100+ Free PGCIL Field Engineer & DT Practice Questions

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2026 Statistics

Key Facts: PGCIL Field Engineer & DT Exam

170 MCQs

Total questions in the Diploma Trainee CBT exam

Official PGCIL DT Notification

75 MCQs

Total questions in the Field Engineer CBT exam

Official PGCIL FE Notification

120 mins

Exam duration for the Diploma Trainee CBT

Official PGCIL DT Notification

60 mins

Exam duration for the Field Engineer CBT

Official PGCIL FE Notification

0.25

Negative marks per wrong answer in DT exam (FE has no negative marking)

Official PGCIL Marking Scheme

PGCIL CBT evaluates Technical Knowledge and Aptitude. Field Engineer has 75 MCQs (no negative marking) in 1 hour. Diploma Trainee has 170 MCQs with negative marking (-0.25) in 2 hours. Application fee is ₹400 for FE, ₹300 for DT.

Sample PGCIL Field Engineer & DT Practice Questions

Try these sample questions to test your PGCIL Field Engineer & DT exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Find the Thevenin's equivalent resistance (Rth) across terminals A and B of a linear circuit if the open-circuit voltage across A-B is 12 V and the short-circuit current through A-B is 3 A.

A.4 ohms

B.36 ohms

C.0.25 ohms

D.9 ohms

Explanation: According to Thevenin's theorem, the equivalent resistance Rth is the ratio of the open-circuit voltage (Vth) to the short-circuit current (Isc). Therefore, Rth = Vth / Isc = 12 V / 3 A = 4 ohms.

2A series RL circuit has R = 10 ohms and L = 2 H. If a DC voltage of 100 V is suddenly applied at t = 0, what is the current in the circuit at t = 0.2 seconds?

A.6.32 A

B.3.68 A

C.10.00 A

D.5.00 A

Explanation: The time constant of a series RL circuit is tau = L / R = 2 / 10 = 0.2 seconds. The transient current equation is i(t) = (V/R) * (1 - e^(-t/tau)). At t = 0.2 seconds, t = tau, so i(0.2) = (100/10) * (1 - e^-1) = 10 * (1 - 0.368) = 10 * 0.632 = 6.32 A.

3What is the quality factor (Q-factor) of a series RLC circuit with R = 5 ohms, L = 20 mH, and C = 2 microfarads?

A.20

B.10

C.50

D.5

Explanation: The quality factor of a series RLC circuit is Q = (1/R) * sqrt(L/C). Substituting the given values, Q = (1/5) * sqrt((20 * 10^-3) / (2 * 10^-6)) = 0.2 * sqrt(10000) = 0.2 * 100 = 20.

4For maximum power transfer from a source to a load in a DC circuit, what should be the relation between load resistance (RL) and source internal resistance (Rs)?

A.RL = Rs

B.RL = 2 * Rs

C.RL = 0.5 * Rs

D.RL = Rs / 4

Explanation: According to the Maximum Power Transfer Theorem, the power transferred from a source to a load is maximum when the load resistance equals the internal resistance of the source (RL = Rs). Under this condition, the efficiency of power transfer is 50%.

5If the Z-parameters of a two-port network are Z11 = 4 ohms, Z12 = Z21 = 2 ohms, and Z22 = 3 ohms, calculate the Y-parameter Y11.

A.0.375 S

B.0.250 S

C.0.500 S

D.0.125 S

Explanation: The relationship between Y-parameters and Z-parameters is determined by matrix inversion: Y11 = Z22 / Delta Z, where Delta Z = Z11*Z22 - Z12*Z21. Here, Delta Z = (4 * 3) - (2 * 2) = 12 - 4 = 8. Thus, Y11 = Z22 / Delta Z = 3 / 8 = 0.375 S.

6A 10 kVA, 2200/220 V transformer has a full-load copper loss of 300 W and iron loss of 200 W. At what percentage of full load will the transformer achieve maximum efficiency?

A.81.6%

B.66.7%

C.50.0%

D.91.2%

Explanation: Maximum efficiency in a transformer occurs when iron loss (constant loss, Pi) equals copper loss (variable loss, Pcu). The fraction of load for maximum efficiency is x = sqrt(Pi / Pcu) = sqrt(200 / 300) = sqrt(2/3) approx 0.816 or 81.6%.

7A 3-phase, 4-pole, 50 Hz induction motor runs at a speed of 1440 rpm. What is the frequency of the rotor current?

A.2.0 Hz

B.50.0 Hz

C.1.5 Hz

D.3.0 Hz

Explanation: First, find synchronous speed: Ns = 120 * f / P = 120 * 50 / 4 = 1500 rpm. The slip s = (Ns - Nr) / Ns = (1500 - 1440) / 1500 = 60 / 1500 = 0.04. The frequency of the rotor current is fr = s * f = 0.04 * 50 = 2.0 Hz.

8In speed control of a DC shunt motor, which method is preferred for obtaining speeds below the base speed?

A.Armature resistance control

B.Field flux control

C.Voltage source frequency control

D.Tapped field control

Explanation: Armature resistance control works by adding external resistance in series with the armature, which reduces the voltage across the armature and drops the speed below the base speed. Field flux control is used for speeds above the base speed by weakening the field flux.

9What does a V-curve of a synchronous motor represent?

A.Armature current versus field current

B.Power factor versus field current

C.Torque versus armature current

D.Speed versus field current

Explanation: The V-curves of a synchronous motor show the relationship between the armature current (Ia) on the y-axis and the field excitation current (If) on the x-axis. The curve is V-shaped, with the minimum armature current corresponding to unity power factor.

10Which losses are primarily determined by conducting the short-circuit test on a transformer?

A.Copper losses at full load

B.Core/Iron losses at rated voltage

C.Friction and windage losses

D.Dielectric insulation losses

Explanation: The short-circuit test on a transformer is performed at rated current by applying a small fraction of rated voltage. Under this condition, core loss is negligible, and the wattmeter reading directly gives the full-load copper loss.

About the PGCIL Field Engineer & DT Exam

The PGCIL recruitment for Field Engineer (on contract) and Diploma Trainee (permanent) is a premier entry point for engineering graduates and diploma holders into the Power Grid Corporation of India. The selection process revolves around a Computer-Based Test (CBT) assessing both Technical Knowledge (core engineering subjects) and General Aptitude. Field Engineer candidates undergo an interview, while Diploma Trainee candidates are selected purely on CBT merit. This practice bank provides 100 high-quality practice questions covering Electrical Engineering, Civil Engineering, and General Aptitude to help candidates master both core technical and aptitude domains.

Questions

100 scored questions

Time Limit

1 hour (Field Engineer) / 2 hours (Diploma Trainee)

Passing Score

Minimum 40% aggregate marks for UR/EWS and 30% for reserved categories (SC/ST/OBC-NCL/PwBD) in the written test.

Exam Fee

₹400 for Field Engineer, ₹300 for Diploma Trainee (General/OBC candidates). SC/ST/PwBD/Ex-SM candidates are exempted. (Power Grid Corporation of India Limited (POWERGRID))

PGCIL Field Engineer & DT Exam Content Outline

40%

Electrical Engineering

Covers Circuit Theory, Power Systems, Electrical Machines, Control Systems, Measurements & Instrumentation, and Electronics.

30%

Civil Engineering

Covers Strength of Materials, Structural Analysis, RCC & Steel Structures, Soil Mechanics, Surveying, and Fluid Mechanics.

30%

General Aptitude

Covers Quantitative Aptitude, Logical Reasoning, Verbal Comprehension, Data Interpretation, and Data Sufficiency.

How to Pass the PGCIL Field Engineer & DT Exam

What You Need to Know

Passing score: Minimum 40% aggregate marks for UR/EWS and 30% for reserved categories (SC/ST/OBC-NCL/PwBD) in the written test.
Exam length: 100 questions
Time limit: 1 hour (Field Engineer) / 2 hours (Diploma Trainee)
Exam fee: ₹400 for Field Engineer, ₹300 for Diploma Trainee (General/OBC candidates). SC/ST/PwBD/Ex-SM candidates are exempted.

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

PGCIL Field Engineer & DT Study Tips from Top Performers

1Focus on core diploma/degree subjects: Network Theory, Machines, and Power Systems for Electrical; Structures, Soil Mechanics, and Surveying for Civil.

2Practice aptitude questions (quantitative, reasoning, verbal) daily, as they make up a significant portion of the paper (25 questions for FE, 50 questions for DT).

3For Diploma Trainee, practice accuracy along with speed, as there is a negative marking of 0.25 for incorrect answers.

4Use previous years' PGCIL questions to understand the difficulty level and typical question distribution.

5Take timed full-length mock tests to practice managing 170 questions in 120 minutes (for DT) or 75 questions in 60 minutes (for FE).

Frequently Asked Questions

What is the PGCIL Field Engineer & Diploma Trainee exam?

It is a competitive Computer-Based Test (CBT) conducted by Power Grid Corporation of India Limited to recruit Field Engineers (on contract) and Diploma Trainees (permanent) in Electrical, Civil, and other engineering disciplines.

What is the difference in exam pattern between Field Engineer and Diploma Trainee?

The Field Engineer exam consists of 75 MCQs (50 Technical + 25 Aptitude) to be solved in 1 hour with no negative marking. The Diploma Trainee exam has 170 MCQs (120 Technical + 50 Aptitude) to be solved in 2 hours with 0.25 negative marking for wrong answers.

What is the selection process for these posts?

For Field Engineer, the selection is based on the CBT score (85% weightage) followed by a personal interview (15% weightage). For Diploma Trainee, selection is based solely on the merit in the CBT (100% weightage), followed by document verification and medical examination.

What are the application fees for PGCIL recruitment?

The application fee is ₹400 for Field Engineer and ₹300 for Diploma Trainee. SC/ST/PwBD/Ex-SM/Departmental candidates are exempted from paying the fee.

What are the minimum qualifying marks in the CBT?

Candidates in the General/EWS category must score a minimum of 40% aggregate marks in the CBT. Reserved category (SC/ST/OBC-NCL/PwBD) candidates must score a minimum of 30% aggregate marks.

100+ Free PGCIL Field Engineer & DT Practice Questions

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