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14.1 Limits, Fits & Geometric Dimensioning & Tolerancing (GD&T)

Key Takeaways

  • The ISO/ANSI limit and fit system defines clearance, transition, and interference fits; the hole-basis system (basic hole HH with lower deviation EI=0EI = 0) is standard industrial practice because standardized tooling (drills, reamers, broaches) fixes hole size while shaft diameters are easily turned or ground to fit.

  • The ASME Y14.5 Datum Reference Frame constrains the six spatial degrees of freedom using the 3-2-1 principle: the primary datum establishes 3 points of contact, the secondary datum establishes 2 points, and the tertiary datum establishes 1 point.

  • Form tolerances (flatness, straightness, circularity, cylindricity) never reference datums, whereas orientation, location, and runout tolerances require datum references to establish true geometric orientation or position.

  • Under Maximum Material Condition (MMC), any departure of the produced feature size from its MMC size boundary provides an equal 'bonus tolerance,' expanding the permissible position tolerance zone while preserving virtual condition assembly boundaries.

  • Tolerance stack-up analysis contrasts deterministic worst-case arithmetic summation (TWC=∑tiT_{WC} = \sum t_i) with statistical Root-Sum-Square (TRSS=∑ti2T_{RSS} = \sqrt{\sum t_i^2}), where RSS assumes independent normal distributions at 3σ3\sigma process limits.

Last updated: October 2026

14.1 Limits, Fits & Geometric Dimensioning & Tolerancing (GD&T)

Precision mechanical design requires exact dimensional control to ensure interchangeability, reliable functional performance, and cost-effective manufacturing. Components fabricated in high-volume production invariably exhibit geometric variations resulting from tool wear, machine vibration, thermal expansion, and metallurgical inhomogeneities. Tolerancing bridges theoretical kinematic design and shop-floor fabrication by defining permissible dimensional and geometric boundaries.


Limits and Fits: Fundamental Terminology & ISO/ANSI Systems

Standardized fit systems classify the relative assembly relationship between two mating cylindrical features—generically designated as a hole (internal feature) and a shaft (external feature).

                    +------------------------------------+ --- Maximum Hole Limit
                    |            HOLE TOLERANCE          |
  Zero Line --------+------------------------------------+ --- Basic Size / Min Hole (EI=0)
  (Basic Size)      |                                    |
                    |   CLEARANCE                        |
                    |                                    |
  ------------------+------------------------------------+ --- Max Shaft Limit (es)
  |                 |            SHAFT TOLERANCE         |
  |                 +------------------------------------+ --- Min Shaft Limit (ei)
  |                                                      |
  +------------------------------------------------------+ --- Shaft Lower Boundary

Core Dimensional Definitions

  • Basic Size (D,dD, d): The theoretical nominal size from which design limits of size are established by the application of allowances and tolerances.
  • Actual Size: The measured physical size of an individual manufactured feature.
  • Limits of Size: The maximum and minimum permissible dimensions for a feature (Dmax⁡,Dmin⁡D_{\max}, D_{\min} for holes; dmax⁡,dmin⁡d_{\max}, d_{\min} for shafts).
  • Tolerance (TT): The total permissible variation of a feature's size:
Thole=Dmax⁡−Dmin⁡=ES−EIT_{\text{hole}} = D_{\max} - D_{\min} = ES - EI Tshaft=dmax⁡−dmin⁡=es−eiT_{\text{shaft}} = d_{\max} - d_{\min} = es - ei
  • Deviations: The algebraic difference between a size limit and the corresponding basic size:
    • Upper Deviation (ESES for holes, eses for shafts):
ES=Dmax⁡−D,es=dmax⁡−dES = D_{\max} - D, \quad es = d_{\max} - d
  • Lower Deviation (EIEI for holes, eiei for shafts):
EI=Dmin⁡−D,ei=dmin⁡−dEI = D_{\min} - D, \quad ei = d_{\min} - d
  • Fundamental Deviation: The deviation that defines the position of the tolerance zone relative to the zero line (the basic size). Under the ISO system, fundamental deviations are designated by uppercase letters (AA through ZCZC) for holes and lowercase letters (aa through zczc) for shafts.

Standard International Tolerance (IT) Grades

Standard tolerance grades designate the magnitude of the tolerance spread across standardized dimensional steps, spanning IT01, IT0, IT1 to IT16:

  • IT01 to IT4: Precision gage making, optical apparatus, lapping, and fine honing.
  • IT5 to IT7: Precision engineering, grinding, reaming, ball and roller bearing fits, precision spindle bores.
  • IT8 to IT11: General mechanical engineering, commercial turning, milling, boring, and cold-drawn components.
  • IT12 to IT16: Coarse manufacturing, sheet metal stamping, sand casting, flame cutting, and rough forging.

The standard tolerance unit ii (in μm\mu\text{m}) for basic sizes up to 500 mm500\,\text{mm} is computed from the geometric mean diameter D=D1D2D = \sqrt{D_1 D_2} of the size band:

i=0.45D3+0.001D[μm]i = 0.45 \sqrt[3]{D} + 0.001 D \quad [\mu\text{m}]

Representative IT grade multipliers relative to ii include:

  • IT5=7i\text{IT5} = 7i
  • IT6=10i\text{IT6} = 10i
  • IT7=16i\text{IT7} = 16i
  • IT8=25i\text{IT8} = 25i
  • IT9=40i\text{IT9} = 40i
  • IT10=64i\text{IT10} = 64i
  • IT11=100i\text{IT11} = 100i

Fit Classifications: Clearance, Transition, and Interference

Mating fits are categorized into three primary functional regimes based on relative tolerance zone placement:

Fit ClassificationDefining ConditionIndustrial ApplicationPreferred Examples
Clearance FitDmin⁡>dmax⁡D_{\min} > d_{\max} (Allowance >0> 0, always positive clearance)Journal bearings, sliding guides, removable locating pinsH11/c11\text{H11/c11} (loose), H9/d9\text{H9/d9} (free running), H8/f7\text{H8/f7} (close running), H7/g6\text{H7/g6} (sliding), H7/h6\text{H7/h6} (locational)
Transition FitTolerance zones overlap; may yield clearance or interferenceAccurate locating dowels, rigid spigots, lightly keyed pulleysH7/k6\text{H7/k6} (true locational), H7/n6\text{H7/n6} (light press locating)
Interference FitDmax⁡<dmin⁡D_{\max} < d_{\min} (Negative clearance, always interference)Shrink fits, permanent press-fitted gears, bearing inner rings on shaftsH7/p6\text{H7/p6} (light drive), H7/s6\text{H7/s6} (medium drive), H7/u6\text{H7/u6} (heavy force/shrink)

Fit Quantities

  • Minimum Clearance (Cmin⁡C_{\min}):
Cmin⁡=Dmin⁡−dmax⁡=EI−esC_{\min} = D_{\min} - d_{\max} = EI - es
  • Maximum Clearance (Cmax⁡C_{\max}):
Cmax⁡=Dmax⁡−dmin⁡=ES−eiC_{\max} = D_{\max} - d_{\min} = ES - ei
  • Maximum Interference (Imax⁡I_{\max}):
Imax⁡=dmax⁡−Dmin⁡=es−EII_{\max} = d_{\max} - D_{\min} = es - EI
  • Minimum Interference (Imin⁡I_{\min}):
Imin⁡=dmin⁡−Dmax⁡=ei−ESI_{\min} = d_{\min} - D_{\max} = ei - ES

Hole-Basis vs. Shaft-Basis System

  1. Hole-Basis System (Basic Hole HH):
    • The basic size is assigned to the minimum hole size (Dmin⁡=DD_{\min} = D).
    • The lower deviation of the hole is identically zero (EI=0EI = 0).
    • The various fits are generated by varying the shaft tolerance zone position (c,d,f,g,h,k,n,p,s,uc, d, f, g, h, k, n, p, s, u).
    • Universal Industrial Preference: Standard hole-making tools (drills, reamers, broaches, plug gages) have fixed physical dimensions and are costly to customize. It is vastly more economical to purchase standardized cutting tools to produce an H7H7 or H8H8 bore and adjust the exterior shaft diameter to the desired fit on a CNC lathe or cylindrical grinder.
  2. Shaft-Basis System (Basic Shaft hh):
    • The basic size is assigned to the maximum shaft size (dmax⁡=dd_{\max} = d).
    • The upper deviation of the shaft is identically zero (es=0es = 0).
    • Selected primarily when a single continuous, precision cold-drawn or ground steel shaft passes through multiple components requiring different fits (e.g., a clearance sleeve bearing, a keyed transition hub, and a press-fit bearing inner ring along one uninterrupted bar).

ASME Y14.5 Geometric Dimensioning & Tolerancing (GD&T)

Traditional coordinate (plus-minus) tolerancing exhibits fundamental engineering shortcomings: it produces rectangular or square tolerance zones (yielding 41.4%41.4\% greater tolerance along diagonals than across axes), lacks clear functional datum precedence, and fails to communicate how parts mate in three-dimensional space.

ASME Y14.5 establishes a symbolic engineering language that explicitly communicates functional design intent, controls geometric relationships, and defines inspection requirements without ambiguity.

The Datum Reference Frame (DRF) & The 3-2-1 Principle

An unconstrained rigid body possesses six spatial degrees of freedom (DOF): three mutually perpendicular translations (Tx,Ty,TzT_x, T_y, T_z) and three rotations (Rx,Ry,RzR_x, R_y, R_z). The Datum Reference Frame constrains these DOFs using the 3-2-1 contact principle:

                                  Z ^ (Normal to Primary)
                                    |
                                    |   +-----------------------+
                                    |  /                       /|
                                    | /   SECONDARY DATUM [B] / |
                                    |/     (2 contact points)/  |
     [C] TERTIARY DATUM ------------+-----------------------+   |
     (1 contact point)              |                       |   |
                                    |   PRIMARY DATUM [A]   |   + ---> Y
                                    |   (3 contact points)  |  /
                                    |                       | /
                                    +-----------------------+/
                                   /
                                  / 
                                 v X
  1. Primary Datum (Datum A): Contacts the part at a minimum of three non-collinear points. Constrains 3 degrees of freedom: translation along the ZZ-axis (TzT_z) and rotation about the XX and YY axes (Rx,RyR_x, R_y).
  2. Secondary Datum (Datum B): Oriented perpendicular to the primary datum, contacting the part at a minimum of two points. Constrains 2 degrees of freedom: translation along the YY-axis (TyT_y) and rotation about the ZZ-axis (RzR_z).
  3. Tertiary Datum (Datum C): Oriented perpendicular to both primary and secondary datums, contacting the part at a minimum of one point. Constrains the final remaining 1 degree of freedom: translation along the XX-axis (TxT_x).

Feature Control Frame Syntax & The Geometric Characteristics

The Feature Control Frame (FCF) is a rectangular compartmented block containing all geometric tolerance instructions for a feature:

+-------+-------------------------+---------+---------+---------+
|  [+]  |  Ø 0.25 [M]            |    A    |  B [M]  |    C    |
+-------+-------------------------+---------+---------+---------+
 Symbol   Tol Zone & Modifiers     Primary   Secondary  Tertiary
          (Dia 0.25 at MMC)         Datum     Datum      Datum

The 2009 edition of ASME Y14.5 listed 14 geometric characteristics in five families. ASME Y14.5-2018 deleted concentricity and symmetry, leaving 12; the two still appear on older drawings and in ISO 1101 (the rows are kept below for recognition):

FamilyGeometric CharacteristicSymbolDatums Permitted?Tolerance Zone Shape
FormFlatness⏥NeverTwo parallel planes
Straightness—NeverTwo parallel lines, or cylindrical zone
Circularity (Roundness)○NeverTwo concentric coplanar circles
Cylindricity⌭NeverTwo coaxial cylinders
ProfileProfile of a Line⌒OptionalTwo non-uniform offset lines
Profile of a Surface⌓Optional / RecommendedTwo offset boundary surfaces
OrientationPerpendicularity⟂MandatoryTwo parallel planes, or cylindrical zone
Parallelism∥MandatoryTwo parallel planes, or cylindrical zone
Angularity∠MandatoryTwo parallel planes inclined at basic angle
LocationPosition⌖MandatoryCylindrical zone (∅\varnothing) or two parallel planes
Concentricity◎MandatoryCylindrical zone centered on datum axis (deleted in Y14.5-2018)
Symmetry⌯MandatoryTwo parallel planes centered on datum plane (deleted in Y14.5-2018)
RunoutCircular Runout↗Mandatory (Axis)Two coplanar circles during 360∘360^\circ rotation
Total Runout⌰Mandatory (Axis)Two coaxial cylinders / parallel planes during rotation + axial traverse

Important

Form tolerances never reference a datum. Flatness, straightness, circularity, and cylindricity evaluate a feature solely against its own ideal geometric form, independent of any external coordinate system or datum plane.


Material Condition Modifiers & Bonus Tolerance Mechanics

Material condition modifiers determine how geometric tolerances interact with feature size variations:

  1. Maximum Material Condition (MMC, M◯\textcircled{\tiny M}):
    • The condition in which a feature of size contains the maximum amount of material within its stated dimensional limits.
    • Internal feature (hole): Minimum hole diameter (Dmin⁡D_{\min}).
    • External feature (shaft/pin): Maximum pin diameter (dmax⁡d_{\max}).
  2. Least Material Condition (LMC, L◯\textcircled{\tiny L}):
    • The condition in which a feature of size contains the minimum amount of material.
    • Internal feature (hole): Maximum hole diameter (Dmax⁡D_{\max}).
    • External feature (shaft/pin): Minimum pin diameter (dmin⁡d_{\min}).
    • Used to protect minimum wall thickness and prevent structural breakout.
  3. Regardless of Feature Size (RFS):
    • The stated geometric tolerance applies strictly at all produced feature sizes.
    • Default rule under ASME Y14.5 (the old S◯\textcircled{\tiny S} symbol is obsolete).

Virtual Condition (VCVC)

Virtual condition is the worst-case boundary generated by the collective effect of a feature's size limit at MMC and its stated geometric tolerance:

  • For an Internal Feature (Hole):
VC=MMC Size−Stated Geometric Tolerance=Dmin⁡−tposVC = \text{MMC Size} - \text{Stated Geometric Tolerance} = D_{\min} - t_{\text{pos}}
  • For an External Feature (Shaft/Pin):
VC=MMC Size+Stated Geometric Tolerance=dmax⁡+tposVC = \text{MMC Size} + \text{Stated Geometric Tolerance} = d_{\max} + t_{\text{pos}}

Bonus Tolerance Derivation

When a feature control frame specifies MMC (M◯\textcircled{\tiny M}), the stated tolerance tstatedt_{\text{stated}} applies strictly when the produced feature is at its MMC size. If the feature departs from MMC toward LMC, the difference between the actual produced size and the MMC size is added directly to the permissible geometric tolerance as bonus tolerance:

Bonus Tolerance=∣Actual Feature Size−MMC Size∣\text{Bonus Tolerance} = |\text{Actual Feature Size} - \text{MMC Size}| Total Permissible Tolerance=tstated+Bonus Tolerance\text{Total Permissible Tolerance} = t_{\text{stated}} + \text{Bonus Tolerance}
  Feature Size:         MMC (Min Hole D_min) -----------------> LMC (Max Hole D_max)
  Permissible Tol:      Stated Tol (t_0)     -----------------> t_0 + (D_max - D_min)
                        |<- Base Tolerance ->|<-  Full Available Bonus Tolerance  ->|

This principle significantly increases manufacturing yields by accepting parts whose position deviates further than the base tolerance, provided their larger size still ensures clearance and prevents functional assembly interference.


Tolerance Stack-Up Analysis: Worst-Case vs. Statistical RSS

Tolerance stack-up analysis calculates the cumulative variation of an assembly gap or critical functional dimension resulting from individual component tolerances along a one-dimensional kinematic loop.

  +------------- A1 ------------+------- A2 -------+------- A3 -------+
  |                                                                   |
  +--------------------------- TOTAL LENGTH L ------------------------+
  |                                                          |<-GAP-> |
  +------------------------------ B1 ------------------------+--------+

1. Worst-Case (Deterministic / Arithmetic) Stack-Up

Worst-case analysis assumes that every component in the assembly chain is manufactured concurrently at its extreme worst-case tolerance limit in the direction that minimizes (or maximizes) the gap:

TWC=∑i=1ntiT_{WC} = \sum_{i=1}^n t_i Gapmin⁡=∑Ai,min⁡−∑Bj,max⁡\text{Gap}_{\min} = \sum A_{i,\min} - \sum B_{j,\max} Gapmax⁡=∑Ai,max⁡−∑Bj,min⁡\text{Gap}_{\max} = \sum A_{i,\max} - \sum B_{j,\min}
  • Characteristics: Guarantees 100%100\% assembly interchangeability with zero non-conformance. However, it forces excessively tight individual part tolerances, drastically driving up machining, tooling, and scrap costs.

2. Statistical Root-Sum-Square (RSS) Stack-Up

Statistical tolerancing is rooted in the Central Limit Theorem. If individual component dimensions vary independently and follow normal (Gaussian) distributions centered between their limits, the probability of all parts simultaneously hitting their worst-case extremes is vanishingly small. The assembly variance equals the sum of the individual variances:

σassembly2=∑i=1nσi2\sigma_{\text{assembly}}^2 = \sum_{i=1}^n \sigma_i^2

Assuming each part tolerance tit_i represents a 3σ3\sigma process boundary (ti=3σit_i = 3\sigma_i):

TRSS=3σassembly=3∑i=1n(ti3)2=∑i=1nti2T_{RSS} = 3\sigma_{\text{assembly}} = 3\sqrt{\sum_{i=1}^n \left( \frac{t_i}{3} \right)^2} = \sqrt{\sum_{i=1}^n t_i^2} Nominal Gap=μgap=∑Ai,nom−∑Bj,nom\text{Nominal Gap} = \mu_{\text{gap}} = \sum A_{i,\text{nom}} - \sum B_{j,\text{nom}} GapRSS limits=μgap±TRSS\text{Gap}_{\text{RSS limits}} = \mu_{\text{gap}} \pm T_{RSS}
  • Modified RSS / Bender Factor: In real-world manufacturing, processes may suffer mean shifts or tool wear drifts. A correction factor CfC_f (typically 1.31.3 to 1.51.5) is applied to standard RSS:
Tmod RSS=Cf∑i=1nti2T_{\text{mod RSS}} = C_f \sqrt{\sum_{i=1}^n t_i^2}

Worked Engineering Examples

Worked Example 1: 1D Tolerance Stack-Up Comparison (Worst-Case vs. RSS)

Problem Statement

A high-speed pump shaft assembly contains three precision spacers (A1,A2,A3A_1, A_2, A_3) stacked axially inside a housing bore (BB). An axial clearance gap GG between the end of spacer A3A_3 and the housing shoulder must be maintained to prevent bearing preloading upon thermal expansion.

Component dimensional specifications:

  • Housing bore depth (BB): 75.00±0.12 mm75.00 \pm 0.12\,\text{mm}
  • Spacer 1 length (A1A_1): 25.00±0.04 mm25.00 \pm 0.04\,\text{mm}
  • Spacer 2 length (A2A_2): 30.00±0.05 mm30.00 \pm 0.05\,\text{mm}
  • Spacer 3 length (A3A_3): 19.50±0.04 mm19.50 \pm 0.04\,\text{mm}

Determine:

  1. The nominal axial clearance gap GnomG_{\text{nom}}.
  2. The worst-case minimum and maximum clearance gaps (GWC,min⁡,GWC,max⁡G_{WC,\min}, G_{WC,\max}) and total worst-case tolerance TWCT_{WC}.
  3. The statistical RSS tolerance TRSST_{RSS} and the predicted 3σ3\sigma clearance limits (GRSS,min⁡,GRSS,max⁡G_{RSS,\min}, G_{RSS,\max}).

Step-by-Step Solution

Step 1: Nominal Gap Calculation
Gnom=Bnom−(A1,nom+A2,nom+A3,nom)G_{\text{nom}} = B_{\text{nom}} - (A_{1,\text{nom}} + A_{2,\text{nom}} + A_{3,\text{nom}}) Gnom=75.00−(25.00+30.00+19.50)=75.00−74.50=0.50 mmG_{\text{nom}} = 75.00 - (25.00 + 30.00 + 19.50) = 75.00 - 74.50 = 0.50\,\text{mm}
Step 2: Worst-Case Tolerance Stack-Up

Identify individual bilateral half-tolerances tit_i:

  • tB=0.12 mmt_B = 0.12\,\text{mm}
  • tA1=0.04 mmt_{A1} = 0.04\,\text{mm}
  • tA2=0.05 mmt_{A2} = 0.05\,\text{mm}
  • tA3=0.04 mmt_{A3} = 0.04\,\text{mm}

Compute total worst-case tolerance:

TWC=tB+tA1+tA2+tA3=0.12+0.04+0.05+0.04=0.25 mmT_{WC} = t_B + t_{A1} + t_{A2} + t_{A3} = 0.12 + 0.04 + 0.05 + 0.04 = 0.25\,\text{mm}

Compute worst-case gap limits:

GWC,min⁡=Bmin⁡−(A1,max⁡+A2,max⁡+A3,max⁡)=(75.00−0.12)−(25.04+30.05+19.54)G_{WC,\min} = B_{\min} - (A_{1,\max} + A_{2,\max} + A_{3,\max}) = (75.00 - 0.12) - (25.04 + 30.05 + 19.54) GWC,min⁡=74.88−74.63=0.25 mmG_{WC,\min} = 74.88 - 74.63 = 0.25\,\text{mm} GWC,max⁡=Bmax⁡−(A1,min⁡+A2,min⁡+A3,min⁡)=(75.00+0.12)−(24.96+29.95+19.46)G_{WC,\max} = B_{\max} - (A_{1,\min} + A_{2,\min} + A_{3,\min}) = (75.00 + 0.12) - (24.96 + 29.95 + 19.46) GWC,max⁡=75.12−74.37=0.75 mmG_{WC,\max} = 75.12 - 74.37 = 0.75\,\text{mm} GapWC=0.50±0.25 mm[0.25 mm to 0.75 mm]\text{Gap}_{WC} = 0.50 \pm 0.25\,\text{mm} \quad [0.25\,\text{mm} \text{ to } 0.75\,\text{mm}]
Step 3: Statistical RSS Tolerance Stack-Up

Compute RSS tolerance:

TRSS=tB2+tA12+tA22+tA32=(0.12)2+(0.04)2+(0.05)2+(0.04)2T_{RSS} = \sqrt{t_B^2 + t_{A1}^2 + t_{A2}^2 + t_{A3}^2} = \sqrt{(0.12)^2 + (0.04)^2 + (0.05)^2 + (0.04)^2} TRSS=0.0144+0.0016+0.0025+0.0016=0.0201=0.1418 mm≈0.14 mmT_{RSS} = \sqrt{0.0144 + 0.0016 + 0.0025 + 0.0016} = \sqrt{0.0201} = 0.1418\,\text{mm} \approx 0.14\,\text{mm}

Compute statistical 3σ3\sigma gap limits:

GRSS,min⁡=Gnom−TRSS=0.50−0.1418=0.3582 mm≈0.36 mmG_{RSS,\min} = G_{\text{nom}} - T_{RSS} = 0.50 - 0.1418 = 0.3582\,\text{mm} \approx 0.36\,\text{mm} GRSS,max⁡=Gnom+TRSS=0.50+0.1418=0.6418 mm≈0.64 mmG_{RSS,\max} = G_{\text{nom}} + T_{RSS} = 0.50 + 0.1418 = 0.6418\,\text{mm} \approx 0.64\,\text{mm} GapRSS=0.50±0.14 mm[0.36 mm to 0.64 mm]\text{Gap}_{RSS} = 0.50 \pm 0.14\,\text{mm} \quad [0.36\,\text{mm} \text{ to } 0.64\,\text{mm}]

Note

The statistical RSS tolerance spread (0.14 mm0.14\,\text{mm}) is 43%43\% narrower than the deterministic worst-case spread (0.25 mm0.25\,\text{mm}). This demonstrates that individual part tolerances can be significantly relaxed under statistical quality control without risking assembly interference.


Worked Example 2: GD&T True Position, MMC Bonus Tolerance & Verification

Problem Statement

A structural mounting bracket contains four clearance holes for M10 bolts. The engineering drawing specifies the following feature control frame and size limits for each hole:

  • Stated size: ∅10.50±0.20 mm\varnothing 10.50 \pm 0.20\,\text{mm}
  • Geometric tolerance: [⌖ | ⌀ 0.30 Ⓜ | A | B | C]
  • Basic true position coordinates: X=60.00 mmX = 60.00\,\text{mm}, Y=40.00 mmY = 40.00\,\text{mm}

During coordinate measuring machine (CMM) inspection, Hole #1 is evaluated:

  • Measured diameter: Dact=10.62 mmD_{\text{act}} = 10.62\,\text{mm}
  • Measured center coordinates: Xact=60.10 mmX_{\text{act}} = 60.10\,\text{mm}, Yact=40.12 mmY_{\text{act}} = 40.12\,\text{mm}

Determine:

  1. The Maximum Material Condition (MMC) size and Least Material Condition (LMC) size.
  2. The virtual condition boundary of the hole.
  3. The actual radial and diametral position deviation of the produced hole center.
  4. The bonus tolerance and total allowable position tolerance at the produced size.
  5. Whether Hole #1 conforms to the GD&T specification.

Step-by-Step Solution

Step 1: Material Condition Sizes

For an internal feature (hole):

MMC Size=Dmin⁡=10.50−0.20=10.30 mm\text{MMC Size} = D_{\min} = 10.50 - 0.20 = 10.30\,\text{mm} LMC Size=Dmax⁡=10.50+0.20=10.70 mm\text{LMC Size} = D_{\max} = 10.50 + 0.20 = 10.70\,\text{mm}
Step 2: Virtual Condition Boundary

For an internal hole at MMC:

VC=Dmin⁡−tstated=10.30 mm−0.30 mm=10.00 mmVC = D_{\min} - t_{\text{stated}} = 10.30\,\text{mm} - 0.30\,\text{mm} = 10.00\,\text{mm}

Any mating pin of diameter ≤10.00 mm\le 10.00\,\text{mm} positioned at true position will assemble without interference.

Step 3: Measured Position Deviation

Compute coordinate offsets from basic true position:

ΔX=Xact−Xbasic=60.10−60.00=+0.10 mm\Delta X = X_{\text{act}} - X_{\text{basic}} = 60.10 - 60.00 = +0.10\,\text{mm} ΔY=Yact−Ybasic=40.12−40.00=+0.12 mm\Delta Y = Y_{\text{act}} - Y_{\text{basic}} = 40.12 - 40.00 = +0.12\,\text{mm}

Compute radial position error (RdevR_{\text{dev}}):

Rdev=(ΔX)2+(ΔY)2=(0.10)2+(0.12)2=0.0100+0.0144=0.0244=0.1562 mmR_{\text{dev}} = \sqrt{(\Delta X)^2 + (\Delta Y)^2} = \sqrt{(0.10)^2 + (0.12)^2} = \sqrt{0.0100 + 0.0144} = \sqrt{0.0244} = 0.1562\,\text{mm}

Compute actual diametral position zone (tactt_{\text{act}}) consumed by the hole:

tact=2Rdev=2×0.1562 mm=0.3124 mm≈0.312 mmt_{\text{act}} = 2 R_{\text{dev}} = 2 \times 0.1562\,\text{mm} = 0.3124\,\text{mm} \approx 0.312\,\text{mm}
Step 4: Bonus Tolerance & Total Allowable Tolerance

The produced hole size is Dact=10.62 mmD_{\text{act}} = 10.62\,\text{mm}. Because Dact>DMMCD_{\text{act}} > D_{\text{MMC}} (10.62>10.3010.62 > 10.30):

Bonus Tolerance=Dact−MMC Size=10.62−10.30=0.32 mm\text{Bonus Tolerance} = D_{\text{act}} - \text{MMC Size} = 10.62 - 10.30 = 0.32\,\text{mm}

Compute total permissible position tolerance zone diameter:

ttotal=tstated+Bonus=0.30 mm+0.32 mm=0.62 mmt_{\text{total}} = t_{\text{stated}} + \text{Bonus} = 0.30\,\text{mm} + 0.32\,\text{mm} = 0.62\,\text{mm}
Step 5: Conformance Evaluation

Compare actual diametral position deviation against the total allowable limit:

tact=0.312 mm≤ttotal=0.620 mmt_{\text{act}} = 0.312\,\text{mm} \le t_{\text{total}} = 0.620\,\text{mm}

Under RFS rules, the hole would have been rejected (0.312>0.3000.312 > 0.300). However, because the MMC modifier was specified and the hole was machined larger than its minimum limit, the bonus tolerance expanded the permissible zone to ∅0.62 mm\varnothing 0.62\,\text{mm}. Therefore, Hole #1 is fully conforming and accepted.

Test Your Knowledge

A production drawing specifies a bore and shaft fit designated as ISO 40 H7/p6. The basic size is 40.00 mm. Under ISO standards, the H7 tolerance is +0.025/-0.000 mm, and the p6 tolerance is +0.042/+0.026 mm. What classification of fit does this assembly represent, and what are the minimum and maximum interference values?

A

Transition fit, with a maximum clearance of 0.025 mm and a maximum interference of 0.042 mm.

B

Interference fit, with a minimum interference of 0.001 mm and a maximum interference of 0.042 mm.

C

Interference fit, with a minimum interference of 0.017 mm and a maximum interference of 0.067 mm.

D

Clearance fit, with a minimum clearance of 0.000 mm and a maximum clearance of 0.042 mm.

Test Your Knowledge

Which of the following geometric tolerances in ASME Y14.5 is strictly prohibited from referencing a datum in its feature control frame?

A

Perpendicularity, because the 90-degree angular relationship is self-contained within the feature.

B

Circular runout, because runout is measured with an indicator while the component rotates freely.

C

Profile of a surface, because surface deviations are computed from nominal CAD mathematical definitions.

D

Flatness, because form tolerances control the feature relative only to itself and cannot reference an external datum.

Test Your Knowledge

An internal hole feature on an aluminum housing is dimensioned as diameter 25.00 (+0.10 / -0.00) mm, controlled with a position tolerance of diameter 0.15 mm at MMC relative to Datums A, B, and C. An inspected component has an actual measured hole diameter of 25.08 mm and an actual diametral position deviation of 0.21 mm. Which statement correctly evaluates the part?

A

The part is conforming: 0.08 mm of bonus tolerance raises the allowable position tolerance to 0.23 mm.

B

The part is non-conforming because bonus tolerance only applies when the hole size is at its minimum limit of 25.00 mm.

C

The part is non-conforming because the actual position deviation of 0.21 mm exceeds the stated drawing tolerance of 0.15 mm.

D

The part is conforming because position tolerances under ASME Y14.5 allow up to 50% deviation regardless of feature size.

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