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9.3 Cross Sections of 3D Figures & Solids of Revolution

Key Takeaways

  • A planar cross section is the 2D intersection of a cutting plane with a 3D solid; for a convex polyhedron, the number of polygon edges cannot exceed the number of intersected faces.

  • Slicing a cube can generate triangles, quadrilaterals (squares, rectangles, trapezoids, rhombi), pentagons, and regular hexagons, but never polygons with 7 or more edges.

  • Planar slices of a cone generate the classic conic sections: circles (parallel to base), ellipses (closed oblique slice), parabolas (parallel to a slant generator), and hyperbolas (cutting both nappes of a double cone).

  • Solids of revolution result from rotating a planar region 360 degrees about a coplanar axis: rotating a rectangle yields a cylinder, a right triangle yields a cone, a semicircle yields a sphere, and a right trapezoid yields a conical frustum.

  • Pappus's Centroid Theorems connect rotational geometry to planar metrics: surface area equals A = 2piy_barL and volume equals V = 2piy_barA, where y_bar is the distance from the generator's centroid to the axis of rotation.

Last updated: September 2026

9.3 Cross Sections of 3D Figures & Solids of Revolution

Geometry of Planar Cross Sections

A planar cross section is the two-dimensional geometric region formed by the intersection of a three-dimensional solid with a cutting plane. Cross-sectional analysis connects spatial geometry to multi-variable calculus, computer-aided design, and medical imaging (tomography).

The fundamental topological and geometric constraints governing cross sections include:

  1. Dimensionality Reduction: Slicing an nn-dimensional Euclidean object with an (n−1)(n-1)-dimensional flat hyperplane produces an (n−1)(n-1)-dimensional subset. In R3\mathbb{R}^3, the intersection of a solid and a 2D plane is always a 2D planar figure (or degenerate 1D line segment/0D point if tangent).
  2. Convex Polyhedron Face Constraint: If a convex polyhedron has FF planar faces, any planar cross section can intersect at most FF faces. Furthermore, because both the polyhedron faces and the cutting plane are flat, the intersection of the cutting plane with any single face is at most a single straight line segment. Therefore, the cross section of a convex polyhedron is always a convex polygon whose number of edges EsliceE_{\text{slice}} satisfies:
3≤Eslice≤F3 \le E_{\text{slice}} \le F

Cross Sections of Polyhedra: The Cube and Tetrahedron

Understanding how cutting planes intersect standard polyhedra is a benchmark skill on the FTCE Mathematics 6-12 examination:

  • Slicing a Solid Cube (F=6F = 6):
    • Triangles (Eslice=3E_{\text{slice}} = 3): Formed when the cutting plane slices through three mutually adjacent faces meeting at a single corner. Slicing equidistant from the vertex produces an equilateral triangle; varying distances produce isosceles or scalene triangles.
    • Quadrilaterals (Eslice=4E_{\text{slice}} = 4): Slicing parallel to any cube face yields a square. Slicing obliquely through four parallel lateral faces yields a non-square rectangle, a rhombus, or a general parallelogram. Slicing through opposite faces at non-parallel angles yields an isosceles trapezoid or general trapezoid.
    • Pentagons (Eslice=5E_{\text{slice}} = 5): Formed when the cutting plane intersects exactly 5 faces of the cube, clipping five edges without intersecting the sixth face.
    • Hexagons (Eslice=6E_{\text{slice}} = 6): Formed when the plane intersects all 6 faces of the cube. If the plane passes through the midpoints of six consecutive edges forming a non-coplanar closed cycle and passes through the cube's geometric center, the cross section is a perfect regular hexagon!
    • Heptagons (Eslice≥7E_{\text{slice}} \ge 7): Strictly impossible. Because a cube has exactly 6 faces and is convex, a flat plane cannot generate 7 or more edges.
  • Regular Tetrahedron (F=4F = 4): Can only produce triangles (Eslice=3E_{\text{slice}} = 3) or quadrilaterals (Eslice=4E_{\text{slice}} = 4). Remarkably, a plane passing symmetrically through four edges parallel to two opposite skew edges forms a square!

Cross Sections of Curved Solids: Cylinders, Cones, and Spheres

  • Right Circular Cylinder:
    • Parallel to base: Circle of radius rr.
    • Oblique plane cutting through the lateral surface without intersecting bases: Ellipse.
    • Perpendicular to base (vertical cut through axis): Rectangle of dimensions 2r×h2r \times h (a square if h=2rh = 2r).
    • Plane cutting through base and lateral wall: Truncated parabolic or hyperbolic segment.
  • Right Circular Cone and Conic Sections:
    • Parallel to base: Circle.
    • Tilted cutting plane through one nappe at an angle greater than the generator slant: Ellipse.
    • Plane parallel to exactly one generating line (element/slant edge) of the cone: Parabola.
    • Plane parallel to the cone's central vertical axis (or cutting both nappes of a double cone at an angle shallower than the generator): Hyperbola.
    • Degenerate cross sections passing through the apex: A single point (tangent to apex), a single straight line (tangent along a generator), or two intersecting lines (vertical plane passing through the apex, which for a single bounded cone appears as an isosceles triangle).
  • Sphere:
    • Every non-empty planar cross section of a sphere of radius RR is ALWAYS a circle.
    • If the cutting plane passes through the sphere's center (distance d=0d = 0), the cross section is a great circle of maximum radius r=Rr = R.
    • If the plane is at perpendicular distance dd from the center (0<d<R0 < d < R), the cross section is a small circle with radius:
r=R2−d2r = \sqrt{R^2 - d^2}
  • If d=Rd = R, the intersection is a single degenerate tangent point.

Solids of Revolution: Rotational Generation Mappings

A solid of revolution is a three-dimensional figure generated by revolving a two-dimensional planar region 360∘360^\circ (2π2\pi radians) around an axis of coplanar rotation.

  • Standard Geometric Profiles:
    1. Rectangle: Rotating a rectangle of dimensions r×hr \times h around an axis containing one of its sides generates a right circular cylinder of radius rr and height hh.
    2. Right Triangle: Rotating a right triangle with legs rr and hh around the leg of length hh generates a right circular cone of base radius rr, altitude hh, and slant height l=r2+h2l = \sqrt{r^2 + h^2}.
    3. Semicircle: Rotating a semicircle of radius rr around its bounding diameter generates a full sphere of radius rr.
    4. Right Trapezoid: Rotating a right trapezoid with parallel bases rr and RR around the leg perpendicular to the bases generates a conical frustum with base radii rr and RR.
    5. Equilateral or Isosceles Triangle: Rotating around its altitude of symmetry yields a single cone. Rotating around its base yields a bicone (two identical cones joined base-to-base).

Quantitative Mensuration of Revolution Solids: Disk, Washer & Shell Methods

Calculus links cross-sectional geometry to rotational volume via single-variable integration:

  • Disk Method (Solid of Revolution without Hole): When the planar region bounded by y=f(x)≥0y = f(x) \ge 0, y=0y = 0, x=ax = a, and x=bx = b is revolved about the x-axis, each vertical strip of width dxdx sweeps out a circular disk of radius R(x)=f(x)R(x) = f(x) and thickness dxdx:
V=π∫ab[f(x)]2 dxV = \pi \int_a^b [f(x)]^2 \, dx
  • Washer Method (Solid of Revolution with Central Void): When the region bounded between outer curve y=R(x)y = R(x) and inner curve y=r(x)y = r(x) is revolved about the x-axis, each vertical strip sweeps out an annular washer with outer radius R(x)R(x) and inner radius r(x)r(x):
V=π∫ab([R(x)]2−[r(x)]2)dxV = \pi \int_a^b \left( [R(x)]^2 - [r(x)]^2 \right) dx
  • Cylindrical Shell Method: Revolving a region bounded by y=f(x)y = f(x) about the vertical y-axis decomposes the solid into concentric cylindrical shells of radius xx, height f(x)f(x), and thickness dxdx:
V=2π∫abxf(x) dxV = 2\pi \int_a^b x f(x) \, dx

Pappus's Centroid Theorems for Rotational Mensuration

Pappus of Alexandria established two powerful theorems uniting rotational mensuration with planar centroids:

Pappus's First Theorem (Surface Area): The area AA of a surface of revolution generated by revolving a plane curve CC about a non-intersecting coplanar axis equals the product of the arc length LL of CC and the distance traveled by the centroid of CC:

A=2πyˉLA = 2\pi \bar{y} L

where yˉ\bar{y} is the perpendicular distance from the curve's centroid to the axis of rotation.

Pappus's Second Theorem (Volume): The volume VV of a solid of revolution generated by revolving a plane region RR about a non-intersecting coplanar axis equals the product of the area AA of RR and the distance traveled by the centroid of RR:

V=2πyˉAV = 2\pi \bar{y} A

where yˉ\bar{y} is the perpendicular distance from the region's centroid to the axis of rotation.


Worked Exemplar: Solid of Revolution Generated by a Trapezoid

Problem: A rectangular region with vertices at (2,0)(2, 0), (5,0)(5, 0), (5,4)(5, 4), and (2,4)(2, 4) is revolved 360∘360^\circ around the y-axis. Calculate the volume of the resulting three-dimensional solid using both the washer method and Pappus's Second Theorem.

  • Solution via Washer Method: The solid generated is a hollow circular cylinder (thick pipe) with outer radius R=5R = 5, inner radius r=2r = 2, and height h=4h = 4. The horizontal cross section at any height y∈[0,4]y \in [0, 4] is a washer with area:
Awasher=πR2−πr2=π(52−22)=π(25−4)=21πA_{\text{washer}} = \pi R^2 - \pi r^2 = \pi(5^2 - 2^2) = \pi(25 - 4) = 21\pi

Integrating across height h=4h = 4:

V=∫0421π dy=21π×4=84πV = \int_0^4 21\pi \, dy = 21\pi \times 4 = 84\pi
  • Solution via Pappus's Second Theorem:
  1. Area of the rectangle: width is 5−2=35 - 2 = 3, height is 4−0=44 - 0 = 4. Area A=3×4=12A = 3 \times 4 = 12.
  2. Centroid of the rectangle: By symmetry, the x-coordinate of the centroid is the midpoint of the horizontal span:
xˉ=2+52=3.5\bar{x} = \frac{2 + 5}{2} = 3.5
  1. Distance traveled by the centroid during a 360∘360^\circ rotation about the y-axis:
d=2πxˉ=2π(3.5)=7πd = 2\pi \bar{x} = 2\pi(3.5) = 7\pi
  1. Volume by Pappus:
V=2πxˉA=(7π)(12)=84πV = 2\pi \bar{x} A = (7\pi)(12) = 84\pi

Both methods independently verify the identical volume of 84π84\pi.


Cross-Section Slicing and Solid of Revolution Mapping Tables

Planar Cross-Section Slices of Common 3D Figures

Solid FigureOrientation / Cutting Plane PositionResulting 2D Cross SectionGeometric / Algebraic Properties
CubeSlicing 3 adjacent faces at a cornerTriangleEquilateral if cuts are equidistant; scalene otherwise
CubeParallel to a faceSquareCongruent to cube faces
CubeOblique cut through 4 parallel facesRectangle / ParallelogramNon-square rectangle or rhombus depending on tilt
CubeCutting 5 facesPentagonAsymmetric 5-sided convex polygon
CubeCutting all 6 faces through centerHexagonRegular hexagon when passing through midpoints
CylinderParallel to circular baseCircleCongruent to base of radius rr
CylinderOblique cut not intersecting baseEllipseMajor axis 2a>2r2a > 2r, minor axis 2b=2r2b = 2r
CylinderPerpendicular to base through centerRectangleDimensions 2r×h2r \times h
ConeParallel to circular baseCircleRadius scales linearly with distance from apex
ConeTilted through one nappeEllipseClosed conic section
ConeParallel to one slant generatorParabolaOpen single-branched conic curve
ConeParallel to central vertical axisHyperbolaIntersects both nappes of double cone
SphereAny non-empty plane at distance d≤Rd \le RCircleRadius r=R2−d2r = \sqrt{R^2 - d^2}; great circle if d=0d = 0

Solids of Revolution Rotation Mappings

2D Generating ShapeAxis of RotationGenerated 3D SolidResulting Metric Formulas
Rectangle (w×hw \times h)Side of length hhRight Circular Cylinderr=wr = w, V=πw2hV = \pi w^2 h, SA=2πw2+2πwhSA = 2\pi w^2 + 2\pi w h
Right Triangle (legs a,ba, b)Leg of length bbRight Circular Coner=ar = a, h=bh = b, V=13πa2bV = \frac{1}{3}\pi a^2 b, l=a2+b2l = \sqrt{a^2+b^2}
Semicircle (radius rr)Bounding diameterSphereV=43πr3V = \frac{4}{3}\pi r^3, SA=4πr2SA = 4\pi r^2
Right Trapezoid (bases r,Rr, R)Perpendicular leg hhConical FrustumV=13πh(R2+Rr+r2)V = \frac{1}{3}\pi h(R^2 + Rr + r^2)
Circle (radius rr)Coplanar line distance R>rR > rTorus (Donut)V=2π2Rr2V = 2\pi^2 R r^2, SA=4π2RrSA = 4\pi^2 R r (by Pappus)
Test Your Knowledge

Which of the following polygons CANNOT be formed by a planar cross section of a solid regular cube?

A

Regular heptagon (7-sided polygon)

B

Regular hexagon

C

Equilateral triangle

D

Non-square rectangle

Test Your Knowledge

A plane intersects a right circular double cone without passing through the apex. If the cutting plane is parallel to exactly one generating line (element) along the lateral surface of the cone, what geometric curve is formed at the cross section?

A

Ellipse

B

Hyperbola

C

Parabola

D

Circle

Test Your Knowledge

A right triangle in the coordinate plane has vertices at (0, 0), (6, 0), and (0, 8). If this planar region is rotated 360 degrees about the y-axis, what is the total volume of the resulting three-dimensional solid of revolution?

A

288*pi

B

128*pi

C

72*pi

D

96*pi

Test Your Knowledge

A rectangular planar region with vertices at (2, 0), (5, 0), (5, 4), and (2, 4) is rotated 360 degrees about the y-axis. What is the total volume of the resulting three-dimensional solid of revolution?

A

100*pi

B

84*pi

C

36*pi

D

168*pi

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