100+ Free JEECUP (UP Polytechnic) Practice Questions

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Key Facts: JEECUP (UP Polytechnic) Exam

100 MCQs

Total questions from Math (50), Physics (25), and Chemistry (25)

JEECUP Notification

150 Minutes

Total duration allowed for the examination

JEECUP Brochure

₹300 / ₹200

Application fee for General/OBC and SC/ST categories

JEECUP Portal

No Penalty

No negative marking for incorrect answers (+4 for correct)

JEECUP Guidelines

The JEECUP Group A Engineering entrance exam features 100 MCQs to be solved in 150 minutes. The syllabus comprises Mathematics (50%), Physics (25%), and Chemistry (25%). The exam fee is ₹300 for General/OBC candidates and ₹200 for SC/ST candidates.

Sample JEECUP (UP Polytechnic) Practice Questions

Try these sample questions to test your JEECUP (UP Polytechnic) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Find the highest common factor (HCF) of the numbers A = 2^3 * 3^2 * 5 and B = 2^2 * 3^3 * 5^2.

A.180

B.60

C.540

D.1800

Explanation: The Highest Common Factor (HCF) of two numbers expressed in their prime factorizations is the product of the lowest powers of each common prime factor. For A = 2^3 * 3^2 * 5 and B = 2^2 * 3^3 * 5^2, the common prime factors are 2, 3, and 5. The lowest power of 2 is 2^2, the lowest power of 3 is 3^2, and the lowest power of 5 is 5^1. Therefore, HCF = 2^2 * 3^2 * 5^1 = 4 * 9 * 5 = 180.

2If the ratio of two numbers a : b is 3 : 4 and the ratio b : c is 8 : 9, what is the ratio a : c in its simplest form?

A.2 : 3

B.3 : 2

C.1 : 2

D.4 : 3

Explanation: To find the ratio a : c, we can multiply the two given ratios: a/c = (a/b) * (b/c) = (3/4) * (8/9). Multiplying the numerators gives 3 * 8 = 24, and multiplying the denominators gives 4 * 9 = 36. Simplifying the fraction 24/36 by dividing both the numerator and the denominator by their greatest common divisor (12) yields 2/3. Thus, the ratio a : c is 2 : 3.

3A shopkeeper sells an article for ₹540, making a profit of 20% on the cost price. What was the cost price of the article?

A.₹450

B.₹432

C.₹480

D.₹400

Explanation: Let the cost price (CP) be x. The selling price (SP) is ₹540, which represents a 20% profit on CP. Therefore, SP = CP * (1 + Profit%). This gives 540 = x * (1 + 0.20) = 1.2x. Solving for x, we get x = 540 / 1.2 = 450. Thus, the cost price of the article was ₹450.

4What is the simple interest earned on a principal sum of ₹5000 invested at an annual interest rate of 6% for a period of 4 years?

A.₹1200

B.₹1000

C.₹800

D.₹1500

Explanation: The formula for simple interest is SI = (P * R * T) / 100, where P is the principal sum, R is the annual interest rate, and T is the time period in years. Substituting the given values: SI = (5000 * 6 * 4) / 100 = 50 * 6 * 4 = 300 * 4 = ₹1200.

5If 12 men can complete a piece of work in 8 days, how many days will it take 16 men to complete the same work at the same rate of productivity?

A.6 days

B.10.67 days

C.4 days

D.9 days

Explanation: The work done is constant, so we can use the formula M1 * D1 = M2 * D2, where M is the number of men and D is the number of days. Here, M1 = 12 men, D1 = 8 days, and M2 = 16 men. Substituting these values: 12 * 8 = 16 * D2. This simplifies to 96 = 16 * D2. Solving for D2, we get D2 = 96 / 16 = 6 days.

6Simplify the expression: (81)^(3/4) * (27)^(-2/3).

A.3

B.1

C.9

D.1/3

Explanation: Express both numbers as powers of 3. We know that 81 = 3^4 and 27 = 3^3. Substituting these into the expression: (3^4)^(3/4) * (3^3)^(-2/3) = 3^(4 * 3/4) * 3^(3 * -2/3) = 3^3 * 3^(-2). Using the law of exponents (x^a * x^b = x^(a+b)): 3^3 * 3^(-2) = 3^(3 - 2) = 3^1 = 3.

7If log_x (243) = 5, what is the value of x?

A.3

B.9

C.2

D.5

Explanation: By the definition of logarithms, log_b (a) = c is equivalent to b^c = a. Therefore, log_x (243) = 5 translates to x^5 = 243. We know that 243 can be written as a power of 3, specifically 3^5 = 3 * 3 * 3 * 3 * 3 = 243. Comparing x^5 = 3^5, we find x = 3.

8Solve the system of linear equations for x: 2x + 3y = 12 and x - y = 1.

A.3

B.2

C.4

D.1

Explanation: From the second equation, we can express y in terms of x: y = x - 1. Substitute this expression into the first equation: 2x + 3(x - 1) = 12. Distributing the 3 gives: 2x + 3x - 3 = 12. Combine like terms: 5x - 3 = 12. Add 3 to both sides: 5x = 15. Divide by 5: x = 3. Checking y: y = 3 - 1 = 2, which satisfies both equations.

9What is the product of the roots of the quadratic equation 3x^2 - 7x + 12 = 0?

A.4

B.-4

C.7/3

D.-7/3

Explanation: For any quadratic equation ax^2 + bx + c = 0, the product of the roots is given by c/a. In the equation 3x^2 - 7x + 12 = 0, we have a = 3, b = -7, and c = 12. Therefore, the product of the roots is c/a = 12 / 3 = 4.

10What is the 15th term of the arithmetic progression (AP): 3, 8, 13, 18, ...?

A.73

B.78

C.68

D.83

Explanation: The formula for the n-th term of an arithmetic progression is a_n = a + (n - 1)d, where a is the first term, d is the common difference, and n is the term number. Here, the first term a = 3, and the common difference d = 8 - 3 = 5. We want to find the 15th term (n = 15). Substitute these values: a_15 = 3 + (15 - 1) * 5 = 3 + 14 * 5 = 3 + 70 = 73.

About the JEECUP (UP Polytechnic) Exam

The Joint Entrance Examination Council, Uttar Pradesh (JEECUP) conducts the UP Polytechnic entrance exam for admissions to Diploma in Engineering (Group A) programs. The exam is a Computer-Based Test (CBT) consisting of 100 multiple-choice questions to be completed in 150 minutes. The syllabus is based on Class 10 and Class 9 science and mathematics curricula. The test has three sections with a 50% weight for Mathematics, 25% for Physics, and 25% for Chemistry. This practice question bank provides exactly 100 model questions with detailed step-by-step solutions.

Questions

100 scored questions

Time Limit

150 minutes

Passing Score

Merit-based (qualifying is typically 30%)

Exam Fee

₹300 for General/OBC, ₹200 for SC/ST. (Joint Entrance Examination Council, Uttar Pradesh (JEECUP))

JEECUP (UP Polytechnic) Exam Content Outline

50%

Mathematics

Number systems, factorization, HCF & LCM, quadratic equations, arithmetic progression, trigonometry, geometry (triangles, circles), mensuration (area, volume), statistics, and probability.

25%

Physics

Measurement, motion in a straight line, Newton's laws, work, energy, and power, hydrostatics, heat and thermal expansion, light reflection and refraction, optical instruments, electrostatics, electric current, Ohm's law, magnetism, and electromagnetism.

25%

Chemistry

Matter and its states, atomic structure, chemical bonding, periodic table classification, acids, bases and salts, metals, non-metals, metallurgy, fuel, carbon and its organic compounds, and basic chemical arithmetic.

How to Pass the JEECUP (UP Polytechnic) Exam

What You Need to Know

Passing score: Merit-based (qualifying is typically 30%)
Exam length: 100 questions
Time limit: 150 minutes
Exam fee: ₹300 for General/OBC, ₹200 for SC/ST.

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

JEECUP (UP Polytechnic) Study Tips from Top Performers

1Prepare from UP Board Class 9 and 10 Mathematics and Science textbooks, as the core questions are directly mapped to this syllabus.

2In Mathematics, focus on quick calculations for trigonometry, quadratic equations, and coordinate geometry, as this section holds 50% weight.

3Practice solving numerical physics questions related to focal length, mirror formula, refraction index, electrical circuits, and series-parallel resistance calculations.

4Understand periodic table trends, balancing chemical equations, and organic chemistry functional groups to secure high marks in Chemistry.

5Take timed mock tests to build the endurance needed for a 150-minute exam, and practice selecting the easiest questions first.

Frequently Asked Questions

Is there negative marking in the JEECUP exam?

No, starting from recent updates in the exam policy, there is no negative marking in the JEECUP exam. For each correct response, candidates receive 4 marks, and zero marks are deducted for incorrect or unanswered questions.

What is the application fee for the UP Polytechnic Exam?

The application fee is ₹300 for General and OBC category candidates, and ₹200 for SC and ST category candidates. Additional bank transaction charges may apply.

Can students outside of Uttar Pradesh apply for JEECUP?

Yes, candidates from other states of India can apply for JEECUP. However, UP domicile candidates receive priority during the seat allocation process under reservations.

What is the minimum age required to apply for JEECUP Group A?

Candidates must be at least 14 years of age as of July 1st of the admission year. There is no maximum age limit for taking the exam.

What is the duration of the JEECUP Group A exam?

The Computer Based Test (CBT) has a duration of 2 hours and 30 minutes, which is exactly 150 minutes.

100+ Free JEECUP (UP Polytechnic) Practice Questions

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