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100+ Free Saxony Abitur Mathematics Practice Questions

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2026 Statistics

Key Facts: Saxony Abitur Mathematics Exam

3 Sachgebiete

Every Prüfungsteil of the Sachsen Mathematik Abitur covers Analysis, Analytische Geometrie/Lineare Algebra and Stochastik

VwV Abiturprüfung 2026, Mathematik Struktur der Prüfungsarbeit

255 / 300 min

Written Gesamtarbeitszeit at Grundkurs- and Leistungskursniveau, including Auswahlzeit

VwV Abiturprüfung 2026, Arbeitszeiten Mathematik

100 / 110 min

Maximum time to hand in Prüfungsteil A (Grundkurs / Leistungskurs) before receiving Hilfsmittel

VwV Abiturprüfung 2026, Mathematik Prüfungsteile A und B

06.05.2026

Written Mathematik date in the 2026 main session; Nachprüfung 21.05.2026

schule.sachsen.de Gymnasium Terminübersicht Abiturprüfung 2026

0–15 Punkte

Grading scale for each Prüfungsfach, from Note 1 (15–13 Punkte) to Note 6 (0 Punkte)

Saxon Oberstufen-/Abiturprüfungsordnung (SOGYA) and related SMK VwV

IQB Formelsammlung

From 2026 Sachsen uses the Mathematisch-naturwissenschaftliche Formelsammlung des IQB in Prüfungsteil B (with MMS)

schule.sachsen.de; VwV Abiturprüfung 2026 Hilfsmittel

Free 100-question English-language MCQ study bank for Sachsen Abitur Mathematik, mapped to Analysis (~40%), Analytische Geometrie/Lineare Algebra (~30%) and Stochastik (~30%), with worked-calculation explanations. Official exam: German free-response Klausur, 255 min (GK) / 300 min (LK), written date 06.05.2026 (Nachprüfung 21.05.2026); MMS + IQB Formelsammlung in Prüfungsteil B only. Not an official-format simulation; no fee for regular school candidates.

Sample Saxony Abitur Mathematics Practice Questions

Try these sample questions to test your Saxony Abitur Mathematics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Using the limit definition of the Ableitung, f'(x0) = lim(h→0) [f(x0+h) − f(x0)] / h, find f'(4) for f(x) = x².
A.8
B.16
C.4
D.32
Explanation: [f(4+h)−f(4)]/h = [(16+8h+h²)−16]/h = (8h+h²)/h = 8+h. As h→0 this tends to 8, so f'(4) = 8, matching the Potenzregel f'(x)=2x at x=4.
2Geometrically, what does the Differenzenquotient [f(x0+h) − f(x0)] / h represent?
A.The slope of the secant line (Sekante) through (x0, f(x0)) and (x0+h, f(x0+h))
B.The slope of the tangent line at x0
C.The y-intercept of the graph
D.The area under the graph between x0 and x0+h
Explanation: The Differenzenquotient compares Δy to Δx between two distinct points, which is the slope of the Sekante joining them. Only as h→0 does it become the Tangentenanstieg (Differentialquotient).
3Evaluate lim(x→3) (x² − 9) / (x − 3).
A.6
B.0
C.The limit does not exist
D.3
Explanation: Factor: x²−9 = (x−3)(x+3), so the expression simplifies to x+3 for x≠3. The limit as x→3 is 3+3 = 6.
4For f(x) = −3x⁴ + 2x, what happens to f(x) as x → +∞?
A.f(x) → −∞
B.f(x) → +∞
C.f(x) → 0
D.f(x) oscillates without a limit
Explanation: The leading term −3x⁴ dominates. Even degree with negative leading coefficient means both ends fall, so f(x) → −∞ as x → +∞.
5Let f(x) = x³ − 5x. Compute f'(2).
A.7
B.12
C.3
D.8
Explanation: f'(x) = 3x² − 5 by Potenz- and Faktorregel. At x=2: f'(2) = 3·4 − 5 = 12 − 5 = 7.
6Let f(x) = 4x³ − 6x² + 1. Compute f'(1).
A.0
B.12
C.6
D.−6
Explanation: f'(x) = 12x² − 12x. At x=1: f'(1) = 12 − 12 = 0.
7What is the slope of the Tangente to f(x) = x² − 5x + 6 at x = 3?
A.1
B.6
C.0
D.−5
Explanation: f'(x) = 2x − 5. At x=3: f'(3) = 6 − 5 = 1, the Anstieg der Tangente.
8A Stammfunktion of f(x) = 6x² is F(x) = 2x³ + C. Which check confirms this via the Hauptsatz idea F' = f?
A.F'(x) = 6x² = f(x)
B.F'(x) = 2x³
C.F'(x) = 6x
D.F'(x) = 2x²
Explanation: Differentiating F(x) = 2x³ + C gives F'(x) = 6x², which equals f(x). That is the defining relationship behind the Hauptsatz der Differential- und Integralrechnung.
9Evaluate ∫ from 0 to 2 of 3x² dx.
A.8
B.6
C.4
D.12
Explanation: A Stammfunktion is x³. By the Hauptsatz: [2³] − [0³] = 8 − 0 = 8.
10The Skalarprodukt of a⃗ = (1, 2, 2) and b⃗ = (2, −1, 2) equals:
A.4
B.0
C.6
D.−2
Explanation: a·b = 1·2 + 2·(−1) + 2·2 = 2 − 2 + 4 = 4.

About the Saxony Abitur Mathematics Practice Questions

Verified exam format metadata for Saxony (Freistaat Sachsen) Abitur Mathematics (Mathematik) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.