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Exam Review

Key Facts: Taiwan Structural Engineering Technologist Examination Exam

6 papers

Constructed-response subjects, equally averaged.

Rules Articles 9–10 and Appendix 2

12 hours

Six two-hour sessions.

MOEX 2026 timetable

NTD 2,300

Standard paper-based senior-examination fee.

MOEX fee schedule

Review selected structural concepts in English, then practice complete written analyses using the code edition and instructions prescribed by official papers.

Sample Taiwan Structural Engineering Technologist Examination Practice Questions

Try these sample questions to review concepts for the Taiwan Structural Engineering Technologist Examination exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 99+ question experience with AI tutoring.

1A structural steel element is subjected to a triaxial stress state with principal stresses σ₁ = 120 MPa, σ₂ = 40 MPa, and σ₃ = -60 MPa. What is the absolute maximum shear stress (τ_max,abs) in the material?
A.90 MPa
B.40 MPa
C.50 MPa
D.80 MPa
Explanation: The absolute maximum shear stress across all planes is determined by the largest Mohr's circle formed by the extreme principal stresses: τ_max,abs = (σ₁ - σ₃) / 2. Substituting the given values yields [120 - (-60)] / 2 = 180 / 2 = 90 MPa.
2A 45-degree rectangular strain rosette mounted on a bridge girder surface measures normal strains ε₀° = 400 × 10⁻⁶, ε₄₅° = 200 × 10⁻⁶, and ε₉₀° = 100 × 10⁻⁶. What is the engineering shear strain γ_xy on the x-y axes?
A.-100 × 10⁻⁶ rad
B.+200 × 10⁻⁶ rad
C.-50 × 10⁻⁶ rad
D.+300 × 10⁻⁶ rad
Explanation: For a 45-degree rosette, the strain transformation formula yields ε₄₅° = (ε₀° + ε₉₀°)/2 + γ_xy/2. Rearranging gives γ_xy = 2ε₄₅° - ε₀° - ε₉₀° = 2(200 × 10⁻⁶) - 400 × 10⁻⁶ - 100 × 10⁻⁶ = -100 × 10⁻⁶ rad.
3A rectangular beam section has width b and depth h and principal centroidal axes y and z. Take normal stress as sigma = (Mz/Iz)*y - (My/Iy)*z. Define tan(theta) = Mz/My and neutral-axis angle tan(alpha) = z/y. For arbitrary bending direction with nonzero My, which general relation follows?
A.tan(α) = (I_z / I_y) tan(θ)
B.tan(α) = (I_y / I_z) tan(θ)
C.tan(α) = tan(θ)
D.tan(α) = (b / h) tan(θ)
Explanation: Set sigma = 0: (Mz/Iz)*y = (My/Iy)*z. Rearranging gives z/y = (Mz/My)*(Iy/Iz), so tan(alpha) = (Iy/Iz)*tan(theta). Explicit angle definitions avoid confusing the loading plane with the moment-vector direction.
4For a thin-walled channel section with flange width b, web height h (between flange centerlines), and uniform wall thickness t, what is the horizontal distance e from the web centerline to the shear center?
A.e = 3b² / (6b + h)
B.e = b / 2
C.e = b² / (2b + h)
D.e = 3b² / (2b + 3h)
Explanation: Integrating the shear flow along both flanges produces flange shear forces V_f = V · b² · h · t / (4 I_x). Taking moments about the web centerline yields V · e = 2 · V_f · (h/2). Substituting I_x = (t · h² / 12)(6b + h) produces e = 3b² / (6b + h).
5A thick-walled hydraulic cylinder has inner radius r_i = 100 mm and outer radius r_o = 200 mm. It is subjected to an internal fluid pressure p_i = 60 MPa with zero external pressure. According to Lamé's equations, what is the maximum hoop (tangential) tensile stress in the cylinder wall?
A.100 MPa
B.60 MPa
C.80 MPa
D.120 MPa
Explanation: Lamé's equation gives the tangential stress as σ_θ(r) = [p_i · r_i² / (r_o² - r_i²)] · [1 + r_o² / r²]. The peak stress occurs at the innermost surface r = r_i: σ_θ,max = p_i · (r_o² + r_i²) / (r_o² - r_i²) = 60 · (200² + 100²) / (200² - 100²) = 60 · (50,000 / 30,000) = 100 MPa.
6A cantilever beam of length L and uniform flexural rigidity EI carries a concentrated tip load P. Using Castigliano's second theorem, what is the tip deflection?
A.P L³ / (3 E I)
B.P L³ / (2 E I)
C.P L⁴ / (8 E I)
D.5 P L³ / (48 E I)
Explanation: The bending moment at distance x from the tip is M(x) = P x. The strain energy is U = ∫ (M² / 2EI) dx = (P² / 2EI) ∫₀ᴸ x² dx = P² L³ / (6EI). Applying Castigliano's second theorem, the deflection under load P is δ = ∂U / ∂P = P L³ / (3EI).
7A structural column of length L with uniform flexural rigidity EI is rigidly fixed at the base and pinned at the top. What is the theoretical Euler elastic buckling load P_cr?
A.2.046 π² E I / L²
B.π² E I / L²
C.4 π² E I / L²
D.0.25 π² E I / L²
Explanation: For a fixed-pinned column, solving the governing differential equation y'''' + k² y'' = 0 with boundary conditions y(0)=0, y'(0)=0, y(L)=0, y''(L)=0 leads to tan(kL) = kL, whose smallest non-zero root is kL ≈ 4.4934. Thus P_cr = (4.4934 / L)² EI ≈ 20.19 EI / L² ≈ 2.046 π² EI / L² (corresponding to effective length factor K ≈ 0.699 ≈ 0.7).
8In the inelastic buckling of intermediate steel columns, Shanley's inelastic column theory resolved the historical paradox between Engesser's tangent modulus theory and the reduced modulus theory by demonstrating that:
A.Bifurcation buckling occurs at the tangent modulus load with increasing axial force, without strain reversal
B.Bifurcation buckling can only occur at the higher reduced modulus load with immediate strain reversal
C.Buckling in the inelastic range is governed strictly by the elastic initial Young's modulus E
D.Inelastic buckling occurs at the average of the tangent modulus load and reduced modulus load
Explanation: Shanley (1947) showed that column deflection initiates at the tangent modulus load P_t = π² E_t I / L² simultaneously with an increase in total axial load, allowing bending without unloading the convex side (no strain reversal). The tangent modulus load is therefore the actual lower bound for inelastic bifurcation.
9According to the Winkler-Bach theory for curved beams subjected to pure bending M, how does the location of the neutral axis compare to the centroidal axis?
A.The neutral axis shifts toward the center of curvature relative to the centroidal axis
B.The neutral axis shifts away from the center of curvature relative to the centroidal axis
C.The neutral axis coincides exactly with the centroidal axis regardless of curvature
D.The neutral axis position depends strictly on Poisson's ratio and not radius of curvature
Explanation: Because fibers closer to the center of curvature have shorter initial lengths, a given rotation produces larger circumferential strains. Equilibrium of axial forces requires the neutral axis to shift inward toward the center of curvature by an eccentricity e = R - R_n, resulting in hyperbolic stress distribution.
10A thin-walled hollow tube with a closed single-cell cross section of enclosed area A_m = 50,000 mm² and uniform wall thickness t = 5 mm is subjected to a pure twisting torque T = 25 kN·m. What is the shear stress τ in the tube wall according to the Bredt-Batho formula?
A.50 MPa
B.100 MPa
C.25 MPa
D.250 MPa
Explanation: By Bredt-Batho theory for closed thin-walled tubes, shear flow is uniform: q = T / (2 A_m). The shear stress is τ = q / t = T / (2 A_m · t). Substituting the parameters: τ = (25 × 10⁶ N·mm) / (2 · 50,000 mm² · 5 mm) = 25,000,000 / 500,000 = 50 MPa.

About the Taiwan Structural Engineering Technologist Examination Exam

Independent English-language MCQ study adaptation for 結構工程技師. Ordinary official papers are Chinese constructed-response examinations requiring full calculations, derivations, and design reasoning. These questions are not an official translation, format simulation, or substitute for written solutions. Article 12's reciprocal foreign-license route has separate assessment and language provisions.

Exam sponsor: Ministry of Examination (考選部 / MOEX). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

2026 day 1: 鋼筋混凝土設計與預力混凝土設計, 結構動力分析與耐震設計, 鋼結構設計. Day 2: 結構學, 土壤力學與基礎設計, 材料力學. Designs and applied cases are written responses. The ordinary exam has no separate mandatory assignment, oral, interview, or hands-on practical stage.

Time Limit

12 testing hours: six 2-hour papers on November 14–15, 2026.

Passing Score

Article 10: mean at least 60 and no zero; if fewer than 16% qualify, the top-16% mechanism requires mean at least 50 and no zero, with cutoff ties included.

Exam / Certification Fees

NTD 2,300 standard registration fee.

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

16 study questions; 1/6 subject weight

Mechanics of Materials (材料力學)

Stress, deformation, energy, stability, and section behavior.

17 study questions; 1/6 subject weight

Theory of Structures (結構學)

Indeterminate analysis, stiffness methods, influence lines, and plastic mechanisms.

17 study questions; 1/6 subject weight

Concrete Design (鋼筋混凝土設計與預力混凝土設計)

Strength, shear, columns, detailing, anchorage, and prestress.

17 study questions; 1/6 subject weight

Steel Design (鋼結構設計)

Member stability, flexure, connections, and seismic systems.

16 study questions; 1/6 subject weight

Soil and Foundation Design (土壤力學與基礎設計)

Soil strength, settlement, earth pressure, footings, and piles.

16 study questions; 1/6 subject weight

Structural Dynamics and Seismic Design (結構動力分析與耐震設計)

Vibration, modes, spectra, and Taiwan building seismic provisions.

Preparing for the Taiwan Structural Engineering Technologist Examination Exam

What You Need to Know

  • Passing score: Article 10: mean at least 60 and no zero; if fewer than 16% qualify, the top-16% mechanism requires mean at least 50 and no zero, with cutoff ties included.
  • Assessment: 2026 day 1: 鋼筋混凝土設計與預力混凝土設計, 結構動力分析與耐震設計, 鋼結構設計. Day 2: 結構學, 土壤力學與基礎設計, 材料力學. Designs and applied cases are written responses. The ordinary exam has no separate mandatory assignment, oral, interview, or hands-on practical stage.
  • Time limit: 12 testing hours: six 2-hour papers on November 14–15, 2026.
  • Exam / certification fees: NTD 2,300 standard registration fee. Official sources

Using Our Practice Resources

  • Work through all 99 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Taiwan Structural Engineering Technologist Examination: Suggested Study Strategy

1Derive results using explicit axes, signs, units, and support conditions.
2Distinguish current Taiwan provisions from older rules and foreign specifications.
3Practice full written concrete, steel, and foundation designs.
4Use official papers for extended seismic and structural calculations.

Frequently Asked Questions

Who can apply?

Appendix 1 includes recognized junior-college-or-higher civil/structural graduates and eligible graduates with seven listed subjects and 20 credits, including specified core subjects. Other statutory routes exist; MOEX assesses credentials.

Is the pass rate fixed at 16%?

No. The top-16% mechanism supplements the 60-average rule when fewer qualify, subject to a 50 minimum and no zero. It is not a published pass-rate statistic or upper quota.

Which code edition should I use?

Follow the edition and assumptions specified by the official paper. This bank identifies current Taiwan provisions where a question tests a local rule; it does not claim equivalence to any official paper.

Does this resource reproduce the official format?

No. It is independent English MCQ study practice, not an official translation, format simulation, or substitute for extended written design work. Examination certification also does not complete every professional practice-license requirement.