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The coefficient of friction between a block and a horizontal surface is 0.2. If the block has a mass of 5 kg, the minimum horizontal force required to just move it is (g = 10 m/s²):

10 N

20 N

5 N

50 N

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Practice Questions100 questions

2026 Statistics

Key Facts: KCET Exam

60 MCQs / 80 minutes

Per paper — Physics, Chemistry, Maths each

cetonline.karnataka.gov.in

+1 / 0

Marking scheme — no negative marking

KEA KCET information brochure

23-24 April 2026

KCET 2026 exam dates

Karnataka Examinations Authority

50% + 50%

Rank weightage — KCET marks plus PUC II PCM

KEA rank calculation rules

100

Free practice questions here

OpenExamPrep

KCET is an offline OMR-based engineering and medical entrance test with 60 MCQs per paper in 80 minutes, +1 mark for correct and 0 for wrong (no negative marking). Engineering aspirants attempt Physics, Chemistry, and Mathematics; the final rank weights KCET 50% and PUC II PCM/PCB marks 50%.

Sample KCET Practice Questions

Try these sample questions to test your KCET exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A particle moves along a straight line with velocity v = 4t + 2 (m/s). What is its displacement between t = 0 and t = 3 s?

A.12 m

B.18 m

C.24 m

D.30 m

Explanation: Displacement is the integral of velocity: s = ∫(4t + 2)dt from 0 to 3 = [2t² + 2t] from 0 to 3 = 18 + 6 = 24 m. This applies the fundamental kinematic relation between v(t) and position.

2A body of mass 2 kg is moving with a velocity of 10 m/s. A force of 4 N acts on it in the direction of motion for 5 s. What is the final kinetic energy?

A.100 J

B.200 J

C.400 J

D.500 J

Explanation: Acceleration a = F/m = 4/2 = 2 m/s². Final velocity v = u + at = 10 + 2(5) = 20 m/s. Kinetic energy KE = ½mv² = ½(2)(20)² = 400 J. Uses Newton's second law and the kinetic energy formula.

3The acceleration due to gravity at a height h above the Earth's surface (where h << R) is approximately:

A.g(1 + 2h/R)

B.g(1 − 2h/R)

C.g(1 + h/R)

D.g(1 − h/R)

Explanation: g at height h: g_h = g(R/(R+h))² = g(1 + h/R)⁻². Using binomial approximation for h << R: (1 + h/R)⁻² ≈ 1 − 2h/R. So g_h ≈ g(1 − 2h/R). This is from the inverse-square law of gravitation.

4The dimensional formula of Planck's constant is the same as that of:

A.Linear momentum

B.Force

C.Angular momentum

D.Energy

Explanation: Planck's constant h has units J·s = kg·m²/s, giving dimensions [M L² T⁻¹]. Angular momentum L = mvr has units kg·m²/s with the same dimensions [M L² T⁻¹]. Both share this dimensional formula.

5A ball is thrown vertically upward with a velocity of 20 m/s. Taking g = 10 m/s², what is the maximum height reached?

A.10 m

B.20 m

C.30 m

D.40 m

Explanation: At maximum height final velocity v = 0. Using v² = u² − 2gh: 0 = (20)² − 2(10)h, so h = 400/20 = 20 m. This is the standard projectile equation under uniform gravity.

6Two vectors of magnitudes 3 and 4 units are at right angles to each other. The magnitude of their resultant is:

A.1 unit

B.5 units

C.7 units

D.12 units

Explanation: For two perpendicular vectors A and B, the magnitude of resultant R = √(A² + B²) = √(9 + 16) = √25 = 5 units. This is the Pythagorean theorem applied to perpendicular vectors.

7A car moving with a velocity of 20 m/s is brought to rest in 5 s by applying brakes. The retardation is:

A.2 m/s²

B.4 m/s²

C.5 m/s²

D.10 m/s²

Explanation: Using v = u + at with v = 0, u = 20 m/s, t = 5 s: 0 = 20 + a(5), so a = −4 m/s². The magnitude of retardation is 4 m/s². Standard kinematic equation under uniform deceleration.

8The coefficient of friction between a block and a horizontal surface is 0.2. If the block has a mass of 5 kg, the minimum horizontal force required to just move it is (g = 10 m/s²):

A.5 N

B.10 N

C.20 N

D.50 N

Explanation: Minimum force to just overcome static friction equals the limiting friction f = μN = μmg = 0.2 × 5 × 10 = 10 N. This applies Coulomb's law of friction with N = mg on horizontal surface.

9An object of mass 10 kg is moving in a circle of radius 5 m with a constant speed of 10 m/s. The centripetal force on the object is:

A.100 N

B.200 N

C.400 N

D.1000 N

Explanation: Centripetal force F = mv²/r = (10)(10)²/5 = 1000/5 = 200 N. This is the net inward force required to maintain circular motion at constant speed.

10Two bodies of masses m and 4m have kinetic energies in the ratio 2 : 1. The ratio of their momenta is:

A.1 : 1

B.1 : √2

C.√2 : 1

D.1 : 2

Explanation: KE = p²/(2m), so p = √(2m·KE). For body 1: p₁ = √(2m·2K) = 2√(mK). For body 2: p₂ = √(2·4m·K) = 2√(2mK). Ratio p₁:p₂ = 2√(mK) : 2√(2mK) = 1 : √2. Uses the momentum-energy relation.

About the KCET Exam

KCET (Karnataka Common Entrance Test) is the state-level entrance exam conducted annually by the Karnataka Examinations Authority for admission to engineering, technology, agriculture, pharmacy, veterinary, B.Sc nursing, BNYS, and other professional courses in Karnataka. For engineering, candidates take three papers — Physics, Chemistry, and Mathematics — each with 60 multiple-choice questions in 80 minutes, held on 23-24 April 2026 in offline OMR format. The exam follows the Karnataka 1st and 2nd PUC syllabus, which is closely aligned with NCERT.

Questions

100 scored questions

Time Limit

80 minutes per paper (3 papers — Physics, Chemistry, Mathematics for engineering)

Passing Score

No fixed pass; KCET rank uses 50% KCET score + 50% PUC II Physics/Chemistry/Maths marks

Exam Fee

INR 500 (Karnataka General); INR 750-1,200 (other categories/outside state) for 2026 (Karnataka Examinations Authority (KEA), Government of Karnataka)

KCET Exam Content Outline

~33%

Physics

1st and 2nd PUC Physics — units and measurements, kinematics, laws of motion, work-energy-power, rotational motion, gravitation, properties of matter, thermodynamics, oscillations, waves, electrostatics, current electricity, magnetism, EMI, AC, EM waves, ray and wave optics, dual nature of matter, atoms and nuclei, semiconductors

~33%

Chemistry

1st and 2nd PUC Chemistry — atomic structure, periodic classification, chemical bonding, states of matter, thermodynamics, equilibrium, redox, hydrogen, s/p/d/f-block, coordination compounds, solid state, solutions, electrochemistry, chemical kinetics, surface chemistry, organic (hydrocarbons, haloalkanes, alcohols-phenols-ethers, aldehydes-ketones-acids, amines, biomolecules, polymers)

~34%

Mathematics

1st and 2nd PUC Mathematics — sets, relations and functions, trigonometric functions, principle of mathematical induction, complex numbers, linear inequalities, permutations and combinations, binomial theorem, sequences and series, straight lines, conic sections, 3D geometry, limits and derivatives, statistics, probability, matrices, determinants, continuity and differentiability, applications of derivatives, integrals and applications, differential equations, vectors, linear programming

How to Pass the KCET Exam

What You Need to Know

Passing score: No fixed pass; KCET rank uses 50% KCET score + 50% PUC II Physics/Chemistry/Maths marks
Exam length: 100 questions
Time limit: 80 minutes per paper (3 papers — Physics, Chemistry, Mathematics for engineering)
Exam fee: INR 500 (Karnataka General); INR 750-1,200 (other categories/outside state) for 2026

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

KCET Study Tips from Top Performers

1Master NCERT Class 11 and Class 12 thoroughly — over 80 percent of KCET questions are directly from NCERT or PUC textbook line-level content

2Solve previous 10 years of KCET papers — many questions repeat with minor variations and the difficulty calibration is best learned from actual papers

3Since there is no negative marking, attempt all 60 questions in every paper — never leave a blank even if it is a guess

4Time per question is about 80 seconds — practise OMR bubbling speed so you do not lose time transferring answers in the last 10 minutes

5Build a formula sheet for Maths and Physics and revise it daily in the last 30 days; for Chemistry, focus on NCERT exemplar problems and named reactions

6Take at least 15 full-length OMR-based mocks under exam conditions to build stamina for back-to-back 80-minute papers

Frequently Asked Questions

What is the KCET 2026 exam pattern?

KCET 2026 is an offline OMR-based exam with three separate papers for engineering aspirants: Physics, Chemistry, and Mathematics. Each paper has 60 multiple-choice questions to be solved in 80 minutes. Medical and veterinary aspirants write Biology instead of (or in addition to) Mathematics. There is +1 mark per correct answer and no negative marking.

When is KCET 2026 scheduled?

KCET 2026 is scheduled by KEA for 23-24 April 2026. Two papers are conducted on day one and the third paper on day two. Kannada Language Test (for Horanadu and Gadinadu Kannadiga candidates) is held on the second afternoon.

What is the application fee for KCET 2026?

For 2026, the KCET application fee is approximately INR 500 for Karnataka General/2A/2B/3A/3B candidates, INR 250 for SC/ST/Category-I from Karnataka, INR 750 for candidates from outside Karnataka, and INR 5,000 (around) for candidates applying from outside India. Check cetonline.karnataka.gov.in for the exact published fees each year.

How is the KCET rank calculated?

The KCET combined rank uses a 50-50 weightage: 50 percent of the KCET marks plus 50 percent of the qualifying exam marks in Physics, Chemistry and Mathematics (or Biology) from 2nd PUC or Class 12. Karnataka domicile candidates and non-Karnataka candidates are ranked separately for state-quota seats.

What is the syllabus for KCET 2026?

KCET follows the Karnataka 1st and 2nd PUC (Pre-University Course) syllabus prescribed by the Department of Pre-University Education. The content is broadly aligned with NCERT Class 11 and Class 12 in Physics, Chemistry, Mathematics, and Biology, so NCERT textbooks are an excellent primary resource.

Is there negative marking in KCET?

No. KCET awards +1 mark for every correct answer and 0 marks for an incorrect or blank answer. There is no negative marking, so candidates should attempt every question — guessing intelligently among the four options costs nothing.

Which colleges accept KCET rank?

KCET rank is used by KEA to allot seats in government and government-aided engineering, medical (private quota only — medical seats use NEET-UG rank for state quota), dental, agricultural, veterinary, pharmacy, nursing, BNYS, B.Arch, and other professional courses across more than 200 colleges in Karnataka including PES, RVCE, BMSCE, MSRIT, BMS, Dayananda Sagar, and university-affiliated colleges.

100+ Free KCET Practice Questions

KCET