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100+ Free Pancyprian Technical School Physics (4-hour) Practice Questions

Cyprus Pancyprian Access Examination Technical School Physics, 4-hour course (ΦΥΣΙΚΗ 4ΩΡΟ ΤΕΧΝΙΚΩΝ ΣΧΟΛΩΝ, code 047) practice questions are available now; exam metadata is being verified.

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2026 Statistics

Key Facts: Pancyprian Technical School Physics (4-hour) Exam

3 hours

Written paper duration per the 2026 Pancyprian timetable

Cyprus Examinations Service

Code 047

Subject code in the official 2026 exam guide (ΦΥΣΙΚΗ 4ΩΡΟ ΤΕΧΝΙΚΩΝ ΣΧΟΛΩΝ)

Cyprus Examinations Service

0-20

Marking scale; feeds the access/ranking grade with no pass/fail mark

Cyprus Examinations Service

4 periods/week

Weekly teaching time of the reduced technical-school physics course

Cyprus technical-school curriculum

24 June 2026

2026 exam date for this subject per the official timetable

Cyprus Examinations Service timetable

8-26 June 2026

Overall 2026 Pancyprian Access Examinations window

Cyprus Examinations Service

100 free MCQs covering the Pancyprian 4-hour technical-school physics syllabus, with over 30% worked numerical problems. This is an English-language study adaptation - the official exam is a 3-hour Greek-language written paper with constructed-response and problem-solving tasks, so practise full written solutions separately.

Sample Pancyprian Technical School Physics (4-hour) Practice Questions

Try these sample questions to test your Pancyprian Technical School Physics (4-hour) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Which of the following physical quantities is a vector?
A.Speed
B.Velocity
C.Distance
D.Temperature
Explanation: Velocity is a vector because it has both magnitude and direction. Speed, distance and temperature are scalars: they are fully described by a number and a unit, with no direction.
2What is the SI unit of acceleration?
A.m/s
B.m/s²
C.km/h
D.N
Explanation: Acceleration is the rate of change of velocity with time, so its unit is (m/s) per second, i.e. metres per second squared (m/s²).
3A car travels 150 m in a straight line in 10 s at constant speed. What is its speed?
A.10 m/s
B.15 m/s
C.25 m/s
D.150 m/s
Explanation: For uniform motion v = x/t = 150 m / 10 s = 15 m/s. Constant speed means equal distances are covered in equal times.
4A motorbike accelerates uniformly from 5 m/s to 25 m/s in 4.0 s. Its acceleration is:
A.5.0 m/s²
B.6.25 m/s²
C.7.5 m/s²
D.20 m/s²
Explanation: a = Δv/Δt = (25 − 5) / 4.0 = 20/4.0 = 5.0 m/s². Acceleration measures the change of velocity per unit time, not the final velocity itself.
5On a velocity–time graph, the area between the graph and the time axis represents:
A.The acceleration of the body
B.The displacement of the body
C.The average speed of the body
D.The force acting on the body
Explanation: Since displacement equals velocity multiplied by time for each small interval, the area under a v–t graph gives the total displacement. The gradient of the same graph gives acceleration.
6A stone is released from rest and falls freely. Taking g = 10 m/s², how far does it fall in the first 5.0 s? (Ignore air resistance.)
A.50 m
B.100 m
C.125 m
D.250 m
Explanation: For free fall from rest, s = ½gt² = ½ × 10 × 5.0² = 5 × 25 = 125 m. The distance grows with the square of the time, which is why 5 s gives far more than 5 × 10 = 50 m.
7In a vacuum, a hammer and a feather are dropped simultaneously from the same height. What happens?
A.The hammer lands first because it is heavier
B.The feather lands first because air resistance vanishes
C.They land at the same time with the same speed
D.The feather floats and never lands
Explanation: Without air resistance all bodies fall with the same acceleration g, independent of their mass — as demonstrated famously on the Moon. Starting from the same height, they take the same time and reach the same speed.
8A car travelling at 20 m/s brakes with constant deceleration of 4.0 m/s² until it stops. The stopping distance is:
A.40 m
B.50 m
C.80 m
D.100 m
Explanation: Using v² = u² + 2as with v = 0: 0 = 20² − 2 × 4.0 × s, so s = 400 / 8.0 = 50 m. Stopping distance grows with the square of the initial speed.
9A body moves with uniform (constant-velocity) rectilinear motion. Its position–time graph is:
A.A parabola
B.A straight line through the origin with constant slope
C.A horizontal line in all cases
D.A curve whose slope increases with time
Explanation: In uniform motion x = vt (if it starts at the origin), so the x–t graph is a straight line whose slope equals the velocity. A horizontal x–t line would mean the body is at rest.
10A lorry drives 60 km from Limassol to Nicosia at an average speed of 30 km/h and returns along the same route at 60 km/h. Its average speed for the whole journey is:
A.40 km/h
B.45 km/h
C.48 km/h
D.50 km/h
Explanation: Total distance = 120 km. Time out = 60/30 = 2 h, time back = 60/60 = 1 h, total 3 h. Average speed = 120/3 = 40 km/h. Average speed is total distance over total time, not the mean of the two speeds.

About the Pancyprian Technical School Physics (4-hour) Practice Questions

Verified exam format metadata for Cyprus Pancyprian Access Examination Technical School Physics, 4-hour course (ΦΥΣΙΚΗ 4ΩΡΟ ΤΕΧΝΙΚΩΝ ΣΧΟΛΩΝ, code 047) is pending. The practice questions above remain available while official exam length, timing, passing score, fee, and administrator details are reviewed.