All Practice Exams

100+ Free BCS Written Physics Practice Questions

Prepare for the BCS Written Post-Related Physics, Subject Code 511, Total Marks 200 exam with instant access — no signup required.

✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately
100+ Questions
100% Free

Loading practice questions...

2026 Statistics

Key Facts: BCS Written Physics Exam

200 marks

Official Physics paper (subject code 511)

BPSC BCS written syllabus PDF

100 + 100

Part I and Part II mark split

BPSC BCS written syllabus PDF

4 hours

Typical BPSC 200-mark written sitting (confirm routine)

Longstanding BPSC written practice; confirm current routine

50% aggregate

Written-stage pass on 900 marks (plus per-paper minima)

BPSC BCS examination page

Tk. 200

General application fee (50th BCS; Tk. 50 reduced categories)

50th BCS circular reporting citing PSC; confirm live circular

Descriptive

Official item type (this bank is an English MCQ study adaptation)

BPSC written syllabus and examination structure

BCS Physics (code 511) is a 200-mark, typically 4-hour descriptive written paper (Part I 100 + Part II 100) inside the 900-mark BPSC written stage. Written pass is 50% aggregate plus any per-paper minima. Application fee Tk. 200 general / Tk. 50 reduced categories (50th BCS; confirm circular). This page offers English MCQs as a study aid, not an official-paper simulation.

Sample BCS Written Physics Practice Questions

Try these sample questions to test your BCS Written Physics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A 2.0 kg particle starts from rest and reaches 6.0 m/s in 3.0 s under a constant net force (friction negligible). What is the magnitude of that force?
A.4.0 N
B.2.0 N
C.6.0 N
D.12 N
Explanation: Newton’s second law gives F = ma. With constant acceleration a = Δv/Δt = 6.0/3.0 = 2.0 m/s², F = 2.0 × 2.0 = 4.0 N. The same result follows from impulse: F Δt = Δp = 2.0 × 6.0, so F = 12/3 = 4.0 N.
2A 0.50 kg particle moves in a plane with velocity components v_x = 4.0 m/s and v_y = 3.0 m/s. What is its kinetic energy?
A.6.25 J
B.3.13 J
C.12.5 J
D.25.0 J
Explanation: Speed satisfies v² = v_x² + v_y² = 16 + 9 = 25 m²/s². Kinetic energy is (1/2)mv² = (1/2)(0.50)(25) = 6.25 J. Work–energy then says this is the work a net force must do to bring the particle from rest to this velocity.
3A conservative force is F = −k x î with k = 200 N/m. How much work does this force do when a particle moves from x = 0.10 m to x = 0.20 m?
A.−3.0 J
B.−6.0 J
C.3.0 J
D.6.0 J
Explanation: For F = −kx the potential is U = (1/2)kx². Then W_cons = −ΔU = −(1/2)k(x₂² − x₁²) = −(100)(0.040 − 0.010) = −3.0 J. Equivalently W = ∫ F dx from 0.10 m to 0.20 m is negative because the force is toward −x while the displacement is toward +x.
4A wheel starts from rest and reaches 20 rad/s in 4.0 s with constant angular acceleration. What is the angular acceleration?
A.5.0 rad/s²
B.2.5 rad/s²
C.10 rad/s²
D.80 rad/s²
Explanation: For uniformly accelerated rotation, ω = ω₀ + αt. With ω₀ = 0, α = ω/t = 20/4.0 = 5.0 rad/s². Angular displacement would be (1/2)αt², which is not asked here.
5A uniform disc of mass 4.0 kg and radius 0.20 m rotates at 10 rad/s about its central axis perpendicular to its plane. Taking I = (1/2)MR², what is its rotational kinetic energy?
A.4.0 J
B.2.0 J
C.8.0 J
D.40 J
Explanation: I = (1/2)(4.0)(0.20)² = 0.080 kg·m². Rotational kinetic energy is (1/2)Iω² = (1/2)(0.080)(100) = 4.0 J. Translational KE is not included because the axis is fixed at the centre.
6A solid cylinder of mass 2.0 kg and radius 0.10 m rolls without slipping at 4.0 m/s. Using I_cm = (1/2)MR², what is the total kinetic energy?
A.8.0 J
B.16 J
C.32 J
D.24 J
Explanation: No-slip means ω = v/R. Total KE = (1/2)Mv² + (1/2)Iω² = (1/2)Mv² + (1/4)Mv² = (3/4)Mv² = 0.75 × 2.0 × 16 = 24 J. The extra 8 J beyond translational KE is rotational energy about the centre of mass.
7Using G = 6.67 × 10⁻¹¹ N·m²/kg², what is the gravitational force between point masses 6.0 kg and 4.0 kg separated by 2.0 m?
A.4.00 × 10⁻¹⁰ N
B.2.00 × 10⁻¹⁰ N
C.1.00 × 10⁻⁹ N
D.4.00 × 10⁻¹¹ N
Explanation: Newton’s law of gravitation is F = GMm/r² = (6.67 × 10⁻¹¹)(24)/(4.0) = (6.67 × 10⁻¹¹)(6.0) = 4.00 × 10⁻¹⁰ N. The force is attractive and equal on each mass.
8Gravitational potential at a distance r from a point mass M is V = −GM/r (zero at infinity). For M = 8.0 × 10²⁴ kg and r = 8.0 × 10⁶ m, with G = 6.67 × 10⁻¹¹ N·m²/kg², what is V?
A.−8.34 × 10⁶ J/kg
B.−6.67 × 10¹³ J/kg
C.6.67 × 10⁷ J/kg
D.−6.67 × 10⁷ J/kg
Explanation: V = −GM/r = −(6.67 × 10⁻¹¹)(8.0 × 10²⁴)/(8.0 × 10⁶) = −(6.67 × 10⁻¹¹)(1.0 × 10¹⁸) = −6.67 × 10⁷ J/kg. The negative sign means a bound gravitational field with V → 0 at infinity.
9If g = 9.80 m/s² at Earth’s surface, what is the acceleration due to gravity at height h = R/4 above the surface? Treat Earth as a sphere of radius R and use g(h) = GM/(R + h)².
A.6.27 m/s²
B.4.90 m/s²
C.7.84 m/s²
D.9.80 m/s²
Explanation: g(h)/g = [R/(R + h)]² = [R/(5R/4)]² = (4/5)² = 0.64, so g(h) = 0.64 × 9.80 = 6.27 m/s². The linear approximation g(1 − 2h/R) is only for h ≪ R and is invalid at h = R/4.
10A wire is under tensile stress 4.0 × 10⁷ Pa and corresponding strain 2.0 × 10⁻⁴. What is Young’s modulus?
A.8.0 × 10³ Pa
B.2.0 × 10³ Pa
C.8.0 × 10¹¹ Pa
D.2.0 × 10¹¹ Pa
Explanation: Young’s modulus is Y = stress/strain = (4.0 × 10⁷)/(2.0 × 10⁻⁴) = 2.0 × 10¹¹ Pa, a typical order of magnitude for metals. Hooke’s law in this form assumes the linear elastic range.

About the BCS Written Physics Exam

BCS Written Post-Related Physics (subject code 511) is the 200-mark descriptive paper for relevant technical and professional cadres in Bangladesh Civil Service recruitment. BPSC splits the official syllabus evenly: Part I (100 marks) covers mechanics, properties of matter, waves and oscillation, heat/thermodynamics/kinetic theory, electricity and magnetism, and optics; Part II (100 marks) covers classical mechanics and special relativity, quantum mechanics, atomic and molecular physics, nuclear physics, solid state physics, and electronics. The official assessment is handwritten, not multiple choice. This free English-language MCQ bank is a study adaptation of that syllabus—not an official translation, format simulation, or substitute for writing full derivations under timed conditions.

Assessment

Official BPSC Physics syllabus (subject code 511): Part I 100 marks (mechanics; properties of matter; waves and oscillation; heat, thermodynamics and kinetic theory; electricity and magnetism; optics) and Part II 100 marks (classical mechanics and special relativity; quantum mechanics; atomic and molecular physics; nuclear physics; solid state physics; electronics). The real paper is descriptive. Technical/professional cadre written set includes this 200-mark post-related paper within the 900-mark written stage; dual-cadre applicants sit it as an extra paper. This 100-question English MCQ bank is a study adaptation only.

Time Limit

4 hours is the duration used for BPSC 200-mark written papers on this site and in longstanding BPSC sitting practice; confirm the current routine

Passing Score

50% aggregate on the 900-mark written examination (BPSC page); per-paper minima also apply as set by BPSC. Confirm the current circular.

Exam Fee

Tk. 200 general (50th BCS); Tk. 50 for ethnic minority, persons with disabilities, and third-gender candidates; no separate written/viva fee is published. Confirm the live circular. (Bangladesh Public Service Commission (BPSC))

BCS Written Physics Exam Content Outline

Part I (100 marks)

Part I — Mechanics

Newton's laws, planar motion, work–energy, rotation, torque, angular momentum, moment of inertia, gravitation, and gravitational potential (BPSC Physics Part I (a)).

Part I (100 marks)

Part I — Properties of Matter, Waves, Heat

Elasticity and beam bending, surface tension and capillarity, viscosity/Poiseuille/Bernoulli, waves, Doppler, SHM and pendulums, heat transfer, thermodynamic laws, Maxwell relations/Clausius–Clapeyron, and kinetic theory (Part I (b)–(d)).

Part I (100 marks)

Part I — Electricity, Magnetism and Optics

Coulomb/Gauss, potential, capacitance, Kirchhoff/Wheatstone, Biot–Savart/Ampère, Faraday, LC and LCR/AC, Huygens, Young, diffraction, Bragg, and resolving power (Part I (e)–(f)).

Part II (100 marks)

Part II — Mechanics, Quantum, Atomic, Nuclear

Rocket motion, Euler–Lagrange and Hamilton, Lorentz/relativistic dynamics, Schrödinger postulates, commutators, uncertainty, angular momentum and spin, WKB, photoelectric/Compton/Bohr, radioactivity, Q-value, fission/fusion, and accelerators (Part II (a)–(d)).

Part II (100 marks)

Part II — Solid State and Electronics

Unit cells, Madelung, Einstein/Debye, Schottky/Frenkel defects, band theory, semiconductors, superconductivity, diodes/rectifiers, BJT, op-amps, SCR/TRIAC, AM/FM, television and radar (Part II (e)–(f)).

How to Pass the BCS Written Physics Exam

What You Need to Know

  • Passing score: 50% aggregate on the 900-mark written examination (BPSC page); per-paper minima also apply as set by BPSC. Confirm the current circular.
  • Assessment: Official BPSC Physics syllabus (subject code 511): Part I 100 marks (mechanics; properties of matter; waves and oscillation; heat, thermodynamics and kinetic theory; electricity and magnetism; optics) and Part II 100 marks (classical mechanics and special relativity; quantum mechanics; atomic and molecular physics; nuclear physics; solid state physics; electronics). The real paper is descriptive. Technical/professional cadre written set includes this 200-mark post-related paper within the 900-mark written stage; dual-cadre applicants sit it as an extra paper. This 100-question English MCQ bank is a study adaptation only.
  • Time limit: 4 hours is the duration used for BPSC 200-mark written papers on this site and in longstanding BPSC sitting practice; confirm the current routine
  • Exam fee: Tk. 200 general (50th BCS); Tk. 50 for ethnic minority, persons with disabilities, and third-gender candidates; no separate written/viva fee is published. Confirm the live circular.

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

BCS Written Physics Study Tips from Top Performers

1Weight revision 50/50 to Part I and Part II; the official paper is 100 marks each.
2Practise full SI-unit workings (forces, Gauss, LCR, Bragg, Bohr, Q-value). Official answers are descriptive derivations, not bubbles.
3Memorize sign conventions: work by a conservative force is −ΔU; photoelectric K_max = hf − φ; Compton shift uses (1 − cos θ).
4For Part II, be able to write Euler–Lagrange, state [x, p] = iħ, and distinguish three-level (ruby) from four-level (He–Ne, Nd:YAG) lasers.
5After these MCQs, time a handwritten 200-mark script. This bank does not replace writing practice.

Frequently Asked Questions

Is the official BCS Physics paper multiple choice?

No. BPSC examines Physics (subject code 511) as a 200-mark descriptive written paper. This site's English MCQs are a study adaptation to drill syllabus facts and calculations, not an official translation or a simulation of the handwritten format.

How is the BCS Physics syllabus split?

The official written syllabus is Part I (100 marks) and Part II (100 marks). Part I is classical undergraduate physics (mechanics through optics). Part II is modern and applied physics (analytical mechanics, relativity, quantum, atomic/molecular, nuclear, solid state, and electronics).

What is the duration and pass rule for the written stage?

BPSC 200-mark written papers are sat in a 4-hour session in longstanding practice; confirm the current routine. The BPSC page states a 50% aggregate pass on the 900-mark written examination, with per-paper minima also applied as set by BPSC.

Who sits the post-related Physics paper?

It is the 200-mark post-related subject for relevant technical/professional cadres. Dual-cadre applicants sit this extra 200-mark paper in addition to the general written set. Confirm which cadres require Physics in the live circular.

What is the application fee?

For the 50th BCS cycle, reporting citing PSC lists Tk. 200 for general candidates and Tk. 50 for ethnic minority, persons with disabilities, and third-gender candidates. There is no separate published written or viva fee. Confirm the live circular and Teletalk payment notice.

How many marks is the viva voce?

The BPSC BCS page still lists viva voce as 200 marks with a 50% pass. Reporting from the 47th BCS onward has described a 100-mark viva, and PSC has discussed reducing it further. Use the figure printed in your circular.

In what language is this practice bank?

Official BPSC papers may be answered in Bangla or English as permitted for the sitting. This bank is an original English-language MCQ study adaptation of the Physics syllabus, not an official translation or a substitute for Bangla/English written answers.