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10.2 Hydrodynamic Journal Bearings & Lubrication Regimes

Key Takeaways

  • The Stribeck curve characterizes lubrication regimes as a function of the dimensionless parameter μN/P\mu N / P, transitioning from boundary lubrication (f≈0.08−0.15f \approx 0.08 - 0.15) through mixed lubrication to full hydrodynamic lubrication (f≈0.001−0.005f \approx 0.001 - 0.005).

  • Petroff's equation Tf=2π2μnr3LcT_f = \frac{2\pi^2 \mu n r^3 L}{c} defines friction torque for a lightly loaded, concentric journal bearing, demonstrating that fluid shear friction scales with the cube of journal radius.

  • The dimensionless Sommerfeld number S=(r/c)2(μn/P)S = (r/c)^2 (\mu n / P) encapsulates all operational variables and dictates the eccentricity ratio ϵ=e/c\epsilon = e/c and minimum film thickness h0=c(1−ϵ)h_0 = c(1 - \epsilon).

  • Raimondi-Boyd charts determine bearing performance variables: minimum film thickness ratio h0/ch_0/c, friction variable (r/c)f(r/c)f, flow variable Q/(rcnL)Q/(r c n L), and side-leakage ratio Qs/QQ_s/Q.

  • Thermal equilibrium requires balancing viscous shear heat generation Hgen=2πTfnH_{\text{gen}} = 2\pi T_f n with lubricant thermal convection Hdiss=ρQeffcpΔTH_{\text{diss}} = \rho Q_{\text{eff}} c_p \Delta T, where the effective circulating flow is Qeff=Q(1−0.5Qs/Q)Q_{\text{eff}} = Q(1 - 0.5 Q_s/Q).

Last updated: October 2026

10.2 Hydrodynamic Journal Bearings & Lubrication Regimes

Hydrodynamic journal bearings (also termed sleeve or fluid-film bearings) are standard support elements in high-speed, heavy-duty rotating machinery such as steam and gas turbines, centrifugal compressors, automotive crankshafts, and electric power generators. Unlike rolling-element bearings that have finite fatigue lives, hydrodynamic bearings operate with complete physical separation between the journal and sleeve surfaces via a continuous, pressurized viscous fluid wedge. Under steady full-film operation, surface wear is virtually non-existent, and vibration damping is exceptionally high.


Lubrication Regimes & The Stribeck Curve

The fundamental operating state of any lubricated sliding interface is characterized by the Stribeck curve, which plots the coefficient of friction ff as a function of the bearing characteristic parameter μNP\frac{\mu N}{P} (or μωP\frac{\mu \omega}{P}), where μ\mu is dynamic viscosity, NN is rotational speed, and PP is unit load:

   Friction
   Coeff (f)
     ^
0.15 |   +----------------+
     |   | Boundary       |\
0.10 |   | Lubrication    | \
     |   +----------------+  \
0.05 |                        \   +-------------+
     |                         \  | Mixed /     |   +---------------------+
     |                          \_| Thin-Film   |  /| Hydrodynamic (Full) |
0.00 |----------------------------+-------------+-/-+---------------------+--->
     0                                       (Knee)               mu * N / P

1. Boundary Lubrication

  • Mechanics: Occurs at very low speeds, high unit loads, or low lubricant viscosity (e.g., during startup, shutdown, or shock overloads). The fluid film is thinner than the composite surface roughness (h0<Rah_0 < R_a).
  • Friction & Wear: High friction coefficient (f≈0.08−0.15f \approx 0.08 - 0.15). High metallic asperity contact occurs. Wear prevention relies entirely on chemical boundary additives (such as zinc dialkyldithiophosphate / ZDDP or sulfur-phosphorus extreme-pressure [EP] compounds) that form low-shear sacrificial films on metal surfaces.

2. Mixed (Thin-Film) Lubrication

  • Mechanics: An intermediate transition zone where the hydrodynamic fluid pressure supports a substantial portion of the applied load, but isolated high asperity peaks still intermittently contact.
  • Friction & Wear: The friction coefficient drops precipitously toward a minimum "knee point" (f≈0.005−0.02f \approx 0.005 - 0.02). Highly unstable; a minor reduction in speed or viscosity can trigger boundary wear.

3. Hydrodynamic (Full-Film / Thick-Film) Lubrication

  • Mechanics: Occurs at high speeds, moderate unit loads, and adequate viscosity. A continuous viscous fluid wedge completely separates the journal and sleeve (h0>3−5Rah_0 > 3 - 5 R_a).
  • Friction & Wear: Ultra-low friction (f≈0.001−0.005f \approx 0.001 - 0.005). Zero metal-to-metal contact; theoretical component life is infinite barring contamination or thermal breakdown. Friction is governed strictly by internal viscous shear stress in the lubricant (τ=μ du/dy\tau = \mu \, du/dy). As μN/P\mu N / P increases beyond the knee point, friction coefficient rises linearly due to viscous drag.

4. Elastohydrodynamic Lubrication (EHL)

  • Mechanics: A specialized regime occurring in non-conformal concentrated contacts (e.g., ball/roller bearings, gear meshes, cam-follower pairs).
  • Characteristics: Extreme localized contact pressures (1−3 GPa1 - 3\,\text{GPa}) cause two phenomena simultaneously: (a) elastic deflection of the mating metallic surfaces, and (b) an exponential increase in lubricant viscosity by three to four orders of magnitude via the Barus equation (μ=μ0eαpp\mu = \mu_0 e^{\alpha_p p}). A microscopic fluid film (0.1−1.0 μm0.1 - 1.0\,\mu\text{m}) is preserved.

Journal Bearing Geometry & Operational Parameters

Consider a journal of diameter dd (radius r=d/2r = d/2) rotating inside a cylindrical bearing sleeve of internal diameter DD (radius R=D/2R = D/2) with axial length LL:

  • Radial Clearance (cc):
c=R−rc = R - r
  • Diametral Clearance (cdc_d):
cd=D−d=2cc_d = D - d = 2c

Typical industrial clearance ratios range from c/r=0.001c/r = 0.001 to 0.0020.002 (11 to 2 mil2\,\text{mil} of radial clearance per inch of journal diameter).

  • Nominal Bearing Unit Pressure (PP): Defined over the projected area Ap=L⋅dA_p = L \cdot d under steady radial load WW:
P=WL⋅d=W2rLP = \frac{W}{L \cdot d} = \frac{W}{2 r L}
  • Length-to-Diameter Ratio (L/dL/d): Standard bearings typically use L/dL/d between 0.50.5 and 1.51.5. High-speed modern turbomachinery designs favor compact ratios (L/d=0.5−0.8L/d = 0.5 - 0.8) to reduce parasitic friction torque and minimize sensitivity to shaft slope/angular misalignment, at the expense of higher end-leakage flow.

Petroff's Classical Friction Formulation

Petroff's equation provides a foundational baseline for friction torque by assuming a lightly loaded, concentric journal (ϵ=0\epsilon = 0) running at constant rotational frequency nn (in rev/s\text{rev/s}):

  • Journal surface speed: U=2πrnU = 2\pi r n
  • Velocity gradient across uniform radial clearance cc: dudy=Uc=2πrnc\frac{du}{dy} = \frac{U}{c} = \frac{2\pi r n}{c}
  • Newton's law of viscosity yields shear stress: τ=μ2πrnc\tau = \mu \frac{2\pi r n}{c}
  • Wetted surface area: A=2πrLA = 2\pi r L

The total viscous shear friction force FfF_f is:

Ff=τA=(μ2πrnc)(2πrL)=4π2μnr2LcF_f = \tau A = \left( \mu \frac{2\pi r n}{c} \right) (2\pi r L) = \frac{4\pi^2 \mu n r^2 L}{c}

Friction torque TfT_f about the journal rotational axis is:

Tf=Ff⋅r=2π2μnr3LcT_f = F_f \cdot r = \frac{2\pi^2 \mu n r^3 L}{c}

Dividing friction force by normal load W=P(2rL)W = P (2 r L) yields Petroff's coefficient of friction ff:

f=FfW=2π2(μnP)(rc)f = \frac{F_f}{W} = 2\pi^2 \left( \frac{\mu n}{P} \right) \left( \frac{r}{c} \right)

Tip

Petroff's equation demonstrates that friction torque scales with the cube of the radius (r3r^3). Reducing journal diameter provides the most potent lever for lowering parasitic horsepower loss in high-speed bearings.


Hydrodynamic Lubrication Theory & Reynolds Equation

When a journal bearing supports a substantial radial load WW, the journal shifts eccentrically within the clearance space by distance ee (center-to-center displacement). This eccentricity establishes a converging fluid wedge in the direction of journal rotation.

                 Bearing Sleeve (Center Ob)
                      /-------------\
                    /                 \
                   |      Journal      |
                   |     (Center Oj)   |
                   |        (->)       |
                    \    e /          /
                      \--/----------/
                        h_0 (Minimum Film)

Fluid drawn into this converging wedge is compressed, developing hydrodynamic pressure governed by the classical 2D Reynolds equation for incompressible thin-film flow:

∂∂x(h3μ∂p∂x)+∂∂z(h3μ∂p∂z)=6U∂h∂x\frac{\partial}{\partial x}\left( \frac{h^3}{\mu} \frac{\partial p}{\partial x} \right) + \frac{\partial}{\partial z}\left( \frac{h^3}{\mu} \frac{\partial p}{\partial z} \right) = 6 U \frac{\partial h}{\partial x}

where x=rθx = r\theta is the circumferential coordinate, zz is the axial coordinate, and h(θ)=c(1+ϵcos⁡θ)h(\theta) = c(1 + \epsilon \cos\theta) is the local oil film thickness.

Key Hydrodynamic Variables

  • Eccentricity Ratio (ϵ\epsilon):
ϵ=ec(0≤ϵ<1)\epsilon = \frac{e}{c} \quad (0 \le \epsilon < 1)
  • Minimum Oil Film Thickness (h0h_0): Occurs at the line of centers downstream of the load line:
h0=c−e=c(1−ϵ)h_0 = c - e = c(1 - \epsilon)
  • Attitude Angle (ϕ\phi): The angle between the applied radial load vector WW and the centerline connecting bearing and journal centers.

The Sommerfeld Number (SS)

The Sommerfeld number (bearing characteristic number) is a dimensionless parameter that encapsulates all geometric, kinematic, and operational variables:

S=(rc)2(μnP)S = \left( \frac{r}{c} \right)^2 \left( \frac{\mu n}{P} \right)

where nn is rotational frequency in rev/s\text{rev/s} (n=Nrpm/60n = N_{\text{rpm}}/60), μ\mu is dynamic viscosity in Pa⋅s\text{Pa}\cdot\text{s} (N⋅s/m2\text{N}\cdot\text{s/m}^2), and P=W/(2rL)P = W/(2 r L) is unit load in Pa\text{Pa}. In US customary units, S=(r/c)2(μn/P)S = (r/c)^2 (\mu n / P) where μ\mu is in reyns\text{reyns} (lbf⋅s/in2\text{lbf}\cdot\text{s/in}^2) and PP is in psi\text{psi}.


Raimondi-Boyd Design Methodology

Because closed-form analytical solutions to the 2D Reynolds equation with axial side leakage do not exist, modern engineering design relies on numerical solutions developed by Raimondi and Boyd. These charts relate the Sommerfeld number SS and aspect ratio L/dL/d to four primary dimensionless performance variables:

  1. Film Thickness Variable: h0c\frac{h_0}{c}
  2. Friction Variable: (rc)f\left( \frac{r}{c} \right) f
  3. Flow Variable: QrcnL\frac{Q}{r c n L}
  4. Side-Leakage Ratio: QsQ\frac{Q_s}{Q}

Representative Raimondi-Boyd Data for L/d=1L/d = 1 (Full 360∘360^\circ Journal Bearing)

Eccentricity ϵ\epsilonFilm Ratio h0/ch_0 / cSommerfeld Number SSFriction Variable (r/c)f(r/c)fFlow Variable Q/(rcnL)Q / (r c n L)Side-Leakage Ratio Qs/QQ_s / Q
0.10.10.90.91.331.3326.426.43.373.370.1500.150
0.20.20.80.80.6310.63112.812.83.593.590.2800.280
0.40.40.60.60.2640.2645.795.793.993.990.4970.497
0.60.60.40.40.1210.1213.223.224.334.330.6800.680
0.80.80.20.20.04460.04461.701.704.624.620.8420.842
0.90.90.10.10.01880.01881.051.054.744.740.9190.919

(Raimondi and Boyd's finite-bearing solutions as tabulated in Shigley. At light loads the friction variable approaches Petroff's value 2π2S2\pi^2 S, a quick check on any chart reading. Interpolate between rows or read the charts for intermediate SS.)

Trumpler's Design Criteria for Safe Operation

To ensure structural integrity and prevent seizure under real-world industrial tolerances, design practice (per P.R. Trumpler) mandates:

  1. Minimum Film Thickness: h0≥0.0002 in+0.00004dh_0 \ge 0.0002\,\text{in} + 0.00004 d (or h0≥5−10 μmh_0 \ge 5 - 10\,\mu\text{m} for precision shafts) to clear circulating particulate contamination.
  2. Maximum Lubricant Temperature: Peak film temperature Tmax⁡≤120∘CT_{\max} \le 120^\circ\text{C} (250∘F250^\circ\text{F}) to prevent thermal oxidation and additive breakdown of mineral oils.
  3. Overload Design Factor: NL≥2.0N_L \ge 2.0, ensuring that doubling the operational load will not reduce h0h_0 below critical asperity contact.

Thermal Equilibrium & Lubricant Heat Balance

Viscous shearing within the oil film generates continuous thermal energy that must be carried away by circulating oil flow. In steady-state operation, thermal equilibrium requires:

Hgen=HdissH_{\text{gen}} = H_{\text{diss}}

1. Heat Generation Rate (HgenH_{\text{gen}})

Hgen=2πTfn=WfU=Wf(2πrn)[Watts]H_{\text{gen}} = 2\pi T_f n = W f U = W f (2\pi r n) \quad [\text{Watts}]

2. Heat Dissipation Rate (HdissH_{\text{diss}})

Lubricant pumped through the bearing carries thermal energy away via end leakage and circulating flow. Using the effective volumetric flow rate QeffQ_{\text{eff}}:

Qeff=Q(1−0.5QsQ)Q_{\text{eff}} = Q \left( 1 - 0.5 \frac{Q_s}{Q} \right) Hdiss=m˙effcpΔT=ρQeffcpΔTH_{\text{diss}} = \dot{m}_{\text{eff}} c_p \Delta T = \rho Q_{\text{eff}} c_p \Delta T

where ρ\rho is lubricant density (typically 850−900 kg/m3850 - 900\,\text{kg/m}^3), cpc_p is specific heat capacity (typically 1,800−2,100 J/(kg⋅∘C)1,800 - 2,100\,\text{J/(kg}\cdot^\circ\text{C)}), and ΔT=Tout−Tin\Delta T = T_{\text{out}} - T_{\text{in}} is the lubricant temperature rise.

Equating Hgen=HdissH_{\text{gen}} = H_{\text{diss}} yields the temperature rise formulation:

ΔT=HgenρQeffcp\Delta T = \frac{H_{\text{gen}}}{\rho Q_{\text{eff}} c_p}

Iterative Viscosity Convergence

Because dynamic viscosity μ\mu decreases exponentially with temperature according to the ASTM D341 / Walther relationship, bearing analysis requires iterative convergence:

  1. Assume an initial average film temperature: Tavg=Tin+ΔT/2T_{\text{avg}} = T_{\text{in}} + \Delta T / 2.
  2. Determine dynamic viscosity μ\mu at TavgT_{\text{avg}} from the lubricant's viscosity-temperature chart.
  3. Compute Sommerfeld number SS, look up (r/c)f(r/c)f and flow parameters, and compute resulting ΔTcalc\Delta T_{\text{calc}}.
  4. Update Tavg,new=Tin+ΔTcalc/2T_{\text{avg,new}} = T_{\text{in}} + \Delta T_{\text{calc}} / 2. Repeat until TavgT_{\text{avg}} converges within ±0.5∘C\pm 0.5^\circ\text{C}.

Worked Engineering Example: Steam Turbine Governor Shaft Bearing

Problem Statement

A full hydrodynamic journal bearing (360∘360^\circ) supports the governor rotor shaft of an industrial steam turbine under the following specifications:

  • Journal diameter: d=50 mmd = 50\,\text{mm} (r=25 mm=0.025 mr = 25\,\text{mm} = 0.025\,\text{m})
  • Bearing length: L=50 mm=0.050 mL = 50\,\text{mm} = 0.050\,\text{m} (L/d=1.0L/d = 1.0)
  • Radial load: W=3,600 NW = 3,600\,\text{N} (3.6 kN3.6\,\text{kN})
  • Rotational speed: N=1,800 rpm  ⟹  n=30 rev/sN = 1,800\,\text{rpm} \implies n = 30\,\text{rev/s} (U=2πrn=4.7124 m/sU = 2\pi r n = 4.7124\,\text{m/s})
  • Radial clearance: c=0.025 mm=25 μmc = 0.025\,\text{mm} = 25\,\mu\text{m} (r/c=1,000r/c = 1,000)
  • Lubricant: ISO VG 32 turbine oil. At the assumed average film temperature (about 50∘C50^\circ\text{C}), dynamic viscosity is μ=0.020 Pa⋅s\mu = 0.020\,\text{Pa}\cdot\text{s} (20 cP20\,\text{cP})
  • Oil properties: density ρ=860 kg/m3\rho = 860\,\text{kg/m}^3, specific heat cp=2,000 J/(kg⋅∘C)c_p = 2,000\,\text{J/(kg}\cdot^\circ\text{C)}
  • Inlet oil supply temperature: Tin=35.0∘CT_{\text{in}} = 35.0^\circ\text{C}

Determine:

  1. The bearing nominal unit pressure PP.
  2. The Sommerfeld number SS.
  3. The minimum oil film thickness h0h_0 and compare against Trumpler's minimum criterion.
  4. The coefficient of friction ff, friction torque TfT_f, and total heat generation rate HgenH_{\text{gen}}.
  5. The total volumetric oil flow rate QQ, side-leakage flow QsQ_s, and lubricant temperature rise ΔT\Delta T.

Step-by-Step Solution

Step 1: Compute Nominal Bearing Pressure (PP)

P=WL⋅d=3,600 N(0.050 m)(0.050 m)=3,6000.0025=1,440,000 Pa=1.44 MPaP = \frac{W}{L \cdot d} = \frac{3,600\,\text{N}}{(0.050\,\text{m})(0.050\,\text{m})} = \frac{3,600}{0.0025} = 1,440,000\,\text{Pa} = 1.44\,\text{MPa}

Step 2: Calculate the Sommerfeld Number (SS)

S=(rc)2(μnP)=(1,000)2⋅(0.020 Pa⋅s)(30 s−1)1.44×106 Pa=106⋅0.601.44×106=0.4167≈0.417S = \left( \frac{r}{c} \right)^2 \left( \frac{\mu n}{P} \right) = (1,000)^2 \cdot \frac{(0.020\,\text{Pa}\cdot\text{s})(30\,\text{s}^{-1})}{1.44 \times 10^6\,\text{Pa}} = 10^6 \cdot \frac{0.60}{1.44 \times 10^6} = 0.4167 \approx 0.417

Step 3: Evaluate Film Thickness & Trumpler's Criterion

S=0.417S = 0.417 falls between the ϵ=0.2\epsilon = 0.2 row (S=0.631S = 0.631) and the ϵ=0.4\epsilon = 0.4 row (S=0.264S = 0.264). Interpolating linearly on SS, the operating point lies a fraction (0.417−0.264)/(0.631−0.264)=0.416(0.417 - 0.264)/(0.631 - 0.264) = 0.416 of the way toward the ϵ=0.2\epsilon = 0.2 row:

  • Eccentricity ratio: ϵ≈0.4−0.416(0.2)=0.32\epsilon \approx 0.4 - 0.416(0.2) = 0.32
  • Minimum film thickness variable: h0/c=1−ϵ≈0.68h_0/c = 1 - \epsilon \approx 0.68

Compute minimum film thickness h0h_0:

h0=c⋅0.68=(25 μm)(0.68)=17.0 μm=0.017 mmh_0 = c \cdot 0.68 = (25\,\mu\text{m})(0.68) = 17.0\,\mu\text{m} = 0.017\,\text{mm}

Check against Trumpler's criterion (h0,min⁡≥0.0002 in+0.00004d≈0.005 mm+0.00004dh_{0,\min} \ge 0.0002\text{ in} + 0.00004 d \approx 0.005\,\text{mm} + 0.00004 d):

h0,min⁡=0.005+0.00004(50)=0.005+0.002=0.007 mm=7.0 μmh_{0,\min} = 0.005 + 0.00004(50) = 0.005 + 0.002 = 0.007\,\text{mm} = 7.0\,\mu\text{m}

Since h0=17.0 μm>7.0 μmh_0 = 17.0\,\mu\text{m} > 7.0\,\mu\text{m}, the film comfortably separates the surfaces.

Step 4: Compute Friction, Torque, and Heat Generation

Interpolating the friction variable the same way:

(rc)f≈5.79+0.416(12.8−5.79)=8.7\left( \frac{r}{c} \right) f \approx 5.79 + 0.416(12.8 - 5.79) = 8.7

(Petroff's concentric estimate, 2π2S=8.22\pi^2 S = 8.2, confirms the magnitude.) The coefficient of friction is:

f=8.7r/c=8.71,000=0.0087f = \frac{8.7}{r/c} = \frac{8.7}{1{,}000} = 0.0087

Friction force and torque:

Ff=f⋅W=(0.0087)(3,600 N)=31.3 NF_f = f \cdot W = (0.0087)(3{,}600\,\text{N}) = 31.3\,\text{N} Tf=Ff⋅r=(31.3 N)(0.025 m)=0.783 N⋅mT_f = F_f \cdot r = (31.3\,\text{N})(0.025\,\text{m}) = 0.783\,\text{N}\cdot\text{m}

Friction heat generation rate:

Hgen=2πTfn=2π(0.783 N⋅m)(30 s−1)=147.6 WH_{\text{gen}} = 2\pi T_f n = 2\pi (0.783\,\text{N}\cdot\text{m})(30\,\text{s}^{-1}) = 147.6\,\text{W}

(Alternatively: Hgen=Ff⋅U=31.3×4.7124=147.6 WH_{\text{gen}} = F_f \cdot U = 31.3 \times 4.7124 = 147.6\,\text{W}.)

Step 5: Compute Oil Flow Rates and Temperature Rise

Interpolating the flow variables:

  • Flow variable: QrcnL≈3.99−0.416(0.40)=3.82\dfrac{Q}{r c n L} \approx 3.99 - 0.416(0.40) = 3.82
  • Side-leakage ratio: QsQ≈0.497−0.416(0.217)=0.41\dfrac{Q_s}{Q} \approx 0.497 - 0.416(0.217) = 0.41

Total volumetric flow rate:

Q=3.82×(0.025 m)×(2.5×10−5 m)×(30 s−1)×(0.050 m)=3.58×10−6 m3/s≈0.215 L/minQ = 3.82 \times (0.025\,\text{m}) \times (2.5 \times 10^{-5}\,\text{m}) \times (30\,\text{s}^{-1}) \times (0.050\,\text{m}) = 3.58 \times 10^{-6}\,\text{m}^3\text{/s} \approx 0.215\,\text{L/min}

Side leakage flow:

Qs=0.41×3.58×10−6=1.47×10−6 m3/sQ_s = 0.41 \times 3.58 \times 10^{-6} = 1.47 \times 10^{-6}\,\text{m}^3\text{/s}

Effective circulating flow carrying heat (half of the side flow is assumed to leave at the inlet temperature):

Qeff=Q(1−0.5QsQ)=3.58×10−6×(1−0.205)=2.85×10−6 m3/sQ_{\text{eff}} = Q \left( 1 - 0.5 \frac{Q_s}{Q} \right) = 3.58 \times 10^{-6} \times (1 - 0.205) = 2.85 \times 10^{-6}\,\text{m}^3\text{/s}

Mass flow rate:

m˙eff=ρQeff=(860)(2.85×10−6)=2.449×10−3 kg/s\dot{m}_{\text{eff}} = \rho Q_{\text{eff}} = (860)(2.85 \times 10^{-6}) = 2.449 \times 10^{-3}\,\text{kg/s}

Lubricant temperature rise:

ΔT=Hgenm˙effcp=147.6 W(2.449×10−3)(2,000)=147.64.897=30.1∘C\Delta T = \frac{H_{\text{gen}}}{\dot{m}_{\text{eff}} c_p} = \frac{147.6\,\text{W}}{(2.449 \times 10^{-3})(2{,}000)} = \frac{147.6}{4.897} = 30.1^\circ\text{C}

The average film temperature is Tavg=Tin+ΔT/2=35.0+15.1=50.1∘CT_{\text{avg}} = T_{\text{in}} + \Delta T / 2 = 35.0 + 15.1 = 50.1^\circ\text{C}. ISO VG 32 oil is roughly 0.0180.018 to 0.020 Pa⋅s0.020\,\text{Pa}\cdot\text{s} near 50∘C50^\circ\text{C}, consistent with the assumed μ=0.020 Pa⋅s\mu = 0.020\,\text{Pa}\cdot\text{s}, so this trial is essentially converged. Had TavgT_{\text{avg}} come out noticeably different, the viscosity would be re-read at the new temperature and Steps 2 to 5 repeated.

Test Your Knowledge

A hydrodynamic journal bearing operating in full-film steady state with radial clearance c=30 μmc = 30\,\mu\text{m} (L/d=1L/d = 1) runs at a Sommerfeld number S=0.15S = 0.15 (eccentricity ratio ϵ≈0.56\epsilon \approx 0.56). If the shaft rotational speed nn is increased by 50% while holding oil viscosity, operating temperature, and applied radial load constant, how do the Sommerfeld number and minimum oil film thickness h0h_0 respond?

A

The Sommerfeld number increases to 0.338, but minimum oil film thickness decreases due to increased viscous shear heating.

B

The Sommerfeld number remains unchanged at 0.15, keeping eccentricity and oil film thickness constant because radial load is constant.

C

The Sommerfeld number decreases to 0.100, driving the journal closer to the bearing wall and decreasing the minimum oil film thickness.

D

The Sommerfeld number increases to 0.225, causing the journal to run with lower eccentricity and increasing the minimum oil film thickness.

Test Your Knowledge

A heavy industrial journal bearing operates near the knee point of the Stribeck curve, at the threshold between mixed lubrication and full hydrodynamic lubrication. An auxiliary cooling water malfunction causes the oil reservoir temperature to increase sharply from 45 deg C to 90 deg C under constant rotational speed and mechanical load. What immediate tribological transition occurs?

A

The bearing shifts deeper into full hydrodynamic lubrication because lower oil viscosity reduces fluid friction torque.

B

The bearing shifts leftward into the mixed or boundary lubrication regime, increasing asperity contact, friction, and wear rate due to viscosity reduction.

C

The bearing transitions into elastohydrodynamic lubrication (EHL) as pressure spikes to compensate for temperature.

D

The friction coefficient decreases monotonically across all operating points because high temperature enhances boundary additive efficacy.

Test Your Knowledge

Petroff's equation defines the friction torque of a lightly loaded, concentric journal bearing as Tf=2π2μnr3LcT_f = \frac{2\pi^2 \mu n r^3 L}{c}. If a designer modifies a bearing by scaling down both the journal radius rr and the radial clearance cc by a factor of 2 (rnew=0.5rr_{\text{new}} = 0.5 r and cnew=0.5cc_{\text{new}} = 0.5 c), while keeping length LL, viscosity μ\mu, and rotational speed nn unchanged, by what factor does the frictional power loss H=2πTfnH = 2\pi T_f n change?

A

Power loss decreases by a factor of 4 (Hnew=0.25HH_{\text{new}} = 0.25 H).

B

Power loss decreases by a factor of 8 (Hnew=0.125HH_{\text{new}} = 0.125 H).

C

Power loss increases by a factor of 2 (Hnew=2.0HH_{\text{new}} = 2.0 H).

D

Power loss remains completely unchanged (Hnew=1.0HH_{\text{new}} = 1.0 H).

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