13.3 Theoretical and Experimental Probability & Compound Events

Key Takeaways

  • Probability quantifies likelihood on a closed scale from 0 (impossible event) to 1 (certain event), with theoretical probability defined as P(A) = (number of favorable outcomes) / (total equally likely outcomes).

  • Experimental (empirical) probability is the observed ratio of successes to trials; by the Law of Large Numbers, experimental probability converges toward theoretical probability as the number of trials approaches infinity.

  • The Complement Rule dictates that P(A') = 1 - P(A); it is especially powerful for solving 'at least one' compound problems via P(at least one) = 1 - P(none).

  • The Fundamental Counting Principle states that if k successive events have n_1, n_2, ..., n_k independent choices, the total compound outcomes equal n_1 × n_2 × ... × n_k.

  • Compound probability rules distinguish between independent events (P(A and B) = P(A) · P(B)), dependent events (P(A and B) = P(A) · P(B|A)), mutually exclusive events (P(A or B) = P(A) + P(B)), and overlapping events (P(A or B) = P(A) + P(B) - P(A and B)).

Last updated: August 2026

Theoretical and Experimental Probability & Compound Events

Quick Answer: On the WEST-B Mathematics subtest (Objective 0016), probability questions require applying exact rules of counting and chance. Core formulas include: Theoretical Probability (P(A)=favorabletotalP(A) = \frac{\text{favorable}}{\text{total}}), Complement Rule (P(A′)=1−P(A)P(A') = 1 - P(A)), Fundamental Counting Principle (n1×n2×⋯×nkn_1 \times n_2 \times \dots \times n_k), Independent Multiplication (P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B)), Dependent Multiplication (P(A and B)=P(A)×P(B∣A)P(A \text{ and } B) = P(A) \times P(B|A)), Overlapping Addition Rule (P(A or B)=P(A)+P(B)−P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)), and the 'At Least One' Rule (P(≥1)=1−P(none)P(\ge 1) = 1 - P(\text{none})).


1. Probability Foundations & Definitions

Probability is the mathematical measure of the likelihood that an event will occur.

+---------------------------------------------------------------------------------------------------+
|                                 PROBABILITY SCALE & TERMINOLOGY                                   |
|                                                                                                   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | TERM                  | DEFINITION                  | MATHEMATICAL NOTATION / EXAMPLE     |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Experiment            | A repeatable process that   | Tossing a coin, rolling a die,      |   |
|   |                       | yields an outcome           | drawing a card                      |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Sample Space (S)      | The set of ALL possible     | Rolling a 6-sided die:              |   |
|   |                       | distinct outcomes           | S = {1, 2, 3, 4, 5, 6}, |S| = 6     |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Event (E)             | Any subset of sample space S| Rolling an even number:             |   |
|   |                       |                             | E = {2, 4, 6}, |E| = 3              |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Probability Axiom     | Probability must fall       | 0 ≤ P(E) ≤ 1                        |   |
|   |                       | strictly between 0 and 1    | (or 0% to 100%)                     |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Impossible Event      | An event that cannot occur  | P(∅) = 0 (e.g., rolling a 7 on die) |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Certain Event         | An event guaranteed to occur| P(S) = 1 (e.g., rolling ≤ 6 on die) |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
+---------------------------------------------------------------------------------------------------+
                                   THE PROBABILITY SCALE

         Impossible             Unlikely             Even Chance           Likely               Certain
             |----------------------|---------------------|-------------------|--------------------|
            0.0                    0.25                  0.50                0.75                 1.0
            0%                     25%                   50%                 75%                  100%
            0                      1/4                   1/2                 3/4                  1

2. Theoretical vs. Experimental Probability & Law of Large Numbers

+---------------------------------------------------------------------------------------------------+
|                       THEORETICAL VS. EXPERIMENTAL PROBABILITY MATRIX                             |
|                                                                                                   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | PROPERTY              | THEORETICAL PROBABILITY     | EXPERIMENTAL (EMPIRICAL) PROBABILITY|
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Calculation Basis     | Mathematical analysis of    | Actual collected data from trials/  |   |
|   |                       | equally likely outcomes     | experiments                         |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Formula               | P(A) = n(A) / n(S)          | P_exp(A) = (Observed Successes) /   |   |
|   |                       |                             | (Total Number of Trials)            |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Example: Fair Coin    | P(Heads) = 1/2 = 0.50       | 54 Heads in 100 flips = 54/100=0.54 |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Law of Large Numbers  | Fixed theoretical benchmark | As trials n → ∞, Experimental P     |   |
|   |                       | value                       | approaches Theoretical P            |   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
+---------------------------------------------------------------------------------------------------+

The Complement Rule

The complement of an event AA (denoted A′A', AcA^c, or not A\text{not } A) consists of all outcomes in sample space SS that are not in AA:

P(A′)=1−P(A)  ⟺  P(A)+P(A′)=1P(A') = 1 - P(A) \iff P(A) + P(A') = 1
  • The 'At Least One' Shortcut: When calculating the probability that an event occurs at least once across multiple trials: P(at least one occurrence)=1−P(zero occurrences)P(\text{at least one occurrence}) = 1 - P(\text{zero occurrences})

3. Counting Principles, Permutations & Combinations

A. The Fundamental Counting Principle (Multiplication Rule)

If an experiment consists of kk consecutive sequential steps, where step 1 can occur in n1n_1 ways, step 2 in n2n_2 ways, ..., and step kk in nkn_k ways, the total number of compound outcomes in the sample space is:

Total Outcomes=n1×n2×n3×⋯×nk\text{Total Outcomes} = n_1 \times n_2 \times n_3 \times \dots \times n_k

Example: A school cafeteria offers a lunch combo with a choice of 3 sandwiches, 4 sides, and 2 drinks. Total distinct lunches =3×4×2=24= 3 \times 4 \times 2 = 24.

B. Permutations vs. Combinations

+---------------------------------------------------------------------------------------------------+
|                                PERMUTATION VS. COMBINATION MATRIX                                 |
|                                                                                                   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | FEATURE               | PERMUTATIONS P(n, r)        | COMBINATIONS C(n, r)                |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Does Order Matter?    | YES (Order / Position counts| NO (Order does not matter; group/   |
|   |                       | e.g., President, VP, Sec)   | committee selection)                |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Mathematical Formula  | P(n, r) = n! / (n - r)!     | C(n, r) = n! / [r! (n - r)!]        |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Example: Select 2     | P(5, 2) = 5 × 4 = 20        | C(5, 2) = (5 × 4) / (2 × 1) = 10    |
|   | items from 5 {A,B,...}| (AB is distinct from BA)    | ({A, B} is same group as {B, A})    |
|   +-----------------------+-----------------------------+-------------------------------------+   |
+---------------------------------------------------------------------------------------------------+

4. Compound Events: Independent vs. Dependent

A compound event involves the simultaneous or sequential occurrence of two or more simple events.

+---------------------------------------------------------------------------------------------------+
|                                 COMPOUND PROBABILITY RULES                                        |
|                                                                                                   |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | EVENT RELATIONSHIP    | CONDITION                   | PROBABILITY FORMULA                 |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Independent Events    | Outcome of Event A does NOT | P(A and B) = P(A) × P(B)            |
|   | (With Replacement)    | affect Event B              |                                     |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Dependent Events      | Outcome of Event A ALTERS   | P(A and B) = P(A) × P(B | A)        |
|   | (Without Replacement) | the sample space of Event B |                                     |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Mutually Exclusive    | Events CANNOT occur at the  | P(A or B) = P(A) + P(B)             |
|   | (Disjoint) Events     | same time: P(A and B) = 0   |                                     |
|   +-----------------------+-----------------------------+-------------------------------------+   |
|   | Overlapping Events    | Events CAN occur            | P(A or B) = P(A) + P(B) - P(A and B)|
|   | (Non-Disjoint)        | simultaneously              |                                     |
|   +-----------------------+-----------------------------+-------------------------------------+   |
+---------------------------------------------------------------------------------------------------+
                       Venn Diagram: Overlapping vs. Disjoint

          Overlapping Events (A ∩ B ≠ ∅)            Mutually Exclusive (Disjoint)
             +----------+   +----------+                +----------+   +----------+
            /   Only A   \ /   Only B   \              /            \ /            \
           |              X              |            |   Event A    |   Event B    |
            \    (A)     / \    (B)     /              \            / \            /
             +----------+   +----------+                +----------+   +----------+
                        Intersection
                         (A and B)

5. Tree Diagrams & Geometric Probability

A. Tree Diagrams

A tree diagram visualizes multi-stage probabilistic experiments by displaying branches for each sequential outcome with conditional probabilities labeled on each branch.

                            Tree Diagram: Two Coin Flips

                                                 Outcome    Probability
                                                +-------+  +-----------+
                                           H -->|  H, H |   1/2 × 1/2 = 1/4
                                  1/2     /     +-------+  +-----------+
                                   +----> H
                                  /       \ 1/2 +-------+  +-----------+
                                 /         T -->|  H, T |   1/2 × 1/2 = 1/4
                              Start             +-------+  +-----------+
                                 \         1/2  +-------+  +-----------+
                                  \ 1/2    H -->|  T, H |   1/2 × 1/2 = 1/4
                                   +----> T     +-------+  +-----------+
                                          \ 1/2 +-------+  +-----------+
                                           T -->|  T, T |   1/2 × 1/2 = 1/4
                                                +-------+  +-----------+

B. Geometric (Area) Probability

In geometric probability, outcomes correspond to points in a geometric region (length, area, or volume):

P(Landing in Target Region)=Area of Target RegionTotal Area of Sample Space RegionP(\text{Landing in Target Region}) = \frac{\text{Area of Target Region}}{\text{Total Area of Sample Space Region}}
  • Concentric Circles Example: If a bullseye has radius rr inside a dartboard of radius RR: P(Bullseye)=πr2πR2=r2R2P(\text{Bullseye}) = \frac{\pi r^2}{\pi R^2} = \frac{r^2}{R^2}

6. Step-by-Step Worked Probability Problems

Problem 1: Dependent Probability (Without Replacement)

Problem: A jar contains 66 red marbles, 44 blue marbles, and 22 yellow marbles (1212 marbles total). Two marbles are drawn at random one after another without replacement. What is the probability that both marbles drawn are red?

Step-by-Step Solution:

  1. Calculate probability of drawing first red marble: P(R1)=Red MarblesTotal Marbles=612=12P(R_1) = \frac{\text{Red Marbles}}{\text{Total Marbles}} = \frac{6}{12} = \frac{1}{2}
  2. Calculate conditional probability of drawing second red marble:
    • One red marble has been removed: 55 red marbles remaining.
    • Total marbles remaining: 12−1=1112 - 1 = 11 marbles.
    P(R2∣R1)=511P(R_2 \mid R_1) = \frac{5}{11}
  3. Multiply probabilities (Multiplication Rule for Dependent Events): P(R1 and R2)=P(R1)×P(R2∣R1)=612×511=12×511=522P(R_1 \text{ and } R_2) = P(R_1) \times P(R_2 \mid R_1) = \frac{6}{12} \times \frac{5}{11} = \frac{1}{2} \times \frac{5}{11} = \frac{5}{22}
  4. Convert to decimal/percentage: 522≈0.2273=22.73%\frac{5}{22} \approx 0.2273 = 22.73\%

Problem 2: Overlapping Addition Rule (Deck of Cards)

Problem: A single card is drawn at random from a standard, well-shuffled 52-card deck. What is the probability that the card drawn is either an Ace OR a Heart?

Step-by-Step Solution:

  1. Identify individual event probabilities:
    • Event AA (Drawing an Ace): There are 44 Aces in a deck   ⟹  P(A)=452\implies P(A) = \frac{4}{52}.
    • Event BB (Drawing a Heart): There are 1313 Hearts in a deck   ⟹  P(B)=1352\implies P(B) = \frac{13}{52}.
  2. Identify overlapping outcomes (A∩BA \cap B):
    • There is exactly 11 card that is both an Ace and a Heart (the Ace of Hearts).
    P(A and B)=152P(A \text{ and } B) = \frac{1}{52}
  3. Apply the Addition Rule for Overlapping Events: P(A or B)=P(A)+P(B)−P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) P(A or B)=452+1352−152=4+13−152=1652P(A \text{ or } B) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{4 + 13 - 1}{52} = \frac{16}{52}
  4. Simplify the fraction: 1652=413≈30.77%\frac{16}{52} = \frac{4}{13} \approx 30.77\%

Problem 3: The 'At Least One' Complement Problem

Problem: A couple plans to have 44 children. Assuming each child is equally likely to be a boy or a girl (P(Boy)=P(Girl)=0.5P(\text{Boy}) = P(\text{Girl}) = 0.5) independently, what is the probability that the couple has at least one girl?

Step-by-Step Solution:

  1. Define the complementary event:
    • The complement of "at least one girl" is "zero girls" (which means all 4 children are boys).
  2. Calculate probability of zero girls (all 4 boys): P(Boy1 and Boy2 and Boy3 and Boy4)=(12)4=116P(\text{Boy}_1 \text{ and } \text{Boy}_2 \text{ and } \text{Boy}_3 \text{ and } \text{Boy}_4) = \left(\frac{1}{2}\right)^4 = \frac{1}{16}
  3. Apply Complement Rule: P(≥1 Girl)=1−P(0 Girls)=1−116=1616−116=1516P(\ge 1 \text{ Girl}) = 1 - P(\text{0 Girls}) = 1 - \frac{1}{16} = \frac{16}{16} - \frac{1}{16} = \frac{15}{16}
  4. Convert to decimal/percentage: 1516=0.9375=93.75%\frac{15}{16} = 0.9375 = 93.75\% There is a 1516\frac{15}{16} (93.75%93.75\%) chance of having at least one girl.
Loading diagram...
Compound Probability Decision Tree
Test Your Knowledge

A bag contains 5 red marbles, 4 blue marbles, and 3 green marbles (12 marbles total). If two marbles are drawn at random one after another without replacement, what is the probability that both marbles drawn are blue?

A

1/9

B

4/33

C

1/11

D

1/12

Test Your Knowledge

A standard 52-card deck is shuffled, and a single card is dealt at random. What is the probability that the card drawn is either a Face card (Jack, Queen, King) OR a Diamond?

A

25/52

B

1/2

C

7/13

D

11/26

Test Your Knowledge

A fair six-sided die is rolled 3 times. What is the probability of rolling at least one 6 across the 3 rolls?

A

91/216

B

125/216

C

1/2

D

1/216

Test Your Knowledge

A high school club must select a 4-person executive leadership team consisting of 1 president, 1 vice president, 1 secretary, and 1 treasurer from a pool of 8 candidates. If no student can hold more than one office, how many different leadership slates are possible?

A

70

B

1,680

C

336

D

40,320

Sections you finish are checked off in the contents.