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Key Facts: AP EAMCET Exam

25%

Qualifying Score

40/160 Marks

160

Total Questions

No negative marking

3 hrs

Exam Time

180 Minutes

₹800

General Fee

APSCHE

JNTUK

Administrator

On behalf of APSCHE

AP EAMCET (EAPCET) is a state-level online entrance exam conducted by JNTU Kakinada on behalf of APSCHE for admissions into professional engineering, agriculture, and pharmacy courses in Andhra Pradesh. The exam has 160 multiple-choice questions with no negative marking and a qualifying score of 25% (40/160 marks) for general candidates.

Sample AP EAMCET Practice Questions

Try these sample questions to review concepts for the AP EAMCET exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1What is the value of i^n + i^(n+1) + i^(n+2) + i^(n+3) for any integer n, where i = sqrt(-1)?
A.0
B.1
C.-1
D.i
Explanation: Factoring out i^n gives i^n * (1 + i + i^2 + i^3) = i^n * (1 + i - 1 - i) = 0.
2If alpha and beta are the roots of the equation x^2 - 5x + 6 = 0, find the equation whose roots are alpha + 1 and beta + 1.
A.x^2 - 7x + 12 = 0
B.x^2 - 5x + 6 = 0
C.x^2 - 6x + 8 = 0
D.x^2 - 8x + 15 = 0
Explanation: The roots of the equation are 2 and 3. The new roots are 3 and 4. The equation is x^2 - (3+4)x + (3*4) = 0, which is x^2 - 7x + 12 = 0.
3If A is a symmetric matrix and B is a skew-symmetric matrix of the same order, then AB - BA is a:
A.Symmetric matrix
B.Skew-symmetric matrix
C.Diagonal matrix
D.Zero matrix
Explanation: Taking the transpose: (AB - BA)^T = (AB)^T - (BA)^T = B^T A^T - A^T B^T = (-B)A - A(-B) = -BA + AB = AB - BA. Since it is equal to its transpose, it is symmetric.
4If A is a square matrix of order 3 and |A| = 4, then the value of |adj(A)| is:
A.16
B.4
C.64
D.12
Explanation: The formula for the determinant of the adjoint of a matrix of order n is |adj(A)| = |A|^(n-1). For n = 3, |adj(A)| = 4^(3-1) = 4^2 = 16.
5Evaluate the determinant: det([[1, a, b+c], [1, b, c+a], [1, c, a+b]]).
A.0
B.a+b+c
C.abc
D.1
Explanation: Add column 2 to column 3: C3 -> C3 + C2. The third column becomes [a+b+c, a+b+c, a+b+c]^T. Factoring out a+b+c leaves column 3 identical to column 1, so the determinant is 0.
6Find the number of ways of selecting 4 letters from the word 'EXAMINATION'.
A.136
B.120
C.220
D.105
Explanation: The word has 11 letters: A(2), I(2), N(2), E, X, M, T, O (8 distinct). Case 1 (2 alike, 2 alike): 3C2 = 3 ways. Case 2 (2 alike, 2 distinct): 3C1 * 7C2 = 3 * 21 = 63. Case 3 (4 distinct): 8C4 = 70. Total = 3 + 63 + 70 = 136.
7Two dice are thrown simultaneously. What is the probability that the sum of the numbers is a prime number?
A.5/12
B.7/12
C.1/2
D.1/3
Explanation: The prime sums possible are 2, 3, 5, 7, and 11. The number of outcomes for each: sum 2 (1 way), sum 3 (2 ways), sum 5 (4 ways), sum 7 (6 ways), sum 11 (2 ways). Total ways = 15. Probability = 15/36 = 5/12.
8If P(A) = 0.4, P(B) = 0.5, and A and B are independent events, find P(A U B).
A.0.7
B.0.9
C.0.2
D.0.8
Explanation: For independent events, P(A n B) = P(A) * P(B) = 0.4 * 0.5 = 0.2. Then, P(A U B) = P(A) + P(B) - P(A n B) = 0.4 + 0.5 - 0.2 = 0.7.
9Find the coefficient of x^4 in the expansion of (1 + x)^10.
A.210
B.120
C.45
D.252
Explanation: The general term is T_(r+1) = 10Cr * x^r. For x^4, r = 4. The coefficient is 10C4 = (10*9*8*7)/(4*3*2*1) = 210.
10Find the middle term in the expansion of (x + 1/x)^10.
A.252
B.210
C.120
D.504
Explanation: The number of terms is 11. The middle term is the 6th term (T_6). T_6 = 10C5 * x^5 * (1/x)^5 = 10C5 = 252.

About the AP EAMCET Exam

State-level entrance examination in Andhra Pradesh for admission into engineering, agriculture, and pharmacy courses.

Exam sponsor: JNTU Kakinada on behalf of APSCHE. The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Questions

160 questions

Time Limit

3 hours

Passing Score

25% (40/160)

Exam / Certification Fees

₹800

Exam sponsor website

Reported exam pass rate: N/A. for qualifying candidates (varies by year) Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

50%

Mathematics

Algebra, Calculus, Coordinate Geometry, Trigonometry, Vectors

25%

Physics

Mechanics, Thermodynamics, Waves, Electromagnetism, Modern Physics

25%

Chemistry

Atomic Structure, Bonding, States of Matter, Thermodynamics, Organic Chemistry

Preparing for the AP EAMCET Exam

What You Need to Know

  • Passing score: 25% (40/160)
  • Exam length: 160 questions
  • Time limit: 3 hours
  • Exam / certification fees: ₹800 Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

AP EAMCET: Suggested Study Strategy

1Focus heavily on Mathematics as it carries 50% of the total marks (80 out of 160).
2Understand the fundamentals of Physics, especially Mechanics and Electromagnetism, which have high weightage.
3In Chemistry, balance study time between Physical, Organic, and Inorganic Chemistry concepts.
4Solve previous years' question papers to get a clear idea of the exam pattern and speed requirement.
5Practice mock tests online since the exam is conducted in Computer Based Test (CBT) mode.

Frequently Asked Questions

What is the AP EAMCET exam?

AP EAMCET (now also known as AP EAPCET) is the Engineering, Agriculture and Pharmacy Common Entrance Test conducted by JNTU Kakinada on behalf of the Andhra Pradesh State Council of Higher Education (APSCHE) for admission into undergraduate engineering, agriculture, and pharmacy courses in the state of Andhra Pradesh.

What is the qualifying score for AP EAMCET?

The qualifying percentage of marks for the AP EAMCET is 25% of the maximum marks, which corresponds to 40 marks out of 160 for general and OBC category candidates. There is no minimum qualifying mark for candidates belonging to Scheduled Castes (SC) and Scheduled Tribes (ST).

How many questions are there in AP EAMCET?

The AP EAMCET exam consists of a total of 160 multiple-choice questions: 80 questions in Mathematics, 40 questions in Physics, and 40 questions in Chemistry. There is no negative marking for incorrect answers.

What is the duration of the exam?

The duration of the AP EAMCET online entrance examination is 3 hours (180 minutes).

What are the core subjects tested in AP EAMCET?

For the Engineering stream, the subjects tested are Mathematics (80 questions), Physics (40 questions), and Chemistry (40 questions).