9.1 Four Forces and Lift Production
Key Takeaways
- In steady unaccelerated flight the four forces balance: lift equals weight and thrust equals drag (PHAK Chapters 4–5).
- Lift is L = CL × ½ ρ V² S. Doubling true airspeed at a constant coefficient of lift quadruples lift.
- PHAK treats Bernoulli’s principle and Newton’s third law as complementary explanations of lift — not a pick-one fight.
- Angle of attack is chord line versus relative wind. Camber, flaps, and airspeed change how much lift that angle produces.
- Extending flaps increases camber (Fowler flaps also increase area), raising CL, lowering stall speed, and adding drag.
ACS PA.I.F.K3 (aerodynamics) and the knowledge base behind PA.VII slow flight and stalls all rest on one picture: four forces, an airfoil, and a lift equation. The Private Pilot Airplane knowledge test does not ask you to derive Navier–Stokes. It does ask whether lift equals weight in a steady climb, whether doubling speed doubles lift, whether Bernoulli “or” Newton is the official story, and what flaps do to camber and stall speed.
Four forces, one equilibrium
PHAK Chapters 4 and 5 name the four aerodynamic forces that act on an airplane in flight.
| Force | Direction | Acts through / produced by | Opposes |
|---|---|---|---|
| Lift | Perpendicular to the flight path (relative wind) | Dynamic pressure on the airfoil; resultant through the center of pressure | Weight |
| Weight | Vertically toward the center of the Earth | Gravity acting at the center of gravity (CG) | Lift |
| Thrust | Generally forward, parallel to the propeller/thrust line | Powerplant and propeller | Drag |
| Drag | Rearward, parallel to the relative wind | Airfoil, fuselage, and every protruding object | Thrust |
Steady, straight, unaccelerated flight is equilibrium. Newton’s third law applied to the airplane as a whole: the sum of the opposing forces is zero. To hold a constant airspeed, thrust equals drag. To hold a constant altitude in level flight, lift equals weight. That pair of equalities is the PAR default. It is also the sentence students over-apply.
In a steady climb or steady descent the airplane is still unaccelerated, so the vector sums still balance, but the neat “lift = weight, thrust = drag” picture is only the level-flight special case. In a climb a component of weight acts rearward along the flight path, so thrust must exceed the aerodynamic drag of the airframe. In a power-off glide a component of weight acts forward and is the “thrust.” PHAK is explicit that some thrust can contribute a vertical component when the nose is high, and some drag can contribute a downward component. For the knowledge test, keep the level-flight equality as the definition of unaccelerated cruise, and do not invent a private-pilot rule that lift always exceeds weight in a climb.
If you add power and hold attitude, airspeed rises until drag again equals the new thrust. If you reduce power, the airplane decelerates until drag falls to match. If lift exceeds weight you accelerate upward (a climb entry, or a balloon). If lift is less than weight you accelerate downward.
The lift equation
PHAK writes the force of lift as
L = CL × ½ ρ V² S
- CL — coefficient of lift. A dimensionless number that packages airfoil shape (camber, thickness, flaps, frost) and angle of attack. For a given wing, CL rises with AOA up to CL-max, then collapses.
- ρ (rho) — air density. High density altitude (hot, high, humid, low pressure) is a smaller ρ and, all else equal, less lift.
- V — true airspeed of the airfoil through the air. Lift is proportional to V squared.
- S — wing area. Twice the area, twice the lift at the same CL, density, and speed.
Worked V² example. Same airplane, same AOA (same CL), same density, same wing area. At 80 knots the wing produces some lift L. At 160 knots, V has doubled, so V² is four times as large and lift is 4L. That is why, in level flight, you lower the nose as you accelerate: if you held AOA constant, lift would balloon you into a climb. Conversely, as you slow, you must raise the nose (increase CL via AOA) to keep L = W. There is a limit to that trade. When AOA reaches critical, CL-max is behind you and the wing stalls — the next section.
Pilots directly control two terms: AOA (elevator) and V (power and pitch). They change S and the camber part of CL when they extend flaps. They do not change ρ except by choosing a different altitude, temperature, or humidity. That is why a hot high-elevation takeoff is a density-altitude problem, not a “the wing forgot how to fly” problem.
Bernoulli and Newton are both PHAK
The trap item is the Bernoulli-only story, often dressed as the equal-transit-time myth (air molecules that split at the leading edge must reunite at the trailing edge, so the longer upper path “must” be faster). PHAK does not teach equal transit time. PHAK Chapter 4 teaches both of the following, as complementary views of one flow:
- Bernoulli’s principle. As the velocity of a moving fluid increases, the pressure within the fluid decreases. The airfoil and its inclination speed the flow over the upper surface, so static pressure there falls. Higher pressure below than above produces a net aerodynamic force.
- Newton’s third law. The airfoil is shaped and inclined so that it turns the flow downward (downwash). The action on the air has an equal-and-opposite reaction on the wing: an upward-forward force.
PHAK is blunt that the pressure difference alone does not account for total lift. The downward-backward flow off the trailing edge is the Newtonian half of the same story. A flat plate at a positive AOA, a symmetrical airfoil, and a paper airplane all produce lift with little or no “longer upper path.” Do not pick Bernoulli or Newton on the test. Pick both.
Camber, chord, relative wind, angle of attack
An airfoil in cross-section has a rounded leading edge, a sharp trailing edge, an upper camber (usually more curved) and a lower camber (often flatter). The chord line is the straight line from the leading-edge extremity to the trailing-edge extremity. The mean camber line sits equidistant from the upper and lower surfaces; it meets the chord at both ends. Camber is the curvature away from the chord. More camber generally means more CL at a given AOA — and more drag.
Relative wind is the airflow opposite the flight path. It is not “the wind reported on ATIS.” In a climb the relative wind comes from ahead and slightly below the airplane’s longitudinal axis; in a descent, from ahead and slightly above.
Angle of attack (AOA, α) is the angle between the chord line and the relative wind. The pilot changes it with elevator. Angle of incidence is a different, fixed angle: chord line versus the airplane’s longitudinal axis. You cannot change incidence from the cockpit. Exam stems that swap those two words are testing vocabulary, not opinions about lift.
For every AOA there is a corresponding airspeed that holds altitude in steady level flight. High AOA + low speed can equal low AOA + high speed. At very high speed in level flight the required AOA can even be slightly negative. The wing still works.
Center of pressure versus CG
The center of pressure (CP) — also called the center of lift — is the average location of the pressure distribution, the point through which the aerodynamic force acts. PHAK: as AOA increases, CP moves forward; as AOA decreases, CP moves aft. That travel changes the pitching moment the wing applies to the airframe.
Weight acts at the CG. Designers place the allowable CG range forward of the typical CP so the wing’s lift, acting aft of the mass, produces a nose-down moment. The horizontal tail is then set to produce a downward force that balances the airplane in pitch. If CP were allowed to sit forward of CG, the wing would try to pitch the nose up — toward the stall — and the tail would have a harder job. Changes in CP with AOA are why aerodynamic balance and controllability change as you slow down or pull up.
An aft CG shortens the tail’s moment arm, reduces the download the tail must make, lowers stall speed slightly, and makes the airplane less longitudinally stable — recovery from a stall can run out of elevator. That story is finished in the weight-and-balance chapter; here, remember that lift does not act at the CG.
How flaps change the wing
Flaps are secondary controls (PA.I.G.K1b) that rewrite the lift equation in the landing pattern. PHAK Chapter 6: when extended, flaps increase the camber of the wing. They increase both lift and induced drag for a given AOA. Fowler flaps also translate aft, increasing S. The higher CL means the same weight can be supported at a lower airspeed, so stall speed falls. The extra drag lets you fly a steeper descent without accelerating.
Typical trainer use, conceptually (confirm the AFM/POH):
- First increment (often about 10°): a useful CL increase with a modest drag rise — a takeoff or soft-field setting.
- Further increments (approach and landing): more camber, more drag, still-lower stall speed — used to steepen the path and slow the airplane.
Plain, split, slotted, and Fowler flaps all increase camber; they differ in how much extra CL they buy and how the pitching moment changes. Do not memorize an unpublished “flaps cut stall speed by 10 knots” number. Read the V-speeds for that airplane, flaps up versus flaps down.
Scenario: Jordan’s downwind-to-final
Jordan is in the pattern at 90 knots, flaps up, roughly L = W at a small AOA. On base he extends the first flap increment. Camber and CL rise; if he holds the same pitch he will balloon, so he retrims to a slightly lower pitch and a lower speed that again makes L = W. On final, full flaps raise CL and drag again. Stall speed is now the flaps-down number, not the clean number. If he later tries to explain why the wing is still flying at 65 knots, the PAR answer is not “Bernoulli beat Newton.” It is a higher CL from more camber, sitting inside L = CL × ½ ρ V² S, with four forces still in equilibrium.
In straight-and-level, unaccelerated cruise, which pair of equalities describes the four forces?
An airplane is in steady level flight. The pilot doubles true airspeed while holding angle of attack and configuration constant. What happens to lift, according to the PHAK lift equation?
Which statement matches PHAK’s explanation of how a wing produces lift?