Part-66 Module 1 Exam Flashcards

Q: How many questions are on the EASA Part-66 Module 1 exam?

Category A candidates sit 16 multiple-choice questions in 20 minutes. B1, B2, B2L, and B3 sit 32 in 40 minutes. All use a 75% pass mark and three-option questions.

Q: What topics does Module 1 Mathematics cover?

The current legal table has six broad rows: arithmetic, simple algebraic expressions, equations, simple geometrical constructions, graphical representation, and trigonometry. Category A uses only arithmetic, expressions, and graphs.

Q: What happens if I fail a Part-66 module exam?

A failed module normally requires a 90-day wait. A retake may occur after 30 days following qualifying tailored Part-147 retraining. Separately, each examination is limited to three attempts in a 12-month period.

Q: Do I need to memorise formulas, or is a formula sheet provided?

Calculators are not allowed under EASA guidance, so practise manual calculation. Confirm practical arrival, accommodation, and any supplied-reference instructions with the examining organisation.

Q: Which regulation sets the current Module 1 syllabus, and does it affect these flashcards?

Use the current consolidated Regulation (EU) No 1321/2014 and latest applicable AMC. The June 12, 2026 transition deadline has passed, and older detailed lists should be treated as supplemental unless currently mapped by your authority or Part-147 provider.

Question 1

How do you add two fractions with different denominators, such as 1/3 + 1/4?

Accepted Answer

Convert both fractions to a common denominator first, then add the numerators. 1/3 = 4/12 and 1/4 = 3/12, so 1/3 + 1/4 = 7/12. You cannot add numerators and denominators separately.

Question 2

Convert the fraction 5/8 to a decimal and a percentage.

Accepted Answer

5/8 = 0.625 = 62.5%. Divide the numerator by the denominator to get the decimal, then multiply by 100 for the percentage.

Question 3

What is the rule for dividing one fraction by another, e.g. 2/3 divided by 4/5?

Accepted Answer

Multiply by the reciprocal of the second fraction: 2/3 divided by 4/5 = 2/3 times 5/4 = 10/12 = 5/6. 'Keep, change, flip' - keep the first fraction, change the divide sign to multiply, flip the second fraction.

Question 4

Divide 120 in the ratio 2:3:5. What is each share?

Accepted Answer

The ratio parts total 2+3+5 = 10, so one part = 120 divided by 10 = 12. The shares are 2x12=24, 3x12=36, and 5x12=60, which sum back to 120.

Question 5

A value increases from 80 to 100. What is the percentage increase?

Accepted Answer

Percentage increase = (increase divided by original) times 100 = (20 divided by 80) times 100 = 25%. Always divide by the ORIGINAL value, not the new one.

Question 6

What is the mean (average) of the measurements 4, 7, 9, 12, and 13?

Accepted Answer

Mean = sum of values divided by number of values = (4+7+9+12+13) divided by 5 = 45 divided by 5 = 9.

Question 7

What is the area of a circle with radius 7 cm (use pi = 22/7)?

Accepted Answer

Area = pi r squared = (22/7) x 7 squared = (22/7) x 49 = 154 cm squared. The radius must be squared before multiplying by pi.

Question 8

A cylindrical fuel tank has radius 2 m and height 5 m. What is its volume?

Accepted Answer

Volume = pi r squared h = pi x 2 squared x 5 = pi x 4 x 5 = 20 pi, approximately 62.8 cubic metres. Volume formulas for solids extend the matching area formula by the extra dimension.

Question 9

What is the area of a right triangle with base 10 cm and height 6 cm?

Accepted Answer

Area = half x base x height = half x 10 x 6 = 30 cm squared. This halves the rectangle formed by the base and height.

Question 10

What is the square root of 144, and the cube root of 27?

Accepted Answer

The square root of 144 is 12, because 12 squared = 144. The cube root of 27 is 3, because 3 cubed = 27. Roots reverse the corresponding power.

Question 11

Convert 2.5 metres into millimetres.

Accepted Answer

1 metre = 1000 mm, so 2.5 m = 2.5 x 1000 = 2500 mm. Multiply by 1000 when converting from metres down to millimetres.

Question 12

A drawing uses a scale of 1:50. A component measures 3 cm on the drawing. What is its real length?

Accepted Answer

Real length = drawing length x scale factor = 3 cm x 50 = 150 cm (1.5 m). A scale of 1:50 means every unit on the drawing represents 50 units in real life.

Question 13

Simplify the expression 3x + 5y - x + 2y.

Accepted Answer

Collect like terms separately: (3x - x) + (5y + 2y) = 2x + 7y. Only terms with the same variable can be combined.

Question 14

Expand the bracket 4(2x - 3).

Accepted Answer

Multiply each term inside the bracket by 4: 4 x 2x - 4 x 3 = 8x - 12.

Question 15

If x = 3, what is the value of 2x squared + 5?

Accepted Answer

Substitute x = 3: 2(3 squared) + 5 = 2(9) + 5 = 18 + 5 = 23. Apply the power to x before multiplying by the coefficient.

Question 16

Simplify the algebraic fraction 6x squared over 2x.

Accepted Answer

Cancel the common factor of 2x: 6x squared over 2x = 3x. Divide the numeric coefficients and subtract the powers of x (x squared divided by x equals x).

Question 17

Solve for x: 3x + 7 = 22.

Accepted Answer

Subtract 7 from both sides: 3x = 15. Divide both sides by 3: x = 5. Whatever operation you apply, apply it to BOTH sides of the equation.

Question 18

Solve the simultaneous equations x + y = 10 and x - y = 4.

Accepted Answer

Add the two equations to eliminate y: 2x = 14, so x = 7. Substitute back into the first equation: 7 + y = 10, so y = 3.

Question 19

Why do you need two equations to solve for two unknowns like x and y?

Accepted Answer

One equation with two unknowns has infinitely many solutions; a second, independent equation narrows the possibilities down to exactly one solution. This is why simultaneous equations must be solved together, not separately.

Question 20

Solve using substitution: y = 2x and 3x + y = 20.

Accepted Answer

Substitute y = 2x into the second equation: 3x + 2x = 20, so 5x = 20, giving x = 4. Then y = 2(4) = 8.

Question 21

After solving 5x - 3 = 17 to get x = 4, how do you check the answer?

Accepted Answer

Substitute x = 4 back into the original equation: 5(4) - 3 = 20 - 3 = 17, which matches the right-hand side, confirming the solution is correct.

Question 22

Solve for x: (x/2) + 3 = 9.

Accepted Answer

Subtract 3 from both sides: x/2 = 6. Multiply both sides by 2 to clear the fraction: x = 12.

Question 23

How do you simplify 3x + 5x - 2?

Accepted Answer

Combine like terms: 3x + 5x = 8x, so the simplified expression is 8x - 2.

Question 24

How does a negative sign affect a bracket?

Accepted Answer

Treat the negative sign as multiplication by -1: -(a - b) becomes -a + b.

Question 25

Evaluate 2a + 3 when a = 4.

Accepted Answer

Substitute 4 for a, multiply first, then add: 2(4) + 3 = 11.

Question 26

Expand 3(x + 2).

Accepted Answer

Use the distributive law: multiply 3 by each term, giving 3x + 6.

Question 27

Solve x + 7 = 12.

Accepted Answer

Subtract 7 from both sides, so x = 5.

Question 28

Solve 3x = 18.

Accepted Answer

Divide both sides by 3, so x = 6.

Question 29

How do you check a solved equation?

Accepted Answer

Substitute the proposed value into the original equation and confirm both sides are equal.

Question 30

What is the first step for 2x + 4 = 14?

Accepted Answer

Subtract 4 from both sides before dividing by 2. This keeps the equation balanced.

Question 31

What does a graph gradient represent?

Accepted Answer

Gradient is vertical change divided by horizontal change: rise over run.

Question 32

How do you locate a graph intercept?

Accepted Answer

An x-intercept occurs where y = 0; a y-intercept occurs where x = 0.

Question 33

What is the defining property of a right angle, and how is it usually marked in a diagram?

Accepted Answer

A right angle measures exactly 90 degrees, formed where two lines are perpendicular to each other; it is typically marked with a small square symbol at the vertex.

Question 34

What does it mean to bisect a line or an angle?

Accepted Answer

Bisecting means dividing something into two exactly equal parts. Bisecting a line finds its exact midpoint; bisecting an angle splits it into two equal angles.

Question 35

How do you tell whether two lines are parallel versus perpendicular?

Accepted Answer

Parallel lines run in the same direction and never meet, no matter how far extended. Perpendicular lines cross at exactly 90 degrees. A pair of lines cannot be both at once.

Question 36

In the straight-line equation y = mx + c, what do m and c represent?

Accepted Answer

m is the gradient (slope) of the line - how steep it is - and c is the y-intercept, the value of y where the line crosses the y-axis (at x = 0).

Question 37

How do you calculate the gradient of a straight line between two points?

Accepted Answer

Gradient = rise divided by run = (change in y) divided by (change in x) between two points on the line. A steeper line has a larger gradient magnitude.

Question 38

Find the gradient and y-intercept of the line y = 3x - 4.

Accepted Answer

Comparing to y = mx + c, the gradient m = 3 and the y-intercept c = -4, meaning the line crosses the y-axis at (0, -4) and rises 3 units for every 1 unit across.

Question 39

What does the x-intercept of a graph represent, and how do you find it?

Accepted Answer

The x-intercept is where the line crosses the x-axis, meaning y = 0 at that point. Set y = 0 in the equation and solve for x to find it.

Question 40

On a distance-time graph, what does the gradient represent?

Accepted Answer

The gradient of a distance-time graph equals speed, since speed is distance divided by time. A steeper gradient means a faster speed; a flat, zero gradient means stationary.

Question 41

On a speed-time graph, what does the gradient represent?

Accepted Answer

The gradient of a speed-time graph equals acceleration, since acceleration is the rate of change of speed with time. A negative gradient indicates deceleration.

Question 42

What does the mnemonic SOH-CAH-TOA stand for?

Accepted Answer

SOH: Sine = Opposite/Hypotenuse. CAH: Cosine = Adjacent/Hypotenuse. TOA: Tangent = Opposite/Adjacent. It defines the three basic trigonometric ratios for a right-angled triangle.

Question 43

What are the values of sin 30 degrees and cos 60 degrees, and why are they equal?

Accepted Answer

Both sin 30 degrees and cos 60 degrees equal 0.5. They are equal because sine and cosine of complementary angles (angles that sum to 90 degrees) are always equal.

Question 44

What is the value of tan 45 degrees, and why does it equal that value?

Accepted Answer

tan 45 degrees = 1.0 exactly, because at 45 degrees the opposite and adjacent sides of a right triangle are equal in length, so opposite divided by adjacent = 1.

Question 45

What are sin 0 degrees and cos 0 degrees?

Accepted Answer

sin 0 degrees = 0 and cos 0 degrees = 1. At 0 degrees there is no 'opposite' side (giving sine 0), while the adjacent side equals the hypotenuse (giving cosine its maximum value of 1).

Question 46

What are sin 45 degrees and cos 45 degrees, and why are they equal?

Accepted Answer

Both equal approximately 0.707 (exactly the square root of 2, over 2). They are equal because 45 degrees is its own complement (45 + 45 = 90), so sine and cosine of 45 degrees must match.

Question 47

State Pythagoras' theorem and what it is used for.

Accepted Answer

For a right-angled triangle, a squared + b squared = c squared, where c is the hypotenuse (the longest side, opposite the right angle). It lets you find any missing side of a right triangle when the other two are known.

Question 48

A right triangle has legs of length 3 and 4. What is the hypotenuse?

Accepted Answer

Using Pythagoras: c squared = 3 squared + 4 squared = 9 + 16 = 25, so c = square root of 25 = 5. This is the well-known 3-4-5 right triangle, a common shortcut for recognising right angles.

Question 49

Which construction bisects a line segment?

Accepted Answer

Equal-radius arcs from both endpoints locate a perpendicular bisector through the segment's midpoint.

Question 50

Which triangle sides does cosine compare?

Accepted Answer

Cosine equals adjacent divided by hypotenuse for a right-angled triangle.

Free Part-66 Module 1 Exam Flashcards

Filter by Topic

Jump to Card

About These Part-66 Module 1 Flashcards

Topics Covered

Frequently Asked Questions

EASA Part-66 Module 01 — Mathematics

Explore More EASA Part-66 Aircraft Maintenance Licence Modules

EASA Part-66 Module 02 — Physics

EASA Part-66 Module 03 — Electrical Fundamentals

EASA Part-66 Module 08 — Basic Aerodynamics

EASA Part-66 Module 10 — Aviation Legislation

EASA Part-66 Module 04 — Electronic Fundamentals

EASA Part-66 Module 06 — Materials and Hardware

More From This Family