100+ Free BVP CET Practice Questions

Pass your Bharati Vidyapeeth Common Entrance Test (BVP CET) — B.Tech exam on the first try — instant access, no signup required.

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2026 Statistics

Key Facts: BVP CET Exam

200 MCQs / 200 marks

B.Tech paper: Math 80 + Physics 60 + Chemistry 60

BVDU B.Tech Entrance Test Details 2026 brochure

180 minutes

Official B.Tech CET duration

BVDU B.Tech Entrance Test Details 2026 brochure

+1 / 0

Marking: +1 correct; no negative marking

BVDU B.Tech Entrance Test Details 2026 brochure

INR 2,000

Commonly listed B.Tech CET application fee (2026)

Careers360 / Collegedunia reporting of BVDU CET 2026 cycle

100

Free practice questions here

OpenExamPrep

BVP CET B.Tech is a 180-minute online MCQ exam with 200 questions (Math 80, Physics 60, Chemistry 60). Marking: +1 correct, no negative marking. Application fee for B.Tech is commonly listed as INR 2,000 for 2026. Syllabus follows Class 11–12 PCM (NCERT / state board).

Sample BVP CET Practice Questions

Try these sample questions to test your BVP CET exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A car accelerates uniformly from rest to 20 m/s in 5 s. What is its acceleration?

A.2 m/s²

B.10 m/s²

C.5 m/s²

D.4 m/s²

Explanation: Using v = u + at with u = 0: 20 = a × 5, so a = 4 m/s². Uniform acceleration means velocity changes at a constant rate.

2A body of mass 5 kg is lifted vertically through 2 m. Taking g = 10 m/s², what is the work done against gravity?

A.100 J

B.50 J

C.10 J

D.25 J

Explanation: Work against gravity W = mgh = 5 × 10 × 2 = 100 J. The force equals weight mg and displacement is along the force direction.

3Two resistors of 4 Ω and 12 Ω are connected in parallel. What is the equivalent resistance?

A.16 Ω

B.6 Ω

C.8 Ω

D.3 Ω

Explanation: Parallel combination: 1/R = 1/4 + 1/12 = 3/12 + 1/12 = 4/12, so R = 3 Ω. Parallel resistance is always less than the smallest resistor.

4The SI unit of electric flux is:

A.V·m

B.V/m

C.N/C

D.C/m²

Explanation: Electric flux Φ = ∫E·dA has SI unit V·m (volt-metre), equivalent to N·m²/C. It measures field lines passing through a surface.

5A particle executes SHM with amplitude A and angular frequency ω. What is its maximum speed?

A.A/ω

B.ωA/2

C.ω²A

D.ωA

Explanation: In SHM, v_max = ωA at the mean position where potential energy is zero and kinetic energy is maximum. Speed is zero at the extremes.

6A convex lens of focal length 20 cm forms a real image at 60 cm from the lens. Where is the object placed?

A.80 cm

B.40 cm

C.15 cm

D.30 cm

Explanation: Lens formula: 1/f = 1/v − 1/u. With f = +20 cm and v = +60 cm (real image): 1/20 = 1/60 − 1/u → 1/u = 1/60 − 1/20 = −2/60, so u = −30 cm. The object is 30 cm on the object side.

7The de Broglie wavelength of an electron accelerated through a potential difference V is proportional to:

A.√V

B.1/V

C.V

D.1/√V

Explanation: λ = h/√(2meV), so λ ∝ 1/√V. Higher accelerating voltage gives shorter wavelength because momentum increases.

8In a p-n junction diode under forward bias, the depletion layer width:

A.Increases

B.Decreases

C.Remains unchanged

D.Becomes zero instantly

Explanation: Forward bias reduces the potential barrier, allowing majority carriers to cross and narrowing the depletion region. Reverse bias widens it.

9A wire of resistance R is stretched to double its length without change in volume. The new resistance is:

A.2R

B.R/4

C.R/2

D.4R

Explanation: Volume constant: L′ = 2L implies A′ = A/2. R′ = ρL′/A′ = ρ(2L)/(A/2) = 4ρL/A = 4R. Resistance scales with length and inversely with area.

10The root-mean-square speed of gas molecules is directly proportional to:

A.T

B.√T

C.T²

D.1/T

Explanation: From kinetic theory, v_rms = √(3kT/m) ∝ √T. RMS speed rises with absolute temperature because average kinetic energy is (3/2)kT.

About the BVP CET Exam

BVP CET (Bharati Vidyapeeth Common Entrance Test) is the university-level entrance exam conducted by Bharati Vidyapeeth (Deemed to be University), Pune, for admission to B.Tech and related programmes at BVDU constituent colleges. The B.Tech paper is an online MCQ test of 200 questions — 80 Mathematics, 60 Physics, and 60 Chemistry — based on the Class 11–12 PCM syllabus published on the university CET syllabus pages. Each correct answer scores 1 mark and there is no negative marking. Duration is 3 hours. Application and scheduling run through the official CET portal (bvducet.bharatividyapeeth.edu).

Questions

200 scored questions

Time Limit

180 minutes (3 hours)

Passing Score

No fixed pass; merit rank for BVDU B.Tech counselling

Exam Fee

INR 2,000 (Bharati Vidyapeeth (Deemed to be University), Pune)

BVP CET Exam Content Outline

40%

Mathematics (80 MCQs × 1 mark)

Sets, relations, functions, complex numbers, quadratic equations, sequences and series, permutations and combinations, binomial theorem, matrices, determinants, trigonometry, coordinate geometry, 3D geometry, limits, continuity, differentiation, integration, differential equations, vectors, probability, linear programming, statistics

30%

Physics (60 MCQs × 1 mark)

Units and measurement, kinematics, laws of motion, work-energy-power, gravitation, properties of matter, thermodynamics, oscillations, waves, electrostatics, current electricity, magnetism, electromagnetic induction, AC, optics, dual nature of matter, atoms and nuclei, semiconductors

30%

Chemistry (60 MCQs × 1 mark)

Mole concept, atomic structure, periodic table, chemical bonding, states of matter, thermodynamics, equilibrium, redox, electrochemistry, kinetics, surface chemistry, s/p/d-block elements, coordination compounds, organic chemistry (GOC, hydrocarbons, haloalkanes, alcohols, carbonyls, amines, biomolecules, polymers)

How to Pass the BVP CET Exam

What You Need to Know

Passing score: No fixed pass; merit rank for BVDU B.Tech counselling
Exam length: 200 questions
Time limit: 180 minutes (3 hours)
Exam fee: INR 2,000

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

BVP CET Study Tips from Top Performers

1Weight Mathematics more heavily in practice — it is 80 of 200 questions (40%) on the official B.Tech blueprint

2Because there is no negative marking, attempt every question after eliminating clearly wrong options

3Drill Class 11–12 NCERT examples first; BVP CET items map to standard PCM entrance topics rather than obscure tricks

4Take full 200-question timed mocks (3 hours) to build pacing across Math, Physics, and Chemistry

5Prioritize high-yield Math units: calculus, coordinate geometry, algebra, and vectors

6Keep a formula sheet for Physics constants and Chemistry stoichiometric conversions — many items are direct applications

Frequently Asked Questions

What is the BVP CET B.Tech 2026 exam pattern?

Per BVDU's B.Tech Entrance Test Details 2026 brochure, the paper has 200 MCQs: 80 Mathematics, 60 Physics, and 60 Chemistry. Duration is 3 hours. Each correct answer scores 1 mark, with no negative marking for wrong or unanswered questions. The test is conducted online (CBT / remote-proctored as notified).

What is the application fee for BVP CET B.Tech 2026?

Major education portals reporting the 2026 B.Tech CET cycle list the application fee as INR 2,000, paid online via the BVDU CET portal. Fees can differ by programme (for example law vs engineering); always confirm the amount shown at checkout on bvducet.bharatividyapeeth.edu before paying.

Is there negative marking in BVP CET?

No. The official B.Tech brochure states that one mark is awarded for each correct answer and there is no negative marking for wrong or unanswered questions.

What syllabus does BVP CET B.Tech follow?

The B.Tech CET syllabus is based on Class 11 and Class 12 Physics, Chemistry, and Mathematics (aligned with NCERT / Maharashtra Board–style coverage). Detailed subject PDFs are linked from bvuniversity.edu.in/admission/cet-syllabus (BTech-2026).

Who is eligible for BVP CET B.Tech?

Candidates must pass 10+2 or equivalent with Physics, Chemistry, and Mathematics. BVDU B.Tech brochures typically require about 50% aggregate in PCM for the general category and 45% for reserved categories (confirm the exact percentages in the current-year brochure). Diploma holders may have lateral-entry routes under separate CET notifications.

Which colleges accept BVP CET scores?

BVP CET scores are used for admission to Bharati Vidyapeeth (Deemed to be University) constituent programmes, including B.Tech at BVDU College of Engineering, Pune, and other notified BVDU campuses/programmes. Seat allotment follows university counselling after the CET result.

How long is the BVP CET B.Tech exam?

The official B.Tech entrance test duration is 3 hours (180 minutes) for the full 200-question PCM paper.