given by n = c/v. Rearranging the formula gives v = c/n. Therefore, v = (3 × 10^8 m/s) / 1.5 = 2.0 × 10^8 m/s.

3According to Ohm's Law, what is the correct mathematical relationship between potential difference (V), electric current (I), and resistance (R)?

A.V = I / R

B.V = I * R

C.V = R / I

D.I = V * R

Explanation: Ohm's Law states that the current flowing through a conductor is directly proportional to the potential difference across its ends, provided temperature remains constant. The constant of proportionality is resistance (R), leading to the formula V = I * R.

4Three resistors of 2 Ω, 3 Ω, and 5 Ω are connected in series. What is the equivalent resistance of the combination?

A.1.0 Ω

B.5.0 Ω

C.10.0 Ω

D.30.0 Ω

Explanation: When resistors are connected in series, the equivalent resistance (R_eq) is the sum of the individual resistances: R_eq = R1 + R2 + R3. Thus, R_eq = 2 Ω + 3 Ω + 5 Ω = 10 Ω.

5Three identical resistors, each of resistance 6 Ω, are connected in parallel. What is the equivalent resistance of this parallel combination?

A.2 Ω

B.6 Ω

C.18 Ω

D.0.5 Ω

Explanation: For parallel resistors, the reciprocal of the equivalent resistance (1/R_eq) is the sum of the reciprocals of the individual resistances: 1/R_eq = 1/R1 + 1/R2 + 1/R3. Since the resistors are identical, 1/R_eq = 3/6 = 1/2. Therefore, R_eq = 2 Ω.

6According to Joule's Law of Heating, what is the formula for the heat (H) produced in a resistor of resistance R when a current I flows through it for time t?

A.H = I * R * t

B.H = I^2 * R * t

C.H = I * R^2 * t

D.H = I^2 * R / t

Explanation: Joule's Law of Heating states that the heat generated in a conductor is directly proportional to: (1) the square of the current (I^2), (2) the resistance of the conductor (R), and (3) the time (t) for which the current flows. The formula is H = I^2 * R * t.

7What is the direction of magnetic field lines outside a bar magnet?

A.From South pole to North pole

B.From North pole to South pole

C.Radially outwards in all directions

D.Circular loops around the center without poles

Explanation: By convention, magnetic field lines emerge from the North pole and enter the South pole outside a magnet. Inside the magnet, the field lines travel from the South pole to the North pole, forming continuous closed loops.

8Which of the following describes the phenomenon of electromagnetic induction?

A.Charging a body by friction

B.Production of a magnetic field due to current flowing through a straight wire

C.Production of induced current in a coil due to relative motion between a magnet and the coil

D.Rotation of an armature coil in an electric motor

Explanation: Electromagnetic induction is the process of generating an electric current (induced current) in a conductor or coil by changing the magnetic field passing through it. This is typically achieved by relative motion between a magnet and the coil, discovered by Michael Faraday.

9In Fleming's Left-Hand Rule, what parameter is represented by the thumb when the forefinger points along the magnetic field and the middle finger points along the current?

A.Direction of the electric current

B.Direction of the magnetic field

C.Direction of the force or motion acting on the conductor

D.Direction of the induced electromotive force

Explanation: Fleming's Left-Hand Rule is used to determine the direction of force on a current-carrying conductor in a magnetic field. When the forefinger points in the direction of the magnetic field and the middle finger points in the direction of the current, the thumb points in the direction of the force or motion of the conductor.

10In Fleming's Right-Hand Rule, which finger represents the direction of the induced current in the conductor?

A.Thumb

B.Forefinger (Index finger)

C.Middle finger

D.Ring finger

Explanation: Fleming's Right-Hand Rule is used for generators to find the direction of induced current. The thumb represents the motion of the conductor, the forefinger represents the magnetic field, and the middle finger points in the direction of the induced current.

About the CG PPT Exam

The CG PPT (Chhattisgarh Pre-Polytechnic Test) is a state-level entrance exam conducted by CG Vyapam for admission to engineering diploma (polytechnic) courses across Chhattisgarh. The offline OMR-based test features 150 multiple-choice questions split between secondary school Science (Physics and Chemistry) and Mathematics. There is no negative marking, and admission is rank-based via state counseling.

Questions

150 scored questions

Time Limit

3 hours

Passing Score

Merit-based (No fixed pass mark; rank-based admissions)

Exam Fee

INR 200 (General) / INR 150 (OBC) / INR 100 (SC/ST/PwD) (Chhattisgarh Professional Examination Board (CG Vyapam))

CG PPT Exam Content Outline

33.3%

Physics

Mechanics, force, work, energy, sound, heat, light (reflection, refraction, lenses), electricity (Ohm's law, resistance, power), magnetic effects, and sources of energy.

33.3%

Chemistry

Matter, atoms and molecules, chemical reactions, acids, bases and salts, metals and non-metals, carbon and its compounds, and periodic element classification.

33.4%

Mathematics

Real numbers, algebra (polynomials, linear equations, quadratic equations), arithmetic progressions, geometry, trigonometry, mensuration (surface areas and volumes), statistics, and probability.

How to Pass the CG PPT Exam

What You Need to Know

Passing score: Merit-based (No fixed pass mark; rank-based admissions)
Exam length: 150 questions
Time limit: 3 hours
Exam fee: INR 200 (General) / INR 150 (OBC) / INR 100 (SC/ST/PwD)

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

CG PPT Study Tips from Top Performers

1Focus on Class 9 and 10 Science (Physics, Chemistry) and Mathematics textbooks from NCERT or Chhattisgarh Board (CGBSE).

2Since there is no negative marking, practice pacing yourself to ensure you can attempt all 150 questions within the 3-hour limit.

3In Mathematics, memorize key formulas for quadratic equations, trigonometry, mensuration (surface area and volumes), and statistics.

4In Science, pay special attention to ray diagrams for light, circuit calculations for electricity, types of chemical reactions, and properties of acids/bases.

5Solve previous years' CG PPT papers to understand the recurring question trends and standard difficulty levels.

6Create a formula sheet for both physics and math to revise in the final days leading up to the entrance test.

Frequently Asked Questions

What is the CG PPT exam pattern?

The CG PPT exam consists of 150 multiple-choice questions (MCQs) in Hindi and English. It is an offline OMR-based test lasting 3 hours (180 minutes). The subjects are Mathematics, Physics, and Chemistry, testing secondary school-level concepts (Class 10 CBSE/State Board syllabus).

Is there negative marking in the CG PPT?

No, there is no negative marking for incorrect or unanswered questions in the CG PPT. Each correct answer receives +1 mark, and no marks are deducted for wrong choices. Therefore, candidates should attempt all 150 questions.

What are the application fees for CG PPT?

The baseline application fees are INR 200 for the General category, INR 150 for OBC, and INR 100 for SC/ST/PwD candidates. Note that the Chhattisgarh government has historically provided fee exemptions for local residents of the state with a valid domicile.

How are seats allocated in CG PPT?

There are no fixed qualifying marks for CG PPT. CG Vyapam prepares a merit list based on the marks scored. Candidates are called for online counseling, where they select colleges and branches based on their rank and reservation criteria.

What is the educational eligibility for CG PPT?

Candidates must have passed Class 10 (or equivalent) from a recognized board with Mathematics and Science as subjects, securing at least 35% marks. The candidate must be a citizen of India; some seats are reserved specifically for candidates with Chhattisgarh domicile.