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6.1 Number Properties, Divisibility Rules & Prime Factorization

Key Takeaways

  • Divisibility rules allow rapid identification of factors without long division: 3 and 9 sum digits, 4 and 8 check trailing digits, and 11 checks alternating digit sums.

  • Every positive integer greater than 1 can be uniquely factorized into a product of prime numbers (Fundamental Theorem of Arithmetic).

  • The total number of positive factors of a number with prime decomposition n = p1^a1 * p2^a2 * ... is given by (a1 + 1)(a2 + 1)...

  • The product of any two positive integers equals the product of their Greatest Common Divisor (GCD) and Least Common Multiple (LCM): a * b = GCD(a,b) * LCM(a,b).

  • The unit digits of powers follow periodic cycles (cyclicity), enabling rapid evaluation of large exponents without full calculation.

Last updated: August 2026

Number Properties, Divisibility Rules & Prime Factorization

Number theory forms the structural foundation of the Quantitative Reasoning section on the National Testing Service (NTS) GAT General examination. A significant portion of quantitative questions evaluates your mastery of integer properties, divisibility shortcuts, prime factor decomposition, and modular patterns. By mastering these fundamental arithmetic principles, you can bypass lengthier long division and algebraic operations, solving GAT quantitative items with speed and precision.


1. Classification of Real Numbers & Arithmetic Parity Rules

Understanding the real number system and the behavioral properties of odd and even integers is essential for solving quantitative comparison and algebraic sufficiency problems on the GAT.

Classification Breakdown

  • Real Numbers (R\mathbb{R}): All numbers on the continuous number line, divided into rational and irrational numbers.
  • Rational Numbers (Q\mathbb{Q}): Numbers expressible in the form pq\frac{p}{q}, where pp and qq are integers and q≠0q \neq 0. Examples include 34\frac{3}{4}, −7-7, 0.250.25, and 0.33‾0.\overline{33}.
  • Irrational Numbers: Non-repeating, non-terminating decimals that cannot be written as fractions. Examples include 2\sqrt{2}, 5\sqrt{5}, π\pi, and ee.
  • Integers (Z\mathbb{Z}): Complete positive and negative whole numbers including zero: {…,−3,−2,−1,0,1,2,3,… }\{\dots, -3, -2, -1, 0, 1, 2, 3, \dots\}.
  • Whole Numbers: Non-negative integers: {0,1,2,3,… }\{0, 1, 2, 3, \dots\}.
  • Natural Numbers (N\mathbb{N}): Positive counting integers: {1,2,3,… }\{1, 2, 3, \dots\}.
  • Prime Numbers: Positive integers strictly greater than 11 that have exactly two positive divisors: 11 and the number itself. The first ten primes are 2,3,5,7,11,13,17,19,23,292, 3, 5, 7, 11, 13, 17, 19, 23, 29.
    • Note: 22 is the only even prime number and the smallest prime number. 11 is neither prime nor composite.
  • Composite Numbers: Positive integers greater than 11 that have more than two positive divisors (e.g., 4,6,8,9,104, 6, 8, 9, 10).

Parity Rules for Even and Odd Integers

Let EE represent an even integer ({0,±2,±4,… }\{0, \pm 2, \pm 4, \dots\}) and OO represent an odd integer ({±1,±3,±5,… }\{\pm 1, \pm 3, \pm 5, \dots\}):

OperationParity RuleAlgebraic Example
Addition / SubtractionE±E=EE \pm E = E6+4=106 + 4 = 10
O±O=EO \pm O = E7+5=127 + 5 = 12
E±O=OE \pm O = O8−3=58 - 3 = 5
MultiplicationE×E=EE \times E = E4×6=244 \times 6 = 24
O×O=OO \times O = O3×7=213 \times 7 = 21
E×O=EE \times O = E4×5=204 \times 5 = 20
Exponents (n≥1n \ge 1)En=EE^n = E43=644^3 = 64
On=OO^n = O53=1255^3 = 125

Key Exam Insight: If the product of a set of integers is odd, every single integer in that set must be odd. If the product of a set of integers is even, at least one integer in the set must be even.

Properties of Consecutive Integers

  • The sum of nn consecutive integers is divisible by nn if nn is an odd integer (e.g., 3+4+5=123 + 4 + 5 = 12, which is divisible by 33).
  • The product of kk consecutive integers is always divisible by k!k! (k factorial). For instance, the product of any three consecutive integers (n(n+1)(n+2)n(n+1)(n+2)) is always divisible by 3!=63! = 6.

2. Universal Divisibility Rules & Multi-Digit Shortcuts

Divisibility tests allow you to determine whether a large integer is divisible by a divisor without conducting time-consuming long division. The table below lists the essential rules tested on the GAT:

DivisorDivisibility CriterionTest Example
2Last digit is even (0,2,4,6,80, 2, 4, 6, 8).4,5864,586 ends in 66 →\rightarrow Divisible.
3Sum of all digits is divisible by 33.7,821→7+8+2+1=187,821 \rightarrow 7+8+2+1 = 18 (18÷3=618 \div 3 = 6) →\rightarrow Divisible.
4Last two digits form a number divisible by 44.19,436→3619,436 \rightarrow 36 (36÷4=936 \div 4 = 9) →\rightarrow Divisible.
5Last digit is 00 or 55.8,9458,945 ends in 55 →\rightarrow Divisible.
6Number satisfies tests for both 2 and 3 (must be even AND digit sum divisible by 33).3,4623,462 is even and sum =15= 15 →\rightarrow Divisible.
7Double the last digit, subtract it from the remaining truncated number; result must be divisible by 77.343→34−(2×3)=28343 \rightarrow 34 - (2 \times 3) = 28 (28÷7=428 \div 7 = 4) →\rightarrow Divisible.
8Last three digits form a number divisible by 88.57,112→11257,112 \rightarrow 112 (112÷8=14112 \div 8 = 14) →\rightarrow Divisible.
9Sum of all digits is divisible by 99.48,357→4+8+3+5+7=2748,357 \rightarrow 4+8+3+5+7 = 27 (27÷9=327 \div 9 = 3) →\rightarrow Divisible.
10Last digit is 00.12,98012,980 ends in 00 →\rightarrow Divisible.
11Difference between the sum of odd-placed digits and even-placed digits is 00 or a multiple of 1111.9,174→(9+7)−(1+4)=16−5=119,174 \rightarrow (9+7) - (1+4) = 16 - 5 = 11 →\rightarrow Divisible.
12Number satisfies tests for both 3 and 4.5,184→5,184 \rightarrow Sum =18= 18 (div by 33), last two =84= 84 (div by 44) →\rightarrow Divisible.
15Number satisfies tests for both 3 and 5.7,425→7,425 \rightarrow Ends in 55, sum =18= 18 →\rightarrow Divisible.

Advanced Composite Divisibility

To test divisibility by any composite number CC, break CC into two coprime factors aa and bb (meaning GCD(a,b)=1\text{GCD}(a,b) = 1) such that C=a×bC = a \times b. The original number is divisible by CC if and only if it is divisible by both aa and bb.

  • To test for 36: Test for 44 and 99 (since GCD(4,9)=1\text{GCD}(4,9) = 1).
  • To test for 72: Test for 88 and 99 (since GCD(8,9)=1\text{GCD}(8,9) = 1).

3. Prime Factorization, Divisor Counting & GCD / LCM Principles

According to the Fundamental Theorem of Arithmetic, every integer greater than 11 can be uniquely represented as a product of prime powers:

n=p1a1⋅p2a2⋅p3a3…pkakn = p_1^{a_1} \cdot p_2^{a_2} \cdot p_3^{a_3} \dots p_k^{a_k}

where p1,p2,…,pkp_1, p_2, \dots, p_k are distinct prime numbers and a1,a2,…,aka_1, a_2, \dots, a_k are positive integer exponents.

Formula for Total Number of Positive Factors

If the canonical prime factorization of nn is p1a1⋅p2a2…pkakp_1^{a_1} \cdot p_2^{a_2} \dots p_k^{a_k}, the total number of positive divisors N(n)N(n) is calculated by adding 11 to each exponent and taking their product:

N(n)=(a1+1)(a2+1)(a3+1)…(ak+1)N(n) = (a_1 + 1)(a_2 + 1)(a_3 + 1) \dots (a_k + 1)

Worked Example of Divisor Count:

Find the total number of positive factors of 360360.

  1. Execute prime factorization: 360=36×10=(22×32)×(2×5)=23×32×51360 = 36 \times 10 = (2^2 \times 3^2) \times (2 \times 5) = 2^3 \times 3^2 \times 5^1.
  2. Apply the divisor formula: N(360)=(3+1)(2+1)(1+1)=4×3×2=24N(360) = (3 + 1)(2 + 1)(1 + 1) = 4 \times 3 \times 2 = 24 total factors.

Greatest Common Divisor (GCD) & Least Common Multiple (LCM)

  • Greatest Common Divisor (GCD / HCF): The largest positive integer that divides two or more integers without leaving a remainder. Found by taking the lowest power of common prime factors.
  • Least Common Multiple (LCM): The smallest positive integer divisible by two or more integers. Found by taking the highest power of all prime factors present.

Core GCD-LCM Theorem:

For any two positive integers aa and bb:

a×b=GCD(a,b)×LCM(a,b)a \times b = \text{GCD}(a, b) \times \text{LCM}(a, b)

Fractional GCD and LCM Rules:

When working with simplified fractions ab\frac{a}{b} and cd\frac{c}{d}:

GCD(ab,cd)=GCD(a,c)LCM(b,d)\text{GCD}\left(\frac{a}{b}, \frac{c}{d}\right) = \frac{\text{GCD}(a, c)}{\text{LCM}(b, d)} LCM(ab,cd)=LCM(a,c)GCD(b,d)\text{LCM}\left(\frac{a}{b}, \frac{c}{d}\right) = \frac{\text{LCM}(a, c)}{\text{GCD}(b, d)}
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Number Theory Problem-Solving Decision Framework

4. Cyclicity of Unit Digits & Remainder Principles

When large powers appear on the GAT (e.g., "What is the units digit of 71437^{143}?"), calculating the actual value is impossible. Instead, exploit the cyclicity of units digits under exponentiation.

Cyclicity Patterns (Base 0 through 9)

Every digit has a predictable repeating cycle of unit digits when raised to successive positive integer powers (n=1,2,3,4,…n = 1, 2, 3, 4, \dots):

Base DigitRepeating Unit Digit CycleCycle Length
0, 1, 5, 6Constant: Always retains the same digit (0,1,5,60, 1, 5, 6).1
44,64, 6 (Odd powers end in 44, Even powers end in 66).2
99,19, 1 (Odd powers end in 99, Even powers end in 11).2
22,4,8,62, 4, 8, 64
33,9,7,13, 9, 7, 14
77,9,3,17, 9, 3, 14
88,4,2,68, 4, 2, 64

Step-by-Step Cyclicity Algorithm:

To find the units digit of BEB^E:

  1. Identify the cycle length CC for base digit BB (use C=4C = 4 as a universal cycle length for all digits).
  2. Calculate the remainder R=E(modC)R = E \pmod C.
  3. If R>0R > 0, the units digit of BEB^E is equal to the units digit of BRB^R.
  4. If R=0R = 0, the units digit of BEB^E is equal to the units digit of BCB^C.

5. Comprehensive GAT Worked Examples

Worked Example 1: Divisibility with Unknown Digits

Question: Find the single digit XX such that the 6-digit number 53X,74453X,744 is divisible by 1111.

Solution:

  1. Apply the divisibility test for 1111: difference between odd-placed digits sum and even-placed digits sum.
  2. Sum of odd-placed digits (from left): 5+X+4=9+X5 + X + 4 = 9 + X.
  3. Sum of even-placed digits (from left): 3+7+4=143 + 7 + 4 = 14.
  4. Difference =(9+X)−14=X−5= (9 + X) - 14 = X - 5.
  5. For the number to be divisible by 1111, (X−5)(X - 5) must equal 00 (or a multiple of 1111).
  6. Setting X−5=0  ⟹  X=5X - 5 = 0 \implies X = 5.
  7. Final Answer: X=5X = 5.

Worked Example 2: Units Digit of Exponential Sums

Question: What is the units digit of 785+3427^{85} + 3^{42}?

Solution:

  1. Evaluate 7857^{85} units digit:
    • Base 77 cycle length is 44: 7,9,3,17, 9, 3, 1.
    • Exponent remainder: 85÷4=2185 \div 4 = 21 remainder 11.
    • So, 7857^{85} has the same units digit as 71=77^1 = \mathbf{7}.
  2. Evaluate 3423^{42} units digit:
    • Base 33 cycle length is 44: 3,9,7,13, 9, 7, 1.
    • Exponent remainder: 42÷4=1042 \div 4 = 10 remainder 22.
    • So, 3423^{42} has the same units digit as 32=93^2 = \mathbf{9}.
  3. Combine units digits: 7+9=16→7 + 9 = 16 \rightarrow units digit is 6\mathbf{6}.
  4. Final Answer: 66.

Worked Example 3: LCM Real-World Application

Question: Three traffic signals flash at intervals of 1212 seconds, 1818 seconds, and 3030 seconds respectively. If they flash together at 9:00 AM, at what time will they next flash simultaneously?

Solution:

  1. Simultaneous flashing occurs at time intervals equal to the LCM of 12,18,12, 18, and 3030.
  2. Prime factorizations:
    • 12=22×3112 = 2^2 \times 3^1
    • 18=21×3218 = 2^1 \times 3^2
    • 30=21×31×5130 = 2^1 \times 3^1 \times 5^1
  3. LCM(12,18,30)=22×32×51=4×9×5=180\text{LCM}(12, 18, 30) = 2^2 \times 3^2 \times 5^1 = 4 \times 9 \times 5 = 180 seconds.
  4. Convert seconds to minutes: 180 seconds=3 minutes180 \text{ seconds} = 3 \text{ minutes}.
  5. Add 33 minutes to 9:00 AM →\rightarrow 9:03 AM.
  6. Final Answer: 9:03 AM.
Test Your Knowledge

If a 5-digit number 73K42 is completely divisible by 9, what is the value of the digit K?

A

2

B

4

C

6

D

8

Test Your Knowledge

What is the total number of positive factors (divisors) of 720?

A

24

B

30

C

36

D

18

Test Your Knowledge

What is the units digit of the expression 7^143?

A

7

B

9

C

3

D

1

Test Your Knowledge

Two numbers are in the ratio 4 : 5 and their Greatest Common Divisor (GCD) is 12. What is the Least Common Multiple (LCM) of these two numbers?

A

120

B

240

C

300

D

60

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