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100+ Free RRB JE CBT 2 Electrical Practice Questions

Pass your RRB Junior Engineer CBT 2 — Electrical & Allied Engineering exam on the first try — instant access, no signup required.

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2026 Statistics

Key Facts: RRB JE CBT 2 Electrical Exam

150

Total Questions

RRB Notification

120 min

Exam Duration

RRB Notification

1/3

Negative Marking

RRB Rules

40%

UR Min Passing

RRB Rules

₹500

General Application Fee

RRB Notification

~3%

Expected Pass Rate

Historical Cutoffs

The RRB JE CBT 2 Electrical & Allied Engineering exam has a 120-minute limit and comprises 150 MCQs. Candidates face a penalty of 1/3rd mark for every wrong answer. While the minimum qualifying mark is 40% for General candidates, the high level of competition requires scores above 75-80% to secure a place on the merit list. The application fee is ₹500 (₹400 refunded after appearing in CBT 1) and registration is conducted via official regional RRB websites.

Sample RRB JE CBT 2 Electrical Practice Questions

Try these sample questions to test your RRB JE CBT 2 Electrical exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A wire of resistance R is stretched such that its length is doubled while maintaining a constant volume. What is the new resistance of the wire?
A.R / 2
B.R
C.2R
D.4R
Explanation: Resistance is given by R = ρL/A. When the length is doubled to 2L, since the volume (V = A * L) remains constant, the cross-sectional area must be halved (A/2). Therefore, the new resistance is R' = ρ(2L)/(A/2) = 4(ρL/A) = 4R.
2Which of the following materials has a negative temperature coefficient of resistance?
A.Copper
B.Silicon
C.Aluminium
D.Nichrome
Explanation: Silicon is a semiconductor. Semiconductors and insulators have a negative temperature coefficient of resistance, meaning their resistance decreases as temperature increases because more charge carriers (electrons and holes) are freed. Metals like copper, aluminium, and alloys like nichrome have a positive temperature coefficient.
3A capacitor of 10 μF is charged to a potential difference of 100 V. What is the electrostatic energy stored in the capacitor?
A.0.05 J
B.0.10 J
C.0.50 J
D.1.00 J
Explanation: The electrostatic energy stored in a capacitor is given by E = 0.5 * C * V^2. Substituting the given values: E = 0.5 * (10 * 10^-6 F) * (100 V)^2 = 0.5 * 10^-5 * 10000 = 0.05 Joules.
4How does the self-inductance of a coil change if the number of turns is doubled, assuming the length and cross-sectional area remain constant?
A.It is halved
B.It remains unchanged
C.It is doubled
D.It increases fourfold
Explanation: Self-inductance (L) of a coil is proportional to the square of the number of turns (N^2), given by the formula L = (μ * N^2 * A) / l. If the number of turns N is doubled, the self-inductance becomes L' = (2N)^2 = 4N^2, which is four times the original value.
5What is the SI unit of electrical conductivity?
A.Ohm-meter
B.Siemens
C.Siemens per meter
D.Henry per meter
Explanation: Electrical conductivity (σ) is the reciprocal of electrical resistivity (ρ). Resistivity has units of ohm-meters (Ω·m). Therefore, conductivity has the unit of (Ω·m)^-1, which is Siemens per meter (S/m).
6Three resistances of 3 Ω, 6 Ω, and 9 Ω are connected in parallel. What is the equivalent resistance of the parallel combination?
A.1.64 Ω
B.3.00 Ω
C.6.00 Ω
D.18.00 Ω
Explanation: For parallel resistors, 1/Req = 1/R1 + 1/R2 + 1/R3. Here, 1/Req = 1/3 + 1/6 + 1/9 = 6/18 + 3/18 + 2/18 = 11/18. Therefore, Req = 18 / 11 ≈ 1.636 Ω, which rounds to 1.64 Ω.
7Under what condition is an electrical source considered to be an ideal voltage source?
A.When its internal resistance is zero
B.When its internal resistance is infinite
C.When its terminal voltage is proportional to the load current
D.When it has a very high efficiency of around 50%
Explanation: An ideal voltage source maintains a constant terminal voltage regardless of the current drawn from it. This requires its internal resistance to be zero, so that there is no internal voltage drop (I * R_int = 0) under any load condition.
8A practical current source is represented by an ideal current source in:
A.Series with an internal resistance
B.Parallel with an internal resistance
C.Series with an internal capacitance
D.Parallel with an internal inductance
Explanation: A practical current source delivers a current that decreases slightly as the terminal voltage increases. It is modeled as an ideal current source in parallel with an internal resistance (Norton equivalent), which represents the leakage path.
9Which of the following parameters of a conductor does not change when the temperature rises?
A.Resistivity
B.Resistance
C.Number density of free electrons
D.Mean free path of electrons
Explanation: For a metal conductor, the number density of free electrons (number of free electrons per unit volume) is essentially independent of temperature, as it is determined by the atomic structure. The resistivity and resistance increase, and the mean free path decreases due to increased lattice vibrations.
10A heating element is rated at 230 V, 1000 W. If it is operated at 115 V, what will be the power consumed by the element?
A.250 W
B.500 W
C.1000 W
D.2000 W
Explanation: Power is given by P = V^2 / R, which implies resistance R = V^2 / P. For the rated values, R = 230^2 / 1000 = 52.9 Ω. When operated at 115 V (which is half of 230 V), the power consumed is P' = V'^2 / R = 115^2 / 52.9 = 250 W. Thus, halving the voltage reduces the power to one-fourth.

About the RRB JE CBT 2 Electrical Exam

Decisive second stage of the RRB Junior Engineer recruitment exam for Electrical Engineering. Tests core technical competence and general engineering subjects.

Questions

150 scored questions

Time Limit

2 hours (120 minutes)

Passing Score

40% (UR/EWS) / 30% (OBC/SC) / 25% (ST)

Exam Fee

₹500 (Railway Recruitment Board (RRB))

RRB JE CBT 2 Electrical Exam Content Outline

67%

Technical Ability (Electrical Engineering)

Circuit theory, machines, power systems, measurements, estimation, utilization, and electronics

10%

General Awareness

History, geography, polity, economy, and current affairs of India

10%

Physics & Chemistry

CBSE 10th standard syllabus covering fundamental chemistry and physics concepts

7%

Basics of Computers & Applications

Architecture, operating systems, networking, web browsers, MS Office, and computer security

6%

Basics of Environment & Pollution Control

Ecosystems, air/water/noise pollution control, waste management, and global warming

How to Pass the RRB JE CBT 2 Electrical Exam

What You Need to Know

  • Passing score: 40% (UR/EWS) / 30% (OBC/SC) / 25% (ST)
  • Exam length: 150 questions
  • Time limit: 2 hours (120 minutes)
  • Exam fee: ₹500

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

RRB JE CBT 2 Electrical Study Tips from Top Performers

1Dedicate at least 70% of your prep time to the technical section, concentrating heavily on Electrical Machines and Power Systems.
2Practice numerical problems daily, especially on AC circuits (RLC series/parallel resonance) and DC network theorems.
3Do not ignore the non-technical sections (50 marks); scoring well in computers and environmental basics can boost your overall rank.
4Solve previous years' papers of RRB JE to understand the exact depth and type of questions asked.
5Work on speed and accuracy. In the exam, you have only 48 seconds per question on average, and negative marking is 1/3rd.

Frequently Asked Questions

What is the exam pattern for RRB JE CBT 2 Electrical?

RRB JE CBT 2 is a computer-based test containing 150 multiple-choice questions with a time limit of 120 minutes. It is divided into 100 questions of Technical Ability (Electrical & Allied Engineering) and 50 questions of non-technical subjects: General Awareness (15), Physics & Chemistry (15), Computers (10), and Environment & Pollution Control (10).

Is there negative marking in RRB JE CBT 2?

Yes, there is negative marking in RRB JE CBT 2. For every incorrect answer, 1/3rd (0.33) of the marks assigned to that question will be deducted. No marks are deducted for unattempted questions, so accuracy is highly important.

What is the qualification fee refund policy for RRB JE?

For General and OBC candidates, the application fee is ₹500, out of which ₹400 is refunded to the candidate's bank account after they appear for the CBT 1 exam. For reserved categories (SC, ST, Female, Minorities, EWS, PwBD), the fee is ₹250, which is fully refunded after appearing in CBT 1, minus bank transaction charges.

What are the minimum qualifying marks for RRB JE CBT 2?

The minimum qualifying marks in CBT 2 are: Unreserved (UR) / EWS - 40%, OBC (NCL) - 30%, SC - 30%, and ST - 25%. However, achieving these minimum marks only qualifies you for consideration; actual cutoff scores for selection are much higher, usually above 75-80% depending on the zone.

Can final year engineering students apply for RRB JE?

No. Candidates must possess the prescribed educational qualification (Diploma or Degree) on or before the closing date of the online registration. Those awaiting final results of the prescribed educational qualification are not eligible to apply.