100+ Free BITSAT Practice Questions

Pass your Birla Institute of Technology and Science Admission Test exam on the first try — instant access, no signup required.

✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately

100+ Questions

100% Free

1 / 100

Question 1

Score: 0/0

The half-life of a radioactive substance is 20 minutes. After 1 hour, what fraction of the original substance remains?

1/4

1/8

1/16

1/3

to track

Same family resources

Explore More India University Entrance Exams

Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.

CSIR NET

Practice Questions100 questions

2026 Statistics

Key Facts: BITSAT Exam

130 + 12 bonus

Total MCQs (main + optional bonus)

admissions.bits-pilani.ac.in

180 minutes

Single-sitting CBT, no sectional timing

BITSAT 2026 Brochure

+3 / -1

Marking scheme (0 for unattempted)

BITS Pilani Admissions

3 campuses

BITS Pilani, Goa, and Hyderabad accept the score

BITS Pilani

100

Free practice questions here

OpenExamPrep

BITSAT is a 180-minute online CBT with 130 MCQs across Physics (30), Chemistry (30), Math or Biology (40), Logical Reasoning (20), and English (10). Marking is +3/-1 with optional 12 bonus questions. Used for admission to BITS Pilani, Goa, and Hyderabad campuses.

Sample BITSAT Practice Questions

Try these sample questions to test your BITSAT exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A particle moves in a straight line with constant acceleration. It covers 10 m in the 4th second and 12 m in the 5th second. What is its acceleration?

A.2 m/s²

B.1 m/s²

C.3 m/s²

D.4 m/s²

Explanation: Distance in nth second is s_n = u + a(2n-1)/2. So s_5 - s_4 = a(2·5-1)/2 - a(2·4-1)/2 = a(9-7)/2 = a. Thus 12 - 10 = a = 2 m/s².

2A block of mass 2 kg is placed on a rough horizontal surface. A force of 10 N applied horizontally just moves it. What is the coefficient of static friction? (Take g = 10 m/s²)

A.0.5

B.0.2

C.1.0

D.0.05

Explanation: At the point of impending motion, applied force equals limiting friction: F = μ_s · mg. So μ_s = F/(mg) = 10/(2·10) = 0.5.

3A body is projected with velocity 20 m/s at 60° to the horizontal. What is its maximum height? (g = 10 m/s²)

A.15 m

B.10 m

C.20 m

D.5 m

Explanation: Maximum height H = (u sin θ)² / (2g) = (20 · sin 60°)² / 20 = (20 · √3/2)² / 20 = (10√3)² / 20 = 300/20 = 15 m.

4Two point charges of +4 μC and -4 μC are placed 0.2 m apart. What is the electric dipole moment of this system?

A.8 × 10⁻⁷ C·m

B.8 × 10⁻⁶ C·m

C.4 × 10⁻⁷ C·m

D.1.6 × 10⁻⁶ C·m

Explanation: Dipole moment p = q · d, where d is the separation. So p = (4 × 10⁻⁶ C)(0.2 m) = 8 × 10⁻⁷ C·m. The direction is from the negative to the positive charge.

5A converging lens has focal length 20 cm. An object is placed 30 cm from it. Where is the image formed?

A.60 cm on the opposite side of the lens

B.12 cm on the opposite side

C.60 cm on the same side as the object

D.10 cm on the opposite side

Explanation: Using the lens formula 1/v − 1/u = 1/f with sign convention u = −30 cm, f = +20 cm: 1/v = 1/20 + 1/(−30) = 3/60 − 2/60 = 1/60, so v = +60 cm. Positive v means image is on the opposite side of the lens.

6The de Broglie wavelength of an electron accelerated through a potential difference of 100 V is approximately:

A.1.23 Å

B.12.3 Å

C.0.12 Å

D.100 Å

Explanation: For an electron accelerated through V volts, λ = 12.27/√V Å. Here λ = 12.27/√100 = 12.27/10 ≈ 1.23 Å.

7A wire of resistance R is stretched uniformly so that its length doubles. What is its new resistance?

A.4R

B.2R

C.R/2

D.R/4

Explanation: Resistance R = ρL/A. Volume is conserved, so if L doubles, A halves. New R' = ρ(2L)/(A/2) = 4·ρL/A = 4R.

8A simple pendulum of length L has time period T on Earth. What is its time period on the Moon, where g is 1/6 of Earth's?

A.T√6

B.T/√6

C.6T

D.T/6

Explanation: Time period T = 2π√(L/g). On the Moon, g_m = g/6, so T_m = 2π√(L/(g/6)) = 2π√(6L/g) = T√6.

9Two resistors of 6 Ω and 3 Ω are connected in parallel. What is their equivalent resistance?

A.2 Ω

B.9 Ω

C.4.5 Ω

D.18 Ω

Explanation: For parallel resistors, 1/R = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2, so R = 2 Ω.

10A satellite is orbiting Earth at a height equal to the Earth's radius R. What is its orbital velocity? (g is surface gravity, R is Earth's radius)

A.√(gR/2)

B.√(gR)

C.√(2gR)

D.√(gR/4)

Explanation: Orbital velocity at radius r is v = √(GM/r). With r = 2R and GM = gR², v = √(gR²/(2R)) = √(gR/2).

About the BITSAT Exam

BITSAT (Birla Institute of Technology and Science Admission Test) is the computer-based entrance exam for admission to integrated first-degree programmes at the BITS Pilani, Goa, and Hyderabad campuses. Conducted by BITS Pilani, it tests 130 MCQs across five sections — Physics (30), Chemistry (30), Mathematics or Biology for B.Pharm (40), Logical Reasoning (20), and English Proficiency (10) — within 180 minutes with no sectional time limits. After answering all 130 questions, candidates who finish early may opt to attempt up to 12 bonus questions (3 each from Physics, Chemistry, Math/Biology, and 3 from English/LR combined) to improve their score, but answers to earlier questions cannot then be changed. BITSAT 2026 is conducted in two sessions: Session 1 on 15-16 April 2026 and Session 2 on 24-26 May 2026.

Questions

100 scored questions

Time Limit

180 minutes

Passing Score

No fixed pass; branch cutoffs vary (typically 300+ for top branches at Pilani)

Exam Fee

INR 3,600 single session / INR 5,600 both sessions (Male); INR 3,100 / INR 4,600 (Female) (Birla Institute of Technology and Science, Pilani (BITS Pilani))

BITSAT Exam Content Outline

23%

Physics

NCERT Class 11-12 Physics — kinematics, laws of motion, work-energy-power, rotational motion, gravitation, thermodynamics, oscillations, waves, electrostatics, current electricity, magnetism, EMI, optics, modern physics

23%

Chemistry

NCERT Class 11-12 Chemistry — physical (mole concept, atomic structure, thermodynamics, equilibrium, electrochemistry, kinetics), organic (hydrocarbons, alcohols/phenols/ethers, carbonyl compounds, amines, biomolecules), inorganic (periodic table, chemical bonding, p-block, d/f-block, coordination compounds)

31%

Mathematics (or Biology for B.Pharm)

NCERT 11-12 Math — algebra (quadratic, complex numbers, sequences), calculus (limits, derivatives, integrals, differential equations), coordinate geometry (lines, conics), trigonometry, vectors, 3D geometry, matrices, determinants, probability, statistics. B.Pharm aspirants attempt Biology instead.

15%

Logical Reasoning

Verbal reasoning (analogies, classification, series completion, logical deductions, blood relations) and non-verbal reasoning (figure series, pattern recognition, mirror/water images, paper folding, embedded figures, cubes and dice)

English Proficiency

Grammar (tenses, articles, prepositions, subject-verb agreement), vocabulary (synonyms, antonyms, one-word substitutes, idioms), reading comprehension, sentence completion and improvement, error spotting

How to Pass the BITSAT Exam

What You Need to Know

Passing score: No fixed pass; branch cutoffs vary (typically 300+ for top branches at Pilani)
Exam length: 100 questions
Time limit: 180 minutes
Exam fee: INR 3,600 single session / INR 5,600 both sessions (Male); INR 3,100 / INR 4,600 (Female)

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

BITSAT Study Tips from Top Performers

1Take 25-30 full-length online BITSAT mocks in the final 2 months — the speed (≈83 seconds per question) is the hardest part for most JEE-trained candidates

2Solve the LR and English sections in under 25 minutes total — these 30 quick questions free time for tougher Math/Physics problems and are the highest-yield ROI on prep

3Focus PCM revision on NCERT line-by-line: BITSAT historically asks several direct NCERT-statement questions, especially in Inorganic Chemistry and Modern Physics

4Practise the optional bonus questions strategically — only attempt them if you are very confident, since bonus answers cannot reuse main-section time and you can no longer go back

5Master the on-screen calculator-free numerical strategies: BITSAT does not provide a calculator, so practice integer arithmetic, log tables from memory, and trig values cold

6Book your slot as early as possible after registration opens — preferred dates and centres fill quickly, especially metro centres like Bangalore, Hyderabad, and Delhi NCR

Frequently Asked Questions

What is the BITSAT 2026 exam pattern?

BITSAT 2026 is a 180-minute computer-based test with 130 MCQs: Physics 30, Chemistry 30, Mathematics or Biology (for B.Pharm) 40, Logical Reasoning 20, and English Proficiency 10. There are no sectional time limits. Candidates who answer all 130 questions before time runs out may optionally attempt up to 12 bonus questions to improve their score, but cannot revise earlier answers after starting the bonus section.

What is the BITSAT marking scheme?

Each correct answer earns +3 marks, each incorrect answer carries -1 negative marking, and unattempted questions get 0. The maximum possible base score is 390 (130 questions x 3 marks); with the optional 12 bonus questions, scores up to 426 are possible. Because of negative marking, candidates should avoid blind guessing.

When is BITSAT 2026 held and how do I apply?

BITSAT 2026 is conducted in two sessions: Session 1 on 15-16 April 2026 and Session 2 on 24-26 May 2026. Candidates may take one session or both (best score is used). Applications are submitted online at admissions.bits-pilani.ac.in. The application window typically opens in January and closes in March, with separate slot booking for each session.

What is the BITSAT 2026 application fee?

For BITSAT 2026, male candidates pay INR 3,600 for a single session and INR 5,600 for both sessions. Female candidates pay a reduced fee of INR 3,100 for a single session and INR 4,600 for both sessions. Candidates outside India (Dubai test centre) pay USD 80 per session.

Which BITS campuses and programmes accept BITSAT?

BITSAT scores are used for admission to integrated first-degree programmes at BITS Pilani (Rajasthan), BITS Goa, and BITS Hyderabad campuses. Programmes include B.E. (Computer Science, Electronics, Mechanical, Chemical, Civil, Electrical etc.), B.Pharm (Biology track), and M.Sc. (Hons.) in Mathematics, Physics, Chemistry, Biological Sciences, Economics, and General Studies.

What is the BITSAT syllabus and how does it compare to JEE?

The BITSAT syllabus closely follows NCERT Class 11 and 12 for Physics, Chemistry, and Mathematics — essentially the same as JEE Main. The key differences are the additional Logical Reasoning (20 Q) and English Proficiency (10 Q) sections, the higher speed required (130 Q in 180 minutes ≈ 83 seconds per question), and the online-only CBT format. Most JEE Main aspirants need only light supplementary prep for LR and English.

What BITSAT score is needed for top branches at BITS Pilani?

Branch cutoffs vary year to year but typically: CS at BITS Pilani requires around 340-355+, Electronics & Communication 320-335+, Mechanical 290-310+. BITS Goa and BITS Hyderabad CS cutoffs run roughly 15-25 marks below Pilani. The cutoffs are released after the iterations of admission, not in advance.

100+ Free BITSAT Practice Questions

BITSAT