7.2 Applied Age Word Problems, Uniform Motion, and Relative Speed

Key Takeaways

  • In age word problems, structure information across past, present, and future epochs in a tabular matrix, enforcing the invariant that the age gap between any two individuals remains constant forever.

  • Apply the uniform motion model d = r × t by identifying the constant parameter (distance, time, or rate) across comparative scenarios to construct a balanced algebraic equation.

  • In opposite-direction travel (closing distance), add speeds (r1 + r2) to find the rate of convergence; in same-direction travel (pursuit problems), subtract speeds (|r1 - r2|) to determine the rate of closure.

  • For river and wind motion, calculate effective velocity as (r_vehicle + r_medium) downstream/tailwind and (r_vehicle - r_medium) upstream/headwind.

  • For equal-distance round trips at different speeds, average speed is never the simple arithmetic mean; it must be calculated using the harmonic mean formula v_avg = (2 × v1 × v2) / (v1 + v2).

Last updated: October 2026

7.2 Applied Age Word Problems, Uniform Motion, and Relative Speed

Important

Age and motion exercises teach translation from words to equations. Fix a reference time, preserve units, and use only the stated motion assumptions. These original contexts are not official examination items.

Civil service examinations consistently feature applied word problems because they evaluate an applicant's capacity to translate narrative real-world conditions into rigorous quantitative models. Diplomatic attachés and foreign service officers must schedule multi-vehicle diplomatic convoys, track repatriation flights across varying jet-stream winds, coordinate regional consular outreach itineraries, and evaluate long-term demographic and career seniority distributions. Understanding the underlying algebraic invariances across time and motion eliminates confusion and accelerates problem-solving speed.


Chronological Age Word Problems: The Invariance Framework

Age word problems describe mathematical relationships connecting the ages of two or more individuals across different chronological epochs (past, present, and future). Solving them systematically requires two principles:

1. The Fundamental Age Invariance

The chronological age difference between any two living persons remains strictly constant across all time:

(A+t)−(B+t)=A−B(A + t) - (B + t) = A - B

If Senior Diplomat AA is 1515 years older than Attaché BB today, AA was 1515 years older than BB ten years ago, and will remain exactly 1515 years older than BB thirty years from now. Ratios change over time, but the absolute difference is invariant.

2. The Epoch Matrix Setup

Never attempt to solve multi-epoch age problems in your head. Immediately construct a 2×32 \times 3 grid in the test booklet margin:

PersonPast Epoch (−k-k years)Present Epoch (t=0t = 0)Future Epoch (+m+m years)
Person AA−kA - kAAA+mA + m
Person BB−kB - kBBB+mB + m

Algebraic Formulation Steps:

  1. Choose a single reference variable for the present age of one individual (usually the younger person, so coefficients remain positive).
  2. Express the other person's present age in terms of that variable using the first relational premise.
  3. Advance or regress both individuals into the second epoch by adding or subtracting the elapsed years.
  4. Set up an equation connecting their ages in that second epoch and solve for the unknown variable.
  5. Re-read the final question carefully: verify whether the question asks for the present age, an age in the past, an age in the future, or the sum of their ages.

Uniform Motion Fundamentals: The d=r×td = r \times t Model

The examples here assume uniform motion unless the stem says otherwise: d=r×td=r\times t. Real acceleration, traffic, and stops require additional information. Do not assume every official word problem uses constant speed.

Unit Consistency and Dimensional Analysis

Before writing an equation, ensure all units match:

  • If distance is in kilometers (km\text{km}) and time is in hours (h\text{h}), speed must be in km/h\text{km/h}.
  • To convert speed from km/h\text{km/h} to meters per second (m/s\text{m/s}), multiply by 518\frac{5}{18}:
72 km/h=72×518=4×5=20 m/s72\text{ km/h} = 72 \times \frac{5}{18} = 4 \times 5 = 20\text{ m/s}
  • To convert minutes to hours, divide by 6060 (e.g., 45 minutes=4560=34 hour=0.75 hour45\text{ minutes} = \frac{45}{60} = \frac{3}{4}\text{ hour} = 0.75\text{ hour}).

The Three Core Uniform Motion Archetypes:

  1. Equal Distance Travelled (d1=d2d_1 = d_2): When two vehicles travel the same distance (e.g., an outbound trip and return trip, or two vehicles traveling between the same two cities), equate their distance expressions:
r1t1=r2t2r_1 t_1 = r_2 t_2
  1. Total Combined Distance (d1+d2=Dtotald_1 + d_2 = D_{\text{total}}): When two vehicles travel toward each other or travel in opposite directions starting from the same point, the sum of their individual distances equals the total separation:
r1t+r2t=Dtotal  ⟹  (r1+r2)t=Dtotalr_1 t + r_2 t = D_{\text{total}} \implies (r_1 + r_2)t = D_{\text{total}}
  1. Distance Separation / Difference (d2−d1=Δdd_2 - d_1 = \Delta d): In pursuit problems where a faster vehicle overtakes a slower vehicle, the faster vehicle must cover the initial head-start distance plus whatever distance the slower vehicle travels.

Relative Speed: Convergence and Pursuit Dynamics

Relative speed is the rate at which the distance between two moving bodies decreases or increases:

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1. Objects Moving in Opposite Directions (Convergence / Separation)

When two vehicles travel toward each other from two points separated by distance DD, they close the gap simultaneously:

Relative Closing Speed=r1+r2\text{Relative Closing Speed} = r_1 + r_2 Time until Collision / Meeting=tmeet=Dr1+r2\text{Time until Collision / Meeting} = t_{\text{meet}} = \frac{D}{r_1 + r_2} Distance from Point 1 where they meet=d1=r1×tmeet\text{Distance from Point 1 where they meet} = d_1 = r_1 \times t_{\text{meet}}

2. Objects Moving in the Same Direction (Pursuit and Overtake)

When Vehicle 2 pursues Vehicle 1, Vehicle 1 has already established a head start:

  1. Compute the head-start distance gap: dlead=r1×thead-startd_{\text{lead}} = r_1 \times t_{\text{head-start}}.
  2. Compute the net rate at which Vehicle 2 gains on Vehicle 1: rrel=r2−r1r_{\text{rel}} = r_2 - r_1 (where r2>r1r_2 > r_1).
  3. Calculate the time required for Vehicle 2 to eliminate the gap:
tovertake=dleadr2−r1t_{\text{overtake}} = \frac{d_{\text{lead}}}{r_2 - r_1}
  1. The total distance from the starting point at the moment of overtake is:
dovertake=r2×tovertaked_{\text{overtake}} = r_2 \times t_{\text{overtake}}

Water Current and Wind Resistance Problems

When a vessel moves through water or an aircraft flies through the atmosphere, the motion of the surrounding fluid medium alters the vehicle's speed relative to the fixed ground:

  • Let rvr_v = speed of vehicle in still water or calm air (cruising speed).
  • Let rmr_m = speed of the water current or wind medium.
DirectionEffective Speed Relative to GroundKinematic Formula
Downstream / TailwindThe medium aids motion (speeds up)rdown=rv+rmr_{\text{down}} = r_v + r_m
Upstream / HeadwindThe medium opposes motion (slows down)rup=rv−rmr_{\text{up}} = r_v - r_m

Resolving Vessel and Medium Speeds from Observed Travel Speeds:

Adding the downstream and upstream rates eliminates the medium speed:

rdown+rup=(rv+rm)+(rv−rm)=2rv  ⟹  rv=rdown+rup2r_{\text{down}} + r_{\text{up}} = (r_v + r_m) + (r_v - r_m) = 2r_v \implies r_v = \frac{r_{\text{down}} + r_{\text{up}}}{2}

Subtracting the upstream rate from the downstream rate isolates the current:

rdown−rup=(rv+rm)−(rv−rm)=2rm  ⟹  rm=rdown−rup2r_{\text{down}} - r_{\text{up}} = (r_v + r_m) - (r_v - r_m) = 2r_m \implies r_m = \frac{r_{\text{down}} - r_{\text{up}}}{2}

Note

The vehicle speed in still medium (rvr_v) is always the arithmetic midpoint of the downstream and upstream speeds, while the current speed (rmr_m) is half the spread between the two speeds.


Average Speed and the Harmonic Mean Formula

A classic trap on the CSE-FSO is calculating the average speed of a round trip by taking the simple arithmetic mean of the two speeds: v1+v22\frac{v_1 + v_2}{2}. For unequal speeds over equal distances with no stops, use the harmonic mean instead; with equal times, an arithmetic mean is appropriate.

The Fundamental Definition of Average Speed

Average speed is defined strictly as total distance divided by total elapsed time:

vavg=dtotalttotal=d1+d2t1+t2v_{\text{avg}} = \frac{d_{\text{total}}}{t_{\text{total}}} = \frac{d_1 + d_2}{t_1 + t_2}

The Harmonic Mean for Equal Distances

When an object travels an equal distance dd at speed v1v_1 and returns over the same distance dd at speed v2v_2:

t1=dv1andt2=dv2t_1 = \frac{d}{v_1} \quad \text{and} \quad t_2 = \frac{d}{v_2} vavg=2ddv1+dv2=2dd(1v1+1v2)=2v1+v2v1v2=2v1v2v1+v2v_{\text{avg}} = \frac{2d}{\frac{d}{v_1} + \frac{d}{v_2}} = \frac{2d}{d\left(\frac{1}{v_1} + \frac{1}{v_2}\right)} = \frac{2}{\frac{v_1 + v_2}{v_1 v_2}} = \frac{2 v_1 v_2}{v_1 + v_2}

Tip

For equal positive distances at unequal positive speeds with no stops, the harmonic mean is lower than the arithmetic mean because more time is spent at the slower speed. If the two speeds are equal, both means agree. With stops, include stop time in total elapsed time.

Test Your Knowledge

A Senior Diplomat at the Department of Foreign Affairs is currently 24 years older than a Junior Foreign Service Attaché. Ten years ago, the Senior Diplomat was twice as old as the Junior Attaché was at that time. How old will the Senior Diplomat be 8 years from now?

A

58 years old

B

62 years old

C

64 years old

D

66 years old

Test Your Knowledge

A diplomatic courier leaves a fictional dispatch office driving along a sufficiently long route at a steady speed of 60 km/h. Exactly 45 minutes later, an emergency security escort vehicle departs from the same office along the exact same route traveling at 80 km/h to deliver supplementary clearance credentials. How many hours after the security escort departs will it overtake the courier, and at what distance from the office will the overtake occur?

A

1.75 hours at 140 km

B

2.25 hours at 180 km

C

2.50 hours at 200 km

D

3.00 hours at 240 km

Test Your Knowledge

A Philippine Coast Guard diplomatic patrol vessel travels between two island consular posts separated by a one-way distance of 72 nautical miles along a tidal strait. Traveling downstream with the current, the vessel completes the journey in 3 hours. On the return trip upstream against the current, the vessel requires 4.5 hours. What is the vessel's cruising speed in still water, and what is its average speed for the entire round trip?

A

20 knots in still water; 20.0 knots average round-trip speed

B

18 knots in still water; 19.2 knots average round-trip speed

C

20 knots in still water; 19.2 knots average round-trip speed

D

22 knots in still water; 18.5 knots average round-trip speed

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