6.2 Fractions, Decimals, Percentages & Profit-Loss Math
Key Takeaways
- To convert a repeating decimal to a vulgar fraction, place the repeating block over an equal number of 9s and simplify.
- Percentage change is always calculated relative to the original base value: Percentage Change = ((New Value - Original Value) / Original Value) * 100%.
- Successive percentage changes of +A% and +B% yield a net change of (A + B + (A * B)/100)%, avoiding common additive errors.
- Profit percentage is calculated on Cost Price (CP), whereas Discount percentage is strictly calculated on Marked Price (MP).
- Simple interest grows linearly with time, whereas compound interest grows exponentially due to interest earning interest.
Fractions, Decimals, Percentages & Profit-Loss Math
Fractions, decimals, percentages, and commercial profit-loss math form the core of practical quantitative reasoning on the NTS GAT General. These concepts evaluate your numerical agility in switching between equivalence formats and solving multi-step financial problems. Whether computing successive retail discounts, adjusting for inflation rates, or determining compound interest yields, mastering these operational rules ensures high performance on test day.
1. Fraction Mechanics & Decimal Conversions
A fraction represents a part of a whole, expressed as $\frac{a}{b}$ where $a$ is the numerator and $b \neq 0$ is the denominator.
Classification of Fractions
- Proper Fraction: Numerator is strictly less than denominator ($a < b$), e.g., $\frac{3}{7}$. Value is strictly less than $1$.
- Improper Fraction: Numerator is greater than or equal to denominator ($a \ge b$), e.g., $\frac{11}{4}$. Value is $\ge 1$.
- Mixed Number: Combination of an integer and a proper fraction, e.g., $2 \frac{3}{4} = \frac{(2 \times 4) + 3}{4} = \frac{11}{4}$.
Rapid Fraction Comparison Methods
When comparing two fractions $\frac{a}{b}$ and $\frac{c}{d}$:
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Cross-Multiplication Shortcut:
- Compute $a \times d$ (left product) and $b \times c$ (right product).
- If $a \cdot d > b \cdot c$, then $\frac{a}{b} > \frac{c}{d}$.
- If $a \cdot d < b \cdot c$, then $\frac{a}{b} < \frac{c}{d}$.
- Example: Compare $\frac{7}{9}$ and $\frac{4}{5}$. Cross products: $7 \times 5 = 35$ vs $9 \times 4 = 36$. Since $35 < 36$, $\frac{7}{9} < \frac{4}{5}$.
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Benchmark Comparison: Compare both fractions against common benchmarks like $\frac{1}{2}$ or $1$.
Converting Repeating Decimals to Vulgar Fractions
Decimals with infinitely repeating digit blocks can be converted into vulgar fractions $\frac{p}{q}$ using algebraic shortcuts:
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Pure Repeating Decimal ($0.\overline{a_1 a_2 \dots a_k}$): Write the repeating block in the numerator over $k$ nines ($9$) in the denominator.
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Mixed Repeating Decimal ($0.b_1 b_2 \dots b_m \overline{a_1 \dots a_k}$): Subtract the non-repeating part from the total number, placed over $k$ nines followed by $m$ zeros. Example: Convert $0.2\overline{36}$ to a fraction:
2. Percentage Fundamentals & Multi-Step Variations
A percentage represents a fraction with a fixed denominator of $100$ ($x% = \frac{x}{100}$).
Core Percentage Formulas
Base Inversion Rule
- If quantity $A$ is $x%$ more than quantity $B$, then $B$ is less than $A$ by:
- If quantity $A$ is $x%$ less than quantity $B$, then $B$ is more than $A$ by:
Example: If Salary A is $25%$ more than Salary B, by what percentage is Salary B less than Salary A?
Net Successive Percentage Change Formula
If a quantity undergoes two successive percentage changes of $A%$ and $B%$, the single equivalent net percentage change is:
(Note: For percentage decreases, enter $A$ or $B$ as negative numbers.)
3. Commercial Arithmetic: Profit, Loss, Markup & Discounts
Commercial arithmetic problems revolve around three core prices: Cost Price (CP), Marked Price (MP) (List Price), and Selling Price (SP).
Fundamental Commercial Formulas
| Concept | Mathematical Equation | Key Dependency |
|---|---|---|
| Profit ($\pi$) | $\pi = SP - CP$ (when $SP > CP$) | Based on $CP$ |
| Loss ($L$) | $L = CP - SP$ (when $CP > SP$) | Based on $CP$ |
| Profit Percentage | $\text{Profit %} = \frac{SP - CP}{CP} \times 100%$ | Always relative to $CP$ |
| Loss Percentage | $\text{Loss %} = \frac{CP - SP}{CP} \times 100%$ | Always relative to $CP$ |
| Marked Price (MP) | $MP = CP \times \left(1 + \frac{\text{Markup %}}{100}\right)$ | Markup relative to $CP$ |
| Discount Percentage | $\text{Discount %} = \frac{MP - SP}{MP} \times 100%$ | Always relative to $MP$ |
| Selling Price (from MP) | $SP = MP \times \left(1 - \frac{\text{Discount %}}{100}\right)$ | Discount relative to $MP$ |
Crucial Distinction: Profit or loss is calculated as a percentage of Cost Price (CP). Discount is calculated as a percentage of Marked Price (MP).
Dishonest Dealer / False Weight Math
If a merchant claims to sell goods at Cost Price but uses a false weight of $W_{\text{false}}$ instead of true weight $W_{\text{true}}$:
4. Simple Interest & Compound Interest Foundations
Financial interest questions test your ability to compute investment growth over time.
Simple Interest (SI)
Interest computed strictly on the initial principal ($P$) throughout the entire investment tenure ($T$ years) at annual rate ($R%$):
Compound Interest (CI)
Interest computed on the principal plus all previously accumulated interest. After $T$ compounding cycles:
Fast Shortcut Formulas for Difference Between CI and SI
- For 2 Years ($T = 2$):
- For 3 Years ($T = 3$):
5. Comprehensive GAT Worked Examples
Worked Example 1: Successive Retail Discounts
Question: An item listed at PKR $10,000$ is sold after two successive discounts of $20%$ and $10%$. Find the final selling price and single equivalent discount percentage.
Solution:
- Use the net change formula for discounts ($A = -20%, B = -10%$):
- Calculate final Selling Price:
- Final Answer: Selling Price = PKR $7,200$; Equivalent Discount = $28%$.
Worked Example 2: Profit & Markup Computation
Question: A trader marks his goods $40%$ above the Cost Price and allows a discount of $15%$ on the Marked Price. What is his net profit percentage?
Solution:
- Let Cost Price ($CP$) $= 100$.
- Marked Price ($MP$) $= 100 + 40% \text{ of } 100 = 140$.
- Selling Price ($SP$) $= MP \times (1 - 0.15) = 140 \times 0.85 = 119$.
- Profit $= SP - CP = 119 - 100 = 19$.
- Profit Percentage $= \frac{19}{100} \times 100% = 19%$.
- Final Answer: $19%$.
Worked Example 3: CI vs SI Difference Problem
Question: The difference between Compound Interest and Simple Interest on a sum of money for $2$ years at $5%$ per annum is PKR $25$. Find the principal sum.
Solution:
- Apply the 2-year shortcut formula: $\text{CI} - \text{SI} = P \left(\frac{R}{100}\right)^2$.
- Substitute given values: $25 = P \left(\frac{5}{100}\right)^2 = P \left(\frac{1}{20}\right)^2 = P \left(\frac{1}{400}\right)$.
- Solve for $P$: $P = 25 \times 400 = 10,000$.
- Final Answer: PKR $10,000$.
A shopkeeper marks an item 25% above its cost price and then offers a discount of 12% on the marked price. What is his net profit percentage?
If the price of petrol increases by 25%, by what percentage must a motorist reduce petrol consumption so that total expenditure on petrol remains unchanged?
What vulgar fraction is equivalent to the repeating decimal 0.4666... (or 0.4[6])?
The difference between simple interest and compound interest (compounded annually) on a certain sum of money for 2 years at 10% per annum is PKR 150. What is the principal sum?