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11.2 Manufacturing Processes, Machine Tools & Machining Calculations

Key Takeaways

  • Metal casting processes select mold types (sand, investment, die, centrifugal) based on production volume and surface finish, with solidification time governed by Chvorinov's Rule t=B(V/A)2t = B (V/A)^2.

  • Bulk metal forming operations (rolling, forging, extrusion, wire drawing) utilize plastic deformation above or below recrystallization temperature to shape metals while refining grain structure.

  • Lathe turning operations determine cutting speed V=πDN1000V = \frac{\pi D N}{1000}, feed rate, machining time Tm=LfNT_m = \frac{L}{f N}, and Material Removal Rate MRR=V⋅f⋅d⋅1000MRR = V \cdot f \cdot d \cdot 1000.

  • Milling performance depends on table feed rate Vf=ft⋅z⋅NV_f = f_t \cdot z \cdot N and volumetric removal rate MRR=w⋅d⋅VfMRR = w \cdot d \cdot V_f for face and end milling cutters.

  • Non-traditional machining processes (EDM, ECM, laser cutting) machine high-strength or complex geometries without mechanical cutting forces using thermal, electrochemical, or optical energy.

Last updated: July 2026

11.2 Manufacturing Processes, Machine Tools & Machining Calculations

Manufacturing engineering converts raw materials into finished engineering components through casting, bulk forming, metal cutting, and non-traditional processing. Mastery of process parameters, material removal rates, tool speeds, and production timing is essential for optimizing manufacturing systems. This section covers fundamental manufacturing processes and machine tool calculations required for the PRC Mechanical Engineering Licensure Examination.


1. Casting Processes & Riser Design

Casting involves pouring liquid metal into a mold cavity containing the desired part shape, where it solidifies. The principal casting methods include:

  • Sand Casting: Expendable molds made of silica sand and binders. Low tooling cost, suitable for large parts (engine blocks, valve bodies), but moderate surface roughness (6.3 to 25 μm Ra6.3 \text{ to } 25 \> \mu\text{m} \text{ Ra}).
  • Investment Casting (Lost-Wax): Slurry coating over disposable wax patterns. Produces near-net-shape components with intricate detail and tight tolerances (0.8 to 3.2 μm Ra0.8 \text{ to } 3.2 \> \mu\text{m} \text{ Ra}), widely used for turbine blades.
  • Die Casting: Permanent steel dies injected with molten metal under high pressure (10 to 175 MPa10 \text{ to } 175 \text{ MPa}). High production rate for non-ferrous alloys (aluminum, zinc, magnesium).
  • Centrifugal Casting: Molten metal poured into a rotating mold (300 to 3000 RPM300 \text{ to } 3000 \text{ RPM}). Centrifugal force pushes dense metal to the outer wall while impurities float to the inner core, producing high-density cylindrical tubes and pipes.

Solidification Modeling: Chvorinov's Rule

To prevent shrinkage porosity, risers must act as molten reservoirs that solidify after the main casting. Solidification time (tt) is modeled by Chvorinov's Rule:

t=B(VA)2t = B \left( \frac{V}{A} \right)^2

where:

  • tt = total solidification time (min or s)
  • BB = mold constant (s/mm2\text{s/mm}^2 or min/cm2\text{min/cm}^2), dependent on mold material, metal properties, and pouring temperature
  • VV = volume of the casting or riser (mm3\text{mm}^3 or cm3\text{cm}^3)
  • AA = cooling surface area (mm2\text{mm}^2 or cm2\text{cm}^2)
  • V/AV/A = modulus of cooling (MM)

To ensure proper feeding, the riser solidification time must exceed the casting solidification time by at least 25%25\%, requiring (V/A)riser≥1.12(V/A)casting(V/A)_{\text{riser}} \ge 1.12 (V/A)_{\text{casting}}.


Worked Step-by-Step Calculation: Riser Sizing via Chvorinov's Rule

Problem: A rectangular steel casting with dimensions 100 mm×200 mm×50 mm100 \text{ mm} \times 200 \text{ mm} \times 50 \text{ mm} is cast in a sand mold with mold constant B=0.004 min/mm2B = 0.004 \text{ min/mm}^2. Determine:

  1. The solidification time of the casting.
  2. The minimum required solidification time for a top cylindrical riser (H=DH = D).

Step 1: Calculate Volume and Surface Area of Rectangular Casting

Vcast=100×200×50=1,000,000 mm3V_{\text{cast}} = 100 \times 200 \times 50 = 1,000,000 \text{ mm}^3 Acast=2(100×200+100×50+200×50)=2(20,000+5,000+10,000)=70,000 mm2A_{\text{cast}} = 2 (100 \times 200 + 100 \times 50 + 200 \times 50) = 2 (20,000 + 5,000 + 10,000) = 70,000 \text{ mm}^2 (VA)cast=1,000,00070,000=14.286 mm\left(\frac{V}{A}\right)_{\text{cast}} = \frac{1,000,000}{70,000} = 14.286 \text{ mm}

Step 2: Calculate Casting Solidification Time

tcast=B(VA)2=0.004×(14.286)2=0.004×204.09=0.816 min(49.0 seconds)t_{\text{cast}} = B \left(\frac{V}{A}\right)^2 = 0.004 \times (14.286)^2 = 0.004 \times 204.09 = 0.816 \text{ min} \quad (49.0 \text{ seconds})

Step 3: Calculate Minimum Riser Solidification Time

triser≥1.25×tcast=1.25×0.816=1.020 mint_{\text{riser}} \ge 1.25 \times t_{\text{cast}} = 1.25 \times 0.816 = 1.020 \text{ min}

2. Bulk Metal Forming Operations

Metal forming shapes solid metals through plastic deformation above or below the recrystallization temperature.

  • Hot Working (T>0.5TmT > 0.5 T_m): Deforms metal above recrystallization temperature. Requires lower forces, eliminates strain hardening, and refines coarse grain structures.
  • Cold Working (T<0.3TmT < 0.3 T_m): Deforms metal at room temperature. Increases yield strength and hardness through work hardening (dislocation multiplication), providing superior dimensional control and bright surface finishes.

Primary Forming Operations

  1. Rolling: Reduces cross-sectional thickness between counter-rotating rolls. Maximum thickness draft per pass: dmax⁡=h0−hf=μ2Rd_{\max} = h_0 - h_f = \mu^2 R, where μ\mu is friction coefficient and RR is roll radius.
  2. Forging: Shapes metal via compressive impact or press forces. Divided into open-die forging, closed-die impression forging (with flash), and flashless precision forging.
  3. Extrusion: Forces a billet through a shaped die orifice (direct/forward vs indirect/backward extrusion). Extrusion ratio Re=A0/AfR_e = A_0 / A_f.
  4. Wire & Bar Drawing: Pulls solid rod through a converging die to reduce diameter. Reduction ratio r=1−(Af/A0)r = 1 - (A_f / A_0).

3. Turning & Lathe Machining Calculations

Lathe turning generates cylindrical surfaces by rotating a workpiece against a single-point cutting tool.

Lathe Turning Setup:
       +-------------------+  <--- Workpiece (Diameter D, RPM N)
  ======|===================|-----> Rotation
       +-------------------+ 
            ^ Tool Feed f (mm/rev)
            | [Tool]

Core Machining Formulas

  1. Cutting Speed (VV): The linear speed of the workpiece surface relative to the tool:

    V=πDN1000(m/min)V = \frac{\pi D N}{1000} \quad (\text{m/min}) N=1000VπD(RPM)N = \frac{1000 V}{\pi D} \quad (\text{RPM})

    where DD is workpiece diameter (mm) and NN is rotational spindle speed (RPM).

  2. Machining Time (TmT_m): The time required to complete a single cutting pass over length LL:

    Tm=L+LofN(minutes)T_m = \frac{L + L_o}{f N} \quad (\text{minutes})

    where LL is cut length (mm), LoL_o is tool approach/overtravel allowance (mm), and ff is feed rate (mm/rev).

  3. Material Removal Rate (MRRMRR): The volumetric rate of metal removed:

    MRR=vf⋅d⋅w=(f⋅N)⋅d⋅(πDavg)=1000⋅V⋅f⋅d(mm3/min)MRR = v_f \cdot d \cdot w = (f \cdot N) \cdot d \cdot (\pi D_{\text{avg}}) = 1000 \cdot V \cdot f \cdot d \quad (\text{mm}^3/\text{min})

    or in cm3/min\text{cm}^3/\text{min}:

    MRR=V⋅f⋅d(cm3/min)MRR = V \cdot f \cdot d \quad (\text{cm}^3/\text{min})

    where dd is depth of cut (mm), ff is feed rate (mm/rev), and VV is cutting speed (m/min).


Worked Step-by-Step Calculation: Lathe Turning

Problem: A cylindrical steel rod of diameter D=80 mmD = 80 \text{ mm} and length L=300 mmL = 300 \text{ mm} is turned on a lathe at a recommended cutting speed V=120 m/minV = 120 \text{ m/min}. The feed rate is set to f=0.30 mm/revf = 0.30 \text{ mm/rev} and depth of cut is d=2.5 mmd = 2.5 \text{ mm}. Allowance for tool entry/exit is Lo=10 mmL_o = 10 \text{ mm}. Calculate:

  1. The required lathe spindle speed NN.
  2. The total machining time TmT_m for one pass.
  3. The Material Removal Rate (MRRMRR) in cm3/min\text{cm}^3/\text{min}.

Step 1: Calculate Spindle Speed (NN)

N=1000VπD=1000×120π×80=120,000251.327=477.46 RPM≈477 RPMN = \frac{1000 V}{\pi D} = \frac{1000 \times 120}{\pi \times 80} = \frac{120,000}{251.327} = 477.46 \text{ RPM} \approx 477 \text{ RPM}

Step 2: Calculate Machining Time (TmT_m) Total travel length Ltotal=L+Lo=300+10=310 mmL_{\text{total}} = L + L_o = 300 + 10 = 310 \text{ mm}.

Tm=LtotalfN=3100.30×477.46=310143.238=2.164 min(2 min 10 sec)T_m = \frac{L_{\text{total}}}{f N} = \frac{310}{0.30 \times 477.46} = \frac{310}{143.238} = 2.164 \text{ min} \quad (2 \text{ min } 10 \text{ sec})

Step 3: Calculate Material Removal Rate (MRRMRR)

MRR=V⋅f⋅d=120 m/min×0.30 mm/rev×2.5 mm=90.0 cm3/minMRR = V \cdot f \cdot d = 120 \text{ m/min} \times 0.30 \text{ mm/rev} \times 2.5 \text{ mm} = 90.0 \text{ cm}^3/\text{min}

4. Milling Operations & Feed Rate Equations

Milling uses multi-tooth rotary cutters to produce flat, contoured, or slotted surfaces. It is categorized into face milling (cutting action on periphery and face) and end milling (cutting slots/pockets with side and end teeth).

Milling Feed Rate & Table Speed (VfV_f)

The linear feed rate of the worktable (VfV_f) depends on the feed per tooth (ftf_t), number of cutter teeth (zz), and spindle speed (NN):

Vf=ft⋅z⋅N(mm/min)V_f = f_t \cdot z \cdot N \quad (\text{mm/min}) MRR=w⋅d⋅Vf(mm3/min)MRR = w \cdot d \cdot V_f \quad (\text{mm}^3/\text{min})

where ww is the width of cut (mm) and dd is the depth of cut (mm).


Worked Step-by-Step Calculation: Milling MRR

Problem: A 100 mm100 \text{ mm} diameter face milling cutter with z=8z = 8 carbide teeth mills a flat steel plate of width w=80 mmw = 80 \text{ mm} at a depth of cut d=3.0 mmd = 3.0 \text{ mm}. The cutting speed is V=150 m/minV = 150 \text{ m/min} and feed per tooth is ft=0.15 mm/toothf_t = 0.15 \text{ mm/tooth}. Calculate:

  1. The spindle speed NN and table feed velocity VfV_f.
  2. The volumetric Material Removal Rate (MRRMRR) in cm3/min\text{cm}^3/\text{min}.

Step 1: Calculate Spindle Speed (NN)

N=1000VπD=1000×150π×100=477.46 RPMN = \frac{1000 V}{\pi D} = \frac{1000 \times 150}{\pi \times 100} = 477.46 \text{ RPM}

Step 2: Calculate Table Feed Rate (VfV_f)

Vf=ft⋅z⋅N=0.15 mm/tooth×8 teeth×477.46 RPM=572.95 mm/minV_f = f_t \cdot z \cdot N = 0.15 \text{ mm/tooth} \times 8 \text{ teeth} \times 477.46 \text{ RPM} = 572.95 \text{ mm/min}

Step 3: Calculate MRR

MRR=w⋅d⋅Vf=80 mm×3.0 mm×572.95 mm/min=137,508 mm3/min=137.51 cm3/minMRR = w \cdot d \cdot V_f = 80 \text{ mm} \times 3.0 \text{ mm} \times 572.95 \text{ mm/min} = 137,508 \text{ mm}^3/\text{min} = 137.51 \text{ cm}^3/\text{min}

5. Drilling, Grinding & Non-Traditional Machining

Drilling Calculations

Drilling produces cylindrical holes using a rotating twist drill bit. The drill point angle (typically 118∘118^\circ) adds an approach height hp=0.3Dh_p = 0.3 D to the hole depth hh. Total drilling time is:

Tm=h+0.3DfNT_m = \frac{h + 0.3 D}{f N}

Grinding

Grinding removes small chips using abrasive grains bonded in a grinding wheel. Grinding wheel surface speed VgV_g must be maintained between 20 and 35 m/s20 \text{ and } 35 \text{ m/s}:

Vg=πDgNg60,000(m/s)V_g = \frac{\pi D_g N_g}{60,000} \quad (\text{m/s})

Non-Traditional Machining Technologies

  1. Electrical Discharge Machining (EDM): Removes material via controlled electro-thermal spark erosion in a dielectric fluid (kerosene/deionized water). Machinability depends solely on thermal properties and electrical conductivity, regardless of material hardness (e.g., hardened tool steels, titanium).
  2. Electrochemical Machining (ECM): Controlled anodic dissolution according to Faraday's Law (m=ItMnFm = \frac{I t M}{n F}). Produces zero tool wear, zero thermal stress, and stress-free mirror finishes on hard alloys.
  3. Laser Beam Machining (LBM): Focuses high-intensity coherent light to melt and vaporize thin metal or ceramic sheets.
  4. Abrasive Waterjet Cutting (AWJC): Uses ultra-high pressure water (300−400 MPa300 - 400 \text{ MPa}) entrained with abrasive garnets to cold-cut thick metal plates without heat-affected zones (HAZ).
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Classification of Manufacturing Processes
Test Your Knowledge

A cylindrical shaft of diameter D = 50 mm is turned on a lathe at a spindle speed N = 500 RPM. What is the cutting speed V of the operation?

A

157.1 m/min

B

78.5 m/min

C

250.0 m/min

D

78.5 m/s

Test Your Knowledge

An end mill cutter with z = 4 teeth operates at a spindle speed N = 1000 RPM. If the recommended feed per tooth is f_t = 0.10 mm/tooth, what is the required table feed speed V_f?

A

100 mm/min

B

250 mm/min

C

400 mm/min

D

4000 mm/min

Test Your Knowledge

A spherical casting has a radius R = 50 mm. If the mold constant is B = 0.002 min/mm², what is the total solidification time of the casting according to Chvorinov's Rule?

A

0.556 min

B

1.111 min

C

2.222 min

D

5.000 min

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