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2.4 Biological Wastewater Treatment & Kinetics

Key Takeaways

  • BOD5 measures the oxygen consumed by microbes over 5 days; ultimate BOD (L0) is the total oxygen demand.

  • Monod kinetics describe biological growth as a function of substrate concentration.

  • The Activated Sludge process is governed by SRT (Mean Cell Residence Time) and the F/M ratio.

  • Biological Nutrient Removal (BNR) removes nitrogen via aerobic nitrification followed by anoxic denitrification.

  • Technologies like MBRs and MBBRs provide advanced treatment in smaller footprints compared to conventional activated sludge.

Last updated: July 2026

Biological Wastewater Treatment & Kinetics

Biological treatment harnesses dense cultures of microorganisms to consume organic pollutants and nutrients from wastewater. The primary goal is the reduction of oxygen-demanding substances to protect receiving waters from oxygen depletion.

Biochemical Oxygen Demand (BOD) Kinetics

BOD is the standard measure of organic pollution. It quantifies the amount of dissolved oxygen consumed by microorganisms while stabilizing organic matter. The standard test is run for 5 days at 20∘C20^\circ C (BOD5BOD_5).

The reaction follows first-order kinetics:

BODt=L0(1−e−kt)BOD_t = L_0 (1 - e^{-kt})

Where:

  • BODtBOD_t = Oxygen consumed at time tt (mg/L)
  • L0L_0 = Ultimate carbonaceous BOD (total oxygen demand, mg/L)
  • kk = BOD reaction rate constant (day−1day^{-1}, base ee)
  • tt = Time (days)

While BOD measures biodegradable organics, Chemical Oxygen Demand (COD) uses a strong chemical oxidant (dichromate) to measure almost all organic matter. Therefore, COD is always greater than or equal to BOD.

Monod Substrate Utilization Kinetics

The growth of biomass in a reactor is limited by the availability of food (substrate). This is modeled by the Monod equation:

μ=μmaxSKs+S\mu = \frac{\mu_{max} S}{K_s + S}

Where:

  • μ\mu = Specific growth rate of the biomass (day−1day^{-1})
  • μmax\mu_{max} = Maximum specific growth rate
  • SS = Substrate concentration (mg/L of BOD)
  • KsK_s = Half-velocity constant (substrate concentration at which μ=0.5μmax\mu = 0.5 \mu_{max})

This demonstrates that at high substrate concentrations (S≫KsS \gg K_s), growth is zero-order (maximum rate). At low concentrations (S≪KsS \ll K_s), growth is first-order with respect to the substrate.

The Activated Sludge Process

Activated sludge is a suspended-growth process. Wastewater enters an aeration basin where mixed liquor (biomass + wastewater) is continuously aerated. The mixture then flows to a secondary clarifier, where the biomass settles. Most of the settled sludge is returned to the aeration basin (Return Activated Sludge, RAS) to maintain a high active biomass concentration, known as Mixed Liquor Suspended Solids (MLSS). A fraction is wasted (Waste Activated Sludge, WAS) to control the system age.

Key Operational Parameters

  1. Mean Cell Residence Time (θc\theta_c or SRT): Also known as Sludge Age. It is the average time a microbe spends in the system. SRT=Mass of MLSS in Aeration BasinMass of Solids Wasted per Day=V⋅XQw⋅Xr+Qeff⋅XeSRT = \frac{\text{Mass of MLSS in Aeration Basin}}{\text{Mass of Solids Wasted per Day}} = \frac{V \cdot X}{Q_w \cdot X_r + Q_{eff} \cdot X_e}

  2. Food-to-Microorganism Ratio (F/M): Represents the daily organic loading per unit of biomass. F/M=Q⋅S0V⋅XF/M = \frac{Q \cdot S_0}{V \cdot X} Where QQ is inflow, S0S_0 is influent BOD, VV is basin volume, and XX is MLSS concentration. A low F/M ratio corresponds to a high SRT (starvation conditions, good settling). A high F/M ratio corresponds to a low SRT (rapid growth, poor settling).

  3. Hydraulic Retention Time (HRT): The average time water spends in the aeration basin. HRT=V/QHRT = V / Q.

Attached Growth and Advanced Technologies

  • Trickling Filters: Fixed-film systems where wastewater is distributed over a bed of rocks or plastic media. Microbes form a biofilm on the media. Oxygen is supplied by natural draft.
  • Moving Bed Biofilm Reactors (MBBR): Suspended plastic carriers provide surface area for biofilm growth within an aerated tank. It combines the benefits of activated sludge and fixed-film systems.
  • Membrane Bioreactors (MBR): Replaces the secondary clarifier of the activated sludge process with microfiltration or ultrafiltration membranes immersed directly in the aeration basin. This allows for extremely high MLSS concentrations and a very small physical footprint, producing high-quality effluent.

Biological Nutrient Removal (BNR)

Conventional activated sludge removes carbon but not nitrogen or phosphorus. BNR requires specific environmental zones (aerobic, anoxic, and anaerobic).

Nitrogen Removal

  1. Nitrification: An aerobic process where autotrophic bacteria (Nitrosomonas and Nitrobacter) oxidize toxic ammonia to nitrite, then to nitrate. NH4++2O2→NO3−+2H++H2ONH_4^+ + 2O_2 \rightarrow NO_3^- + 2H^+ + H_2O This process requires immense amounts of oxygen and destroys alkalinity, lowering the pH.

  2. Denitrification: An anoxic process (no dissolved oxygen, but nitrate is present). Heterotrophic bacteria strip the oxygen from nitrate, releasing harmless nitrogen gas. NO3−+Organics→N2(g)+CO2+H2ONO_3^- + \text{Organics} \rightarrow N_2(g) + CO_2 + H_2O

Enhanced Biological Phosphorus Removal (EBPR)

EBPR involves cycling biomass through an anaerobic zone (no DO, no nitrate) followed by an aerobic zone. Under anaerobic stress, Phosphorus Accumulating Organisms (PAOs) release phosphorus to consume volatile fatty acids. When subsequently aerated, they undergo "luxury uptake," consuming much more phosphorus than they released. The phosphorus is permanently removed when the sludge is wasted.

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Modified Ludzack-Ettinger (MLE) Process for Nitrogen Removal
Test Your Knowledge

In the context of the Activated Sludge process, what is the primary purpose of the Return Activated Sludge (RAS) line?

A

To provide a source of dissolved oxygen to the incoming primary effluent.

B

To maintain a high concentration of active biomass (MLSS) in the aeration basin.

C

To waste excess solids from the system and control the sludge age.

D

To convert nitrate to nitrogen gas in the secondary clarifier.

Test Your Knowledge

Which of the following environments is required for biological denitrification to occur?

A

Aerobic conditions with high dissolved oxygen.

B

Anaerobic conditions with no dissolved oxygen and no nitrate.

C

Anoxic conditions with nitrate present but no dissolved oxygen.

D

High pH conditions with excess alkalinity.

Test Your Knowledge

Based on BOD first-order kinetics, if the BOD reaction rate constant (k) increases due to a higher temperature, what happens to the 5-day BOD (BOD5) assuming L0 remains constant?

A

BOD5 decreases.

B

BOD5 remains exactly the same.

C

BOD5 increases, but will eventually exceed L0.

D

BOD5 increases, approaching L0 more rapidly.

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