100+ Free JEE Advanced Practice Questions

Pass your Joint Entrance Examination (Advanced) exam on the first try — instant access, no signup required.

✓ No registration✓ No credit card✓ No hidden fees✓ Start practicing immediately

100+ Questions

100% Free

1 / 100

Question 1

Score: 0/0

A diffraction grating produces first-order maximum at 30 degrees for light of wavelength 500 nm. The grating spacing d is:

250 nm

2000 nm

1000 nm (1 micrometre)

500 nm

to track

Same family resources

Explore More India University Entrance Exams

Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.

COMEDK UGET

Practice Questions100 questions

2026 Statistics

Key Facts: JEE Advanced Exam

23 IITs

Institutions admit through JEE Advanced

Joint Admission Board (jeeadv.ac.in)

2 papers x 3 hours

Paper 1 and Paper 2, both compulsory

JEE Advanced Information Brochure

~2.5 lakh

Top JEE Main scorers eligible to attempt Advanced

JAB eligibility criteria

2 attempts

Maximum attempts in two consecutive years

JEE Advanced eligibility rules

INR 3,200

Registration fee for general male candidates (India)

JEE Advanced 2025 brochure

100

Free practice questions available here

OpenExamPrep

JEE Advanced is India's most competitive undergraduate entrance exam, used by all 23 IITs for B.Tech admissions. Two 3-hour computer-based papers (both compulsory) test Physics, Chemistry and Mathematics with variable negative marking. Only top JEE Main qualifiers may attempt it.

Sample JEE Advanced Practice Questions

Try these sample questions to test your JEE Advanced exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A particle moves along the x-axis with velocity v(t) = 6t^2 - 4t (m/s). What is its acceleration at t = 2 s?

A.20 m/s^2

B.16 m/s^2

C.8 m/s^2

D.24 m/s^2

Explanation: Acceleration a = dv/dt = 12t - 4. At t = 2 s: a = 12(2) - 4 = 24 - 4 = 20 m/s^2.

2A projectile is fired up an incline of angle 30 degrees with velocity 20 m/s at 60 degrees to the horizontal. The component of initial velocity along the incline is closest to:

A.10 m/s

B.17.3 m/s

C.20 m/s

D.5 m/s

Explanation: Take the incline as the x'-axis. The angle of the velocity vector above the incline is 60 - 30 = 30 degrees, so the along-incline component is 20 cos(30 deg) = 20 x (sqrt(3)/2) ≈ 17.3 m/s.

3A block of mass 2 kg on a horizontal surface has mu_s = 0.4 and mu_k = 0.3. A horizontal force of 6 N is applied. The friction force on the block is (g = 10 m/s^2):

A.6 N (static, block stationary)

B.8 N

C.4 N

D.0 N

Explanation: Maximum static friction = mu_s mg = 0.4 x 2 x 10 = 8 N. Applied force (6 N) < 8 N, so the block remains stationary and friction equals the applied force, 6 N.

4A variable force F = 3x^2 N acts on a body along the x-axis. Work done in moving the body from x = 0 to x = 2 m is:

A.8 J

B.12 J

C.6 J

D.24 J

Explanation: W = integral from 0 to 2 of 3x^2 dx = [x^3] from 0 to 2 = 8 - 0 = 8 J.

5Two bodies of masses m and 2m have equal kinetic energies. The ratio of their linear momenta p_1 : p_2 is:

A.1 : sqrt(2)

B.1 : 2

C.sqrt(2) : 1

D.2 : 1

Explanation: KE = p^2 / (2m), so p = sqrt(2 m KE). For equal KE: p_1 / p_2 = sqrt(m / 2m) = 1 / sqrt(2).

6A uniform disc of mass M and radius R rolls without slipping on a horizontal surface with centre-of-mass speed v. Its total kinetic energy is:

A.(3/4) M v^2

B.(1/2) M v^2

C.M v^2

D.(1/4) M v^2

Explanation: KE_total = (1/2) M v^2 + (1/2) I omega^2. For a disc I = (1/2) M R^2 and rolling: omega = v/R. So rotational KE = (1/2)(1/2 M R^2)(v^2/R^2) = (1/4) M v^2. Total = (1/2 + 1/4) M v^2 = (3/4) M v^2.

7A particle executes SHM with amplitude A. At what displacement is its kinetic energy equal to its potential energy?

A.A / sqrt(2)

B.A / 2

C.A sqrt(3) / 2

D.A

Explanation: In SHM, PE = (1/2) k x^2 and KE = (1/2) k (A^2 - x^2). Setting KE = PE: A^2 - x^2 = x^2, so 2 x^2 = A^2 and x = A / sqrt(2).

8A satellite is in a circular orbit of radius r around Earth. If its orbital radius is increased to 4r, the new orbital period (originally T) becomes:

A.8 T

B.2 T

C.4 T

D.16 T

Explanation: By Kepler's third law, T^2 proportional to r^3. So T_new / T = (4r / r)^(3/2) = 4^(3/2) = 8. T_new = 8 T.

9A wire of length L and cross-sectional area A under tensile force F stretches by delta L. Young's modulus Y is:

A.F L / (A delta L)

B.F A / (L delta L)

C.F delta L / (A L)

D.A L / (F delta L)

Explanation: Y = stress / strain = (F / A) / (delta L / L) = F L / (A delta L).

10Water flows through a horizontal pipe whose cross-section narrows from 4 cm^2 to 1 cm^2. If the speed at the wider end is 1 m/s, the speed at the narrower end is:

A.4 m/s

B.2 m/s

C.0.25 m/s

D.16 m/s

Explanation: Continuity: A_1 v_1 = A_2 v_2. So v_2 = (4 / 1) x 1 = 4 m/s.

About the JEE Advanced Exam

JEE Advanced is the gateway exam for admission to undergraduate B.Tech, B.S. and integrated programmes at the 23 Indian Institutes of Technology (IITs). Only candidates who qualify in JEE Main can attempt JEE Advanced. The exam is held in computer-based mode and consists of two compulsory papers (Paper 1 and Paper 2), each three hours long, covering Physics, Chemistry and Mathematics at a highly conceptual Class 11-12 level.

Questions

100 scored questions

Time Limit

3 hours per paper (Paper 1 + Paper 2, both compulsory)

Passing Score

Subject- and category-specific cutoffs set by JAB each year (general: ~10% per subject, ~35% aggregate)

Exam Fee

INR 3,200 (general male); INR 1,600 (female/SC/ST/PwD); USD 90 (SAARC) / USD 180 (non-SAARC) (IIT (Joint Admission Board), conducted by one of the 7 zonal IITs each year)

JEE Advanced Exam Content Outline

~33%

Physics

Mechanics, gravitation, properties of matter, heat and thermodynamics, waves, electrostatics and current electricity, magnetism, electromagnetic induction, AC circuits, ray and wave optics, modern physics and semiconductor electronics.

~33%

Chemistry

Physical chemistry (atomic structure, thermodynamics, equilibrium, electrochemistry, kinetics), inorganic chemistry (periodic table, s/p/d-block, coordination compounds, metallurgy, qualitative analysis), organic chemistry (mechanisms, named reactions, biomolecules, polymers).

~34%

Mathematics

Algebra, complex numbers, matrices and determinants, trigonometry, 2D/3D coordinate geometry, differential and integral calculus, differential equations, vector algebra, probability and statistics.

How to Pass the JEE Advanced Exam

What You Need to Know

Passing score: Subject- and category-specific cutoffs set by JAB each year (general: ~10% per subject, ~35% aggregate)
Exam length: 100 questions
Time limit: 3 hours per paper (Paper 1 + Paper 2, both compulsory)
Exam fee: INR 3,200 (general male); INR 1,600 (female/SC/ST/PwD); USD 90 (SAARC) / USD 180 (non-SAARC)

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

JEE Advanced Study Tips from Top Performers

1Master NCERT Class 11-12 Physics, Chemistry and Mathematics thoroughly — JEE Advanced applications start from NCERT concepts

2Solve previous 10-15 years of JEE Advanced papers under timed conditions; question style and depth repeat

3Practice multi-concept problems daily — Advanced rewards linking topics across chapters rather than rote application

4Build numerical-value answer accuracy with rough work discipline; calculator is not allowed inside the exam hall

5Revise organic reaction mechanisms and inorganic qualitative analysis with structured flowcharts in the last month

Frequently Asked Questions

Who can attempt JEE Advanced?

Only the top approximately 2.5 lakh (250,000) JEE Main scorers across all categories are eligible. Candidates must be under 25 years old (30 for reserved categories) and may attempt JEE Advanced a maximum of two times in two consecutive years.

How is JEE Advanced different from JEE Main?

JEE Main is the screening exam conducted by NTA for admission to NITs, IIITs and other CFTIs and qualifies candidates for JEE Advanced. JEE Advanced is conducted by the IITs themselves and is significantly more conceptual, with question types beyond standard MCQs (multiple-correct, numerical-value, paragraph-based) and variable negative marking.

What is the structure of JEE Advanced?

Two compulsory papers (Paper 1 and Paper 2), each 3 hours, in computer-based test (CBT) mode. Each paper has Physics, Chemistry and Mathematics sections with multiple question formats including single-correct MCQs, multiple-correct MCQs, numerical-value answers, paragraph-based and matching items.

Is there negative marking in JEE Advanced?

Yes — but unlike JEE Main, negative marking in JEE Advanced varies by question type. Single-correct MCQs typically have -1 for a wrong answer; multiple-correct items award partial credit when some correct options are chosen and apply -2 for any wrong selection; numerical-value items usually have no negative marking.

Which IIT conducts JEE Advanced in 2026?

JEE Advanced is conducted on a rotational basis by one of the seven zonal IITs (Bombay, Delhi, Guwahati, Kanpur, Kharagpur, Madras, Roorkee) on behalf of the Joint Admission Board (JAB). Check the official jeeadv.ac.in website for the current year's organising institute.

100+ Free JEE Advanced Practice Questions

JEE Advanced