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4.4 Trigonometric Functions, Identities & Right-Triangle Applications

Key Takeaways

  • The unit circle x2+y2=1x^2 + y^2 = 1 defines cos⁡θ\cos\theta as the xx-coordinate and sin⁡θ\sin\theta as the yy-coordinate of a point at angle θ\theta (in radians, where π rad=180∘\pi\text{ rad} = 180^\circ); tan⁡θ=sin⁡θcos⁡θ\tan\theta = \frac{\sin\theta}{\cos\theta} represents the slope of the terminal ray.

  • The fundamental Pythagorean identity sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1 generates the secondary identities 1+tan⁡2θ=1cos⁡2θ=sec⁡2θ1 + \tan^2\theta = \frac{1}{\cos^2\theta} = \sec^2\theta and 1+cot⁡2θ=csc⁡2θ1 + \cot^2\theta = \csc^2\theta.

  • The primary trigonometric functions exhibit distinct periodicities and domains: sin⁡(x)\sin(x) and cos⁡(x)\cos(x) have period 2π2\pi and range [−1,1][-1, 1], while tan⁡(x)\tan(x) has period π\pi, domain R∖{π2+kπ}\mathbb{R} \setminus \{\frac{\pi}{2} + k\pi\}, and vertical asymptotes at x=π2+kπx = \frac{\pi}{2} + k\pi.

  • Essential double-angle formulas include sin⁡(2θ)=2sin⁡θcos⁡θ\sin(2\theta) = 2\sin\theta\cos\theta and cos⁡(2θ)=cos⁡2θ−sin⁡2θ=2cos⁡2θ−1=1−2sin⁡2θ\cos(2\theta) = \cos^2\theta - \sin^2\theta = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta.

  • Right-triangle ratios obey SOH CAH TOA (sin⁡θ=opphyp\sin\theta = \frac{\text{opp}}{\text{hyp}}, cos⁡θ=adjhyp\cos\theta = \frac{\text{adj}}{\text{hyp}}, tan⁡θ=oppadj\tan\theta = \frac{\text{opp}}{\text{adj}}), enabling rapid non-calculator evaluation of geometric angles and side lengths.

Last updated: September 2026

4.4 Trigonometric Functions, Identities & Right-Triangle Applications

Trigonometry on the Bocconi Admission Test bridges geometric intuition and algebraic manipulation. Trigonometric problems appear as standalone algebraic identity simplifications, trigonometric equation solving, or right-triangle side evaluations within composite geometric figures. Because calculators are prohibited, candidates must master exact trigonometric values at standard reference angles, unit circle symmetries, and algebraic substitutions using Pythagorean and double-angle identities.


1. Radian Measure, Conversion & The Unit Circle

Radian Definition

A radian is the measure of a central angle that subtends an arc equal in length to the radius of the circle: θ=sr\theta = \frac{s}{r}.

  • A full revolution (360∘360^\circ) equals the ratio of circumference to radius: 2πrr=2π\frac{2\pi r}{r} = 2\pi radians.
  • Fundamental Equivalence: π rad=180∘\pi \text{ rad} = 180^\circ
  • Conversion Formulas: Radians=Degrees×π180∘,Degrees=Radians×180∘π\text{Radians} = \text{Degrees} \times \frac{\pi}{180^\circ}, \qquad \text{Degrees} = \text{Radians} \times \frac{180^\circ}{\pi}

The Unit Circle Definition

In the Cartesian plane, the unit circle is defined by x2+y2=1x^2 + y^2 = 1 centered at the origin O(0,0)O(0, 0). For any real number θ\theta, consider the terminal ray rotating counterclockwise from the positive xx-axis. The terminal ray intersects the unit circle at a unique point P(x,y)P(x, y):

x=cos⁡(θ),y=sin⁡(θ),tan⁡(θ)=yx=sin⁡(θ)cos⁡(θ)(x≠0)x = \cos(\theta), \qquad y = \sin(\theta), \qquad \tan(\theta) = \frac{y}{x} = \frac{\sin(\theta)}{\cos(\theta)} \quad (x \neq 0)

Quadrant Signs: The ASTC Rule

The signs of the trigonometric functions across the four Cartesian quadrants follow the mnemonic ASTC ("All Students Take Calculus"):

QuadrantAngle RangeCoordinates (x,y)(x, y)Positive FunctionsNegative Functions
I0<θ<π20 < \theta < \frac{\pi}{2}x>0,y>0x > 0, y > 0All (sin⁡,cos⁡,tan⁡\sin, \cos, \tan)None
IIπ2<θ<π\frac{\pi}{2} < \theta < \pix<0,y>0x < 0, y > 0Sine (sin⁡\sin)cos⁡,tan⁡\cos, \tan
IIIπ<θ<3π2\pi < \theta < \frac{3\pi}{2}x<0,y<0x < 0, y < 0Tangent (tan⁡\tan)sin⁡,cos⁡\sin, \cos
IV3π2<θ<2π\frac{3\pi}{2} < \theta < 2\pix>0,y<0x > 0, y < 0Cosine (cos⁡\cos)sin⁡,tan⁡\sin, \tan

2. Table of Exact Trigonometric Values at Reference Angles

Instant recall of exact trigonometric values at standard angles is essential for non-calculator exam speed:

DegreesRadianssin⁡(θ)\sin(\theta)cos⁡(θ)\cos(\theta)tan⁡(θ)\tan(\theta)
0∘0^\circ000=020 = \frac{\sqrt{0}}{2}1=421 = \frac{\sqrt{4}}{2}00
30∘30^\circπ6\frac{\pi}{6}12=12\frac{1}{2} = \frac{\sqrt{1}}{2}32\frac{\sqrt{3}}{2}13=33\frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}
45∘45^\circπ4\frac{\pi}{4}22\frac{\sqrt{2}}{2}22\frac{\sqrt{2}}{2}11
60∘60^\circπ3\frac{\pi}{3}32\frac{\sqrt{3}}{2}12=12\frac{1}{2} = \frac{\sqrt{1}}{2}3\sqrt{3}
90∘90^\circπ2\frac{\pi}{2}1=421 = \frac{\sqrt{4}}{2}0=020 = \frac{\sqrt{0}}{2}Undefined
180∘180^\circπ\pi00−1-100
270∘270^\circ3π2\frac{3\pi}{2}−1-100Undefined
360∘360^\circ2π2\pi001100

Mental Mnemonic for Sines: From 00 to π2\frac{\pi}{2}, the values of sin⁡(θ)\sin(\theta) follow 02,12,22,32,42\frac{\sqrt{0}}{2}, \frac{\sqrt{1}}{2}, \frac{\sqrt{2}}{2}, \frac{\sqrt{3}}{2}, \frac{\sqrt{4}}{2}. Cosine reverses this sequence.


3. Graphs, Periodicity & Asymptotes

Sine: y=sin⁡(x)y = \sin(x)

  • Domain: R=(−∞,∞)\mathbb{R} = (-\infty, \infty).
  • Range: [−1,1][-1, 1].
  • Periodicity: Fundamental period T=2πT = 2\pi: sin⁡(x+2kπ)=sin⁡(x)\sin(x + 2k\pi) = \sin(x) for all k∈Zk \in \mathbb{Z}.
  • Parity: Odd function (symmetric about origin): sin⁡(−x)=−sin⁡(x)\sin(-x) = -\sin(x).
  • Zeros: x=kπx = k\pi for k∈Zk \in \mathbb{Z}.

Cosine: y=cos⁡(x)y = \cos(x)

  • Domain: R=(−∞,∞)\mathbb{R} = (-\infty, \infty).
  • Range: [−1,1][-1, 1].
  • Periodicity: Fundamental period T=2πT = 2\pi: cos⁡(x+2kπ)=cos⁡(x)\cos(x + 2k\pi) = \cos(x) for all k∈Zk \in \mathbb{Z}.
  • Parity: Even function (symmetric about yy-axis): cos⁡(−x)=cos⁡(x)\cos(-x) = \cos(x).
  • Zeros: x=π2+kπx = \frac{\pi}{2} + k\pi for k∈Zk \in \mathbb{Z}.

Tangent: y=tan⁡(x)y = \tan(x)

  • Domain: R∖{π2+kπ∣k∈Z}\mathbb{R} \setminus \{\frac{\pi}{2} + k\pi \mid k \in \mathbb{Z}\}.
  • Range: (−∞,∞)(-\infty, \infty).
  • Periodicity: Fundamental period T=πT = \pi: tan⁡(x+kπ)=tan⁡(x)\tan(x + k\pi) = \tan(x) for all k∈Zk \in \mathbb{Z}.
  • Parity: Odd function: tan⁡(−x)=−tan⁡(x)\tan(-x) = -\tan(x).
  • Vertical Asymptotes: Occur where cos⁡(x)=0\cos(x) = 0, at x=π2+kπx = \frac{\pi}{2} + k\pi.

4. Fundamental Trigonometric Identities

The Pythagorean Identity and Its Variants

Because (x,y)=(cos⁡θ,sin⁡θ)(x, y) = (\cos\theta, \sin\theta) lies on the unit circle x2+y2=1x^2 + y^2 = 1:

sin⁡2(θ)+cos⁡2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1

Dividing this master identity yields two secondary forms:

  1. Dividing by cos⁡2(θ)\cos^2(\theta) (for cos⁡θ≠0\cos\theta \neq 0): 1+tan⁡2(θ)=1cos⁡2(θ)=sec⁡2(θ)1 + \tan^2(\theta) = \frac{1}{\cos^2(\theta)} = \sec^2(\theta)
  2. Dividing by sin⁡2(θ)\sin^2(\theta) (for sin⁡θ≠0\sin\theta \neq 0): 1+cot⁡2(θ)=1sin⁡2(θ)=csc⁡2(θ)1 + \cot^2(\theta) = \frac{1}{\sin^2(\theta)} = \csc^2(\theta)

Cofunction and Supplementary Identities

  • Cofunction (Complementary angles, sum = π2\frac{\pi}{2}): sin⁡(π2−θ)=cos⁡(θ),cos⁡(π2−θ)=sin⁡(θ),tan⁡(π2−θ)=cot⁡(θ)\sin\left(\frac{\pi}{2} - \theta\right) = \cos(\theta), \qquad \cos\left(\frac{\pi}{2} - \theta\right) = \sin(\theta), \qquad \tan\left(\frac{\pi}{2} - \theta\right) = \cot(\theta)
  • Supplementary Angles (sum = π\pi): sin⁡(π−θ)=sin⁡(θ),cos⁡(π−θ)=−cos⁡(θ),tan⁡(π−θ)=−tan⁡(θ)\sin(\pi - \theta) = \sin(\theta), \qquad \cos(\pi - \theta) = -\cos(\theta), \qquad \tan(\pi - \theta) = -\tan(\theta)

5. Double-Angle and Addition Formulas

Angle Addition and Subtraction Formulas

sin⁡(α±β)=sin⁡(α)cos⁡(β)±cos⁡(α)sin⁡(β)\sin(\alpha \pm \beta) = \sin(\alpha)\cos(\beta) \pm \cos(\alpha)\sin(\beta) cos⁡(α±β)=cos⁡(α)cos⁡(β)∓sin⁡(α)sin⁡(β)\cos(\alpha \pm \beta) = \cos(\alpha)\cos(\beta) \mp \sin(\alpha)\sin(\beta) tan⁡(α±β)=tan⁡(α)±tan⁡(β)1∓tan⁡(α)tan⁡(β)\tan(\alpha \pm \beta) = \frac{\tan(\alpha) \pm \tan(\beta)}{1 \mp \tan(\alpha)\tan(\beta)}

Double-Angle Formulas

Setting α=β=θ\alpha = \beta = \theta yields the core double-angle relations:

  1. Sine Double Angle: sin⁡(2θ)=2sin⁡(θ)cos⁡(θ)\sin(2\theta) = 2\sin(\theta)\cos(\theta)
  2. Cosine Double Angle (Three Equivalent Forms): cos⁡(2θ)=cos⁡2(θ)−sin⁡2(θ)\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta) cos⁡(2θ)=2cos⁡2(θ)−1\cos(2\theta) = 2\cos^2(\theta) - 1 cos⁡(2θ)=1−2sin⁡2(θ)\cos(2\theta) = 1 - 2\sin^2(\theta)
  3. Tangent Double Angle: tan⁡(2θ)=2tan⁡(θ)1−tan⁡2(θ)\tan(2\theta) = \frac{2\tan(\theta)}{1 - \tan^2(\theta)}

Power-Reduction Formulas

Rearranging the cosine double-angle equations expresses squared terms as linear harmonics:

sin⁡2(θ)=1−cos⁡(2θ)2,cos⁡2(θ)=1+cos⁡(2θ)2\sin^2(\theta) = \frac{1 - \cos(2\theta)}{2}, \qquad \cos^2(\theta) = \frac{1 + \cos(2\theta)}{2}

6. Right-Triangle Trigonometry (SOH CAH TOA)

In a Euclidean right-angled triangle with acute angle θ\theta:

sin⁡(θ)=OppositeHypotenuse,cos⁡(θ)=AdjacentHypotenuse,tan⁡(θ)=OppositeAdjacent\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}, \qquad \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}}, \qquad \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}

Oblique Triangle Laws

For any general triangle with sides a,b,ca, b, c and opposite angles A,B,CA, B, C:

  • Law of Sines: Relates sides to the circumradius RR: asin⁡(A)=bsin⁡(B)=csin⁡(C)=2R\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} = 2R
  • Law of Cosines: The generalization of the Pythagorean theorem: c2=a2+b2−2abcos⁡(C)c^2 = a^2 + b^2 - 2ab\cos(C)
  • Trigonometric Area: Area=12absin⁡(C)\text{Area} = \frac{1}{2} a b \sin(C)

7. Solving Elementary Trigonometric Equations on [0,2π)[0, 2\pi)

Trigonometric equations test your ability to factor polynomial structures and identify all angular solutions within a specified interval.

The 3-Step Solution Protocol

  1. Unify the Argument: Use double-angle identities to express all terms with the same argument (e.g., convert sin⁡(2x)\sin(2x) to 2sin⁡xcos⁡x2\sin x \cos x).
  2. Form a Polynomial in a Single Function: Use sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1 to obtain an equation entirely in sin⁡x\sin x or entirely in cos⁡x\cos x.
  3. Substitute and Solve: Let u=sin⁡xu = \sin x (or cos⁡x\cos x), solve the polynomial for u∈[−1,1]u \in [-1, 1], and find all corresponding angles xx on [0,2π)[0, 2\pi).

Critical Bocconi Trap: Never divide both sides by a trigonometric function! In an equation like sin⁡(2x)=cos⁡(x)  ⟹  2sin⁡xcos⁡x=cos⁡x\sin(2x) = \cos(x) \implies 2\sin x \cos x = \cos x, dividing by cos⁡x\cos x loses the solutions where cos⁡x=0\cos x = 0. Instead, factor: cos⁡x(2sin⁡x−1)=0\cos x (2\sin x - 1) = 0.


8. Worked Step-by-Step Examples

Example 1: Evaluating Functions from Quadrant Data

Given that sin⁡(θ)=−513\sin(\theta) = -\frac{5}{13} and π<θ<3π2\pi < \theta < \frac{3\pi}{2} (Quadrant III), calculate cos⁡(θ)\cos(\theta) and cos⁡(2θ)\cos(2\theta).

  1. Find cos⁡(θ)\cos(\theta): cos⁡2(θ)=1−sin⁡2(θ)=1−(−513)2=1−25169=144169\cos^2(\theta) = 1 - \sin^2(\theta) = 1 - \left(-\frac{5}{13}\right)^2 = 1 - \frac{25}{169} = \frac{144}{169} In Quadrant III, cosine is strictly negative: cos⁡(θ)=−144169=−1213\cos(\theta) = -\sqrt{\frac{144}{169}} = -\frac{12}{13}.
  2. Calculate cos⁡(2θ)\cos(2\theta) using cos⁡(2θ)=cos⁡2(θ)−sin⁡2(θ)\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta): cos⁡(2θ)=(−1213)2−(−513)2=144169−25169=119169\cos(2\theta) = \left(-\frac{12}{13}\right)^2 - \left(-\frac{5}{13}\right)^2 = \frac{144}{169} - \frac{25}{169} = \frac{119}{169}

Example 2: Solving a Factored Trigonometric Equation

Find all solutions to 2sin⁡2(x)+3cos⁡(x)−3=02\sin^2(x) + 3\cos(x) - 3 = 0 in the interval [0,2π)[0, 2\pi).

  1. Substitute sin⁡2(x)=1−cos⁡2(x)\sin^2(x) = 1 - \cos^2(x): 2(1−cos⁡2x)+3cos⁡x−3=0  ⟹  2−2cos⁡2x+3cos⁡x−3=0  ⟹  −2cos⁡2x+3cos⁡x−1=02(1 - \cos^2 x) + 3\cos x - 3 = 0 \implies 2 - 2\cos^2 x + 3\cos x - 3 = 0 \implies -2\cos^2 x + 3\cos x - 1 = 0
  2. Multiply by −1-1: 2cos⁡2x−3cos⁡x+1=02\cos^2 x - 3\cos x + 1 = 0.
  3. Factor the quadratic: (2cos⁡x−1)(cos⁡x−1)=0(2\cos x - 1)(\cos x - 1) = 0.
  4. Set each factor to zero:
    • Branch 1: cos⁡x=1  ⟹  x=0\cos x = 1 \implies x = 0 on [0,2π)[0, 2\pi).
    • Branch 2: cos⁡x=12  ⟹  x=π3\cos x = \frac{1}{2} \implies x = \frac{\pi}{3} (Quadrant I) and x=2π−π3=5π3x = 2\pi - \frac{\pi}{3} = \frac{5\pi}{3} (Quadrant IV).
  5. Complete solution set: x∈{0,π3,5π3}x \in \{0, \frac{\pi}{3}, \frac{5\pi}{3}\} (3 distinct solutions).

Example 3: Identity Simplification

Simplify E=sin⁡(2θ)−sin⁡(θ)cos⁡(2θ)−cos⁡(θ)+1E = \frac{\sin(2\theta) - \sin(\theta)}{\cos(2\theta) - \cos(\theta) + 1} for all θ\theta where defined.

  1. Expand double angles: sin⁡(2θ)=2sin⁡θcos⁡θ\sin(2\theta) = 2\sin\theta\cos\theta and cos⁡(2θ)=2cos⁡2θ−1\cos(2\theta) = 2\cos^2\theta - 1.
  2. Numerator: 2sin⁡θcos⁡θ−sin⁡θ=sin⁡θ(2cos⁡θ−1)2\sin\theta\cos\theta - \sin\theta = \sin\theta(2\cos\theta - 1).
  3. Denominator: (2cos⁡2θ−1)−cos⁡θ+1=2cos⁡2θ−cos⁡θ=cos⁡θ(2cos⁡θ−1)(2\cos^2\theta - 1) - \cos\theta + 1 = 2\cos^2\theta - \cos\theta = \cos\theta(2\cos\theta - 1).
  4. Cancel common non-zero factor (2cos⁡θ−1)(2\cos\theta - 1): E=sin⁡θ(2cos⁡θ−1)cos⁡θ(2cos⁡θ−1)=sin⁡θcos⁡θ=tan⁡(θ)E = \frac{\sin\theta(2\cos\theta - 1)}{\cos\theta(2\cos\theta - 1)} = \frac{\sin\theta}{\cos\theta} = \tan(\theta)
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Trigonometric Framework: Unit Circle & Identities
Test Your Knowledge

If cos(θ) = -3/5 and π < θ < 3π/2 (Quadrant III), what is the exact value of sin(2θ)?

A

-24/25

B

24/25

C

7/25

D

-7/25

Test Your Knowledge

How many distinct solutions does the trigonometric equation 2cos²(x) - cos(x) - 1 = 0 have in the half-open interval [0, 2π)?

A

1

B

2

C

3

D

4

Test Your Knowledge

Which of the following expressions is identically equal to sin(2θ) / (1 + cos(2θ)) for all θ where the expression is defined?

A

cot(θ)

B

sin(θ)

C

2tan(θ)

D

tan(θ)

Sections you finish are checked off in the contents.