100+ Free MHT-CET Practice Questions

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The MHT-CET PCM exam allots 2 marks per Math question and 1 mark per Physics or Chemistry question. If there are 50 Math, 50 Physics, and 50 Chemistry questions, the total marks possible is:

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Practice Questions100 questions

2026 Statistics

Key Facts: MHT-CET Exam

150 MCQs / 200 marks

PCM paper structure (Phy 50 + Chem 50 + Math 50 with double weight)

MHT-CET 2026 Information Brochure

INR 1300 / INR 1000

Application fee (General / Reserved categories)

cetcell.mahacet.org

180 minutes

Total exam time (90 min Math + 90 min Physics/Chemistry)

CET Cell Maharashtra

80 / 20

Class 12 to Class 11 syllabus weightage (Maharashtra State Board)

MHT-CET 2026 Syllabus PDF

100

Free practice questions here

OpenExamPrep

MHT-CET PCM is a 180-minute computer-based test with 150 MCQs (50 each of Physics, Chemistry, Math) for 200 marks. Math is double-weighted at +2 per question; Physics/Chemistry are +1 each. NO negative marking. Fee is INR 1300 General / INR 1000 Reserved. Syllabus is 80% Class 12, 20% Class 11 Maharashtra State Board.

Sample MHT-CET Practice Questions

Try these sample questions to test your MHT-CET exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A particle moves in a straight line with velocity v = 4t² − 6t + 2 m/s. What is its acceleration at t = 2 s?

A.8 m/s²

B.10 m/s²

C.12 m/s²

D.14 m/s²

Explanation: Acceleration a = dv/dt = 8t − 6. At t = 2 s, a = 8(2) − 6 = 10 m/s². Differentiation of the velocity-time function gives instantaneous acceleration.

2A body of mass 2 kg is acted upon by a force of 10 N for 5 seconds. What is the change in momentum?

A.20 kg·m/s

B.50 kg·m/s

C.25 kg·m/s

D.10 kg·m/s

Explanation: Impulse equals change in momentum: Δp = F × t = 10 × 5 = 50 kg·m/s. Mass is not needed because impulse directly gives momentum change.

3Two resistors of 6 Ω and 3 Ω are connected in parallel. What is the equivalent resistance?

A.9 Ω

B.2 Ω

C.4.5 Ω

D.1.5 Ω

Explanation: For parallel resistors: 1/R = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, so R = 2 Ω. Parallel resistance is always less than the smallest individual resistance.

4Which of the following has the highest first ionization enthalpy?

A.Li

B.Na

C.K

D.Cs

Explanation: First ionization enthalpy decreases down Group 1 because atomic size increases and the outermost electron experiences weaker effective nuclear attraction. Li, being the smallest, has the highest IE among alkali metals.

5If sin θ = 3/5 and θ is acute, what is the value of cos 2θ?

A.7/25

B.−7/25

C.24/25

D.16/25

Explanation: Using the identity cos 2θ = 1 − 2sin²θ = 1 − 2(9/25) = 1 − 18/25 = 7/25. The double-angle formula directly gives the answer when sin θ is known.

6A projectile is launched at 45° with initial speed 20 m/s. What is its maximum height? (g = 10 m/s²)

A.5 m

B.10 m

C.15 m

D.20 m

Explanation: Maximum height H = u²sin²θ/(2g) = (20)²(sin 45°)²/(2 × 10) = 400 × (1/2)/20 = 10 m. The vertical component of velocity determines maximum height.

7A solid sphere rolls without slipping down an incline. What fraction of its total kinetic energy is rotational?

A.1/2

B.1/3

C.2/7

D.1/5

Explanation: For a solid sphere, I = (2/5)MR². Translational KE = (1/2)Mv², rotational KE = (1/2)(2/5)MR²(v/R)² = (1/5)Mv². Total = (7/10)Mv². Rotational fraction = (1/5)/(7/10) = 2/7.

8What is the equivalent capacitance when three capacitors of 2 μF, 3 μF, and 6 μF are connected in series?

A.1 μF

B.11 μF

C.0.5 μF

D.3.6 μF

Explanation: For series capacitors: 1/C = 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1. So C = 1 μF. Series capacitance is always less than the smallest individual capacitor.

9The de Broglie wavelength of an electron accelerated through a potential difference of 100 V is approximately:

A.0.123 nm

B.1.23 nm

C.12.3 nm

D.0.0123 nm

Explanation: Using λ = h/√(2meV) or the simplified formula λ = 1.227/√V nm (when V is in volts), λ = 1.227/√100 = 1.227/10 ≈ 0.123 nm. This is the basis for electron diffraction.

10An ideal gas undergoes isothermal expansion from volume V to 2V at temperature T. What is the work done by the gas? (n moles)

A.nRT ln 2

B.nRT

C.2nRT

D.nRT/2

Explanation: For isothermal expansion of an ideal gas, W = nRT ln(V₂/V₁) = nRT ln(2V/V) = nRT ln 2. Since T is constant, ΔU = 0 and Q = W.

About the MHT-CET Exam

MHT-CET (Maharashtra Health and Technical Common Entrance Test) is the state-level entrance exam conducted by the CET Cell of the Government of Maharashtra. It is the primary admission gateway to Maharashtra's engineering, pharmacy, and agriculture undergraduate programmes including top colleges like College of Engineering Pune (COEP), Veermata Jijabai Technological Institute (VJTI), and Institute of Chemical Technology (ICT). The exam has two paper variants — PCM for Engineering (Physics + Chemistry + Mathematics) and PCB for Pharmacy/Agriculture (Physics + Chemistry + Biology). The PCM paper consists of 150 MCQs (50 each of Physics, Chemistry, Mathematics) for a total of 200 marks; Mathematics carries double weight (2 marks per question) versus Physics/Chemistry (1 mark each). The syllabus is drawn 80% from Class 12 and 20% from Class 11 of the Maharashtra State Board, with strict 1:1 mapping to NCERT-aligned chapters. The CBT runs in two sessions: Paper-1 (Mathematics) for 90 minutes, then Paper-2 (Physics + Chemistry combined) for 90 minutes. There is NO negative marking, encouraging full attempts.

Questions

100 scored questions

Time Limit

180 minutes (Math 90 min + Physics/Chemistry 90 min)

Passing Score

No fixed pass; CAP counselling cutoffs (95+ percentile for COEP, VJTI, ICT)

Exam Fee

INR 1300 (General); INR 1000 (Reserved) (State Common Entrance Test Cell, Government of Maharashtra)

MHT-CET Exam Content Outline

25%

Physics (50 MCQs × 1 mark)

Class 12 (80%): rotational motion, oscillations, gravitation, mechanical properties, thermodynamics, kinetic theory, wave-optics, ray-optics, electrostatics, current electricity, magnetism, EMI, AC, EM waves, dual nature, atoms/nuclei, semiconductors. Class 11 (20%): kinematics, laws of motion, work-energy-power, properties of matter.

25%

Chemistry (50 MCQs × 1 mark)

Class 12 (80%): solid state, solutions, electrochemistry, chemical kinetics, surface chemistry, p/d/f-block, coordination compounds, haloalkanes and haloarenes, alcohols/phenols/ethers, aldehydes/ketones/acids, amines, biomolecules, polymers, chemistry in everyday life. Class 11 (20%): basic concepts of chemistry, atomic structure, periodicity, chemical bonding, redox, hydrogen, s-block, p-block (groups 13-14), hydrocarbons.

50%

Mathematics (50 MCQs × 2 marks)

Class 12 (80%): mathematical logic, matrices, trigonometric functions, pair of straight lines, vectors, line/plane, LPP, continuity, differentiation, applications of derivatives, integration, definite integrals, application of integrals, differential equations, probability distributions, statistics. Class 11 (20%): trigonometry, sets/relations/functions, complex numbers, sequences and series, permutations and combinations, conic sections.

How to Pass the MHT-CET Exam

What You Need to Know

Passing score: No fixed pass; CAP counselling cutoffs (95+ percentile for COEP, VJTI, ICT)
Exam length: 100 questions
Time limit: 180 minutes (Math 90 min + Physics/Chemistry 90 min)
Exam fee: INR 1300 (General); INR 1000 (Reserved)

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

MHT-CET Study Tips from Top Performers

1Master the Maharashtra State Bureau Class 12 textbook (Balbharati) cover-to-cover — 80% of questions come directly from this textbook's worked examples and end-of-chapter problems

2Practice Mathematics intensively — 50 Math questions × 2 marks = 100 marks (50% of total). A strong Math score alone can push you above 95 percentile

3Use the absence of negative marking strategically — attempt every single question, even when unsure. There is zero penalty for wrong answers

4Take at least 15-20 full-length CBT mock tests in the 6 weeks before the exam — the Maharashtra CET Cell offers official sample papers and abhyas.mahacet.org has free mock interface practice

5Focus on Class 12 Physics chapters that dominate the paper: rotational motion, oscillations, electrostatics, current electricity, EMI, optics, and modern physics (these typically account for 70%+ of Physics marks)

6For Chemistry, balance Physical (kinetics, electrochemistry, solutions) with Organic (named reactions, IUPAC, isomerism) and Inorganic (p/d/f-block, coordination) — sub-equally distributed in MHT-CET

Frequently Asked Questions

What is the MHT-CET 2026 exam pattern?

MHT-CET PCM is a computer-based test of 150 MCQs over 180 minutes. Paper-1 (Mathematics) has 50 questions in 90 minutes at 2 marks each = 100 marks. Paper-2 combines Physics (50 Qs) and Chemistry (50 Qs) in 90 minutes at 1 mark each = 100 marks. Total 200 marks. There is NO negative marking, so candidates should attempt all questions.

When will MHT-CET 2026 be conducted?

MHT-CET 2026 PCM (Engineering) is scheduled across 11-19 April 2026 with a re-exam window of 14-17 May 2026. MHT-CET 2026 PCB (Pharmacy/Agri) is scheduled across 21-26 April 2026 with a re-exam window of 10-11 May 2026. Multiple shifts are conducted at centres across Maharashtra and selected outside-state cities. The official information bulletin on cetcell.mahacet.org has shift-wise schedules.

What is the application fee for MHT-CET 2026?

The application fee for MHT-CET 2026 is INR 1300 for General category and outside-Maharashtra candidates, and INR 1000 for Maharashtra-domiciled SC/ST/OBC/SBC/VJ/NT/EWS/PwD/female candidates. Fees are paid online through the official MHT-CET registration portal during the application window in early 2026.

What is the syllabus distribution between Class 11 and Class 12?

MHT-CET 2026 follows an 80:20 weightage — 80% of questions are from the Class 12 Maharashtra State Board syllabus and 20% from the Class 11 syllabus. The syllabus is identical to NCERT-aligned Maharashtra State Bureau of Textbook Production (Balbharati) Class 11 and 12 Science textbooks. Candidates should master the Class 12 textbook chapters first.

What colleges accept MHT-CET scores?

MHT-CET PCM scores are used for admission to engineering and technology UG programmes across Maharashtra including College of Engineering Pune (COEP), VJTI Mumbai, Institute of Chemical Technology (ICT) Mumbai, Pune Institute of Computer Technology (PICT), Walchand College of Engineering Sangli, and over 350 affiliated engineering colleges under DTE Maharashtra's Centralised Admission Process (CAP).

Is there negative marking in MHT-CET?

No, MHT-CET 2026 has NO negative marking for either PCM or PCB papers. This is a major difference from JEE Main (which has -1 for wrong answers) and means candidates should attempt every question, including educated guesses when unsure. Mathematics questions carry 2 marks each; Physics and Chemistry carry 1 mark each.

How does MHT-CET differ from JEE Main?

MHT-CET tests Maharashtra State Board (Balbharati) Class 11/12 syllabus with state-level conceptual depth, while JEE Main covers NCERT-aligned CBSE syllabus with deeper problem-solving emphasis. MHT-CET has no negative marking, simpler numerical answer formats (pure MCQ), and shorter calculation steps. MHT-CET is accepted only for Maharashtra state-quota seats; JEE Main is accepted nationally including IITs (via JEE Advanced) and NITs/IIITs.

100+ Free MHT-CET Practice Questions

MHT-CET