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2.3 Sequences, Patterns & Algebra Foundations

Key Takeaways

  • Linear arithmetic sequences have a constant common difference (d), allowing the nth term formula to be determined as dn + c, where c is the zero-th term.

  • Special sequences to recognise on sight are square numbers (1, 4, 9, 16, 25), cube numbers (1, 8, 27, 64, 125) and triangular numbers (1, 3, 6, 10, 15), because their gaps are not constant.

  • Questions ask for an earlier term, a distant term or the position of a value, and only the position-to-term rule dn + c answers all three; a non-whole-number position proves a value is not in the sequence.

  • Algebraic expressions combine variables and constants; expressions are simplified by collecting like terms and evaluated via numerical substitution.

  • Simple linear equations are solved using inverse operations to isolate the unknown variable on one side of the equals sign.

Last updated: August 2026

2.3 Sequences, Patterns & Algebra Foundations

Recognizing numerical patterns, working with prime numbers, and solving algebraic equations are key components of both the Mathematics and Non-Verbal Reasoning sections of the Kent Test. This section covers arithmetic sequences, position-to-term rules, number theory, algebraic simplification, and equation solving.

Arithmetic Sequences & nthn\text{th} Term Rules

An arithmetic sequence is a list of numbers with a constant common difference between consecutive terms.

Term-to-Term vs. Position-to-Term Rules

  • Term-to-term rule: Describes how to get from one term to the next (e.g., "add 5").
  • Position-to-term (nthn\text{th} term) rule: Provides a direct algebraic formula to calculate the nthn\text{th} term based on its position number nn.

Step-by-Step Method to Find the nthn\text{th} Term (dn+cdn + c)

  1. Calculate the common difference (dd) between consecutive terms. This forms the coefficient of nn (dndn).
  2. Compare the dndn table with the actual sequence to find the zero-th term (c=a1−dc = a_1 - d).
  3. Combine into the general expression dn+cdn + c.

Worked Example: Find the nthn\text{th} term formula for the sequence 3,8,13,18,23,…3, 8, 13, 18, 23, \dots and calculate the 50th term.

  1. Common Difference: 8−3=58 - 3 = 5, 13−8=5→d=513 - 8 = 5 \rightarrow d = 5. The term contains 5n5n.
  2. Zero-th Term (cc): First term is 33. Subtract difference 55: 3−5=−23 - 5 = -2.
  3. Formula: nth term=5n−2n\text{th}\text{ term} = 5n - 2.
  4. 50th Term Calculation: Substitute n=50n = 50: 5(50)−2=250−2=2485(50) - 2 = 250 - 2 = 248.

Special Non-Linear Sequences

  • Square Numbers (n2n^2): 1,4,9,16,25,36,49,64,81,100,121,144,…1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, \dots
  • Cube Numbers (n3n^3): 1,8,27,64,125,216,…1, 8, 27, 64, 125, 216, \dots
  • Triangular Numbers (n(n+1)2\frac{n(n+1)}{2}): 1,3,6,10,15,21,28,…1, 3, 6, 10, 15, 21, 28, \dots
  • Fibonacci Sequence: Each term is the sum of the preceding two terms (1,1,2,3,5,8,13,21,…1, 1, 2, 3, 5, 8, 13, 21, \dots).

Reading a Sequence Backwards and Sideways

Not every sequence question asks for the next term. Three variants recur, and each needs the rule in a different form.

Find an earlier term. Given 17, 23, 29, 35 and asked for the term before 17, subtract the common difference: 17−6=1117 - 6 = \mathbf{11}. Children who only ever practise "what comes next" freeze on this.

Find a distant term. Given 5, 9, 13, 17 and asked for the 30th term, do not count forwards. Use the position-to-term rule: d=4d = 4, the zero-th term is 11, so the rule is 4n+14n + 1 and the 30th term is 4(30)+1=1214(30) + 1 = \mathbf{121}.

Find the position of a value. Given the same sequence, ask whether 83 appears. Solve 4n+1=834n + 1 = 83, giving n=20.5n = 20.5. Because nn is not a whole number, 83 is not in the sequence. A non-integer answer is the proof, and questions are written to test exactly that reasoning.

Descending and Fractional Sequences

  • Descending: 47, 41, 35, 29 has d=−6d = -6, so the rule is −6n+53-6n + 53. The sign of dd must be carried through every step.
  • Fractional: 12,34,1,54\frac{1}{2}, \frac{3}{4}, 1, \frac{5}{4} increases by 14\frac{1}{4}. Convert to quarters first — 24,34,44,54\frac{2}{4}, \frac{3}{4}, \frac{4}{4}, \frac{5}{4} — and the pattern becomes obvious.
  • Decimal: 0.3, 0.55, 0.8, 1.05 increases by 0.25. Reading the gap once, precisely, prevents a run of wrong terms.

Prime numbers, factors, HCF and LCM support the harder sequence and pattern questions, and they are covered in full in section 2.6.


Algebraic Notation, Simplification & Substitution

Algebra uses letters (variables) to represent unknown values.

Key Rules of Algebraic Notation

  • 3×x3 \times x is written as 3x3x.
  • x÷4x \div 4 is written as x4\frac{x}{4}.
  • a×ba \times b is written as abab.
  • x×xx \times x is written as x2x^2.

Collecting Like Terms

Only terms with exact matching variable combinations can be combined.

  • Example: Simplify 4x+3y−2x+7y−54x + 3y - 2x + 7y - 5.
    • Combine xx-terms: 4x−2x=2x4x - 2x = 2x.
    • Combine yy-terms: 3y+7y=10y3y + 7y = 10y.
    • Constant: −5-5.
    • Simplified expression: 2x+10y−52x + 10y - 5.

Algebraic Substitution

Replace variables with their given numerical values and calculate using BIDMAS.

Worked Example: Evaluate 2a2−3bc2a^2 - 3bc when a=3a = 3, b=−2b = -2, and c=5c = 5.

  1. Evaluate a2a^2: 32=93^2 = 9.
  2. First term: 2×9=182 \times 9 = 18.
  3. Second term: 3×(−2)×5=3×(−10)=−303 \times (-2) \times 5 = 3 \times (-10) = -30.
  4. Subtract: 18−(−30)=18+30=4818 - (-30) = 18 + 30 = 48.

Solving Linear Equations & Function Machines

To solve an equation, perform inverse operations equally to both sides to isolate the unknown variable.

Inverse Operation Pairs

  • Addition (+)↔\text{+}) \leftrightarrow Subtraction (-\text{-})
  • Multiplication (×)↔\times) \leftrightarrow Division (÷\div)
  • Squaring (x2)↔x^2) \leftrightarrow Square Root (x\sqrt{x})

Solving Equations with Unknowns on Both Sides

Worked Example: Solve 7x−5=3x+117x - 5 = 3x + 11.

  1. Subtract 3x3x from both sides: 7x−3x−5=11→4x−5=117x - 3x - 5 = 11 \rightarrow 4x - 5 = 11.
  2. Add 55 to both sides: 4x=11+5→4x=164x = 11 + 5 \rightarrow 4x = 16.
  3. Divide both sides by 44: x=164→x=4x = \frac{16}{4} \rightarrow x = 4.

Function Machines

A function machine applies a sequence of operations to an input number to yield an output. To find an unknown input when given the output, work backwards from right to left using inverse operations.

  • Example: Input→[×4]→[−7]→Output 29\text{Input} \rightarrow [\times 4] \rightarrow [-7] \rightarrow \text{Output } 29.
  • Reverse: 29→+736→÷4929 \xrightarrow{+7} 36 \xrightarrow{\div 4} 9. Input = 99.
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Function Machine & Inverse Operations Workflow
Test Your Knowledge

What is the nth term formula for the arithmetic sequence 3, 8, 13, 18, 23, ...?

A

3n + 5

B

5n + 3

C

5n - 1

D

5n - 2

Test Your Knowledge

For the sequence 5, 9, 13, 17, ... is 83 a term, and if so which one?

A

Yes, it is the 20th term

B

No, because solving 4n + 1 = 83 gives n = 20.5, which is not a whole number

C

Yes, it is the 21st term

D

No, because the sequence only contains odd multiples of 5

Test Your Knowledge

Solve the equation for x: 7x - 5 = 3x + 11.

A

x = 1.6

B

x = 3

C

x = 4

D

x = 5

Test Your Knowledge

If a = 3, b = -2, and c = 5, what is the value of the expression 2a² - 3bc?

A

-12

B

48

C

18

D

36

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