2.3 AC Fundamentals, Reactance & Magnetism

Key Takeaways

  • Faraday's Law of Induction states that induced electromotive force is directly proportional to the rate of change of magnetic flux (e=−NΔΦΔte = -N \frac{\Delta\Phi}{\Delta t}), with the induced polarity opposing the change per Lenz's Law.

  • Root-Mean-Square (RMS) voltage represents the effective heating value of an alternating sine wave, equivalent to DC: Vrms=Vp2≈0.707×VpV_{rms} = \frac{V_p}{\sqrt{2}} \approx 0.707 \times V_p, while peak voltage is Vp≈1.414×VrmsV_p \approx 1.414 \times V_{rms}.

  • Inductive reactance (XL=2πfLX_L = 2\pi f L) opposes current flow due to counter-EMF and increases linearly with frequency; in a pure inductor, voltage leads current by 90° (ELI).

  • Capacitive reactance (XC=12πfCX_C = \frac{1}{2\pi f C}) opposes AC voltage changes and decreases inversely with frequency; in a pure capacitor, current leads voltage by 90° (ICE).

  • Direct current operates at zero frequency (f=0 Hzf = 0\text{ Hz}), resulting in zero inductive reactance (XL=0 ΩX_L = 0\ \Omega) and infinite capacitive reactance (XC=∞ ΩX_C = \infty\ \Omega, completely blocking DC).

Last updated: October 2026

2.3 AC Fundamentals, Reactance & Magnetism

Alternating current (AC) is the global standard for commercial and industrial electric power distribution. Unlike direct current, which maintains unidirectional charge drift, alternating current periodically reverses direction and continuously modulates its instantaneous amplitude. Understanding how alternating magnetic and electric fields interact with inductive and capacitive circuit components is crucial for commercial electrical construction, motor installations, and power quality analysis.


Principles of Electromagnetism & Induction

Every electrical current produces an associated magnetic field. When current flows through a straight conductor, concentric lines of magnetic flux (Φ\Phi) circulate around the wire per the right-hand rule (pointing the right thumb in the direction of conventional current curls the fingers in the direction of the magnetic field).

Core Magnetic Quantities

  • Magnetic Flux (Φ\Phi): The total quantity of magnetic field lines, measured in Webers (Wb) (1 Wb=108 magnetic lines or Maxwells1\text{ Wb} = 10^8\text{ magnetic lines or Maxwells}). In imperial trade contexts, lines of flux are often termed Maxwells.
  • Magnetic Flux Density (BB): The concentration of flux lines per unit area perpendicular to the field, measured in Teslas (T) (1 Tesla=1 Wb/m2=10,000 Gauss1\text{ Tesla} = 1\text{ Wb/m}^2 = 10,000\text{ Gauss}): B=ΦAB = \frac{\Phi}{A}
  • Magnetomotive Force (MMF or F\mathcal{F}): The magnetic potential created by a coil to establish flux, measured in ampere-turns (A-t): MMF=N×I\text{MMF} = N \times I Where NN is the number of coil turns and II is current in Amperes.
  • Permeability (μ\mu): The ease with which a magnetic material accommodates magnetic flux. Ferromagnetic materials (iron, electrical steel) have relative permeabilities hundreds to thousands of times higher than air, concentrating flux within transformer and motor stator cores.
  • Reluctance (R\mathcal{R}): The opposition a magnetic circuit offers to magnetic flux, analogous to electrical resistance (Ohm's Law for magnetic circuits: Φ=MMFR\Phi = \frac{\text{MMF}}{\mathcal{R}}).

Faraday's Law & Lenz's Law

In 1831, Michael Faraday established Faraday's Law of Electromagnetic Induction: whenever the magnetic flux linking an electrical conductor changes over time, an electromotive force (voltage) is induced across the conductor terminals:

e=−NΔΦΔte = -N \frac{\Delta\Phi}{\Delta t}

Where:

  • e=instantaneous induced voltage (Volts)e = \text{instantaneous induced voltage (Volts)}
  • N=number of turns in the conductor coilN = \text{number of turns in the conductor coil}
  • ΔΦΔt=time rate of change of magnetic flux (Webers per second)\frac{\Delta\Phi}{\Delta t} = \text{time rate of change of magnetic flux (Webers per second)}

The negative sign represents Lenz's Law: the polarity of the induced EMF always opposes the original change in magnetic flux that produced it. In motors and transformers, this induced potential is termed Counter-Electromotive Force (CEMF) or back-EMF, which acts as a self-regulating electrical brake restricting current flow.


Generation and Metrics of AC Sinusoidal Waveforms

When a single rectangular conductive loop rotates at a constant angular velocity (ω=2πf\omega = 2\pi f) within a uniform stationary magnetic field, the instantaneous voltage induced along its conductors is proportional to the sine of the rotation angle (θ=ωt\theta = \omega t):

v(t)=Vpsin⁡(2πft)v(t) = V_p \sin(2\pi f t)

  • At 0∘0^\circ, the conductor moves parallel to magnetic flux lines; rate of flux cutting is zero, generating 0 Volts0\text{ Volts}.
  • At 90∘90^\circ, the conductor cuts perpendicularly through maximum flux density, generating positive peak voltage (+Vp+V_p).
  • At 180∘180^\circ, motion is again parallel to flux, returning to 0 Volts0\text{ Volts}.
  • At 270∘270^\circ, the conductor cuts flux in the opposite direction, generating negative peak voltage (−Vp-V_p).
  • At 360∘360^\circ, the cycle completes.
Voltage
  +Vp |        ***
      |      *     *
    0 +----*---------*---------*---- Time (t)
      |               *     *
  -Vp |                 ***
      0°      90°    180°    270°   360°
      |<------- 1 Cycle (T) -------->|

Sinusoidal Parameters

  1. Cycle: One complete positive alternation and one complete negative alternation (360∘360^\circ or 2π2\pi radians).
  2. Frequency (ff): The number of complete cycles occurring per second, measured in Hertz (Hz). North American commercial power operates at 60 Hz60\text{ Hz}. In an AC alternator, frequency depends on rotational speed (NN in RPM) and number of field poles (PP): f=P×N120f = \frac{P \times N}{120}
  3. Period (TT): The duration in seconds required to complete one full cycle: T=1fT = \frac{1}{f} At 60 Hz60\text{ Hz}: T=160≈0.01667 seconds=16.67 millisecondsT = \frac{1}{60} \approx 0.01667\text{ seconds} = 16.67\text{ milliseconds}.
  4. Peak Voltage (VpV_p or VpeakV_{peak}): Maximum instantaneous voltage measured from the zero axis to the crest.
  5. Peak-to-Peak Voltage (Vp−pV_{p-p}): Total voltage difference between positive and negative crests: Vp−p=2×VpV_{p-p} = 2 \times V_p
  6. Root-Mean-Square (RMS) Voltage (VrmsV_{rms}): The effective value of an AC wave. RMS represents the equivalent DC potential that delivers exactly the same heating power (I2RI^2R) to a pure resistance: Vrms=Vp2≈0.7071×VpVp=2×Vrms≈1.4142×VrmsV_{rms} = \frac{V_p}{\sqrt{2}} \approx 0.7071 \times V_p \qquad V_p = \sqrt{2} \times V_{rms} \approx 1.4142 \times V_{rms} AC meters normally display an RMS or RMS-calibrated value, but an average-responding meter is accurate only for the waveform for which it is calibrated. A true-RMS meter is required for reliable measurements of distorted waveforms. A nominal 120V120\text{V} sinusoidal AC receptacle has a peak voltage of 120×1.4142≈169.7 V120 \times 1.4142 \approx 169.7\text{ V} and a peak-to-peak voltage of 339.4 V339.4\text{ V}.
  7. Average Voltage (VavgV_{avg}): The arithmetic mean of all instantaneous values over one half-cycle alternation: Vavg=2π×Vp≈0.637×Vp=0.900×VrmsV_{avg} = \frac{2}{\pi} \times V_p \approx 0.637 \times V_p = 0.900 \times V_{rms}
ParameterFormula from Peak (VpV_p)Formula from RMS (VrmsV_{rms})Nominal 120V SystemNominal 277V System
Peak (VpV_p)VpV_p1.4142×Vrms1.4142 \times V_{rms}169.7 V169.7\text{ V}391.7 V391.7\text{ V}
Peak-to-Peak (Vp−pV_{p-p})2×Vp2 \times V_p2.8284×Vrms2.8284 \times V_{rms}339.4 V339.4\text{ V}783.5 V783.5\text{ V}
RMS (VrmsV_{rms})0.7071×Vp0.7071 \times V_pVrmsV_{rms}120.0 V120.0\text{ V}277.0 V277.0\text{ V}
Average (VavgV_{avg})0.6370×Vp0.6370 \times V_p0.9003×Vrms0.9003 \times V_{rms}108.0 V108.0\text{ V}249.4 V249.4\text{ V}

Purely Resistive AC Circuits

In an AC circuit containing only pure non-inductive resistance (e.g., baseboard electric strip heaters, incandescent filament lamps):

  • Voltage and current are completely in phase (phase angle θ=0∘\theta = 0^\circ).
  • Both waveforms pass through zero and peak at the exact same instant.
  • Ohm's Law and Joule's Law apply directly using RMS values: Irms=VrmsRP=Vrms×Irms=Irms2R=Vrms2RI_{rms} = \frac{V_{rms}}{R} \qquad P = V_{rms} \times I_{rms} = I_{rms}^2 R = \frac{V_{rms}^2}{R}

Inductance (LL) & Inductive Reactance (XLX_L)

Inductance (LL, measured in Henries, H) is the property of an electrical circuit that opposes any change in circuit current. A circuit has an inductance of 1 Henry1\text{ Henry} if a current changing at the rate of 1 Ampere per second1\text{ Ampere per second} induces a counter-EMF of 1 Volt1\text{ Volt} across its terminals:

VL=LΔiΔtV_L = L \frac{\Delta i}{\Delta t}

Inductive Phase Relationship: ELI

Because counter-EMF directly resists the growth of current, current cannot rise instantaneously when alternating voltage is applied. In a purely inductive circuit, voltage leads current by 90∘90^\circ (or current lags voltage by 90∘90^\circ). This fundamental relationship is captured by the first half of the trade mnemonic:

Note

ELI: In an Inductive circuit (LL), Electromotive force (EE) leads Current (II) by 90∘90^\circ.

Inductive Reactance Formula

The opposition to alternating current presented by an inductor is termed Inductive Reactance (XLX_L, measured in Ohms, Ω\Omega):

XL=2πfLX_L = 2\pi f L

Where:

  • XL=inductive reactance in Ohms (Ω)X_L = \text{inductive reactance in Ohms (}\Omega\text{)}
  • f=frequency in Hertz (Hz)f = \text{frequency in Hertz (Hz)}
  • L=inductance in Henries (H)L = \text{inductance in Henries (H)}
  • 2π≈6.28322\pi \approx 6.2832 (the angular frequency constant ω=2πf\omega = 2\pi f)

Worked Example: Calculate the inductive reactance and current for a 120 mH120\text{ mH} (0.12 H0.12\text{ H}) solenoid coil connected across a 120V,60 Hz120\text{V}, 60\text{ Hz} control circuit.

  1. Calculate XLX_L: XL=2×π×60 Hz×0.12 H≈376.99×0.12≈45.24 ΩX_L = 2 \times \pi \times 60\text{ Hz} \times 0.12\text{ H} \approx 376.99 \times 0.12 \approx 45.24\ \Omega
  2. Calculate current: IL=VXL=120 V45.24 Ω≈2.65 Amps (lagging voltage by 90∘)I_L = \frac{V}{X_L} = \frac{120\text{ V}}{45.24\ \Omega} \approx 2.65\text{ Amps (lagging voltage by } 90^\circ)

Capacitance (CC) & Capacitive Reactance (XCX_C)

Capacitance (CC, measured in Farads, F) is the property of an electrical circuit that opposes any change in circuit voltage by storing electrostatic energy between conductive plates separated by an insulating dielectric:

C=QVC = \frac{Q}{V}

Because the Farad is an exceptionally large unit, craft applications utilize microfarads (μF=10−6 F\mu\text{F} = 10^{-6}\text{ F}) or picofarads (pF=10−12 F\text{pF} = 10^{-12}\text{ F}).

Capacitive Phase Relationship: ICE

When alternating voltage is applied across a capacitor, charging current flows into the plates at its highest rate when the voltage is passing through zero (maximum rate of voltage change Δv/Δt\Delta v / \Delta t). As the capacitor charges to peak voltage, current drops to zero. In a purely capacitive circuit, current leads voltage by 90∘90^\circ:

Note

ICE: In a Capacitive circuit (CC), Current (II) leads Electromotive force (EE) by 90∘90^\circ.

Combining both relationships yields the trade mnemonic: ELI the ICE man.

Capacitive Reactance Formula

The opposition to alternating current presented by a capacitor is termed Capacitive Reactance (XCX_C, measured in Ohms, Ω\Omega):

XC=12πfCX_C = \frac{1}{2\pi f C}

Where:

  • XC=capacitive reactance in Ohms (Ω)X_C = \text{capacitive reactance in Ohms (}\Omega\text{)}
  • f=frequency in Hertz (Hz)f = \text{frequency in Hertz (Hz)}
  • C=capacitance in Farads (F)C = \text{capacitance in Farads (F)}

Worked Example: Calculate the capacitive reactance and current for a 35 μF35\ \mu\text{F} motor-run capacitor connected across a 240V,60 Hz240\text{V}, 60\text{ Hz} single-phase motor circuit.

  1. Convert microfarads to Farads: C=35 μF=35×10−6 F=0.000035 FC = 35\ \mu\text{F} = 35 \times 10^{-6}\text{ F} = 0.000035\text{ F}
  2. Calculate XCX_C: XC=12×π×60 Hz×(35×10−6 F)=1376.99×0.000035=10.013195≈75.79 ΩX_C = \frac{1}{2 \times \pi \times 60\text{ Hz} \times (35 \times 10^{-6}\text{ F})} = \frac{1}{376.99 \times 0.000035} = \frac{1}{0.013195} \approx 75.79\ \Omega
  3. Calculate current: IC=VXC=240 V75.79 Ω≈3.17 Amps (leading voltage by 90∘)I_C = \frac{V}{X_C} = \frac{240\text{ V}}{75.79\ \Omega} \approx 3.17\text{ Amps (leading voltage by } 90^\circ)

Frequency Response of Reactances

The mathematical structures of XLX_L and XCX_C show opposing behaviors across the frequency spectrum:

  • Inductive Reactance (XL=2πfLX_L = 2\pi f L): Directly proportional to frequency (XL∝fX_L \propto f). At direct current (f=0 Hzf = 0\text{ Hz}), an ideal inductor exhibits zero reactance (XL=0 ΩX_L = 0\ \Omega), acting as a direct short circuit. As frequency rises, XLX_L increases linearly, opposing high frequencies (choke behavior).
  • Capacitive Reactance (XC=12πfCX_C = \frac{1}{2\pi f C}): Inversely proportional to frequency (XC∝1fX_C \propto \frac{1}{f}). At direct current (f=0 Hzf = 0\text{ Hz}), capacitive reactance is infinite (XC=∞ ΩX_C = \infty\ \Omega), completely blocking steady DC current. As frequency increases, XCX_C drops toward zero, allowing high-frequency AC signals to pass freely.
Reactance (Ω)
  ^          / Inductive (XL = 2πfL)
  |         /  
  |        /   
  |       /    
  |      /     
  |     /      
  |    /_______ Capacitive (XC = 1 / 2πfC)
  |   /        ` - . _
  +--+----------------> Frequency (f)
     0
PropertyPure Resistance (RR)Pure Inductance (LL)Pure Capacitance (CC)
Opposition UnitOhms (Ω\Omega)Ohms (Ω\Omega, XLX_L)Ohms (Ω\Omega, XCX_C)
Phase RelationshipIn phase (θ=0∘\theta = 0^\circ)Voltage leads Current by 90∘90^\circ (ELI)Current leads Voltage by 90∘90^\circ (ICE)
FormulaR=ρL/AR = \rho L / AXL=2πfLX_L = 2\pi f LXC=1/(2πfC)X_C = 1 / (2\pi f C)
Response to Frequency (f↑f \uparrow)Constant (Independent of ff)Increases linearly (XL↑X_L \uparrow)Decreases inversely (XC↓X_C \downarrow)
Direct Current (f=0 Hzf = 0\text{ Hz})Normal opposition (RR)Zero reactance (XL=0 ΩX_L = 0\ \Omega, Short)Infinite reactance (XC=∞ ΩX_C = \infty\ \Omega, Open)
Loading diagram...
Phase Relationships in AC Circuit Elements (ELI the ICE man)
Test Your Knowledge

A digital multimeter measuring a purely sinusoidal commercial AC lighting circuit displays a reading of 277V RMS. What is the peak voltage (V_p) of this alternating waveform?

A

176.5 V

B

195.8 V

C

391.7 V

D

554.0 V

Test Your Knowledge

An inductive filter choke has an inductance of 0.08 H connected to a 120V, 60 Hz AC distribution circuit. What is the inductive reactance (X_L) of the choke, and what is the phase relationship between voltage and current?

A

15.08 Ω; current leads voltage by 90°

B

30.16 Ω; current leads voltage by 90°

C

15.08 Ω; voltage leads current by 90°

D

30.16 Ω; voltage leads current by 90°

Test Your Knowledge

A power-factor correction capacitor rated at 50 μF is energized by a 240V, 60 Hz single-phase feeder. What is the capacitive reactance (X_C) of this capacitor?

A

53.05 Ω

B

18.85 Ω

C

106.10 Ω

D

1.88 Ω

Test Your Knowledge

If the operating frequency of an AC power system is doubled from 60 Hz to 120 Hz, how do the inductive reactance (X_L) of an inductor and the capacitive reactance (X_C) of a capacitor change?

A

X_L halves and X_C doubles.

B

X_L doubles and X_C halves.

C

Both X_L and X_C double in direct proportion to frequency.

D

Both X_L and X_C remain unchanged because component inductance and capacitance are fixed.

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