7.4 Foundation and Retaining Wall Mechanics

Key Takeaways

  • Spread footings distribute structural loads over a broad area of soil; eccentric loads create a non-uniform pressure distribution that must be carefully calculated.
  • Deep foundations, like piles and drilled shafts, derive their load-carrying capacity from a combination of skin friction along the shaft and end bearing at the tip.
  • Retaining wall stability requires checking three primary failure modes: overturning, sliding, and bearing capacity failure.
  • Active earth pressure pushes a retaining wall outward, while passive earth pressure provides resistance against sliding.
  • The factor of safety against overturning is calculated as the ratio of resisting moments (due to the wall's weight) to overturning moments (due to lateral earth pressure).
Last updated: July 2026

Foundation and Retaining Wall Mechanics

The interface between a structure and the earth is governed by geotechnical engineering and structural mechanics. Foundations must safely transmit the loads from the superstructure into the ground without causing bearing capacity failure or excessive settlement. Retaining walls must hold back massive volumes of soil, resisting lateral earth pressures. For the PE Construction exam, you must be proficient in analyzing pressure distributions under footings and checking the stability of retaining systems, as these are critical tasks during excavation, shoring, and foundation construction.

Why This Topic Matters for the PE Construction Exam

Construction activities inherently involve moving earth and building temporary or permanent structures to hold it back. You may need to design a temporary thrust block, analyze the stability of an existing retaining wall during adjacent excavation, or verify the bearing pressure under a crane outrigger pad. The exam tests your ability to apply statics to soil masses and foundation elements, calculating overturning moments, sliding resistance, and base pressures.

Spread Footings and Pressure Distribution

Spread footings (shallow foundations) distribute concentrated column or wall loads over a sufficiently large area of soil so that the bearing pressure does not exceed the soil's allowable bearing capacity.

Uniform Pressure

When a vertical load ($P$) is applied exactly at the centroid of a footing with area ($A$), the pressure distribution is uniform:

q=PAq = \frac{P}{A}

Eccentric Loading

Loads are rarely perfectly concentric. Columns may transfer bending moments ($M$) to the footing, or the load $P$ may be applied at an eccentricity $e$ ($e = M/P$). This creates a non-uniform pressure distribution.

The combined stress formula is used to find the maximum and minimum soil pressures:

q=PA±MSq = \frac{P}{A} \pm \frac{M}{S}

Where $S$ is the section modulus of the footing base. For a rectangular footing of width $B$ and length $L$, $S = \frac{L B^2}{6}$ (bending about the axis parallel to L).

If the eccentricity $e > B/6$ (meaning the resultant force falls outside the "middle third" of the footing), the minimum calculated pressure becomes negative. Since soil cannot take tension, a different formula is required to calculate the peak pressure of the resulting triangular distribution.

Deep Foundations

When surface soils are weak, deep foundations (piles, drilled shafts, caissons) transfer loads to deeper, stronger strata.

Axial Capacity

The ultimate axial capacity ($Q_u$) of a deep foundation is the sum of two components:

Qu=Qs+QpQ_u = Q_s + Q_p

  1. Skin Friction ($Q_s$): The shear resistance generated along the sides of the pile shaft as it attempts to move through the soil. It is calculated by multiplying the unit friction resistance by the surface area of the shaft in contact with the soil.
  2. End Bearing ($Q_p$): The resistance generated at the very tip (toe) of the pile pushing into the bearing stratum. It is calculated by multiplying the unit bearing capacity by the cross-sectional area of the pile tip.

Pile Driving Formulas

During construction, dynamic pile driving formulas (like the Engineering News Record or ENR formula) are sometimes used to estimate pile capacity based on the energy of the hammer and the "set" (penetration per blow) of the pile during the final stages of driving.

Retaining Wall Stability

Retaining walls hold back soil, creating lateral earth pressures. The primary force pushing the wall is the active earth pressure. Resistance against sliding is provided by friction at the base and passive earth pressure acting on the buried toe of the wall.

Stability analysis involves checking three potential failure modes:

1. Overturning

The lateral earth pressure tends to tip the wall over, rotating about its front toe. The weight of the wall (and the soil resting on the heel of a cantilever wall) provides the resisting moment.

FSoverturning=MresistingMoverturningFS_{\text{overturning}} = \frac{\sum M_{\text{resisting}}}{\sum M_{\text{overturning}}}

A Factor of Safety (FS) of at least 1.5 to 2.0 is typically required.

2. Sliding

The lateral earth pressure pushes the wall horizontally. This is resisted by friction between the base of the footing and the soil, and sometimes by a keyway extending into the soil.

FSsliding=FresistingFdrivingFS_{\text{sliding}} = \frac{\sum F_{\text{resisting}}}{\sum F_{\text{driving}}}

The resisting force is calculated as $R = N \times \mu$, where $N$ is the total normal (vertical) force and $\mu$ is the coefficient of friction. An FS of 1.5 is standard.

3. Bearing Capacity

The combined vertical loads and overturning moments create a pressure distribution under the base (as described in the Spread Footings section). The maximum pressure ($q_{max}$) must not exceed the allowable bearing capacity of the soil.

Worked Check: Overturning and Sliding

Consider a solid concrete gravity retaining wall. Total weight of wall $W = 5,000$ lbs/ft acting at a distance of 2 ft from the toe. The lateral active earth pressure resultant force $P_a = 2,000$ lbs/ft acting horizontally at a height of 3 ft above the toe. Coefficient of friction $\mu = 0.5$.

  1. Overturning Check:

    • Overturning Moment: $M_o = P_a \times 3\text{ft} = 2,000 \times 3 = 6,000$ ft-lbs.
    • Resisting Moment: $M_r = W \times 2\text{ft} = 5,000 \times 2 = 10,000$ ft-lbs.
    • $FS_{\text{overturning}} = 10,000 / 6,000 = 1.67$ (Acceptable).
  2. Sliding Check:

    • Driving Force: $P_a = 2,000$ lbs.
    • Resisting Force (Friction): $F_r = W \times \mu = 5,000 \times 0.5 = 2,500$ lbs.
    • $FS_{\text{sliding}} = 2,500 / 2,000 = 1.25$ (Marginal/Low, often requires 1.5).
Test Your Knowledge

A footing is subjected to a vertical load and a bending moment, resulting in an eccentricity 'e'. According to the 'middle third' rule, what condition must be met to ensure that the entire base of the footing remains in compression (no tension in the soil)?

A
B
C
D
Test Your Knowledge

In the context of deep foundations, which of the following best describes 'skin friction'?

A
B
C
D