100+ Free JEE Main Practice Questions

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A current of 2 A flows through a 5 ohm resistor for 30 seconds. The heat dissipated is:

1200 J

600 J

60 J

300 J

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Practice Questions100 questions

2026 Statistics

Key Facts: JEE Main Exam

75 questions

Total in Paper 1 (25 each in Physics, Chemistry, Math)

NTA JEE Main Information Bulletin 2026

3 hours

Duration of Paper 1

NTA

+4 / -1

MCQ marking; numerical questions carry no negative

NTA marking scheme

Top 250,000

Candidates qualify for JEE Advanced

Joint Admission Board

2 sessions

January and April each year

NTA

JEE Main Paper 1 is a 3-hour computer-based test of 75 questions covering Physics, Chemistry, and Mathematics from the Class 11-12 NCERT syllabus. Conducted by NTA in two sessions per year, it determines NIT/IIIT admission and qualification for JEE Advanced.

Sample JEE Main Practice Questions

Try these sample questions to test your JEE Main exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1The dimensional formula of pressure is:

A.M L^-1 T^-2

B.M L T^-2

C.M L^2 T^-2

D.M L^-2 T^-2

Explanation: Pressure = Force / Area = (M L T^-2) / (L^2) = M L^-1 T^-2. This dimensional formula is identical to that of stress and Young's modulus.

2A particle is thrown vertically upward with velocity 20 m/s. Taking g = 10 m/s^2, the maximum height reached is:

A.20 m

B.10 m

C.40 m

D.30 m

Explanation: Using v^2 = u^2 - 2gh with v = 0 at max height: 0 = (20)^2 - 2(10)h, so h = 400/20 = 20 m.

3A projectile is fired at angle 45 degrees with initial speed 20 m/s. Taking g = 10 m/s^2, the horizontal range is:

A.40 m

B.20 m

C.80 m

D.10 m

Explanation: Range R = u^2 sin(2 theta) / g = (400)(sin 90) / 10 = 400/10 = 40 m.

4A block of mass 2 kg rests on a horizontal floor with coefficient of static friction 0.4. The minimum horizontal force required to just start moving it is (g = 10 m/s^2):

A.8 N

B.4 N

C.20 N

D.2 N

Explanation: Limiting friction = mu_s x N = 0.4 x (2 x 10) = 8 N. The applied force must equal or exceed 8 N to overcome static friction.

5Two masses 3 kg and 5 kg are connected by a string over a frictionless pulley (Atwood machine). The acceleration of the system is (g = 10 m/s^2):

A.2.5 m/s^2

B.1.25 m/s^2

C.5 m/s^2

D.10 m/s^2

Explanation: For an Atwood machine: a = (m2 - m1) g / (m1 + m2) = (5 - 3)(10) / 8 = 20/8 = 2.5 m/s^2.

6A 0.5 kg ball moving at 10 m/s strikes a wall and rebounds at 8 m/s. The magnitude of impulse on the ball is:

A.9 N s

B.1 N s

C.5 N s

D.18 N s

Explanation: Impulse = change in momentum = m(v_final - v_initial) = 0.5[(-8) - 10] = 0.5(-18) = -9 N s. Magnitude is 9 N s.

7Work done by a constant force of 10 N acting at 60 degrees to the displacement of 5 m is:

A.25 J

B.50 J

C.43.3 J

D.12.5 J

Explanation: W = F d cos(theta) = 10 x 5 x cos(60) = 50 x 0.5 = 25 J.

8A body of mass 5 kg is moving with velocity 4 m/s. Its kinetic energy is:

A.40 J

B.20 J

C.80 J

D.100 J

Explanation: KE = (1/2) m v^2 = (1/2)(5)(16) = 40 J.

9The moment of inertia of a uniform solid sphere of mass M and radius R about an axis through its centre is:

A.(2/5) M R^2

B.(2/3) M R^2

C.(1/2) M R^2

D.M R^2

Explanation: For a uniform solid sphere about a diameter, I = (2/5) M R^2 — a standard result derived by integrating ring elements.

10A flywheel rotating at 600 rpm is brought to rest in 10 s by a constant torque. The angular retardation is:

A.2 pi rad/s^2

B.pi rad/s^2

C.60 rad/s^2

D.10 rad/s^2

Explanation: Initial omega = 2 pi x (600/60) = 20 pi rad/s. alpha = (omega_f - omega_i) / t = (0 - 20 pi)/10 = -2 pi rad/s^2; magnitude 2 pi rad/s^2.

About the JEE Main Exam

JEE Main is India's national engineering entrance examination conducted by the National Testing Agency (NTA). Paper 1 is the gateway to undergraduate engineering admission at NITs, IIITs, and other Centrally Funded Technical Institutes, and serves as the qualifying test for JEE Advanced (IITs). The exam runs twice a year in January and April sessions.

Questions

100 scored questions

Time Limit

3 hours (180 minutes); 3 hours 20 minutes for PwBD candidates

Passing Score

No fixed pass mark; ranks computed via NTA percentile, top ~250,000 qualify for JEE Advanced

Exam Fee

INR 1000 (General male, Paper 1, India centre); reduced fees for women, SC/ST/PwD; higher for foreign centres (National Testing Agency (NTA))

JEE Main Exam Content Outline

33%

Physics — Mechanics and Thermal Physics

Units and measurements, kinematics, laws of motion, work-energy-power, rotational motion, gravitation, properties of solids and fluids, thermodynamics, kinetic theory, oscillations and waves

33%

Physics — Electromagnetism, Optics, and Modern Physics

Electrostatics, current electricity, magnetic effects, EMI and AC, EM waves, ray and wave optics, dual nature of matter, atoms and nuclei, semiconductor electronics

33%

Chemistry — Physical

Atomic structure, periodic properties, chemical bonding, states of matter, thermodynamics, equilibrium, redox, electrochemistry, chemical kinetics, surface chemistry

33%

Chemistry — Inorganic and Organic

Periodic table groups, hydrogen, s-block, p-block, d/f-block, coordination compounds; organic principles, hydrocarbons, haloalkanes, oxygen/nitrogen functional groups, biomolecules, polymers

34%

Mathematics — Algebra and Calculus

Sets, relations, functions, complex numbers, quadratics, matrices and determinants, permutations and combinations, binomial theorem, sequences and series, limits, continuity, differentiation, integration, differential equations

34%

Mathematics — Geometry, Trigonometry, Vectors, Statistics

Straight lines, circles, conic sections, 3D geometry, vector algebra, trigonometric identities and equations, inverse trig, statistics and probability, mathematical reasoning

How to Pass the JEE Main Exam

What You Need to Know

Passing score: No fixed pass mark; ranks computed via NTA percentile, top ~250,000 qualify for JEE Advanced
Exam length: 100 questions
Time limit: 3 hours (180 minutes); 3 hours 20 minutes for PwBD candidates
Exam fee: INR 1000 (General male, Paper 1, India centre); reduced fees for women, SC/ST/PwD; higher for foreign centres

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

JEE Main Study Tips from Top Performers

1Master NCERT Class 11 and 12 textbooks first — JEE Main does not test beyond NCERT scope

2Practice previous-year question papers (2019 onwards under NTA) to learn the typical difficulty band and time pressure

3Use mock tests in CBT format to build the on-screen calculator and navigation muscle memory

4Skip-and-return strategy: avoid the -1 penalty by leaving genuinely unknown MCQs blank, but attempt all 5 numerical-value questions per section since they carry no negative marking

Frequently Asked Questions

How many times is JEE Main conducted each year?

NTA conducts JEE Main twice a year — Session 1 in January and Session 2 in April. Candidates may appear in both sessions, and the better of the two NTA scores is used for ranking.

What is the marking scheme for JEE Main Paper 1?

Each section has 20 MCQs and 5 numerical-value questions. Correct answer: +4. Incorrect MCQ: -1 (negative marking). Incorrect numerical-value answer: 0 (no negative marking). Unattempted: 0.

What is the syllabus for JEE Main 2026?

The syllabus is based on the NCERT Class 11 and Class 12 textbooks for Physics, Chemistry, and Mathematics. NTA revised the syllabus in 2024, removing some topics; the same trimmed syllabus continues for 2026.

What rank is needed to qualify for JEE Advanced?

The top 250,000 candidates (across all categories) in JEE Main Paper 1 qualify to write JEE Advanced, which is the entrance for the IITs. Cut-off percentile varies each year by category.

Is JEE Main online or offline?

Paper 1 (B.E./B.Tech) is conducted in Computer-Based Test (CBT) mode only. Paper 2A (B.Arch) Drawing section remains pen-and-paper; the rest of Paper 2 is also CBT.

100+ Free JEE Main Practice Questions

JEE Main