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3.1 Fractions: Types, Equivalencies & Operations

Key Takeaways

  • Rational numbers are numbers expressible as ab\frac{a}{b} where a,b∈Za, b \in \mathbb{Z} and b≠0b \neq 0; improper fractions (∣a∣≥b|a| \ge b) and mixed numbers represent the same quantity in different formats.

  • Adding and subtracting fractions with unlike denominators requires finding the Least Common Denominator (LCD), which is the Least Common Multiple (LCM) of the denominators.

  • Multiplying fractions involves multiplying numerators together and denominators together, while dividing fractions requires multiplying by the reciprocal of the divisor ("invert and multiply").

  • Simplifying fractions to lowest terms requires dividing both numerator and denominator by their Greatest Common Divisor (GCD), ensuring irreducible representation.

Last updated: August 2026

3.1 Fractions: Types, Equivalencies & Operations

Quick Summary: Rational numbers are numbers that can be written as a ratio of two integers ab\frac{a}{b} with b≠0b \neq 0. Mastering fraction arithmetic requires a fluent understanding of equivalent fractions, least common denominators for addition and subtraction, and reciprocal multiplication for division. In Ontario's Grade 7–9 mathematics curriculum, teachers must address common student misconceptions—such as adding numerators and denominators directly—by reinforcing visual area models, fraction strips, and algebraic field properties.


1. Classifying Rational Numbers & Fraction Forms

A rational number is any real number that can be expressed as the quotient of two integers ab\frac{a}{b}, where ( a ) is the numerator, ( b ) is the denominator, and b≠0b \neq 0. Rational numbers encompass integers, finite (terminating) decimals, repeating decimals, and fractions.

Fractions occur in three primary structural formats:

  1. Proper Fractions: The absolute value of the numerator is strictly less than the absolute value of the denominator (( |a| < b )). A proper fraction represents a quantity strictly between ( 0 ) and ( 1 ) (or ( -1 ) and ( 0 )). Examples: 34,710,−512\frac{3}{4}, \frac{7}{10}, -\frac{5}{12}.

  2. Improper Fractions: The absolute value of the numerator is greater than or equal to the absolute value of the denominator (∣a∣≥b|a| \ge b). An improper fraction represents a quantity greater than or equal to ( 1 ). Examples: 94,155,227\frac{9}{4}, \frac{15}{5}, \frac{22}{7}.

  3. Mixed Numbers: An expression combining a non-zero integer and a proper fraction, written in the form wabw\frac{a}{b} (which implicitly denotes w+abw + \frac{a}{b} for positive values). Examples: 214,3582\frac{1}{4}, 3\frac{5}{8}.

Conversion Algorithms

  • Converting Mixed Numbers to Improper Fractions: Multiply the whole number ( w ) by the denominator ( b ), add the numerator ( a ), and place the result over the original denominator:

    wab=w⋅b+abw\frac{a}{b} = \frac{w \cdot b + a}{b}

    Example: Convert 4374\frac{3}{7} to an improper fraction: 4⋅7+37=28+37=317\frac{4 \cdot 7 + 3}{7} = \frac{28 + 3}{7} = \frac{31}{7}.

  • Converting Improper Fractions to Mixed Numbers: Perform integer division of numerator ( a ) by denominator ( b ). The quotient becomes the whole number ( w ), and the remainder ( r ) becomes the new numerator over ( b ):

    ab=q+rb=qrbwhere a=q⋅b+r and 0≤r<b.\frac{a}{b} = q + \frac{r}{b} = q\frac{r}{b} \quad \text{where } a = q \cdot b + r \text{ and } 0 \le r < b.

    Example: Convert 385\frac{38}{5} to a mixed number: 38÷5=738 \div 5 = 7 with remainder ( 3 ), yielding 7357\frac{3}{5}.


2. Equivalent Fractions & Simplifying to Lowest Terms

The Fundamental Property of Fractions states that multiplying or dividing both the numerator and denominator of a fraction by the same non-zero real number ( k ) produces an equivalent fraction:

ab=a⋅kb⋅k=a÷kb÷k(b,k≠0)\frac{a}{b} = \frac{a \cdot k}{b \cdot k} = \frac{a \div k}{b \div k} \quad (b, k \neq 0)

Simplifying to Lowest Terms (Irreducible Form)

A fraction ab\frac{a}{b} is in lowest terms (or irreducible) when gcd⁡(a,b)=1\operatorname{gcd}(a, b) = 1; that is, the greatest common divisor of numerator ( a ) and denominator ( b ) is 1.

To simplify a fraction:

  1. Find the Greatest Common Divisor (GCD) of the numerator and denominator using prime factorization or the Euclidean Algorithm.
  2. Divide both numerator and denominator by the GCD.

Example: Simplify 84126\frac{84}{126}.

  • Prime factorization of 84: 22⋅3⋅72^2 \cdot 3 \cdot 7.
  • Prime factorization of 126: 2⋅32⋅72 \cdot 3^2 \cdot 7.
  • gcd⁡(84,126)=21⋅31⋅71=42\operatorname{gcd}(84, 126) = 2^1 \cdot 3^1 \cdot 7^1 = 42.
  • Divide numerator and denominator by 42: 84÷42126÷42=23\frac{84 \div 42}{126 \div 42} = \frac{2}{3}.

3. Addition and Subtraction of Fractions

Like Denominators

When denominators are identical, add or subtract the numerators while keeping the denominator unchanged:

ac±bc=a±bc\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

Unlike Denominators & Finding the Least Common Denominator (LCD)

When adding or subtracting fractions with different denominators:

  1. Determine the Least Common Denominator (LCD), which is the Least Common Multiple (LCM) of the denominators: LCD=lcm⁡(b,d)\text{LCD} = \operatorname{lcm}(b, d).
  2. Rewrite each fraction as an equivalent fraction with the LCD as its denominator.
  3. Add or subtract the numerators.
  4. Simplify the resulting fraction to lowest terms or a mixed number.
ab±cd=a⋅(LCDb)±c⋅(LCDd)LCD\frac{a}{b} \pm \frac{c}{d} = \frac{a \cdot \left(\frac{\text{LCD}}{b}\right) \pm c \cdot \left(\frac{\text{LCD}}{d}\right)}{\text{LCD}}

Example: Compute 56−38\frac{5}{6} - \frac{3}{8}.

  • lcm⁡(6,8)=24\operatorname{lcm}(6, 8) = 24.
  • Rewrite: 5⋅46⋅4−3⋅38⋅3=2024−924=1124\frac{5 \cdot 4}{6 \cdot 4} - \frac{3 \cdot 3}{8 \cdot 3} = \frac{20}{24} - \frac{9}{24} = \frac{11}{24}.

Mixed Number Addition & Subtraction Strategies

When operating on mixed numbers, candidate teachers can choose between two methods:

  • Method 1 (Improper Fraction Conversion): Convert all mixed numbers to improper fractions, compute using common denominators, and convert back. This method eliminates errors caused by regrouping/borrowing.
  • Method 2 (Whole and Fractional Part Separation): Separate whole numbers and fractions. When subtracting, if the fractional minuend is smaller than the fractional subtrahend, borrow ( 1 ) (written as dd\frac{d}{d}) from the whole number component.

4. Multiplication and Division of Fractions

Multiplication of Fractions

To multiply two fractions, multiply their numerators together and their denominators together:

ab×cd=a⋅cb⋅d\frac{a}{b} \times \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

Pedagogical Tip (Cross-Simplification): Simplify common factors between any numerator and any denominator before multiplying to keep calculations efficient and avoid large intermediate numbers.

Division of Fractions and Reciprocals

The multiplicative inverse or reciprocal of a non-zero fraction ab\frac{a}{b} is ba\frac{b}{a}, because ab×ba=1\frac{a}{b} \times \frac{b}{a} = 1.

To divide by a fraction, multiply by its reciprocal ("Invert and Multiply"):

ab÷cd=ab×dc=a⋅db⋅c(b,c,d≠0)\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c} = \frac{a \cdot d}{b \cdot c} \quad (b, c, d \neq 0)

Mathematical Proof/Justification: Multiply both the numerator fraction and denominator fraction of the complex fraction abcd\frac{\frac{a}{b}}{\frac{c}{d}} by the reciprocal of the denominator dc\frac{d}{c}:

abcd=ab×dccd×dc=a⋅db⋅c1=ab×dc\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{\frac{a}{b} \times \frac{d}{c}}{\frac{c}{d} \times \frac{d}{c}} = \frac{\frac{a \cdot d}{b \cdot c}}{1} = \frac{a}{b} \times \frac{d}{c}

5. Fraction Operations Summary Matrix

OperationRule / FormulaKey ActionWorked Example
Additionab+cd=ad+bcbd\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}Find LCD, convert, add numerators25+14=8+520=1320\frac{2}{5} + \frac{1}{4} = \frac{8 + 5}{20} = \frac{13}{20}
Subtractionab−cd=ad−bcbd\frac{a}{b} - \frac{c}{d} = \frac{ad - bc}{bd}Find LCD, convert, subtract numerators79−16=14−318=1118\frac{7}{9} - \frac{1}{6} = \frac{14 - 3}{18} = \frac{11}{18}
Multiplicationab×cd=a⋅cb⋅d\frac{a}{b} \times \frac{c}{d} = \frac{a \cdot c}{b \cdot d}Cross-cancel common factors first415×58=1⋅13⋅2=16\frac{4}{15} \times \frac{5}{8} = \frac{1 \cdot 1}{3 \cdot 2} = \frac{1}{6}
Divisionab÷cd=ab×dc\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}Invert divisor, multiply numerators & denominators310÷920=310×209=1⋅21⋅3=23\frac{3}{10} \div \frac{9}{20} = \frac{3}{10} \times \frac{20}{9} = \frac{1 \cdot 2}{1 \cdot 3} = \frac{2}{3}

6. Step-by-Step Worked Problems

Worked Problem 1: Mixed Number Subtraction with Borrowing

Problem: Evaluate 716−3347\frac{1}{6} - 3\frac{3}{4} and express the result as a mixed number in lowest terms.

Step-by-Step Solution:

  1. Method 1: Convert to Improper Fractions

    • Convert 7167\frac{1}{6}: 7⋅6+16=436\frac{7 \cdot 6 + 1}{6} = \frac{43}{6}.
    • Convert 3343\frac{3}{4}: 3⋅4+34=154\frac{3 \cdot 4 + 3}{4} = \frac{15}{4}.
  2. Find the Least Common Denominator (LCD)

    • Denominators are 6 and 4. lcm⁡(6,4)=12\operatorname{lcm}(6, 4) = 12.
  3. Convert to Equivalent Fractions with Denominator 12

    • 436=43⋅26⋅2=8612\frac{43}{6} = \frac{43 \cdot 2}{6 \cdot 2} = \frac{86}{12}.
    • 154=15⋅34⋅3=4512\frac{15}{4} = \frac{15 \cdot 3}{4 \cdot 3} = \frac{45}{12}.
  4. Subtract Numerators

    8612−4512=86−4512=4112\frac{86}{12} - \frac{45}{12} = \frac{86 - 45}{12} = \frac{41}{12}
  5. Convert Back to a Mixed Number

    • 41÷12=341 \div 12 = 3 with a remainder of ( 5 ).
    • Final Answer: 35123\frac{5}{12}.

Worked Problem 2: Recipe Scaling Multi-Step Problem

Problem: A catering recipe that serves 6 people requires 2142\frac{1}{4} cups of milk. A chef needs to scale the recipe to serve 15 people. The chef has a container with 5 cups of milk. How much additional milk is needed, or how much milk will be left over?

Step-by-Step Solution:

  1. Calculate the Scaling Factor

    Scale Factor=Target ServingsOriginal Servings=156=52=2.5\text{Scale Factor} = \frac{\text{Target Servings}}{\text{Original Servings}} = \frac{15}{6} = \frac{5}{2} = 2.5
  2. Calculate Total Milk Required

    • Convert 2142\frac{1}{4} to improper fraction: 94\frac{9}{4}.
    • Multiply by scale factor 52\frac{5}{2}: Milk Required=94×52=458 cups\text{Milk Required} = \frac{9}{4} \times \frac{5}{2} = \frac{45}{8} \text{ cups}
    • Express as a mixed number: 45÷8=55845 \div 8 = 5\frac{5}{8} cups.
  3. Compare Available Milk to Required Milk

    • Milk available: ( 5 ) cups =408= \frac{40}{8} cups.
    • Difference: 408−458=−58\frac{40}{8} - \frac{45}{8} = -\frac{5}{8} cups.
    • Final Answer: The chef does not have enough milk; an additional 58\frac{5}{8} cup of milk is needed.

Worked Problem 3: Shared Measurement Allocation Word Problem

Problem: An art teacher has a spool of decorative ribbon measuring 183418\frac{3}{4} metres. She cuts pieces measuring 1381\frac{3}{8} metres each for a student project. How many complete pieces can she cut, and what is the exact length of the remaining ribbon leftover on the spool?

Step-by-Step Solution:

  1. Set Up Division for Number of Pieces

    Number of pieces=1834÷138\text{Number of pieces} = 18\frac{3}{4} \div 1\frac{3}{8}
  2. Convert to Improper Fractions

    • 1834=18⋅4+34=75418\frac{3}{4} = \frac{18 \cdot 4 + 3}{4} = \frac{75}{4}.
    • 138=1⋅8+38=1181\frac{3}{8} = \frac{1 \cdot 8 + 3}{8} = \frac{11}{8}.
  3. Apply Invert and Multiply Rule

    754÷118=754×811=75⋅21⋅11=15011\frac{75}{4} \div \frac{11}{8} = \frac{75}{4} \times \frac{8}{11} = \frac{75 \cdot 2}{1 \cdot 11} = \frac{150}{11}
  4. Extract Complete Pieces and Fractional Part

    • 150÷11=13150 \div 11 = 13 with remainder ( 7 ), so 15011=13711\frac{150}{11} = 13\frac{7}{11}.
    • This yields 13 complete pieces.
  5. Calculate Remaining Length in Metres

    • Length used for 13 pieces: 13×138=13×118=1438=177813 \times 1\frac{3}{8} = 13 \times \frac{11}{8} = \frac{143}{8} = 17\frac{7}{8} metres.
    • Remaining ribbon on spool: 1834−1778=754−1438=1508−1438=7818\frac{3}{4} - 17\frac{7}{8} = \frac{75}{4} - \frac{143}{8} = \frac{150}{8} - \frac{143}{8} = \frac{7}{8} metre.
    • Final Answer: 13 complete pieces can be cut, with 78\frac{7}{8} metre of ribbon remaining.
Test Your Knowledge

Evaluate 615−2346\frac{1}{5} - 2\frac{3}{4} and express the result as a mixed number in lowest terms.

A

39203\frac{9}{20}

B

37203\frac{7}{20}

C

49204\frac{9}{20}

D

313203\frac{13}{20}

Test Your Knowledge

A mathematics teacher has 8348\frac{3}{4} cups of liquid solution for a chemistry demonstration. Each experiment group requires 78\frac{7}{8} cup. How many complete experiment groups can be supplied?

A

8 groups

B

9 groups

C

10 groups

D

11 groups

Test Your Knowledge

A Grade 7 student calculates 25+13=38\frac{2}{5} + \frac{1}{3} = \frac{3}{8}. Which pedagogical diagnostic correctly identifies the student's error and provides the correct answer?

A

The student multiplied numerators and denominators instead of adding; the correct answer is 215\frac{2}{15}.

B

The student added the numerators directly and added the denominators directly; the correct answer is 1115\frac{11}{15}.

C

The student inverted the second fraction before adding; the correct answer is 65\frac{6}{5}.

D

The student found a common denominator but subtracted instead of adding; the correct answer is 115\frac{1}{15}.

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