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100+ Free European Baccalaureate Physics Practice Questions
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2026 Statistics
Key Facts: European Baccalaureate Physics Exam
OSGES 2021-01-D-56
Official European Schools S6–S7 4-Period Physics Syllabus
Office of the Secretary-General of the European Schools
3 Hours
Duration of the official written Baccalaureate examination
Eursc Baccalaureate Regulations
Min 6.0/10
Overall pass mark required for the European Baccalaureate diploma
European Baccalaureate Handbook
4 Core Units
Fields, Oscillations & Waves, Quantum Physics, Nuclear & Relativity
European Schools Curriculum Board
100
High-quality practice questions in this OpenExamPrep bank
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The European Baccalaureate Physics is administered by the Office of the Secretary-General of the European Schools (OSGES). Official assessment involves written/oral components graded on a 0-10 scale (passing score 5.0). Local questions on OpenExamPrep are an English-language MCQ study adaptation designed for syllabus revision.
Sample European Baccalaureate Physics Practice Questions
Try these sample questions to test your European Baccalaureate Physics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.
1Two point masses, M and m, are separated by a distance r in vacuum. If the separation distance is reduced to r/3, by what factor does the gravitational force between them increase?
A.9
B.3
C.1/3
D.1/9
Explanation: According to Newton's law of universal gravitation, the gravitational force F is inversely proportional to the square of the separation distance r (F = G*M*m/r^2). Decreasing the distance by a factor of 3 increases the force by a factor of 3^2 = 9. The other choices represent linear scaling or inverse scaling.
2A satellite of mass m moves in a circular orbit of radius r around a planet of mass M. What is the satellite's orbital speed v?
A.v = G * M / r
B.v = sqrt(G * M / r)
C.v = sqrt(G * M / r^2)
D.v = G * M / r^2
Explanation: Equating the gravitational force G*M*m/r^2 to the centripetal force m*v^2/r yields v^2 = G*M/r, so v = sqrt(G*M/r). The incorrect choices lack the square root, incorrectly includes r^2 inside the square root, and represent gravitational field strength rather than velocity.
3What is the gravitational potential V at a distance r from a point mass M, taking zero potential at infinity?
A.-G * M / r^2
B.-G * M * m / r
C.-G * M / r
D.+G * M / r
Explanation: Gravitational potential V is defined as work done per unit mass bringing a test mass from infinity to distance r, giving V = -G*M/r. The incorrect choices represent field strength with a negative sign, potential energy (U) rather than potential (V), or omit the necessary negative sign for attractive fields.
4Which of Kepler's laws states that the square of the orbital period T of a planet is directly proportional to the cube of the semi-major axis a of its orbit (T^2 proportional to a^3)?
A.Kepler's First Law
B.Kepler's Second Law
C.Kepler's Law of Equipartition
D.Kepler's Third Law
Explanation: Kepler's Third Law (Harmonic Law) states T^2 / a^3 = constant for all bodies orbiting the same central mass. Kepler's First Law describes elliptical orbits, Kepler's Second Law states equal areas are swept in equal times (conservation of angular momentum), and Equipartition is a statistical thermodynamics theorem.
5Two positive point charges +q and +4q are separated by a distance d. At what distance x from +q along the line joining them is the net electric field zero?
A.d / 3
B.d / 4
C.d / 2
D.2d / 3
Explanation: Setting electric fields equal: k*q/x^2 = k*(4q)/(d-x)^2 => 1/x = 2/(d-x) => d - x = 2x => 3x = d => x = d/3. The incorrect choices forget to take the square root of 4, ignore charge magnitude difference, or give distance from +4q rather than +q.
6A uniform electric field of magnitude E = 2000 N/C exists between two parallel metal plates separated by d = 0.05 m. What is the potential difference V between the plates?
A.40,000 V
B.100 V
C.400 V
D.200 V
Explanation: In a uniform electric field, potential difference V = E * d = 2000 N/C * 0.05 m = 100 V. The incorrect choices incorrectly divides E by d, multiplies by 2, or doubles the actual voltage.
7An electron (charge -e, mass m) enters a region of uniform magnetic field B with velocity v perpendicular to the field lines. What is the radius r of its circular path?
A.r = q * B / (m * v)
B.r = m * v^2 / (q * B)
C.r = m * v / (e * B)
D.r = e * B * v / m
Explanation: Equating magnetic Lorentz force e*v*B to centripetal force m*v^2/r gives e*v*B = m*v^2/r, so r = m*v / (e*B). this choice is inverted, this choice has v squared in the numerator, and this choice is acceleration rather than radius.
8A straight wire of length L = 0.40 m carries a current I = 5.0 A directed along the +x axis in a uniform magnetic field B = 0.30 T directed along the +y axis. What are the magnitude and direction of the magnetic force on the wire?
A.0.60 N in the -z direction
B.0.12 N in the +z direction
C.0.60 N in the +y direction
D.0.60 N in the +z direction
Explanation: Magnetic force magnitude F = I * L * B * sin(90 deg) = 5.0 * 0.40 * 0.30 = 0.60 N. By the right-hand rule, (+x) x (+y) = (+z) direction. this choice gives opposite direction, this choice miscalculates magnitude (5*0.4*0.3 != 0.12), and this choice gives force parallel to field which is impossible.
9A circular loop of area A = 0.02 m^2 is placed in a uniform magnetic field of B = 0.5 T. If the plane of the loop makes an angle of 30 degrees with the field lines, what is the magnetic flux through the loop?
A.0.005 Wb
B.0.010 Wb
C.0.0087 Wb
D.0.000 Wb
Explanation: Magnetic flux Phi = B * A * cos(theta), where theta is the angle between the field and normal to the loop. Since the loop plane makes 30 deg with field, normal makes theta = 90 - 30 = 60 deg. Thus Phi = 0.5 * 0.02 * cos(60 deg) = 0.01 * 0.5 = 0.005 Wb. this choice forgets cos(theta), this choice uses cos(30 deg), and this choice assumes parallel alignment.
10A coil with N = 100 turns and enclosed area A = 0.01 m^2 is in a magnetic field that changes uniformly from 0.1 T to 0.5 T in 0.2 seconds. What is the magnitude of the induced electromotive force (EMF) in the coil?
A.20 V
B.2.0 V
C.0.2 V
D.10 V
Explanation: By Faraday's law, magnitude of induced EMF = N * |dPhi/dt| = N * A * (dB/dt) = 100 * 0.01 * (0.4 T / 0.2 s) = 1.0 * 2.0 = 2.0 V. this choice forgets to multiply by area 0.01, this choice misplaces a decimal point, and this choice uses total field instead of change in field.
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