All Practice Exams

Free Practice Questions for Pancyprian Chemistry

Exam-style questions and explanations by OpenExamPrep.

✓ No registration✓ No credit card
100+ Questions
100% Free

Loading practice questions...

Exam Review

Key Facts: Pancyprian Chemistry Exam

019

Official subject code for ΧΗΜΕΙΑ in the 2026 Pancyprian Access Examinations

Cyprus Examinations Service

3 hours per the official 2026 timetable

Official examination duration from the 2026 timetable

Cyprus Examinations Service

EUR 25

2026 fee per access subject (not code 032)

Cyprus Examinations Service

0–20

Marking scale for each Pancyprian subject

Cyprus Examinations Service

8–26 June 2026

Examination period of the 2026 Pancyprian Access Examinations

Cyprus Examinations Service

100

Original practice questions in this study bank

OpenExamPrep

Free 100-question English-language MCQ study bank for Pancyprian Chemistry (code 019). Official duration: 3 hours per the official 2026 timetable. Official fee: EUR 25.00 per access subject in 2026. This bank is a study aid, not an official translation or format simulation.

Sample Pancyprian Chemistry Practice Questions

Try these sample questions to review concepts for the Pancyprian Chemistry exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1How many moles are contained in 11.0 g of carbon dioxide, CO2? (Molar mass of CO2 = 44.0 g/mol)
A.0.25 mol
B.0.50 mol
C.1.0 mol
D.4.0 mol
Explanation: Moles are calculated as n = m/M = 11.0 g / 44.0 g/mol = 0.25 mol. This is the fundamental mass-to-moles conversion used throughout stoichiometry.
2A solution is prepared by dissolving 0.50 mol of NaCl in water and making the total volume up to 2.0 L. What is the molar concentration of the solution?
A.1.0 M
B.0.50 M
C.0.25 M
D.4.0 M
Explanation: Molarity c = n/V = 0.50 mol / 2.0 L = 0.25 mol/L. Concentration always refers to the final total volume of solution, not the volume of water added.
3How many O2 molecules are present in 2.00 mol of oxygen gas? (Avogadro's constant NA = 6.02 x 10^23 mol^-1)
A.6.02 x 10^23
B.1.204 x 10^24
C.3.01 x 10^23
D.2.41 x 10^24
Explanation: Number of particles N = n x NA = 2.00 mol x 6.02 x 10^23 mol^-1 = 1.204 x 10^24 molecules. One mole of any substance contains Avogadro's number of particles.
450.0 mL of a 2.0 M HCl solution is diluted with water to a final volume of 250 mL. What is the concentration of the diluted solution?
A.0.10 M
B.0.25 M
C.8.0 M
D.0.40 M
Explanation: During dilution the moles of solute stay constant, so c1V1 = c2V2: c2 = (2.0 M x 50.0 mL) / 250 mL = 0.40 M. The volume increased fivefold, so the concentration falls fivefold.
5For the reaction 2H2 + O2 -> 2H2O, a mixture contains 4 mol of H2 and 3 mol of O2. What is the maximum amount of water that can be produced?
A.6 mol
B.4 mol
C.3 mol
D.2 mol
Explanation: 4 mol of H2 requires only 2 mol of O2 (ratio 2:1), so H2 is the limiting reactant. From the 2:2 ratio, 4 mol of H2 produces 4 mol of H2O, leaving 1 mol of O2 in excess.
620 g of NaCl is dissolved in 180 g of water. What is the mass percent (% w/w) concentration of the solution?
A.11.1%
B.20%
C.10%
D.9.1%
Explanation: Mass percent = (mass of solute / mass of solution) x 100 = 20 g / (20 g + 180 g) x 100 = 10%. The denominator is the total mass of the solution, not the mass of the solvent.
7What is the molar mass of calcium hydroxide, Ca(OH)2? (Ar: Ca = 40, O = 16, H = 1)
A.74 g/mol
B.57 g/mol
C.68 g/mol
D.90 g/mol
Explanation: M = 40 + 2 x (16 + 1) = 40 + 34 = 74 g/mol. The subscript 2 outside the bracket multiplies the whole OH group, so the formula unit contains 2 O and 2 H atoms.
8What volume does 1.00 mol of an ideal gas occupy at 273 K and 1.00 atm (standard temperature and pressure)?
A.11.2 L
B.24.5 L
C.44.8 L
D.22.4 L
Explanation: At STP (273 K, 1 atm) one mole of any ideal gas occupies the molar volume 22.4 L. This follows from V = nRT/P with R = 0.0821 L atm K^-1 mol^-1.
9In the ammonia synthesis N2 + 3H2 -> 2NH3, how many moles of NH3 are produced when 9 mol of H2 reacts completely with excess N2?
A.9 mol
B.3 mol
C.6 mol
D.13.5 mol
Explanation: The mole ratio H2:NH3 is 3:2, so n(NH3) = 9 mol x (2/3) = 6 mol. Stoichiometric coefficients give the conversion factor between reactant and product.
10When 50 g of pure CaCO3 is completely decomposed by heating (CaCO3 -> CaO + CO2), what volume of CO2 is released at STP? (M(CaCO3) = 100 g/mol; molar volume at STP = 22.4 L/mol)
A.22.4 L
B.11.2 L
C.5.6 L
D.44.8 L
Explanation: n(CaCO3) = 50 g / 100 g/mol = 0.50 mol. The 1:1 ratio gives 0.50 mol of CO2, which at STP occupies 0.50 x 22.4 L = 11.2 L.

About the Pancyprian Chemistry Exam

The Pancyprian Access Examination in Chemistry (code 019, ΧΗΜΕΙΑ) is a centrally set 2026 subject assessment administered by the Examinations Service of the Cyprus Ministry of Education, Sport and Youth for university admission ranking in Cyprus and Greece. A 3-hour written Chemistry paper in Greek with theory and quantitative problem-solving. English-language MCQ study adaptation including calculation items; not an official translation or format simulation.

Exam sponsor: Examinations Service, Cyprus Ministry of Education, Sport and Youth. The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

A 3-hour written Chemistry paper in Greek with theory and quantitative problem-solving. English-language MCQ study adaptation including calculation items; not an official translation or format simulation.

Time Limit

3 hours per the official 2026 timetable

Passing Score

Marked on a 0–20 scale; no pass mark — feeds the access/ranking grade (βαθμός πρόσβασης) for Cyprus and Greece public university allocation.

Exam / Certification Fees

EUR 25.00 per access subject for 2026 (EUR 50.00 only for Practical Physical Performance Test code 032), payable electronically by card during the official 2–17 April 2026 payment window per Examinations Service notices.

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

30%

Stoichiometry And Solutions

Practice coverage of stoichiometry and solutions mapped to the official Pancyprian syllabus for this subject.

20%

Acids Bases And Ph

Practice coverage of acids bases and ph mapped to the official Pancyprian syllabus for this subject.

20%

Organic Chemistry

Practice coverage of organic chemistry mapped to the official Pancyprian syllabus for this subject.

15%

Chemical Equilibrium

Practice coverage of chemical equilibrium mapped to the official Pancyprian syllabus for this subject.

15%

Redox Electrochemistry

Practice coverage of redox electrochemistry mapped to the official Pancyprian syllabus for this subject.

Preparing for the Pancyprian Chemistry Exam

What You Need to Know

  • Passing score: Marked on a 0–20 scale; no pass mark — feeds the access/ranking grade (βαθμός πρόσβασης) for Cyprus and Greece public university allocation.
  • Assessment: A 3-hour written Chemistry paper in Greek with theory and quantitative problem-solving. English-language MCQ study adaptation including calculation items; not an official translation or format simulation.
  • Time limit: 3 hours per the official 2026 timetable
  • Exam / certification fees: EUR 25.00 per access subject for 2026 (EUR 50.00 only for Practical Physical Performance Test code 032), payable electronically by card during the official 2–17 April 2026 payment window per Examinations Service notices. Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

Pancyprian Chemistry: Suggested Study Strategy

1Read the official 2026 specification row for code 019 (ΧΗΜΕΙΑ) on the Examinations Service guide before drilling MCQs.
2After each wrong answer, rewrite the rule or concept in your own words with one new example.
3Schedule weekly timed practice with official past papers so you build the non-MCQ skills the real paper requires.
4Track weak categories from this bank and re-test them after 48 hours.
5Confirm logistics (centre, materials, language of response) from panexams.moec.gov.cy announcements, not from third-party summaries.

Frequently Asked Questions

Is this the official Pancyprian Chemistry exam?

No. The official assessment is administered by the Cyprus Examinations Service as a constructed-response, drawing, performance or mixed paper under code 019. This bank is a free English-language MCQ study adaptation for revision; practise every required non-MCQ component with official past papers and the specification.

How is the subject marked?

Like all Pancyprian access subjects it is marked on a 0–20 scale. There is no pass mark; the grade contributes to the access/ranking grade used for admission to public universities in Cyprus and Greece.

What is the 2026 exam fee?

EUR 25.00 per access subject (EUR 50.00 only for Practical Physical Performance Test code 032), payable by card in the official 2–17 April 2026 window, with exemptions for specified groups.

Who can sit this examination?

Final-year student or graduate of a Cyprus public secondary school (lyceum cycle), the English School Nicosia, a licensed private school, or an equivalent foreign upper-secondary school (with certification), within Examinations Service nationality/residence rules. Applications are electronic; un-promoted final-year students with 135+ absences are excluded.

Why is the practice bank in English?

OpenExamPrep publishes one English-language practice URL per exam. Where the tested skill is another language, stems/options may retain that language while explanations stay in English. The bank is not an official translation of the Greek (or other) exam environment.

How should I use this bank with official materials?

Use the bank to diagnose weak syllabus areas, then switch to Θέματα - Λύσεις and the official specification on panexams.moec.gov.cy for timed written, drawing or performance practice that this bank does not simulate.