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Key Facts: European Baccalaureate Biology Exam

180 Minutes

Written exam duration

OSGES Syllabus

5.0 / 10

Passing mark

European Schools Regulations

5 Core Blocks

Curriculum topic breakdown

OSGES Biology Curriculum

S6 & S7

Target secondary school years

European Schools

100 Questions

Practice question count

OpenExamPrep

The European Baccalaureate Biology is administered by the Office of the Secretary-General of the European Schools (OSGES). Official assessment involves written/oral components graded on a 0-10 scale (passing score 5.0). Local questions on OpenExamPrep are an English-language MCQ study adaptation designed for syllabus revision.

Sample European Baccalaureate Biology Practice Questions

Try these sample questions to review concepts for the European Baccalaureate Biology exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Which physicochemical property of water is primarily responsible for preventing rapid temperature fluctuations in living organisms and aquatic ecosystems?
A.Low dielectric constant allowing nonpolar organic compounds to precipitate
B.High density of solid ice compared to liquid water
C.High specific heat capacity resulting from an extensive intermolecular hydrogen-bonding network
D.Formation of non-covalent hydrophobic interactions between water and lipid molecules
Explanation: Water possesses a remarkably high specific heat capacity (4.184 J/g·°C) because a significant amount of heat energy must be absorbed to break its extensive intermolecular hydrogen bonds before the kinetic energy of individual molecules can increase. This thermal buffering capability stabilizes internal cellular temperatures and aquatic environments against sudden external temperature changes.
2Which molecular feature of phospholipids causes them to spontaneously assemble into a bilayer structure in an aqueous cellular environment?
A.Amphipathic structure containing a hydrophilic phosphate head and hydrophobic fatty acid tails
B.Presence of covalent disulfide bridges linking adjacent glycerol backbones
C.Rigid steroid ring structure that repels water molecules on both sides of the membrane
D.High concentration of ionic peptide bonds between polar amino acid side chains
Explanation: Phospholipids are amphipathic molecules with a polar, hydrophilic phosphate-containing head group and two nonpolar, hydrophobic fatty acid tails. In water, hydrophobic interactions drive the nonpolar tails to face inward away from water, while the polar heads face outward toward the aqueous cytosol and extracellular fluid, creating a stable bilayer.
3How does active transport across a cell membrane fundamental differ from facilitated diffusion?
A.Active transport moves molecules down their concentration gradient without requiring membrane transport proteins
B.Facilitated diffusion hydrolyzes ATP to alter the shape of carrier channel proteins
C.Active transport utilizes specific channel proteins while facilitated diffusion relies solely on lipid solubility
D.Active transport moves solutes against their concentration gradient and requires cellular energy such as ATP
Explanation: Active transport pumps solutes against their electrochemical or concentration gradient (from lower to higher concentration) and requires metabolic energy (typically ATP hydrolysis or electrochemical gradient coupling). In contrast, facilitated diffusion is a passive process moving solutes down their concentration gradient through transmembrane channel or carrier proteins without ATP consumption.
4What is the correct pathway for a newly synthesized secretory protein through the endomembrane system of a eukaryotic cell?
A.Smooth ER → Golgi apparatus → Rough ER → Lysosome → Plasma membrane
B.Rough ER → Transport vesicle → Golgi apparatus → Secretory vesicle → Plasma membrane
C.Nucleolus → Mitochondria → Golgi apparatus → Peroxisome → Extracellular space
D.Golgi apparatus → Rough ER → Transport vesicle → Endosome → Plasma membrane
Explanation: Secretory proteins are translated by ribosomes attached to the Rough Endoplasmic Reticulum (ER), where they enter the ER lumen for folding. They are packaged into transport vesicles that travel to the cis-face of the Golgi apparatus for glycosylation and sorting, exit the trans-Golgi in secretory vesicles, and fuse with the plasma membrane via exocytosis.
5How does a competitive enzyme inhibitor affect the kinetic parameters Km (Michaelis constant) and Vmax (maximum reaction velocity)?
A.Increases Km while leaving Vmax unchanged
B.Decreases Vmax while leaving Km unchanged
C.Decreases both Km and Vmax proportionally
D.Increases Vmax and decreases Km
Explanation: A competitive inhibitor binds reversibly to the active site of an enzyme, competing directly with the substrate. This increases the apparent Km (meaning higher substrate concentration is needed to reach half-maximal velocity), but Vmax remains unchanged because high substrate concentrations can completely outcompete the inhibitor.
6Which chemical bonds in the adenosine triphosphate (ATP) molecule store the readily accessible energy released during cellular work?
A.Glycosidic linkages between ribose and adenine
B.Hydrogen bonds linking nitrogenous bases
C.Phosphoanhydride bonds between adjacent phosphate groups
D.Phosphodiester bonds in the ribose-phosphate backbone
Explanation: ATP stores metabolic energy in high-energy phosphoanhydride bonds linking its three phosphate groups. Hydrolysis of the terminal phosphoanhydride bond (converting ATP to ADP + Pi) releases approximately 30.5 kJ/mol of free energy (ΔG°' = -30.5 kJ/mol) due to electrostatic repulsion relief and resonance stabilization of inorganic phosphate.
7Where in a eukaryotic cell does glycolysis take place, and what is its net chemical yield per mole of glucose oxidized?
A.Mitochondrial matrix; Yielding 2 acetyl-CoA, 2 FADH2, and 4 ATP
B.Cytosol; Yielding 2 pyruvate, 2 NADH, and 2 net ATP
C.Inner mitochondrial membrane; Yielding 2 lactate, 2 NAD+, and 36 ATP
D.Stroma; Yielding 2 glyceraldehyde-3-phosphate, 2 NADPH, and 4 ATP
Explanation: Glycolysis occurs entirely within the cytosol of eukaryotic cells. It breaks down one 6-carbon glucose molecule into two 3-carbon pyruvate molecules, consuming 2 ATP during the investment phase and producing 4 ATP (via substrate-level phosphorylation) and 2 NADH, resulting in a net yield of 2 pyruvate, 2 NADH, and 2 net ATP.
8During pyruvate oxidation in the mitochondrial matrix, what key conversion must pyruvate undergo before entering the Krebs cycle?
A.Reduction to lactate by lactate dehydrogenase, releasing NADPH
B.Phosphorylation to fructose-1,6-bisphosphate by phosphofructokinase
C.Isomerization to oxaloacetate via ATP-dependent condensation
D.Decarboxylation and oxidation to form acetyl-CoA, releasing CO2 and reducing NAD+ to NADH
Explanation: In the mitochondrial matrix, pyruvate dehydrogenase converts 3-carbon pyruvate into 2-carbon acetyl-CoA. This oxidative decarboxylation removes one carbon atom as CO2, oxidizes the remaining acetyl group while reducing NAD+ to NADH, and attaches coenzyme A to yield acetyl-CoA, which then enters the Krebs cycle by condensing with oxaloacetate.
9What directly drives the synthesis of ATP by ATP synthase during oxidative phosphorylation in mitochondria?
A.Electrochemical proton gradient (proton-motive force) flowing from the intermembrane space back into the matrix
B.Direct transfer of phosphate groups from phosphoenolpyruvate onto ADP substrate molecules
C.Active transport of sodium ions from the matrix into the cytoplasm through protein channels
D.Oxidation of water molecules releasing high-energy oxygen gas directly to ATP synthase
Explanation: Electron transport chain complexes (I, III, and IV) pump protons (H+) from the mitochondrial matrix into the intermembrane space, generating a steep electrochemical gradient. Protons diffuse down this gradient back into the matrix through the F0 channel of ATP synthase, driving rotational conformational changes in the F1 catalytic subunit that phosphorylate ADP to ATP (chemiosmosis).
10What is the primary biological purpose of fermentation pathways (such as lactic acid or ethanol fermentation) under anaerobic conditions?
A.To produce maximum amounts of ATP per molecule of glucose oxidized
B.To generate oxygen gas required for mitochondrial electron transport
C.To regenerate NAD+ from NADH so that glycolysis can continue producing ATP
D.To convert toxic pyruvate into non-reactive carbon dioxide gas
Explanation: In the absence of oxygen (the terminal electron acceptor in aerobic respiration), electron transport halts and NADH accumulates. Fermentation pathways transfer electrons from NADH back onto pyruvate or its derivatives (forming lactate or ethanol + CO2), regenerating free NAD+ so glycolysis can continue generating 2 net ATP per glucose via substrate-level phosphorylation.

About the European Baccalaureate Biology Exam

The European Baccalaureate Biology evaluates S6-S7 European Baccalaureate candidates on official OSGES syllabus learning outcomes. Note: Official examinations consist of written constructed-response papers and oral assessments; the 100 questions provided here are an English-language MCQ study adaptation for core concept revision.

Exam sponsor: Office of the Secretary-General of the European Schools (OSGES). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Official written paper and/or oral examination; 100 local practice MCQs for self-assessment.

Time Limit

180 minutes (3 hours)

Passing Score

5.0 out of 10.0 (50%)

Exam / Certification Fees

EUR 111.49 Baccalaureate registration fee

Exam sponsor website

Reported exam pass rate: 85-90%. This describes exam candidates, not OpenExamPrep users or results from using our resources. Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

20%

Cell Biology & Biochemistry

Ultrastructure of prokaryotic and eukaryotic cells, organelle function, biological membranes and transport mechanisms, biomolecules, enzyme kinetics, cellular respiration, and photosynthesis.

20%

Molecular Biology & Genetics

Nucleic acid structure, DNA replication, transcription, RNA processing, translation, genetic code, gene expression regulation, Mendelian genetics, sex linkage, and gene mutations.

20%

Human Physiology & Homeostasis

Nervous impulse propagation, synaptic transmission, endocrine systems and hormonal control, osmoregulation and nephron function, blood circulation, and immune defense mechanisms.

20%

Ecology & Ecosystem Dynamics

Energy flow through trophic levels, biogeochemical cycles (carbon and nitrogen), population growth models, biotic/abiotic interactions, ecological succession, and human environmental impacts.

20%

Evolution & Biotechnology

Darwinian natural selection, speciation mechanisms, Hardy-Weinberg population genetics, phylogenetic analysis, recombinant DNA technology, PCR, gel electrophoresis, and genetic engineering.

Preparing for the European Baccalaureate Biology Exam

What You Need to Know

  • Passing score: 5.0 out of 10.0 (50%)
  • Assessment: Official written paper and/or oral examination; 100 local practice MCQs for self-assessment.
  • Time limit: 180 minutes (3 hours)
  • Exam / certification fees: EUR 111.49 Baccalaureate registration fee Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

European Baccalaureate Biology: Suggested Study Strategy

1Understand energy transformations in photosynthesis and cellular respiration, paying close attention to ATP yield, electron transport chains, and compartmentalization.
2Master central dogma processes (DNA replication, transcription, translation) and calculate Mendelian inheritance ratios for autosomal and sex-linked traits.
3Review homeostatic feedback loops in human physiology, especially kidney osmoregulation, thyroid/blood glucose regulation, and synaptic action potential transmission.
4Practice interpreting ecological models, including trophic efficiency calculations, logistic population growth curves, and nitrogen cycle pathways.
5Familiarize yourself with laboratory biotechnology tools, such as restriction endonuclease digestion patterns, gel electrophoresis bands, and PCR cycle steps.

Frequently Asked Questions

What is the format and duration of the European Baccalaureate Biology exam?

The official written examination lasts 180 minutes (3 hours) for the 4-period option. It assesses both theoretical concepts and analytical problem-solving skills.

What grading scale is used for the European Baccalaureate Biology exam?

The paper is marked on a 0 to 10 scale, with a passing threshold of 5.0 out of 10. Marks contribute directly to the candidate's final European Baccalaureate diploma grade.

Who sets the syllabus for European Baccalaureate Biology?

The syllabus is established and harmonized across all European Schools by the Office of the Secretary-General of the European Schools (OSGES).

What main topics are covered in the S6-S7 European Baccalaureate Biology syllabus?

The syllabus focuses on five major blocks: Cell Biology & Biochemistry, Molecular Genetics & Inheritance, Human Physiology & Homeostasis, Ecology & Ecosystem Dynamics, and Evolution & Biotechnology.