10.4 The Unit Circle, Radian Measure & Trigonometric Functions

Key Takeaways

  • An angle of θ radians intercepts an arc of length s = rθ, and 180° equals π radians.

  • On the unit circle, the terminal side of angle θ meets the circle at (cos θ, sin θ), which gives the identity sin²θ + cos²θ = 1.

  • Values for angles beyond 90° come from the reference angle, with signs set by quadrant; for example, cos 225° = −√2/2.

  • For y = a sin(b(x − h)) + d, the amplitude is |a|, the period is 2π/|b|, and the midline is y = d.

  • The Law of Cosines, c² = a² + b² − 2ab cos C, solves SAS and SSS triangles and reduces to the Pythagorean theorem when C = 90°.

Last updated: September 2026

10.4 The Unit Circle, Radian Measure and Trigonometric Functions

Competency 011 asks you to use the unit circle in the coordinate plane to explore properties of trigonometric functions, and Competency 006 lists trigonometric functions among the nonlinear relations you must analyze. Section 7.3 defined sine, cosine and tangent for acute angles in right triangles. This section extends them to every angle with the coordinate plane and adds the Law of Sines and Law of Cosines, which appear on the official Definitions and Formulas page.


Angles in Standard Position and Radian Measure

An angle is in standard position when its vertex is at the origin and its initial side lies along the positive xx-axis. Counterclockwise rotation is positive and clockwise rotation is negative. Coterminal angles share a terminal side. For example, 60∘60^\circ, 420∘420^\circ and −300∘-300^\circ are coterminal.

A radian is the angle that subtends an arc equal in length to the radius. For any circle,

θ (in radians)=srsos=rθ\theta \text{ (in radians)} = \frac{s}{r} \qquad\text{so}\qquad s = r\theta

A full turn subtends the whole circumference, 2πr2\pi r, so 360∘=2π360^\circ = 2\pi radians and 180∘=π180^\circ = \pi radians.

  • Degrees to radians: multiply by π180\frac{\pi}{180}. For example, 135∘=3π4135^\circ = \frac{3\pi}{4}.
  • Radians to degrees: multiply by 180π\frac{180}{\pi}. For example, 5π6=150∘\frac{5\pi}{6} = 150^\circ.
  • Arc length: a central angle of 3π4\frac{3\pi}{4} in a circle of radius 8 cm cuts off s=8⋅3π4=6π≈18.85s = 8 \cdot \frac{3\pi}{4} = 6\pi \approx 18.85 cm.
  • Sector area in radians: A=12r2θA = \frac{1}{2}r^2\theta.

The Unit Circle Definitions

On the circle x2+y2=1x^2 + y^2 = 1, let the terminal side of angle θ\theta meet the circle at (x,y)(x, y). Then

cos⁡θ=x,sin⁡θ=y,tan⁡θ=yx (x≠0)\cos\theta = x, \qquad \sin\theta = y, \qquad \tan\theta = \frac{y}{x}\ (x \ne 0)

For an acute angle, drop a perpendicular to the xx-axis. You get a right triangle with hypotenuse 1, so these definitions match SOH-CAH-TOA from section 7.3.

Because every point satisfies x2+y2=1x^2 + y^2 = 1, the Pythagorean identity follows at once:

sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1

Special angles in Quadrant I

θ\theta00π6\frac{\pi}{6} (30°)π4\frac{\pi}{4} (45°)π3\frac{\pi}{3} (60°)π2\frac{\pi}{2} (90°)
(cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta)(1,0)(1, 0)(32,12)\left(\frac{\sqrt3}{2}, \frac12\right)(22,22)\left(\frac{\sqrt2}{2}, \frac{\sqrt2}{2}\right)(12,32)\left(\frac12, \frac{\sqrt3}{2}\right)(0,1)(0, 1)
tan⁡θ\tan\theta0033\frac{\sqrt3}{3}113\sqrt3undefined

These coordinates come straight from the 45°-45°-90° and 30°-60°-90° triangles scaled to hypotenuse 1.

Other quadrants: reference angles and signs

The reference angle is the acute angle between the terminal side and the xx-axis. Find the values for the reference angle, then attach signs by quadrant:

  • Quadrant I: all positive.
  • Quadrant II: sine positive (cosine and tangent negative).
  • Quadrant III: tangent positive (sine and cosine negative).
  • Quadrant IV: cosine positive (sine and tangent negative).

Examples:

  • sin⁡150∘=+sin⁡30∘=12\sin 150^\circ = +\sin 30^\circ = \frac12 (Quadrant II).
  • cos⁡225∘=−cos⁡45∘=−22\cos 225^\circ = -\cos 45^\circ = -\frac{\sqrt2}{2} (Quadrant III).
  • tan⁡300∘=−tan⁡60∘=−3\tan 300^\circ = -\tan 60^\circ = -\sqrt3 (Quadrant IV).
  • The point at 210∘210^\circ is (−32,−12)\left(-\frac{\sqrt3}{2}, -\frac12\right).

Graphs of the Trigonometric Functions

Unwrap the unit circle. Plot the angle θ\theta on the horizontal axis and the yy-coordinate (sine) or xx-coordinate (cosine) on the vertical axis, and you get periodic waves:

  • y=sin⁡xy = \sin x: period 2π2\pi, range [−1,1][-1, 1], zeros at multiples of π\pi, maximum at π2\frac{\pi}{2}.
  • y=cos⁡xy = \cos x: the same shape shifted left by π2\frac{\pi}{2}; it starts at its maximum, cos⁡0=1\cos 0 = 1.
  • y=tan⁡xy = \tan x: period π\pi, with vertical asymptotes where cos⁡x=0\cos x = 0 (at x=±π2,…x = \pm\frac{\pi}{2}, \dots).

For y=asin⁡(b(x−h))+dy = a\sin\big(b(x - h)\big) + d (the same transformation rule as section 6.4):

  • Amplitude =∣a∣= \lvert a \rvert.
  • Period =2π∣b∣= \dfrac{2\pi}{\lvert b \rvert}.
  • Midline y=dy = d, and phase shift hh.

Modeling example. A Ferris wheel 40 m in diameter has its center 22 m above the ground and completes a turn every 8 minutes. A rider starts at the bottom. Height as a function of time is H(t)=22−20cos⁡(2π8t)H(t) = 22 - 20\cos\left(\frac{2\pi}{8}t\right). The amplitude is 20 (the radius), the midline is 22, and the period is 8. At t=4t = 4 minutes, H=22−20cos⁡π=42H = 22 - 20\cos\pi = 42 m, the top of the wheel.


Solving Any Triangle: Law of Sines and Law of Cosines

Both laws are printed on the Definitions and Formulas page. You still need to know when each one applies.

Law of Sines: sin⁡Aa=sin⁡Bb=sin⁡Cc\dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c}. Use it when you know two angles and a side (AAS or ASA), or two sides and a non-included angle (SSA, the ambiguous case from section 8.2).

Example: In a triangle with A=40∘A = 40^\circ, B=65∘B = 65^\circ and a=10a = 10,

b=10sin⁡65∘sin⁡40∘≈10(0.9063)0.6428≈14.10b = \frac{10\sin 65^\circ}{\sin 40^\circ} \approx \frac{10(0.9063)}{0.6428} \approx 14.10

Law of Cosines: c2=a2+b2−2abcos⁡Cc^2 = a^2 + b^2 - 2ab\cos C. Use it when you know two sides and the included angle (SAS), or all three sides (SSS).

Example: Two sides of 5 and 8 enclose a 60∘60^\circ angle. Then

c2=25+64−2(5)(8)(0.5)=49,c=7c^2 = 25 + 64 - 2(5)(8)(0.5) = 49, \qquad c = 7

When C=90∘C = 90^\circ, cos⁡C=0\cos C = 0 and the Law of Cosines reduces to the Pythagorean theorem. This connection is worth pointing out to students.

Area of any triangle: Area=12absin⁡C\text{Area} = \frac12 ab\sin C. For the 5–8–60° triangle the area is 12(5)(8)32=103≈17.3\frac12(5)(8)\frac{\sqrt3}{2} = 10\sqrt3 \approx 17.3.


Calculator and Teaching Notes

  • Scientific calculators like the TI-30XS include SIN, COS, TAN and their inverses, plus a degree/radian mode setting. A wrong mode is the most common reason for a "wrong" trigonometric answer: sin⁡30\sin 30 in radian mode is about −0.988-0.988, not 0.50.5.
  • Middle school students meet the ideas behind this topic informally, through similar right triangles (the ratios stay constant) and circle measurement (C=2πrC = 2\pi r and π\pi as a ratio). Radians grow naturally from the question "how many radius-lengths fit along the arc?"
  • A common misconception is that sin⁡(2x)=2sin⁡x\sin(2x) = 2\sin x. Test x=90∘x = 90^\circ: sin⁡180∘=0\sin 180^\circ = 0, but 2sin⁡90∘=22\sin 90^\circ = 2.
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Finding a Trigonometric Value for Any Angle
Test Your Knowledge

Which ordered pair gives the point where the terminal side of a 210° angle in standard position meets the unit circle?

A
(−32,−12)\left(-\frac{\sqrt{3}}{2}, -\frac{1}{2}\right)
B
(−12,−32)\left(-\frac{1}{2}, -\frac{\sqrt{3}}{2}\right)
C
(32,−12)\left(\frac{\sqrt{3}}{2}, -\frac{1}{2}\right)
D
(−32,12)\left(-\frac{\sqrt{3}}{2}, \frac{1}{2}\right)
Test Your Knowledge

A central angle of 3π4\frac{3\pi}{4} radians is drawn in a circle with radius 8 cm. What is the length of the intercepted arc?

A

3π cm

B

6π cm

C

12π cm

D

135 cm

Test Your Knowledge

Two sides of a triangular garden measure 5 m and 8 m, and the angle between them is 60°. How long is the third side?

A

√89 m, using the Pythagorean theorem

B

13 m, adding the two sides

C

7 m, using the Law of Cosines

D

8.6 m, using the Law of Sines

Sections you finish are checked off in the contents.