100+ Free Ruankao Network Planning Designer (Senior) Practice Questions

Prepare for the Computer Technology and Software Professional Qualification (Level) Examination — Senior Network Planning Designer (计算机技术与软件专业技术资格（水平）考试 — 高级网络规划设计师) exam with instant access — no signup required.

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2026 Statistics

Key Facts: Ruankao Network Planning Designer (Senior) Exam

45/75 × 3

Passing score required on each of the three subjects in the same sitting

National 软考 fixed passing standard (60% of 75) cited in 深人考发〔2026〕7号

240 + 120 minutes

Combined 综合知识+案例分析 then separate 论文

软考 computer-based sitting rules for senior qualifications

150 / 120 minutes

综合知识 maximum / minimum before leftover time goes to 案例分析

软考 senior CBT combined-sitting rule

24–27 Oct 2026

Only 2026 sitting window for Network Planning Designer

计考办〔2026〕1号 / 深人考发〔2026〕7号

RMB 73/subject

Guangdong/Shenzhen fee example

粤发改价格函〔2024〕1073 via 深人考发〔2026〕7号

No score rollover

All three subjects must be passed together

软考 three-subject sitting rule

软考 Senior Network Planning Designer is a Chinese CBT qualification: choice plus case papers in one 240-minute sitting (综合知识 max 150 / min 120 minutes) and a 120-minute 论文, 45/75 on each of three subjects, no score rollover. The 2026 sitting is 24–27 October 2026 only. This 100-question English MCQ bank adapts TCP/IP, large-network design, security products, and case/paper judgment; it is not an official paper.

Sample Ruankao Network Planning Designer (Senior) Practice Questions

Try these sample questions to test your Ruankao Network Planning Designer (Senior) exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1In 软考网络规划设计师 computer-system teaching, which description matches classic Von Neumann architecture?

A.Instructions and data use completely separate memories with no shared bus

B.A single main memory holds both instructions and data on a shared bus

C.The ALU stores the operating system in ROM and never reads RAM

D.I/O devices fetch and execute the machine-instruction stream instead of the CPU

Explanation: Von Neumann architecture stores programs and data in the same main memory and uses a shared bus, so instruction fetch and data access compete (the Von Neumann bottleneck). Harvard architecture splits instruction and data memories. The ALU does not replace RAM as the OS store, and I/O devices do not execute the instruction stream in place of the CPU.

2A disk array must copy a large backup image into RAM with minimal per-byte CPU involvement. Which I/O method is designed for that transfer?

A.Programmed I/O that busy-waits on every byte in the CPU

B.DMA (direct memory access) by a controller into main memory

C.Disabling interrupts and having the CPU poll the controller status register

D.Replacing the memory bus with an RS-232 serial console

Explanation: DMA lets an I/O controller move blocks between a device and main memory while the CPU continues other work, with an interrupt typically only at completion. Programmed I/O/polling burns CPU cycles on every transfer. Keyboard polling and RS-232 consoles are unrelated to bulk disk-to-RAM copies.

3A file server needs to survive any single disk failure and keep most of the raw capacity. Which RAID level stripes data and distributed parity (not a full mirror)?

A.RAID 0 striping with no redundancy

B.RAID 1 mirroring of entire disks

C.RAID 5 striped data with distributed parity

D.JBOD concatenation with no RAID protection

Explanation: RAID 5 stripes data and parity across disks so any one disk can fail and capacity is about (N−1) disks. RAID 0 has no redundancy. RAID 1 mirrors whole disks and uses 50% of raw capacity on a pair. JBOD is not a redundant RAID level.

4Why do 网络规划设计师 textbooks place SRAM cache between the CPU and DRAM?

A.To hold recently used blocks so average access time is lower than DRAM alone

B.To assign public IPv4 addresses to campus hosts

C.To terminate BGP sessions on the processor die

D.To convert analog voice to Ethernet frames

Explanation: Cache exploits temporal and spatial locality: recently or nearby referenced blocks are reused in fast SRAM, so the CPU waits on DRAM less often. Cache does not allocate IP addresses, speak BGP, or act as a voice codec or NIC.

5A classic telephone voice channel is band-limited to 4 kHz and sampled at the Nyquist rate with 8-bit linear PCM. What is the resulting bit rate?

A.32 kbps

B.64 kbps

C.128 kbps

D.1.544 Mbps

Explanation: Nyquist sampling of a 4 kHz analog voice signal requires at least 8 kHz. With 8 bits per sample, 8000 × 8 = 64 000 bit/s, the DS0/E0 64 kbps timeslot used in PCM hierarchies. 32 kbps is a common ADPCM rate, 128 kbps is two such channels, and 1.544 Mbps is a T1 line rate, not a single voice PCM stream.

6Nyquist’s noiseless-channel formula is C = 2B log2(M). For B = 4 kHz and 16-level signaling (M = 16), what is C?

A.8 kbps

B.16 kbps

C.32 kbps

D.64 kbps

Explanation: log2(16) = 4, so C = 2 × 4000 × 4 = 32 000 bit/s. The factor 2B is the maximum symbol rate; each symbol carries 4 bits when M = 16. 8 kbps would be 2B with binary signaling forgotten; 16 kbps is B log2(M) without the 2; 64 kbps is PCM voice, not this Nyquist example.

7Ethernet frames carry a 32-bit FCS. Which error-detection method is that FCS?

A.Even parity over each byte only

B.A simple Internet checksum as in IPv4 headers

C.CRC (cyclic redundancy check) using a generator polynomial

D.A Hamming SECDED code that corrects two-bit errors in hardware

Explanation: IEEE 802.3 uses a CRC-32 frame check sequence computed from a generator polynomial; it detects burst errors far better than per-byte parity or the IPv4 header checksum. Ethernet FCS is detection, not a Hamming corrector for two-bit errors on the wire.

8DWDM packs many optical channels onto one fiber by assigning each channel a different wavelength. That is an example of which multiplexing method?

A.TDM (time-division multiplexing) of 64 kbps timeslots only

B.FDM/WDM (frequency/wavelength-division multiplexing)

C.Statistical multiplexing of Ethernet collision domains

D.CDMA spreading codes on a copper access loop

Explanation: WDM (including DWDM/CWDM) is optical frequency-division multiplexing: channels occupy different wavelengths on one fiber. TDM shares time slots on one wavelength or electrical stream. Ethernet statistical multiplexing and CDMA are different sharing methods and are not how DWDM grids are built.

9Classic 10BASE5/10BASE-T Ethernet used Manchester line coding. What is the characteristic of Manchester encoding?

A.A mid-bit transition represents the bit and also supplies a clock edge

B.A long string of 1s produces no transitions, so the receiver loses clock

C.Each bit is sent as five baud using 4B/5B as on FDDI only

D.The line is analog QAM with no binary mid-bit edge

Explanation: Manchester encoding places a guaranteed transition in the middle of each bit interval, encoding the bit value by the direction of that edge and giving the receiver a clock. NRZ can have long runs without transitions. 4B/5B is a block code used on 100BASE-X/FDDI, not Manchester. QAM is a passband analog scheme.

10Two codewords differ in 3 bit positions (Hamming distance 3). How many bit errors can this code always detect, and how many can it always correct?

A.Detect 3 and correct 3

B.Detect 2 and correct 1

C.Detect 1 and correct 2

D.Detect 0 and correct 3

Explanation: For minimum distance d, a code can detect up to d−1 errors and correct up to floor((d−1)/2) errors. With d = 3 that is detect 2 and correct 1. It cannot reliably correct 2-bit errors or detect 3-bit errors as a guaranteed bound.

About the Ruankao Network Planning Designer (Senior) Exam

The Ruankao Senior Network Planning Designer exam (软考高级网络规划设计师) is a national computer-technology qualification under MIIT and MOHRSS. Official 考试说明 (https://www.ruankao.org.cn/article/content/bkzn/03_04.html) requires data communication, computer networks and systems, LAN/WAN/Internet, TCP/IP, network computing and applications, network products, cybersecurity products, project management for network projects, large-network design/deploy/manage, test/evaluation, laws/standards, applied math/econ/management, and English reading. Qualified candidates produce network requirements specifications, logical and physical designs, project plans, and test/ops mechanisms at 高级工程师 level. The qualification is offered only in the 2026 lower-half window 24–27 October 2026 per 计考办〔2026〕1号 / 深人考发〔2026〕7号. Delivery is computer-based in Chinese: 综合知识+案例分析 combined 240 minutes, then 论文 120 minutes. All three papers must reach 45/75; scores do not roll. There is no education or experience restriction under 国人部发〔2003〕39号. Fees are set provincially. This OpenExamPrep bank is an English-language MCQ study adaptation, not an official translation or a substitute for the written case and 论文 papers.

Assessment

Computer-based senior sitting. 综合知识 and 案例分析 are combined for 240 minutes: 综合知识 maximum 150 minutes and minimum 120 minutes; leftover time is 案例分析. After submitting 综合知识, candidates who will not sit 案例分析 may leave; those continuing may leave 60 minutes before the combined end. 论文 is 120 minutes and may not be submitted early. All three subjects must reach 45/75 in the same sitting; scores do not roll.

Time Limit

240 minutes (综合知识+案例分析) + 120 minutes (论文)

Passing Score

45/75 each of three subjects

Exam Fee

Provincially set (e.g. Guangdong/Shenzhen RMB 73/subject per 粤发改价格函〔2024〕1073 and 深人考发〔2026〕7号) (MIIT & MOHRSS / ruankao.org.cn)

Ruankao Network Planning Designer (Senior) Exam Content Outline

12%

data-communication-and-computer-systems

Data-communication principles (capacity, encoding, multiplexing, error control) and computer-system basics named in the official 考试说明

22%

lan-wan-internet-tcpip

LAN/WAN/Internet technologies and TCP/IP, including IPv4 subnetting and link-capacity calculations used on 综合知识 and 案例分析

15%

network-products-and-applications

Network products (routers, switches, WLAN, load balancers, storage) and network computing/application deployment norms

15%

security-products-and-policy

Cybersecurity and information-security technology, security products (firewall, VPN, IPS, WAF, 网闸), and application policy including 等保

20%

large-network-design-deploy-test

Large- and medium-network logical/physical design, hierarchical core/aggregation/access, dual-core dual-link deploy, and test/evaluation (RFC 2544, Y.1564, OTDR)

16%

project-management-law-math-case

Network-project PM tools, PRC laws/standards, applied math/econ/management, 案例分析 judgment, and 论文 structure

How to Pass the Ruankao Network Planning Designer (Senior) Exam

What You Need to Know

Passing score: 45/75 each of three subjects
Assessment: Computer-based senior sitting. 综合知识 and 案例分析 are combined for 240 minutes: 综合知识 maximum 150 minutes and minimum 120 minutes; leftover time is 案例分析. After submitting 综合知识, candidates who will not sit 案例分析 may leave; those continuing may leave 60 minutes before the combined end. 论文 is 120 minutes and may not be submitted early. All three subjects must reach 45/75 in the same sitting; scores do not roll.
Time limit: 240 minutes (综合知识+案例分析) + 120 minutes (论文)
Exam fee: Provincially set (e.g. Guangdong/Shenzhen RMB 73/subject per 粤发改价格函〔2024〕1073 and 深人考发〔2026〕7号)

Keys to Passing

Work through all 100 available questions
Review every answer and explanation
Track weak areas and revisit them
Use our AI tutor for tough concepts

Ruankao Network Planning Designer (Senior) Study Tips from Top Performers

1Drill IPv4 VLSM and usable-host arithmetic (2^h − 2) until you can size campus VLANs without a calculator.

2On hierarchical-design items, map functions: core = high-speed forwarding, 汇聚层 = VLAN routing/ACL/QoS, 接入层 = user access and port security.

3For capacity items, convert units first (MB vs Mb) and apply utilization or oversubscription explicitly.

4Memorize 等保2.0 technical classes (安全物理环境, 安全通信网络, 安全区域边界, 安全计算环境, 安全管理中心) and CII 三同步 (同步规划、同步建设、同步使用).

5Treat 案例分析 as constraint-reading: name the missing redundancy, the wrong OSPF area, or the device placed on the wrong layer before you calculate.

6For 论文, pick the topic that matches a real project you can describe (role, topology, technologies, problems, results); write the abstract last so it matches the body.

Frequently Asked Questions

What is the Ruankao Senior Network Planning Designer qualification?

It is the Senior Network Planning Designer subject (高级网络规划设计师) in the Computer Technology and Software Professional Qualification (Level) Examination (软考). Official 考试说明: https://www.ruankao.org.cn/article/content/bkzn/03_04.html. Passing confers the corresponding senior professional qualification (高级工程师 level).

How is the official exam structured and scored?

Three subjects must be passed together. 综合知识 and 案例分析 are combined for 240 minutes: 综合知识 maximum 150 minutes and minimum 120 minutes; leftover time is 案例分析. 论文 is 120 minutes and may not be handed in early. Each subject is scored out of 75; all three must reach 45 in the same sitting. Scores do not roll.

Who may sit the exam, and what does it cost?

There is no education or experience restriction under 国人部发〔2003〕39号. Fees are set by each province. Shenzhen/Guangdong charge RMB 73 per subject (深人考发〔2026〕7号 citing 粤发改价格函〔2024〕1073), so three subjects are billed as three fees in that example.

When is the 2026 sitting?

Network Planning Designer is offered only in the lower-half-year window. Provincial notices implementing 计考办〔2026〕1号 place the 2026 sitting on 24–27 October 2026. It is not in the May 2026 upper-half list. Register through https://www.ruankao.org.cn/.

Why are these practice questions in English?

The official exam is in Chinese (officialLanguages: zh). 案例分析 is a written short-answer paper and 论文 is a written essay. This OpenExamPrep bank is an English-language MCQ study adaptation of syllabus knowledge and case/paper judgment. It is not an official translation, not a CBT simulation, and not a substitute for practicing Chinese case write-ups and 论文.