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93+ Free ЦТ Physics Practice Questions

Prepare for the ЦТ/ЦЭ Physics (Belarus Centralized Testing / Centralized Exam) exam with instant access — no signup required.

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2026 Statistics

Key Facts: ЦТ Physics Exam

30

total tasks (10 Part A + 20 Part B)

РИКЗ Specification 2026

210 min

exam duration

РИКЗ

0–100

score scale

Ministry of Education of Belarus

4.50 BYN

registration fee per subject (0.1 base amount)

РИКЗ 2026

20 / 10

minimum admission cutoff points

Ministry of Education Rules

The Belarus ЦТ/ЦЭ Physics examination has 30 tasks (10 Part A + 20 Part B) completed in 210 minutes. Scored 0–100 with admission cutoffs of 20 points (1st profile) and 10 points (2nd profile), registration costs 0.1 base amount (4.50 BYN in 2026). Practice with 93 questions covering mechanics, thermodynamics, and electromagnetism.

Sample ЦТ Physics Practice Questions

Try these sample questions to test your ЦТ Physics exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 93+ question experience with AI tutoring.

1A cyclist travels the first half of a straight distance at a constant speed of v1 = 12 km/h and the second half of the distance at a constant speed of v2 = 20 km/h. What is the average speed of the cyclist over the entire distance?
A.15.0 km/h
B.16.0 km/h
C.14.4 km/h
D.18.0 km/h
Explanation: Average speed over equal distance segments is given by the harmonic mean: v_avg = 2 / (1/v1 + 1/v2) = 2 * v1 * v2 / (v1 + v2) = 2 * 12 * 20 / (12 + 20) = 480 / 32 = 15.0 km/h.
2A car starts from rest with a constant acceleration of a = 2.0 m/s². What distance does the car cover during the fourth second of its motion (from t = 3 s to t = 4 s)?
A.16.0 m
B.7.0 m
C.8.0 m
D.9.0 m
Explanation: The distance traveled during the n-th second from rest is given by s_n = a/2 * (2n - 1). For n = 4 and a = 2.0 m/s²: s_4 = (2.0 / 2) * (2*4 - 1) = 1.0 * 7 = 7.0 m. Alternatively, s(4) - s(3) = 0.5 * 2 * 4² - 0.5 * 2 * 3² = 16 - 9 = 7.0 m.
3A body is thrown vertically upward with an initial velocity of v0 = 30 m/s. Taking g = 10 m/s² and neglecting air resistance, what is the height of the body 4.0 seconds after the launch?
A.45 m
B.50 m
C.40 m
D.35 m
Explanation: Using the vertical displacement formula h(t) = v0*t - 0.5*g*t²: h(4) = 30 * 4 - 0.5 * 10 * 4² = 120 - 5 * 16 = 120 - 80 = 40 m.
4A stone is thrown horizontally from a tower of height h = 20 m with an initial speed of v0 = 15 m/s. Taking g = 10 m/s² and neglecting air resistance, what is the magnitude of the stone's velocity just before it hits the ground?
A.20 m/s
B.35 m/s
C.18 m/s
D.25 m/s
Explanation: The vertical component of velocity upon impact is v_y = sqrt(2*g*h) = sqrt(2 * 10 * 20) = sqrt(400) = 20 m/s. The horizontal component remains constant at v_x = 15 m/s. The total speed is v = sqrt(v_x² + v_y²) = sqrt(15² + 20²) = sqrt(225 + 400) = sqrt(625) = 25 m/s.
5A projectile is launched from ground level with an initial velocity of v0 = 20 m/s at an angle of 30° to the horizontal. Taking g = 10 m/s², what is the flight time of the projectile until it returns to the ground?
A.2.0 s
B.1.0 s
C.3.0 s
D.1.5 s
Explanation: The total flight time for a projectile returning to launch level is T = (2 * v0 * sin(alpha)) / g = (2 * 20 * sin(30°)) / 10 = (40 * 0.5) / 10 = 2.0 s.
6A point on the rim of a wheel of radius R = 0.5 m rotates with a constant linear speed of v = 4 m/s. What is the centripetal acceleration of this point?
A.8 m/s²
B.32 m/s²
C.16 m/s²
D.4 m/s²
Explanation: Centripetal acceleration is given by a_c = v² / R = 4² / 0.5 = 16 / 0.5 = 32 m/s².
7Two trains move towards each other on parallel tracks with speeds of 72 km/h (20 m/s) and 54 km/h (15 m/s) relative to the ground. The length of the first train is 140 m and the length of the second train is 210 m. How long does it take for them to pass completely by each other?
A.14 s
B.20 s
C.10 s
D.7 s
Explanation: The relative speed when moving toward each other is v_rel = v1 + v2 = 20 + 15 = 35 m/s. The total distance to clear each other is the sum of their lengths: L = L1 + L2 = 140 + 210 = 350 m. The time required is t = L / v_rel = 350 / 35 = 10 s.
8A vehicle moving at a speed of v0 = 20 m/s brakes with a constant acceleration of magnitude a = 4.0 m/s². What is the stopping distance of the vehicle?
A.40 m
B.80 m
C.100 m
D.50 m
Explanation: Using the kinematic formula v² - v0² = -2*a*s with final velocity v = 0: s = v0² / (2*a) = 20² / (2 * 4.0) = 400 / 8.0 = 50 m.
9A horizontal force of F = 18 N is applied to a box of mass m = 3.0 kg on a rough horizontal floor. The coefficient of kinetic friction is mu = 0.20. Taking g = 10 m/s², what is the acceleration of the box?
A.4.0 m/s²
B.6.0 m/s²
C.2.0 m/s²
D.5.0 m/s²
Explanation: The normal force is N = m*g = 3.0 * 10 = 30 N. The friction force is F_fr = mu * N = 0.20 * 30 = 6.0 N. By Newton's second law: F_net = F - F_fr = 18 - 6.0 = 12 N. Acceleration a = F_net / m = 12 / 3.0 = 4.0 m/s².
10A block of mass m = 2.0 kg slides down an inclined plane angled at alpha = 30° with a constant speed. What is the coefficient of kinetic friction mu between the block and the incline?
A.0.50
B.0.58
C.0.87
D.0.29
Explanation: When a block slides down at a constant speed, acceleration is zero, meaning the component of gravity down the incline balances friction: m*g*sin(alpha) = mu * m*g*cos(alpha). Therefore, mu = tan(alpha) = tan(30°) = 1 / sqrt(3) ≈ 0.58 (or sqrt(3)/3).

About the ЦТ Physics Exam

The Physics Centralized Testing (ЦТ) and Centralized Exam (ЦЭ) is the core engineering and physical science entrance examination administered by RIKZ in Belarus. The test consists of 30 tasks (10 closed-ended Part A items and 20 open-ended Part B items) sat over 210 minutes (3.5 hours). A simple single-line calculator (arithmetic operations, square root, percentages, one memory cell) is permitted. This practice bank provides 93 worked quantitative and conceptual questions covering all official RIKZ domains.

Questions

30 scored questions

Time Limit

210 minutes

Passing Score

20/100 (1st profile) or 10/100 (2nd profile)

Exam Fee

4.50 BYN (Republican Institute for Knowledge Control (РИКЗ))

ЦТ Physics Exam Content Outline

~30%

Mechanics

Kinematic equations, Newton's laws, gravitation, momentum and energy conservation, work, power, and oscillations.

~20%

Molecular Physics & Thermodynamics

Mendeleev-Clapeyron equation, isobaric/isochoric/isothermal processes, internal energy, heat, and efficiency.

~25%

Electromagnetism

Coulomb's law, electric field, Ohm's law, Kirchhoff's rules, Lorentz force, Faraday's law, and inductance.

~15%

Optics

Snell's law, thin lens formula, ray tracing, interference, diffraction grating, and photon energy.

~10%

Quantum & Nuclear Physics

Einstein's photoelectric equation, atomic energy levels, alpha/beta decay, and binding energy.

How to Pass the ЦТ Physics Exam

What You Need to Know

  • Passing score: 20/100 (1st profile) or 10/100 (2nd profile)
  • Exam length: 30 questions
  • Time limit: 210 minutes
  • Exam fee: 4.50 BYN

Keys to Passing

  • Work through all 93 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

ЦТ Physics Study Tips from Top Performers

1Review standard physical constants (g = 9.8 or 10 m/s², c, h, e, R, NA, k) and ensure consistent SI unit conversion.
2Practice drawing free-body diagrams for dynamics problems involving friction, inclined planes, and pulley systems.
3Master circuit reduction techniques and power dissipation formulas in series-parallel resistor networks.
4Work through the 100 practice items to build calculation speed and verify formula applications.

Frequently Asked Questions

What is the format of the ЦТ Physics exam?

The official RIKZ examination comprises 30 tasks: 10 closed multiple-choice tasks in Part A and 20 open numerical calculation tasks in Part B, taking 210 minutes.

Are calculators allowed on the ЦТ Physics test in Belarus?

Yes. Simple, non-programmable calculators capable of performing basic arithmetic operations and trigonometric functions (without text storage or communication capabilities) are officially allowed.

What is the passing score for university engineering programs?

When Physics is the 1st profile subject, the minimum admission cutoff is 20 points out of 100; when it is the 2nd profile subject, the cutoff is 10 points.

How much is the exam registration fee?

The fee for Centralized Testing (ЦТ) is 0.1 of a base amount (4.50 BYN in 2026) per subject. The Centralized Exam (ЦЭ) for school graduates is free.

Is this bank the same language and format as the real ЦТ Physics paper?

No. The official RIKZ paper is sat in Belarusian or Russian and consists of 10 Part A items offering five answer options plus 20 Part B tasks whose answers must be written out as whole numbers in the stated units. This bank is an English-language MCQ study adaptation with four options per question — a study aid for the official content, not an official translation or a format simulation.