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100+ Free FL Mechanical Practice Questions

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2026 Statistics

Key Facts: FL Mechanical Exam

70%

Passing score

DBPR

130

Scored questions

DBPR At a Glance

7.5 hrs

Time allowed

DBPR At a Glance

$135

Registration fee

Professional Testing, Inc.

4 yrs

Experience req

CILB

These are independently written, English-language multiple-choice study questions built from the official CILB Mechanical content outline. They are an MCQ study adaptation of an open-book exam and do not reproduce CILB's item bank or simulate the official open-book format. Use them to review HVACR systems, refrigeration, piping, duct design, controls, combustion air, fuel gas, energy conservation, codes, equipment sizing, and OSHA safety before sitting for the official Pearson VUE trade examination.

Sample FL Mechanical Practice Questions

Try these sample questions to test your FL Mechanical exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A supply air duct delivers 1,200 CFM with a temperature rise of 20°F across a heating coil. Using the sensible heat formula Qs = 1.08 × CFM × ΔT, what is the sensible heat output?
A.19,440 BTU/hr
B.25,920 BTU/hr
C.21,600 BTU/hr
D.14,400 BTU/hr
Explanation: Apply the sensible heat formula: Qs = 1.08 × 1,200 CFM × 20°F = 25,920 BTU/hr. The 1.08 factor is derived from the density of standard air (0.075 lb/ft³) times its specific heat (0.24 BTU/lb·°F) times 60 minutes per hour. This is the workhorse formula for converting airflow and temperature change into a heat rate for design and verification.
2A 5-ton air-conditioning system is operating at rated capacity. How many BTU per hour of heat does it remove from the conditioned space?
A.12,000 BTU/hr
B.36,000 BTU/hr
C.60,000 BTU/hr
D.72,000 BTU/hr
Explanation: One ton of refrigeration equals 12,000 BTU/hr, defined as the heat absorbed by one ton of ice melting in 24 hours. Five tons therefore removes 5 × 12,000 = 60,000 BTU/hr. This relationship is the foundation for residential and commercial cooling capacity ratings.
3An air handler supplies 2,000 CFM. The moisture removed from the air is 30 grains per pound of dry air. Using Ql = 0.68 × CFM × ΔW, what is the latent cooling capacity?
A.40,800 BTU/hr
B.20,400 BTU/hr
C.61,200 BTU/hr
D.13,600 BTU/hr
Explanation: Apply the latent heat formula: Ql = 0.68 × 2,000 CFM × 30 grains = 40,800 BTU/hr. The 0.68 constant combines air density (0.075 lb/ft³), the latent heat of vaporization (1,060 BTU/lb), 7,000 grains per pound, and 60 minutes per hour. Latent cooling is the energy used to condense or remove moisture from the air.
4Air enters a cooling coil at 1,500 CFM with an enthalpy of 31.5 BTU/lb and leaves at 23.0 BTU/lb. Using Qt = 4.5 × CFM × Δh, what is the total cooling load?
A.57,375 BTU/hr
B.38,250 BTU/hr
C.51,000 BTU/hr
D.45,000 BTU/hr
Explanation: Apply the total heat formula: Qt = 4.5 × 1,500 CFM × (31.5 − 23.0) = 4.5 × 1,500 × 8.5 = 57,375 BTU/hr. The 4.5 factor is the product of air density (0.075 lb/ft³) and 60 minutes per hour. Total heat includes both sensible (temperature) and latent (humidity) energy changes, so it is the best choice when enthalpy is known.
5An air-conditioning system is oversized for the space it serves. Which operating problem is most likely to result?
A.Extended run cycles that dehumidify well
B.Short cycles that leave the space clammy and humid
C.Constant low suction pressure at the compressor
D.Compressor damage from long off-periods
Explanation: An oversized system satisfies the thermostat quickly, so run cycles are short and the coil does not stay cold long enough to remove moisture. The result is poor dehumidification and a clammy, humid space despite reaching setpoint. Proper equipment selection matches the calculated load rather than a rule-of-thumb square-foot number, which is exactly the design discipline tested on this exam.
6A 3-ton split air conditioner draws 3,000 watts while cooling at its rated capacity. What is its Energy Efficiency Ratio (EER)?
A.10.0
B.12.0
C.14.0
D.16.0
Explanation: EER = (cooling capacity in BTU/hr) ÷ (electrical input in watts). A 3-ton unit has 36,000 BTU/hr capacity, so EER = 36,000 ÷ 3,000 = 12.0. EER is a steady-state efficiency rating; compare it with SEER, which is a seasonal average. Both are used to verify that equipment meets the Florida Building Code, Energy Conservation minimums.
7A room has a sensible cooling load of 18,000 BTU/hr. The supply air is 55°F and room design is 75°F. What airflow (CFM) is required to deliver this sensible cooling?
A.833 CFM
B.1,000 CFM
C.750 CFM
D.625 CFM
Explanation: Rearrange Qs = 1.08 × CFM × ΔT to solve for CFM: CFM = 18,000 ÷ (1.08 × (75 − 55)) = 18,000 ÷ (1.08 × 20) = 18,000 ÷ 21.6 = 833 CFM. The temperature difference is the return minus the supply, and the 1.08 constant represents the heat-carrying capacity of standard air per degree per CFM.
8On a psychrometric chart, a condition has a dry-bulb temperature of 80°F and a wet-bulb temperature of 67°F. Which statement about this air state is correct?
A.The wet-bulb depression is 13°F
B.The wet-bulb depression is 27°F
C.The relative humidity is 100%
D.The dew point exceeds the dry-bulb temperature
Explanation: Wet-bulb depression is the difference between dry-bulb and wet-bulb temperatures: 80 − 67 = 13°F. A larger depression indicates drier air, while a zero depression means the air is saturated (100% relative humidity). Dew point can never exceed the dry-bulb temperature, and a 13°F depression clearly indicates the air is not saturated.
9When designing a low-pressure residential duct system, the Trane Ductulator is most commonly used with which design method?
A.Static regain method
B.Equal friction method
C.Velocity reduction method
D.Constant velocity method
Explanation: The Ductulator is built around the equal friction method, which holds a constant pressure drop per 100 feet of duct (commonly 0.08 in wc for low-pressure systems) and selects duct sizes accordingly. The user enters CFM, reads the friction rate, and the wheel shows the matching round diameter and rectangular equivalents. Static regain is used more often on larger, higher-velocity commercial systems.
10A ductulator is used at a friction rate of 0.08 in wc per 100 ft to size a supply run carrying 400 CFM. The ductulator indicates a 10-inch round duct. What is the approximate air velocity?
A.About 735 fpm
B.About 500 fpm
C.About 1,200 fpm
D.About 300 fpm
Explanation: The 10-inch round duct has a cross-sectional area of π × (5/12)² ≈ 0.545 ft², so velocity = 400 CFM ÷ 0.545 ft² ≈ 734 fpm. A 10-inch duct at 400 CFM and 0.08 friction is a typical residential supply sizing. Velocity in the 700–900 fpm range keeps noise and static reasonable for low-pressure supply runs.

About the FL Mechanical Exam

The Florida Certified Mechanical Contractor trade knowledge exam tests installation, maintenance, and design of central air-conditioning, refrigeration, heating, and ventilating systems, including ductwork, boilers and unfired pressure vessels, lift station equipment and piping, fuel gas and process piping, pneumatic and direct digital control wiring, and condensate drainage. It draws on the Florida Building Code (Mechanical, Fuel Gas, Energy Conservation), NFPA 90A/90B/96/99, SMACNA duct construction standards, the Trane Ductulator, refrigeration and air conditioning technology, the Pipefitter's Handbook, and OSHA 29 Part 1926. Candidates must navigate a broad reference set under a 7.5-hour open-book, computer-based format.

Questions

130 scored questions

Time Limit

7.5 hours

Passing Score

70%

Exam Fee

$135 registration + $40 trade exam administration (Florida DBPR Bureau of Education and Testing; administered by Professional Testing, Inc. and Pearson VUE)

FL Mechanical Exam Content Outline

9%

Pre-installation and Design Engineering

Load calculations, equipment selection, psychrometrics, duct design, system layout, and pre-installation planning for mechanical and HVACR systems.

9%

Ductwork and HVAC Materials

Duct sizing and construction (SMACNA metal, flexible, fibrous glass), supports, sealing, materials, and the Trane Ductulator equal-friction method.

12%

Installation of Refrigeration and HVAC Systems

Refrigerant piping, charging, evacuation, superheat/subcooling, TXV and metering devices, oil return, heat pump reversing valves, and system installation practices.

14%

Installation of Mechanical Systems

Boilers, unfired pressure vessels, hydronic and chilled-water piping, lift stations, pneumatic and DDC controls, condensate drains, medical gas piping, and pressure/process piping.

9%

Installation of Refrigeration and HVAC Equipment and Components

Condensers, evaporators, compressors, air handlers, condensate pumps, thermostats, combustion air, and venting for refrigeration and HVAC equipment.

14%

Installation of Mechanical Equipment and Components

Gas piping and shutoff valves, fuel gas appliances, LPG piping, pressure testing, venting categories, regulators, boilers, lift station pumps, and mechanical equipment installation.

9%

Maintenance Analysis of Refrigeration and HVAC Systems

Troubleshooting refrigeration and HVAC systems: short cycling, superheat and subcooling diagnosis, frosting coils, head pressure, pump-down, leak detection, and oil return.

5%

Maintenance Service of Refrigeration and HVAC Systems

Preventive maintenance and service procedures: filter replacement, belt tension, coil cleaning, refrigerant recovery, and motor amperage checks.

9%

Safety and Equipment

OSHA 29 Part 1926 construction safety: ladders, fall protection, lifting, lockout/tagout, PPE for refrigerants, confined spaces, scaffolds, hazard communication, and GFCI.

2%

Excavating

Trench and excavation safety: cave-in protection thresholds, soil types, sloping and benching, and competent-person requirements per OSHA 1926.652.

5%

Energy Management

Duct insulation R-values, SEER/EER, economizers, demand control ventilation, building envelope infiltration, and Florida Building Code Energy Conservation compliance.

3%

Indoor Air Quality

ASHRAE 62.1 ventilation rates, CO2 monitoring and demand control ventilation, MERV filtration ratings, and IAQ fundamentals.

How to Pass the FL Mechanical Exam

What You Need to Know

  • Passing score: 70%
  • Exam length: 130 questions
  • Time limit: 7.5 hours
  • Exam fee: $135 registration + $40 trade exam administration

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

FL Mechanical Study Tips from Top Performers

1Tab and highlight the 2023 Florida Building Code (Mechanical, Fuel Gas, Energy Conservation) and NFPA 90A/90B/96/99 chapters before exam day; reference navigation speed is decisive on an open-book test.
2Practice the core calculation formulas until automatic: sensible heat Qs = 1.08 x CFM x deltaT, total heat Qt = 4.5 x CFM x delta h, latent Ql = 0.68 x CFM x delta W, and ton = 12,000 BTU/hr.
3Use the Trane Ductulator for equal-friction duct sizing at 0.08 in wc/100 ft and confirm velocity stays within residential and commercial ranges.
4Master combustion air sizing from the FBC-Fuel Gas (IFGC 304): two-opening method at 1 sq in per 4,000 BTU/hr and one-opening at 1 sq in per 3,000 BTU/hr.
5Review OSHA 29 Part 1926 thresholds: 6 ft fall protection, 5 ft trench shoring, 4:1 ladder angle, 10 ft scaffold protection, and GFCI for 120V 15/20A receptacles.

Frequently Asked Questions

Are these the real CILB exam questions?

No. These are independently written study questions built from the official CILB Mechanical content outline. They are an English-language MCQ study aid and do not reproduce CILB's item bank or substitute for the official open-book examination.

What is the format of the exam?

130 scored multiple-choice questions, 7.5 hours, open-book, computer-based at Pearson VUE centers, administered through Professional Testing, Inc. Passing score 70%.

Is the exam open-book?

Yes. Candidates may bring only the approved references listed on the DBPR Construction Examinations Reference Lists (effective January 1, 2026).

What experience is required?

Generally 4 years of trade experience including at least 1 year as a foreman, or a qualifying combination of education and experience; confirm with DBPR.